Samacheer Kalvi Class 4 Maths Solutions Term 3 Chapter 5 Money Exercise 5.4

Step-by-Step Textbook Solutions for Class 4 Maths Chapter 05 Money

Access comprehensive textbook solutions for Chapter 05 Money using the official curriculum guides for Class 4 Maths. Designed to align with the 2026-27 TN Board standards, these detailed answers help students reinforce core academic concepts.

Download Chapter 05 Money Textbook Solutions PDF

View or download the dedicated Chapter 05 Money solution resource below. Engaging with these textbook answers under focused study conditions ensures continuous academic progress and mastery of the 2026-27 curriculum for Maths.

Question 1. Priya bought 20 balloons. If the cost of one balloon is Rs 6, then find the cost of 20 balloons.
Answer: First, we know the cost of one balloon is Rs 6. To find the cost of 20 balloons, we need to multiply the number of balloons by the cost of one balloon.
Cost of one balloon = Rs 6
Cost of 20 balloons = \( 20 \times 6 \)
Cost of 20 balloons = Rs 120.
So, Priya spent Rs 120 in total for 20 balloons. Buying in bulk often helps in planning party expenses.
In simple words: To find the total cost, we multiply the number of balloons (20) by the price of one balloon (Rs 6), which gives Rs 120.

🎯 Exam Tip: When finding the total cost for multiple items, always multiply the number of items by the cost of one item. Make sure to include the correct currency symbol in your final answer.

 

Question 2. Chinthamani bought 28 chocolate for her birthday. If the cost of a chocolate is Rs 7 then find the total cost of 28 chocolates.
Answer: We are given the cost of one chocolate and the number of chocolates Chinthamani bought. To find the total cost, we multiply these two values.
Cost of one chocolate = Rs 7
Number of chocolates = 28
Total cost of 28 chocolates = \( 28 \times 7 \)
Total cost of 28 chocolates = Rs 196.
So, Chinthamani spent Rs 196 for all the chocolates for her birthday. It is important to calculate total expenses when planning events.
In simple words: Multiply the number of chocolates (28) by the cost of one chocolate (Rs 7) to get the total cost, which is Rs 196.

🎯 Exam Tip: Clearly state the given information and the operation (multiplication in this case) you are using to solve the problem. Double-check your multiplication for accuracy.

 

Question 3. Ashok purchased 9 decorative papers at the cost of Rs 450 for his town festival. Find the cost of a decorative paper?
Answer: Here, we know the total cost for many items and the number of items. To find the cost of just one item, we need to divide the total cost by the number of items.
Cost of 9 decorative papers = Rs 450
Number of decorative papers = 9
Cost of 1 decorative paper = \( \text{Rs } 450 \div 9 \)
Cost of 1 decorative paper = Rs 50.
Each decorative paper cost Rs 50. Knowing the unit cost helps in budgeting for future purchases.
In simple words: To find the cost of one paper, divide the total cost (Rs 450) by the number of papers (9), which gives Rs 50 per paper.

🎯 Exam Tip: When given a total cost for multiple items and asked for the cost of one, always use division. Ensure your division is accurate and present the answer with the correct unit.

 

Question 4. Geethanjali bought 10 pencils at the cost of Rs 70 from the supermarket. Find the cost of a pencil?
Answer: Geethanjali bought 10 pencils for a total of Rs 70. To find the cost of a single pencil, we will divide the total amount paid by the number of pencils.
Cost of 10 pencils = Rs 70
Number of pencils = 10
Cost of 1 pencil = \( \text{Rs } 70 \div 10 \)
Cost of 1 pencil = Rs 7.
So, each pencil cost Rs 7. Understanding the price per item is useful for smart shopping.
In simple words: Divide the total money spent (Rs 70) by the number of pencils (10) to find that each pencil cost Rs 7.

🎯 Exam Tip: Remember that division helps you find the value of a single unit when you know the total value and quantity. Practice simple division facts for quick calculations.

