Samacheer Kalvi Class 4 Maths Solutions Term 1 Chapter 1 Geometry Exercise 1.5

Get the most accurate TN Board Solutions for Class 4 Maths Chapter 01 Geometry here. Updated for the 2026-27 academic session, these solutions are based on the latest TN Board textbooks for Class 4 Maths. Our expert-created answers for Class 4 Maths are available for free download in PDF format.

Detailed Chapter 01 Geometry TN Board Solutions for Class 4 Maths

For Class 4 students, solving TN Board textbook questions is the most effective way to build a strong conceptual foundation. Our Class 4 Maths solutions follow a detailed, step-by-step approach to ensure you understand the logic behind every answer. Practicing these Chapter 01 Geometry solutions will improve your exam performance.

Class 4 Maths Chapter 01 Geometry TN Board Solutions PDF

Tamilnadu Samacheer Kalvi 4th Maths Solutions Term 1 Chapter 1 Geometry Ex 1.5

A. Find the perimeter of the following figures

 

Question (i) A quadrilateral with sides 6 cm, 8 cm, 3 cm, and 5 cm.
Answer: To find the perimeter, add up the lengths of all the sides of the figure. For this quadrilateral, the sides are 6 cm, 8 cm, 3 cm, and 5 cm long. Adding these lengths (6 + 8 + 3 + 5) gives a total perimeter of 22 cm. The perimeter is the total distance around the shape.
In simple words: You add all the side lengths together: 6 + 8 + 3 + 5. This gives 22 cm.

🎯 Exam Tip: Always make sure to add every side length of a polygon to find its perimeter, even if the sides are different lengths.

 

Question (ii) A trapezoid with sides 7 cm, 10 cm, 5 cm, and 2 cm.
Answer: To find the perimeter of this figure, we add the lengths of all its sides. The sides are 7 cm, 10 cm, 5 cm, and 2 cm. Adding these lengths together (7 + 10 + 5 + 2) gives a total perimeter of 24 cm. Perimeter is the measure of the boundary of any closed shape.
In simple words: Add all sides: 7 + 10 + 5 + 2. The total is 24 cm.

🎯 Exam Tip: The perimeter is simply the distance around the outer edge of any two-dimensional shape.

 

Question (iii) A parallelogram with sides 7 cm, 4 cm, 7 cm, and 4 cm.
Answer: For this parallelogram-like figure, the perimeter is found by adding the lengths of all its four sides. The side lengths are 7 cm, 4 cm, 7 cm, and 4 cm. Adding these together (7 + 4 + 7 + 4) results in a perimeter of 22 cm. This shows how opposite sides are equal in parallelograms.
In simple words: Add the sides: 7 + 4 + 7 + 4. The perimeter is 22 cm.

🎯 Exam Tip: Remember that for any polygon, the perimeter is calculated by summing the lengths of all its sides.

 

Question (iv) A square with each side measuring 11 cm.
Answer: To calculate the perimeter of this square, we add the length of each of its four equal sides. Since each side is 11 cm, the total perimeter is 11 + 11 + 11 + 11, which equals 44 cm. You could also multiply the side length by 4 since all sides are equal.
In simple words: Add all four sides: 11 + 11 + 11 + 11. This gives 44 cm.

🎯 Exam Tip: For a square, a quick way to find the perimeter is to multiply the length of one side by 4.

 

Question (v) A rectangle with sides 10 cm and 5 cm.
Answer: For this rectangle, we find the perimeter by adding the lengths of all four sides. The two longer sides are 10 cm each, and the two shorter sides are 5 cm each. So, 10 + 5 + 10 + 5 equals 30 cm. Rectangles always have two pairs of equal sides.
In simple words: Add the lengths of all sides: 10 + 5 + 10 + 5. The perimeter is 30 cm.

🎯 Exam Tip: The perimeter of a rectangle can be found by adding the length and width and then multiplying by 2: \( 2 \times (\text{length} + \text{width}) \).

B. Solve the following

 

Question 1. A side of a square-shaped sandbox in Gandhi Park measures 30 cm. Determine the perimeter of the sand box.
Answer: The sandbox is shaped like a square, and each of its sides measures 30 cm. To find the perimeter, we add all four side lengths together: 30 cm + 30 cm + 30 cm + 30 cm. This sums up to a total perimeter of 120 cm. Since it's a square, you can also multiply the side length by 4.
In simple words: Each side of the square sandbox is 30 cm. Add all four sides (30 + 30 + 30 + 30) to get 120 cm.

🎯 Exam Tip: Remember that all sides of a square are equal, which simplifies perimeter calculations significantly.

