Samacheer Kalvi Class 12 Business Maths Solutions Chapter 10 Operations Research Exercise 10.3

Get the most accurate TN Board Solutions for Class 12 Business Maths Chapter 10 Operations Research here. Updated for the 2026-27 academic session, these solutions are based on the latest TN Board textbooks for Class 12 Business Maths. Our expert-created answers for Class 12 Business Maths are available for free download in PDF format.

Detailed Chapter 10 Operations Research TN Board Solutions for Class 12 Business Maths

For Class 12 students, solving TN Board textbook questions is the most effective way to build a strong conceptual foundation. Our Class 12 Business Maths solutions follow a detailed, step-by-step approach to ensure you understand the logic behind every answer. Practicing these Chapter 10 Operations Research solutions will improve your exam performance.

Class 12 Business Maths Chapter 10 Operations Research TN Board Solutions PDF

 

Question 1. Given the following pay-off matrix (in rupees) for three strategies and two states for nature. Select a strategy using each of the following rule (i) Maximin (ii) Minimax

StrategyStates-of-nature
\( E_1 \)\( E_2 \)
\( S_1 \)4060
\( S_2 \)10-20
\( S_3 \)-40150

Answer:
StrategyStates of natureMinimumMaximum
\( E_1 \)\( E_2 \)
\( S_1 \)40604060
\( S_2 \)10-20-2010
\( S_3 \)-40150-40150
(i) Maximin:
First, we find the minimum pay-off for each strategy: for \( S_1 \) it is 40, for \( S_2 \) it is -20, and for \( S_3 \) it is -40. Then, we choose the maximum of these minimum values, which is Max(40, -20, -40) = 40. So, strategy \( S_1 \) is selected. The maximin approach aims to maximize the minimum possible gain, focusing on the safest outcome.
(ii) Minimax:
To use the minimax rule, we first identify the maximum possible pay-off for each strategy. For \( S_1 \), the maximum is 60. For \( S_2 \), the maximum is 10. For \( S_3 \), the maximum is 150. Then, we select the minimum among these maximum values: min(60, 10, 150) = 10. This means strategy \( S_2 \) is chosen. The minimax approach focuses on minimizing the maximum possible loss or risk, aiming for the least bad outcome.
In simple words: For maximin, find the lowest profit for each plan and pick the highest of those lowest profits. For minimax, find the highest profit for each plan and pick the lowest of those highest profits.

🎯 Exam Tip: Remember to clearly define strategies (rows) and states of nature (columns) to correctly apply decision criteria like Maximin and Minimax.

 

Question 2. A farmer wants to decide which of three crops he should plant on his 100 acre farm. The profit from each is dependent on the rainfall during the growing season. The farmer has categorized the amount of rainfall as high medium and low. His estimated profit for each is shown in the table. In the farmer wishes to plant only crop, decide which should be his best crop using (i) Maximin (ii) Minimax

RainfallEstimated Conditional Profit(Rs.)
Crop ACrop BCrop C
High800035005000
Medium450045005000
Low200050004000

Answer:
RainfallEstimated conditional Profit (Rs.)minimummaximum
Crop ACrop BCrop C
High80003500500035008000
Medium45004500500045005000
Low20005000400020005000
(i) Maximin:
For the maximin rule, we first look at the minimum profit for each rainfall category across all crops. For High rainfall, the minimum profit is Rs. 3500. For Medium rainfall, the minimum is Rs. 4500. For Low rainfall, the minimum is Rs. 2000. We then find the maximum of these minimums: Max(3500, 4500, 2000) = Rs. 4500. Therefore, the decision would be based on the 'Medium' rainfall scenario, which gives the highest minimum profit. This method focuses on maximizing the minimum guaranteed profit, even if it means not choosing the highest possible overall profit.
(ii) Minimax:
For the minimax rule, we first find the maximum profit for each rainfall category across all crops. For High rainfall, the maximum profit is Rs. 8000. For Medium rainfall, the maximum is Rs. 5000. For Low rainfall, the maximum is Rs. 5000. Then, we select the minimum of these maximums: min(8000, 5000, 5000) = Rs. 5000. This means the decision points towards both the 'Medium' and 'Low' rainfall scenarios as optimal, suggesting crops performing well in those conditions. The minimax approach is often chosen by decision-makers who are risk-averse and want to avoid the worst possible outcome.
In simple words: For Maximin, you find the smallest profit in each row (rainfall) and then pick the largest of these smallest profits. For Minimax, you find the largest profit in each row and then pick the smallest of those largest profits.

🎯 Exam Tip: When applying Maximin or Minimax, make sure you consistently apply the rule to either rows (strategies) or columns (states of nature) based on what the question asks you to decide.

 

Question 3. The research department of Hindustan Ltd. has recommended to pay marketing department to launch a shampoo of three different types. The marketing types of shampoo to be launched under the following T estimated pay-offs for various level of sales. What will be the marketing manager's decision if (i) Maximin and (ii) Minimax principle applied?

