Samacheer Kalvi Class 5 Maths Solutions Term 3 Chapter 1 Geometry Exercise 1.1

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Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 3 Chapter 1 Geometry Ex 1.1

 

Question 1. How much wire will be needed to make a rectangle of length 6 cm and breadth 3 cm?
Answer: To find the amount of wire needed, we need to calculate the perimeter of the rectangle. A rectangle has two lengths and two breadths. The perimeter is found by adding up all the sides. So, the perimeter is \( 6 \text{ cm} + 3 \text{ cm} + 6 \text{ cm} + 3 \text{ cm} = 18 \text{ cm} \). This means 18 cm of wire will be needed.
In simple words: Add all four sides of the rectangle to find the total length of wire. The perimeter is 18 cm.

🎯 Exam Tip: Remember the formula for the perimeter of a rectangle: \( 2 \times (\text{length} + \text{breadth}) \). This makes calculations quicker and helps avoid mistakes.

 

Question 2. If the length of a rectangle is 14 m and its breadth is 10 m, what is its perimeter?
Answer: The perimeter of a rectangle is the total distance around its boundary. We can calculate this by adding the lengths of all four sides. Since opposite sides of a rectangle are equal, the perimeter is \( 14 \text{ m} + 10 \text{ m} + 14 \text{ m} + 10 \text{ m} = 48 \text{ m} \). So, the perimeter of this rectangle is 48 meters.
In simple words: Add the two lengths and two breadths together to get the perimeter. The perimeter is 48 meters.

🎯 Exam Tip: Always include the correct units (like meters or centimeters) in your final answer for perimeter or area questions.

 

Question 3. Each side of a square is 7 m long. Find its perimeter.
Answer: A square has four sides that are all equal in length. To find the perimeter, we add the length of each side together. So, the perimeter is \( 7 \text{ m} + 7 \text{ m} + 7 \text{ m} + 7 \text{ m} = 28 \text{ m} \). You can also multiply the side length by 4 for a square.
In simple words: A square has four equal sides. Add 7 meters four times to find the perimeter, which is 28 meters.

🎯 Exam Tip: For squares, remember the simple formula: Perimeter = \( 4 \times \text{side} \). This is a shortcut for adding all four equal sides.

 

Question 4. If we take 2 rounds of a field, that is 340 m long and 160 m wide. Find the distance covered in kilometers?
Answer: First, we need to find the perimeter of the rectangular field for one round. The perimeter is \( 340 \text{ m} + 160 \text{ m} + 340 \text{ m} + 160 \text{ m} = 1000 \text{ m} \). Since 1000 meters is equal to 1 kilometer, one round covers 1 km. For 2 rounds, the total distance covered is \( 2 \times 1 \text{ km} = 2 \text{ km} \).
In simple words: Find the distance around the field (perimeter) for one round. Then, multiply that by 2 because you take two rounds. Convert the total distance from meters to kilometers. The distance covered is 2 km.

🎯 Exam Tip: Always pay attention to the units requested in the question (e.g., kilometers instead of meters) and convert your final answer accordingly.

 

Question 5. Sanju completes 10 rounds around a square park every day. If one side of the park is 110 m, then find the distance covered by Sanju in a day in terms of kilometers and metres.
Answer: First, let's find the perimeter of the square park for one round. Since each side is 110 m, the perimeter is \( 4 \times 110 \text{ m} = 440 \text{ m} \). Sanju completes 10 rounds, so the total distance covered is \( 10 \times 440 \text{ m} = 4400 \text{ m} \). To convert this to kilometers, we divide by 1000 (because 1 km = 1000 m). So, \( \frac{4400}{1000} \text{ km} = 4.4 \text{ km} \). This can also be written as 4 kilometers and 400 meters.
In simple words: Calculate the perimeter of the square park for one round. Multiply it by 10 for 10 rounds. Then, change the total distance from meters to kilometers and meters. Sanju covers 4.4 km or 4 km and 400 m.

🎯 Exam Tip: When converting between meters and kilometers, remember that 1000 meters make 1 kilometer. This conversion is a common step in distance problems.

TN Board Solutions for Class 5 Maths Chapter 01 Geometry

Chapter Exercise Answers for Class 5 Maths

Review comprehensive exercise answers for Class 5 Maths Chapter 01 Geometry. Fully updated to match current TN Board syllabus guidelines, these textbook solutions help students verify their work and maintain accurate study notes.

Detailed Answer Guides for Chapter 01 Geometry

Clear, methodical explanations accompany every challenging problem within the Class 5 Maths text. Engaging with these detailed answers lays a solid foundation for advanced learning and improves foundational clarity for upcoming assessments.

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Yes, our experts have revised the Samacheer Kalvi Class 5 Maths Solutions Term 3 Chapter 1 Geometry Exercise 1.1 as per 2026 exam pattern. All textbook exercises have been solved and have added explanation about how the Maths concepts are applied in case-study and assertion-reasoning questions.

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