 

Question 2. Find the perimeter of a rectangle, whose sides are 12 cm and 8 cm.
Answer: We need to find the perimeter of a rectangle with sides measuring 12 cm and 8 cm. A rectangle has two pairs of equal sides. So, we add all four sides: 12 cm + 8 cm + 12 cm + 8 cm, which gives a total perimeter of 40 cm. You can also use the formula \( 2 \times (\text{length} + \text{width}) \).
In simple words: The rectangle has sides of 12 cm and 8 cm. Add all four sides (12 + 8 + 12 + 8) to get 40 cm.

🎯 Exam Tip: The perimeter of a rectangle is calculated by adding two times its length and two times its width.

 

Question 3. Find the perimeter of the triangle, whose sides are 13 cm, 5 cm and 14 cm.
Answer: To find the perimeter of a triangle, we simply add the lengths of all its three sides. For this triangle, the sides are 13 cm, 5 cm, and 14 cm. When we add these lengths together (13 + 5 + 14), the total perimeter is 32 cm. The perimeter represents the total boundary length of the triangle.
In simple words: Add all three side lengths of the triangle: 13 + 5 + 14. The total perimeter is 32 cm.

🎯 Exam Tip: For any triangle, its perimeter is always the sum of its three side lengths, regardless of its shape.

 

Question 4. The adjacent sides of a parallelogram are 6 cm and 7 cm. What is the perimeter of the parallelogram?
Answer: A parallelogram has opposite sides that are equal in length. If two adjacent sides are 6 cm and 7 cm, then the other two sides will also be 6 cm and 7 cm respectively. So, the perimeter is 6 cm + 7 cm + 6 cm + 7 cm, which equals 26 cm. You can also use the formula \( 2 \times (\text{side 1} + \text{side 2}) \).
In simple words: A parallelogram has opposite sides equal. So, the sides are 6 cm, 7 cm, 6 cm, and 7 cm. Add them all (6 + 7 + 6 + 7) to get 26 cm.

🎯 Exam Tip: Remember that opposite sides of a parallelogram are equal, which is key to finding its perimeter.

 

Question 5. The sides of a trapezoid measures 8 cm, 7 cm, 4 cm and 5 cm respectively. What is the perimeter of the trapezoid?
Answer: To find the perimeter of a trapezoid, we add the lengths of all its four sides. The given side lengths are 8 cm, 7 cm, 4 cm, and 5 cm. Adding these together (8 + 7 + 4 + 5) gives a total perimeter of 24 cm. The perimeter shows the total length around the outer boundary of the trapezoid.
In simple words: Add all four sides of the trapezoid: 8 + 7 + 4 + 5. The total perimeter is 24 cm.

🎯 Exam Tip: For any four-sided figure (quadrilateral) with unequal sides, simply add all four distinct side lengths to find the perimeter.

TN Board Solutions Class 4 Maths Chapter 01 Geometry

Students can now access the TN Board Solutions for Chapter 01 Geometry prepared by teachers on our website. These solutions cover all questions in exercise in your Class 4 Maths textbook. Each answer is updated based on the current academic session as per the latest TN Board syllabus.

Detailed Explanations for Chapter 01 Geometry

Our expert teachers have provided step-by-step explanations for all the difficult questions in the Class 4 Maths chapter. Along with the final answers, we have also explained the concept behind it to help you build stronger understanding of each topic. This will be really helpful for Class 4 students who want to understand both theoretical and practical questions. By studying these TN Board Questions and Answers your basic concepts will improve a lot.

Benefits of using Maths Class 4 Solved Papers

Using our Maths solutions regularly students will be able to improve their logical thinking and problem-solving speed. These Class 4 solutions are a guide for self-study and homework assistance. Along with the chapter-wise solutions, you should also refer to our Revision Notes and Sample Papers for Chapter 01 Geometry to get a complete preparation experience.

FAQs

Where can I find the latest Samacheer Kalvi Class 4 Maths Solutions Term 1 Chapter 1 Geometry Exercise 1.5 for the 2026-27 session?

The complete and updated Samacheer Kalvi Class 4 Maths Solutions Term 1 Chapter 1 Geometry Exercise 1.5 is available for free on StudiesToday.com. These solutions for Class 4 Maths are as per latest TN Board curriculum.

Are the Maths TN Board solutions for Class 4 updated for the new 50% competency-based exam pattern?

Yes, our experts have revised the Samacheer Kalvi Class 4 Maths Solutions Term 1 Chapter 1 Geometry Exercise 1.5 as per 2026 exam pattern. All textbook exercises have been solved and have added explanation about how the Maths concepts are applied in case-study and assertion-reasoning questions.

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Toppers recommend using TN Board language because TN Board marking schemes are strictly based on textbook definitions. Our Samacheer Kalvi Class 4 Maths Solutions Term 1 Chapter 1 Geometry Exercise 1.5 will help students to get full marks in the theory paper.

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Yes, we provide bilingual support for Class 4 Maths. You can access Samacheer Kalvi Class 4 Maths Solutions Term 1 Chapter 1 Geometry Exercise 1.5 in both English and Hindi medium.

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