 

Question 5. Kuppan bought pencil and pen for Rs 24.50 and Rs 6.50 from his total amount Rs 50. Find the total cost of things that he bought. Also find the balance amount?
Answer: First, we need to find the total money Kuppan spent on the pencil and pen. Then, we will find out how much money he has left from his total amount.
Price of a pencil = Rs 24.50
Price of a pen = Rs 6.50
Total cost of items bought (Sum) = Rs \( 24.50 + 6.50 \)
Total cost of items bought = Rs 31.00.
Total amount Kuppan had = Rs 50.00
Balance amount = Total amount - Total cost of items
Balance amount = Rs \( 50.00 - 31.00 \)
Balance amount = Rs 19.00.
Kuppan spent Rs 31.00 and has Rs 19.00 left. Always check if you have enough money before making purchases.
In simple words: Kuppan spent Rs 24.50 for a pencil and Rs 6.50 for a pen, so he spent a total of Rs 31.00. From his Rs 50.00, he has Rs 19.00 left over.

🎯 Exam Tip: This question has two parts: finding the total cost and finding the balance. Make sure to answer both parts clearly. Decimal addition and subtraction require careful alignment of the decimal point.

 

Question 6. A teacher went to the science exhibition with their student. The entry fee is Rs 250 and the teacher bought some materials for the school for Rs 320, she had the balance amount of Rs 330, find the amount that she had?
Answer: To find the total amount of money the teacher had initially, we need to add up all the money she spent and the money she had left as a balance.
Entry fee = Rs 250
Cost of materials = Rs 320
Balance amount remaining = Rs 330
Total amount she had = Entry fee + Cost of materials + Balance amount
Total amount she had = Rs \( 250 + 320 + 330 \)
Total amount she had = Rs 900.
The teacher started with Rs 900. It's like working backward to find the original amount.
In simple words: Add the money spent on entry fee (Rs 250), materials (Rs 320), and the money she had left (Rs 330) to find the total amount she had at the start, which is Rs 900.

🎯 Exam Tip: When finding an initial amount, sum up all expenses and the remaining balance. This helps reconstruct the starting financial position.

Free TN Board Textbook Explanations: Class 4 Maths Chapter 05 Money

Accessing Chapter 05 Money Solutions

Review comprehensive exercise answers for Class 4 Maths Chapter 05 Money. Fully updated to match current TN Board syllabus guidelines, these textbook solutions help students verify their work and maintain accurate study notes.

Concept-Driven Answers for Class 4 Maths

Clear, methodical explanations accompany every challenging problem within the Class 4 Maths text. Engaging with these detailed answers lays a solid foundation for advanced learning and improves foundational clarity for upcoming assessments.

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FAQs

Where can I find the latest Samacheer Kalvi Class 4 Maths Solutions Term 3 Chapter 5 Money Exercise 5.4 for the 2026-27 session?

The complete and updated Samacheer Kalvi Class 4 Maths Solutions Term 3 Chapter 5 Money Exercise 5.4 is available for free on StudiesToday.com. These solutions for Class 4 Maths are as per latest TN Board curriculum.

Are the Maths TN Board solutions for Class 4 updated for the new 50% competency-based exam pattern?

Yes, our experts have revised the Samacheer Kalvi Class 4 Maths Solutions Term 3 Chapter 5 Money Exercise 5.4 as per 2026 exam pattern. All textbook exercises have been solved and have added explanation about how the Maths concepts are applied in case-study and assertion-reasoning questions.

How do these Class 4 TN Board solutions help in scoring 90% plus marks?

Toppers recommend using TN Board language because TN Board marking schemes are strictly based on textbook definitions. Our Samacheer Kalvi Class 4 Maths Solutions Term 3 Chapter 5 Money Exercise 5.4 will help students to get full marks in the theory paper.

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Yes, we provide bilingual support for Class 4 Maths. You can access Samacheer Kalvi Class 4 Maths Solutions Term 3 Chapter 5 Money Exercise 5.4 in both English and Hindi medium.

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