Step-by-Step Textbook Solutions for Class 4 Maths Chapter 04 Measurements
Review structured textbook solutions for Class 4 Maths Chapter 04 Measurements. Built according to TN Board guidelines for the 2026-27 academic year, these downloadable answers support daily revision and problem-solving accuracy.
Download Chapter 04 Measurements Textbook Solutions PDF
Navigate directly to the solved Maths textbook exercises using the digital viewer below. Each solution includes detailed step-by-step explanations, allowing students to instantly cross-check their work and identify areas requiring further revision.
Tamilnadu Samacheer Kalvi 4th Maths Solutions Term 1 Chapter 4 Measurements Ex 4.4
Question 1. Deenu bought 15 m 43 cm of shirt material and 23 m 94cm of trouser material. Find the total length of the material bought by him.
Answer:
Deenu bought shirt material = 15 m 43 cm
Deenu bought trouser material = 23 m 94 cm
To find the total length, we add the measurements:
\( \begin{array}{r@{\,}l@{\quad}r} \text{m} & \text{cm} \\ 15 & 43 \\ + \quad 23 & 94 \\ \hline \mathbf{39} & \mathbf{37} \\ \hline \end{array} \)
When adding, 43 cm + 94 cm = 137 cm. Since 100 cm makes 1 m, we carry over 1 m and 37 cm remains. Then, 15 m + 23 m + 1 m (carried over) = 39 m.
Total length of material = 39 m 37 cm
In simple words: To find the total material, we add the length of shirt material and trouser material. Remember to convert 100 cm into 1 meter when adding.
🎯 Exam Tip: When adding measurements like meters and centimeters, always add centimeters first. If the sum of centimeters is 100 or more, convert 100 cm to 1 m and add it to the meter column.
Question 2. A fisherman bought 2 nets. The length of first and second nets are 23 m 43 cm and 25m 63 cm. What is the total length of nets?
Answer:
First Net length = 23 m 43 cm
Second Net length = 25 m 63 cm
To find the total length, we add the two net lengths:
\( \begin{array}{r@{\,}l@{\quad}r} \text{m} & \text{cm} \\ 23 & 43 \\ + \quad 25 & 63 \\ \hline \mathbf{49} & \mathbf{06} \\ \hline \end{array} \)
Adding 43 cm + 63 cm gives 106 cm. We convert 100 cm into 1 m, leaving 6 cm. The 1 m is then added to the meter column: 23 m + 25 m + 1 m = 49 m.
Total length of the net = 49 m 06 cm
In simple words: We add the lengths of the two nets. If the sum of centimeters is more than 99, we convert 100 cm to 1 meter and carry it over to the meter sum.
🎯 Exam Tip: Always align the 'm' (meters) and 'cm' (centimeters) columns correctly when doing addition or subtraction to avoid errors, just like with standard numbers.
Question 3. Agathiya bought 70m 42cm of wire to fence his garden. He used only 43m 51cm of wire. Find the length of the remaining wire.
Answer:
Total length of wire = 70 m 42 cm
Agathiya used wire = 43 m 51 cm
To find the remaining wire, we subtract the used length from the total length:
\( \begin{array}{r@{\,}l@{\quad}r} \text{m} & \text{cm} \\ ^69 & ^{142} \\ 70 & 42 \\ - \quad 43 & 51 \\ \hline \mathbf{26} & \mathbf{91} \\ \hline \end{array} \)
Since 42 cm is less than 51 cm, we borrow 1 m (which is 100 cm) from 70 m. So, 70 m becomes 69 m, and 42 cm becomes 142 cm. Now, 142 cm - 51 cm = 91 cm. And 69 m - 43 m = 26 m.
Remaining length of wire = 26 m 91 cm
In simple words: To find out how much wire is left, subtract the used wire length from the total wire length. You might need to borrow from the meter part if the centimeter part is too small.
🎯 Exam Tip: When subtracting measurements, if the centimeters to be subtracted are more than the available centimeters, borrow 1 meter (which is 100 cm) from the meters column. This is a common point of error.
Question 4. A shopkeeper sold 37m 69cm cloth out of 93 m 75cm in stock. How much stock is left with him?
Answer:
Total stock of cloth = 93 m 75 cm
Cloth sold = 37 m 69 cm
To find the remaining stock, we subtract the sold cloth from the total stock:
\( \begin{array}{r@{\,}l@{\quad}r} \text{m} & \text{cm} \\ ^8 & ^13 & ^6 & ^{15} \\ 9 & 3 & 7 & 5 \\ - \quad 3 & 7 & 6 & 9 \\ \hline \mathbf{5} & \mathbf{6} & \mathbf{0} & \mathbf{6} \\ \hline \end{array} \)
Starting with centimeters, 75 cm is greater than 69 cm, so we can directly subtract: 75 cm - 69 cm = 6 cm. For meters, we need to subtract 37 m from 93 m. We borrow from the tens place of meters to make the subtraction possible. 93 m - 37 m = 56 m. So, the remaining cloth is 56 m 06 cm. Note that the source image shows a different borrowing method than a standard subtraction, but the result is correct for 93-37.
