Samacheer Kalvi Class 5 Maths Solutions Term 3 Chapter 1 Geometry Exercise 1.1

Get the most accurate TN Board Solutions for Class 5 Maths Chapter 01 Geometry here. Updated for the 2026-27 academic session, these solutions are based on the latest TN Board textbooks for Class 5 Maths. Our expert-created answers for Class 5 Maths are available for free download in PDF format.

Detailed Chapter 01 Geometry TN Board Solutions for Class 5 Maths

For Class 5 students, solving TN Board textbook questions is the most effective way to build a strong conceptual foundation. Our Class 5 Maths solutions follow a detailed, step-by-step approach to ensure you understand the logic behind every answer. Practicing these Chapter 01 Geometry solutions will improve your exam performance.

Class 5 Maths Chapter 01 Geometry TN Board Solutions PDF

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 3 Chapter 1 Geometry Ex 1.1

 

Question 1. How much wire will be needed to make a rectangle of length 6 cm and breadth 3 cm?
Answer: To find the amount of wire needed, we need to calculate the perimeter of the rectangle. A rectangle has two lengths and two breadths. The perimeter is found by adding up all the sides. So, the perimeter is \( 6 \text{ cm} + 3 \text{ cm} + 6 \text{ cm} + 3 \text{ cm} = 18 \text{ cm} \). This means 18 cm of wire will be needed.
In simple words: Add all four sides of the rectangle to find the total length of wire. The perimeter is 18 cm.

🎯 Exam Tip: Remember the formula for the perimeter of a rectangle: \( 2 \times (\text{length} + \text{breadth}) \). This makes calculations quicker and helps avoid mistakes.

 

Question 2. If the length of a rectangle is 14 m and its breadth is 10 m, what is its perimeter?
Answer: The perimeter of a rectangle is the total distance around its boundary. We can calculate this by adding the lengths of all four sides. Since opposite sides of a rectangle are equal, the perimeter is \( 14 \text{ m} + 10 \text{ m} + 14 \text{ m} + 10 \text{ m} = 48 \text{ m} \). So, the perimeter of this rectangle is 48 meters.
In simple words: Add the two lengths and two breadths together to get the perimeter. The perimeter is 48 meters.

🎯 Exam Tip: Always include the correct units (like meters or centimeters) in your final answer for perimeter or area questions.

 

Question 3. Each side of a square is 7 m long. Find its perimeter.
Answer: A square has four sides that are all equal in length. To find the perimeter, we add the length of each side together. So, the perimeter is \( 7 \text{ m} + 7 \text{ m} + 7 \text{ m} + 7 \text{ m} = 28 \text{ m} \). You can also multiply the side length by 4 for a square.
In simple words: A square has four equal sides. Add 7 meters four times to find the perimeter, which is 28 meters.

🎯 Exam Tip: For squares, remember the simple formula: Perimeter = \( 4 \times \text{side} \). This is a shortcut for adding all four equal sides.

 

Question 4. If we take 2 rounds of a field, that is 340 m long and 160 m wide. Find the distance covered in kilometers?
Answer: First, we need to find the perimeter of the rectangular field for one round. The perimeter is \( 340 \text{ m} + 160 \text{ m} + 340 \text{ m} + 160 \text{ m} = 1000 \text{ m} \). Since 1000 meters is equal to 1 kilometer, one round covers 1 km. For 2 rounds, the total distance covered is \( 2 \times 1 \text{ km} = 2 \text{ km} \).
In simple words: Find the distance around the field (perimeter) for one round. Then, multiply that by 2 because you take two rounds. Convert the total distance from meters to kilometers. The distance covered is 2 km.

🎯 Exam Tip: Always pay attention to the units requested in the question (e.g., kilometers instead of meters) and convert your final answer accordingly.

 

Question 5. Sanju completes 10 rounds around a square park every day. If one side of the park is 110 m, then find the distance covered by Sanju in a day in terms of kilometers and metres.
Answer: First, let's find the perimeter of the square park for one round. Since each side is 110 m, the perimeter is \( 4 \times 110 \text{ m} = 440 \text{ m} \). Sanju completes 10 rounds, so the total distance covered is \( 10 \times 440 \text{ m} = 4400 \text{ m} \). To convert this to kilometers, we divide by 1000 (because 1 km = 1000 m). So, \( \frac{4400}{1000} \text{ km} = 4.4 \text{ km} \). This can also be written as 4 kilometers and 400 meters.
In simple words: Calculate the perimeter of the square park for one round. Multiply it by 10 for 10 rounds. Then, change the total distance from meters to kilometers and meters. Sanju covers 4.4 km or 4 km and 400 m.

🎯 Exam Tip: When converting between meters and kilometers, remember that 1000 meters make 1 kilometer. This conversion is a common step in distance problems.

TN Board Solutions Class 5 Maths Chapter 01 Geometry

Students can now access the TN Board Solutions for Chapter 01 Geometry prepared by teachers on our website. These solutions cover all questions in exercise in your Class 5 Maths textbook. Each answer is updated based on the current academic session as per the latest TN Board syllabus.

Detailed Explanations for Chapter 01 Geometry

Our expert teachers have provided step-by-step explanations for all the difficult questions in the Class 5 Maths chapter. Along with the final answers, we have also explained the concept behind it to help you build stronger understanding of each topic. This will be really helpful for Class 5 students who want to understand both theoretical and practical questions. By studying these TN Board Questions and Answers your basic concepts will improve a lot.

Benefits of using Maths Class 5 Solved Papers

Using our Maths solutions regularly students will be able to improve their logical thinking and problem-solving speed. These Class 5 solutions are a guide for self-study and homework assistance. Along with the chapter-wise solutions, you should also refer to our Revision Notes and Sample Papers for Chapter 01 Geometry to get a complete preparation experience.

FAQs

Where can I find the latest Samacheer Kalvi Class 5 Maths Solutions Term 3 Chapter 1 Geometry Exercise 1.1 for the 2026-27 session?

The complete and updated Samacheer Kalvi Class 5 Maths Solutions Term 3 Chapter 1 Geometry Exercise 1.1 is available for free on StudiesToday.com. These solutions for Class 5 Maths are as per latest TN Board curriculum.

Are the Maths TN Board solutions for Class 5 updated for the new 50% competency-based exam pattern?

Yes, our experts have revised the Samacheer Kalvi Class 5 Maths Solutions Term 3 Chapter 1 Geometry Exercise 1.1 as per 2026 exam pattern. All textbook exercises have been solved and have added explanation about how the Maths concepts are applied in case-study and assertion-reasoning questions.

How do these Class 5 TN Board solutions help in scoring 90% plus marks?

Toppers recommend using TN Board language because TN Board marking schemes are strictly based on textbook definitions. Our Samacheer Kalvi Class 5 Maths Solutions Term 3 Chapter 1 Geometry Exercise 1.1 will help students to get full marks in the theory paper.

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Yes, we provide bilingual support for Class 5 Maths. You can access Samacheer Kalvi Class 5 Maths Solutions Term 3 Chapter 1 Geometry Exercise 1.1 in both English and Hindi medium.

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