Types of shampooEstimated Sales (in Units)
15000100005000
Egg shampoo301010
Clinic Shampoo40155
Deluxe Shampoo55203

Answer:
Types of shampooEstimated Sales (in units)MinimumMaximum
15000100005000
Egg shampoo3010101030
Clinic shampoo40155540
Deluxe shampoo55203355
(i) Maximin:
To apply the maximin principle, we first find the minimum sales for each type of shampoo. For Egg shampoo, the minimum sales are 10 units. For Clinic shampoo, the minimum is 5 units. For Deluxe shampoo, the minimum is 3 units. We then choose the maximum of these minimums: Max(10, 5, 3) = 10. Therefore, Egg Shampoo is the chosen product. The maximin strategy helps ensure the best possible outcome even in the worst-case sales scenario.
(ii) Minimax:
For the minimax rule, we identify the maximum sales for each type of shampoo. For Egg shampoo, the maximum sales are 30 units. For Clinic shampoo, the maximum is 40 units. For Deluxe shampoo, the maximum is 55 units. Then, we find the minimum of these maximum values: min(30, 40, 55) = 30. This leads to the selection of Egg Shampoo, as it minimizes the maximum potential sales value. This method helps in choosing an option that performs relatively well, even if the absolute best outcome is not achieved.
In simple words: For maximin, find the lowest sales for each shampoo type and pick the highest of these. For minimax, find the highest sales for each shampoo type and pick the lowest of these.

🎯 Exam Tip: When using payoff matrices, clearly list the minimums (for maximin) or maximums (for minimax) for each strategy before making the final selection.

 

Question 4. Following pay-off matrix, which is the optimal decision under of the following rule (i) maximin (ii) minimax

ActStates of nature
\( S_1 \)\( S_2 \)\( S_3 \)\( S_4 \)
\( A_1 \)149105
\( A_2 \)111087
\( A_3 \)9101011
\( A_4 \)8101113

Answer:
ActStates of natureMinimumMaximum
\( S_1 \)\( S_2 \)\( S_3 \)\( S_4 \)
\( A_1 \)149105514
\( A_2 \)111087711
\( A_3 \)9101011911
\( A_4 \)8101113813
(i) Maximin:
For the maximin rule, we first find the minimum pay-off for each action. For \( A_1 \), the minimum is 5. For \( A_2 \), it is 7. For \( A_3 \), it is 9. For \( A_4 \), it is 8. Then, we find the maximum of these minimum values. The calculation provided is Max(5, 7, 9, 8) = 5. Based on this, alternative \( A_1 \) is chosen. This method focuses on achieving the highest guaranteed return, even if it means foregoing potentially higher, but riskier, gains.
(ii) Minimax:
For the minimax rule, we first find the maximum pay-off for each action. For \( A_1 \), the maximum is 14. For \( A_2 \), it is 11. For \( A_3 \), it is 11. For \( A_4 \), it is 13. Then, we select the minimum of these maximum values: min(14, 11, 11, 13) = 11. Since both \( A_2 \) and \( A_3 \) have this minimum maximum pay-off, both are considered optimal alternatives. The minimax strategy helps to minimize the potential for the worst possible outcome, making it suitable for risk-averse decision-makers.
In simple words: For maximin, find the smallest outcome for each action and pick the action with the largest of these smallest outcomes. For minimax, find the largest outcome for each action and pick the action with the smallest of these largest outcomes.

🎯 Exam Tip: Always check if there are multiple optimal alternatives for minimax or maximin criteria, as shown here with \( A_2 \) and \( A_3 \).

TN Board Solutions Class 12 Business Maths Chapter 10 Operations Research

Students can now access the TN Board Solutions for Chapter 10 Operations Research prepared by teachers on our website. These solutions cover all questions in exercise in your Class 12 Business Maths textbook. Each answer is updated based on the current academic session as per the latest TN Board syllabus.

Detailed Explanations for Chapter 10 Operations Research

Our expert teachers have provided step-by-step explanations for all the difficult questions in the Class 12 Business Maths chapter. Along with the final answers, we have also explained the concept behind it to help you build stronger understanding of each topic. This will be really helpful for Class 12 students who want to understand both theoretical and practical questions. By studying these TN Board Questions and Answers your basic concepts will improve a lot.

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FAQs

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The complete and updated Samacheer Kalvi Class 12 Business Maths Solutions Chapter 10 Operations Research Exercise 10.3 is available for free on StudiesToday.com. These solutions for Class 12 Business Maths are as per latest TN Board curriculum.

Are the Business Maths TN Board solutions for Class 12 updated for the new 50% competency-based exam pattern?

Yes, our experts have revised the Samacheer Kalvi Class 12 Business Maths Solutions Chapter 10 Operations Research Exercise 10.3 as per 2026 exam pattern. All textbook exercises have been solved and have added explanation about how the Business Maths concepts are applied in case-study and assertion-reasoning questions.

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