Remaining cloth = 56 m 06 cm
In simple words: To find how much cloth is left, take away the amount sold from the total amount. This is a simple subtraction problem.
🎯 Exam Tip: Always double-check your subtraction by adding the result to the subtracted number to see if it equals the original total. For instance, 56 m 06 cm + 37 m 69 cm should equal 93 m 75 cm.
Question 5. I bought 125 metres of orange fabric and 50 metres of yellow fabric in a fabric shop. I have used 13 metres of the orange fabric and 12 metres of yellow fabric. How many metres of fabric is remaining with me?
Answer:
Length of orange fabric bought = 125 m
Length of yellow fabric bought = 50 m
Total fabric bought = 125 m + 50 m = 175 m
Fabric used: 13 m orange + 12 m yellow = 25 m
Remaining fabric = Total fabric bought - Total fabric used
Remaining fabric = 175 m - 25 m = 150 m
So, 150 metres of fabric is remaining.
In simple words: First, add all the fabric bought. Then, add all the fabric used. Finally, subtract the used fabric from the total bought fabric to find what is left.
🎯 Exam Tip: Break down word problems with multiple steps into smaller, manageable calculations. First, find the total quantity bought, then the total quantity used, and finally perform the final operation.
Question 6. Velu is 1 m 15 cm tall. Her friend Babu is 1 m 30 cm tall. Who is taller and by how much?
Answer:
Babu's height = 1 m 30 cm
Velu's height = 1 m 15 cm
To find who is taller and by how much, we compare their heights and subtract:
\( \begin{array}{r@{\,}l@{\quad}r} \text{m} & \text{cm} \\ 1 & 30 \\ - \quad 1 & 15 \\ \hline \mathbf{0} & \mathbf{15} \\ \hline \end{array} \)
Comparing 1 m 30 cm and 1 m 15 cm, Babu is taller because 30 cm is more than 15 cm. To find the difference, we subtract Velu's height from Babu's height. 30 cm - 15 cm = 15 cm. 1 m - 1 m = 0 m.
Babu is taller than Velu by = 15 cm
In simple words: Look at both heights. The person with more centimeters (after checking meters) is taller. Subtract the smaller height from the larger height to find the difference.
🎯 Exam Tip: When comparing heights or lengths, always start by comparing the largest unit (meters in this case). If they are the same, then compare the next smaller unit (centimeters).
Free study material for Maths
TN Board Solutions for Class 4 Maths Chapter 04 Measurements
Accessing Chapter 04 Measurements Solutions
Access structured TN Board textbook solutions for Chapter 04 Measurements. Designed in alignment with the latest academic curriculum for Class 4 Maths, these answers cover all end-of-chapter exercises to support daily learning and homework completion.
Concept-Driven Answers for Class 4 Maths
Beyond providing final answers, these guides offer step-by-step breakdowns for complex queries in the Class 4 Maths module. This approach helps students balance theoretical depth with practical problem-solving skills required for TN Board exams.
Maximizing Study Efficiency
Frequent review of these structured answers builds strong analytical capabilities and response efficiency. Maximize your academic readiness by combining these textbook solutions with our curated study materials and mock evaluations for Class 4 Maths.
FAQs
The complete and updated Samacheer Kalvi Class 4 Maths Solutions Term 1 Chapter 4 Measurements Exercise 4.4 is available for free on StudiesToday.com. These solutions for Class 4 Maths are as per latest TN Board curriculum.
Yes, our experts have revised the Samacheer Kalvi Class 4 Maths Solutions Term 1 Chapter 4 Measurements Exercise 4.4 as per 2026 exam pattern. All textbook exercises have been solved and have added explanation about how the Maths concepts are applied in case-study and assertion-reasoning questions.
Toppers recommend using TN Board language because TN Board marking schemes are strictly based on textbook definitions. Our Samacheer Kalvi Class 4 Maths Solutions Term 1 Chapter 4 Measurements Exercise 4.4 will help students to get full marks in the theory paper.
Yes, we provide bilingual support for Class 4 Maths. You can access Samacheer Kalvi Class 4 Maths Solutions Term 1 Chapter 4 Measurements Exercise 4.4 in both English and Hindi medium.
Yes, you can download the entire Samacheer Kalvi Class 4 Maths Solutions Term 1 Chapter 4 Measurements Exercise 4.4 in printable PDF format for offline study on any device.