Samacheer Kalvi Class 10 Science Solutions Chapter 1 Laws of Motion

Get the most accurate TN Board Solutions for Class 10 Science Chapter 01 Laws of Motion here. Updated for the 2026-27 academic session, these solutions are based on the latest TN Board textbooks for Class 10 Science. Our expert-created answers for Class 10 Science are available for free download in PDF format.

Detailed Chapter 01 Laws of Motion TN Board Solutions for Class 10 Science

For Class 10 students, solving TN Board textbook questions is the most effective way to build a strong conceptual foundation. Our Class 10 Science solutions follow a detailed, step-by-step approach to ensure you understand the logic behind every answer. Practicing these Chapter 01 Laws of Motion solutions will improve your exam performance.

Class 10 Science Chapter 01 Laws of Motion TN Board Solutions PDF

I. Choose The Correct Answer

 

Question 1. Inertia of a body depends on:
(a) weight of the object
(b) acceleration due to gravity of the planet
(c) mass of the object
(d) both (a) & (b)
Answer: (c) mass of the object
In simple words: How much a body resists changes to its motion depends on its mass. The more mass it has, the harder it is to move or stop.

๐ŸŽฏ Exam Tip: Remember that inertia is a direct measure of mass. A heavier object has more inertia, meaning it's harder to start or stop moving.

 

Question 2. Impulse is equals to _____.
(a) rate of change of momentum
(b) rate of force and time
(c) change of momentum
(d) rate of change of mass.
Answer: (c) change of momentum
In simple words: Impulse is the total change in an object's momentum. It is like the "push" or "hit" an object receives, which changes how fast and in what direction it is moving.

๐ŸŽฏ Exam Tip: Impulse is literally defined as the change in momentum. The unit of impulse (Newton-second) is the same as the unit of momentum (kg m/s).

 

Question 3. Newton's III law is applicable:
(a) for a body is at rest
(b) for a body in motion
(c) both (a) & (b)
(d) only for bodies with equal masses
Answer: (c) both (a) & (b)
In simple words: Newton's third law, which states that for every action there is an equal and opposite reaction, applies to objects whether they are sitting still or moving. It is a fundamental law of interaction between objects.

๐ŸŽฏ Exam Tip: Newton's third law describes interactions between objects and applies universally, regardless of their state of motion or mass. Focus on the 'interaction' aspect for full marks.

 

Question 4. Plotting a graph for momentum on the X-axis and time on Y-axis. Slope of momentum โ€“ time graph gives _____.
(b) Acceleration
(c) Force
(d) Rate of force.
Answer: (c) Force
In simple words: If you draw a graph where momentum is on the X-axis and time is on the Y-axis, the slope of that line will show you the force. This is because force is how quickly momentum changes over time.

๐ŸŽฏ Exam Tip: Recall Newton's second law: \( F = \frac{\Delta p}{\Delta t} \). This directly relates force to the rate of change of momentum, which is represented by the slope on a momentum-time graph.

 

Question 5. In which of the following sport the turning effect of force is used?
(a) swimming
(b) tennis
(c) cycling
(d) hockey
Answer: (c) cycling
In simple words: When you ride a bicycle, you use your hands to turn the handlebars. This turning action is an example of applying a force to create a turning effect, which is called torque, to steer the bike.

๐ŸŽฏ Exam Tip: The "turning effect of force" is also known as torque or moment of force. It's essential for sports and activities involving rotation, like steering or pedaling.

 

Question 6. The unit of 'g' is \( \text{ms}^{-2} \). It can be also expressed as:
(a) \( \text{cm s}^{-2} \)
(b) \( \text{N kg}^{-1} \)
(c) \( \text{N m}^{2}\text{kg}^{-1} \)
(d) \( \text{cm}^{2}\text{s}^{-2} \)
Answer: (a) \( \text{cm s}^{-2} \)
In simple words: The unit for 'g' (acceleration due to gravity) is usually meters per second squared. This can also be written as centimeters per second squared, just in a different unit system, but the meaning is the same.

๐ŸŽฏ Exam Tip: Acceleration is change in velocity over time, so its units are always (distance)/(time) squared. While \( \text{N kg}^{-1} \) is also a valid unit for 'g' (from \( F = mg \)), the options were looking for a direct conversion of the acceleration unit itself.

 

Question 7. One kilogram force equals to _____.
(a) 9.8 dyne
(b) \( 9.8 \times 10^4 \text{ N} \)
(c) \( 98 \times 10^4 \text{ dyne} \)
(d) 980 dyne.
Answer: (c) \( 98 \times 10^4 \text{ dyne} \)
In simple words: One kilogram-force is the force caused by gravity on a 1-kilogram mass. This is equal to 9.8 Newtons, which can also be written as \( 98 \times 10^4 \) dynes when converting to a smaller unit of force.

๐ŸŽฏ Exam Tip: Remember the conversion factor between Newton and dyne: \( 1 \text{ N} = 10^5 \text{ dyne} \). Also, \( 1 \text{ kgf} = 9.8 \text{ N} \). Combine these to get the answer.

 

Question 8. The mass of a body is measured on planet Earth as M kg. When it is taken to a planet of radius half that of the Earth then its value will be ..... kg.
(a) 4 M
(b) 2 M
(c) M/4
(d) M
Answer: (d) M
In simple words: Mass is how much "stuff" an object is made of. It does not change based on where the object is located. So, if an object has mass M on Earth, it will still have mass M on another planet, no matter its size.

๐ŸŽฏ Exam Tip: Distinguish between mass and weight. Mass is an intrinsic property of an object and remains constant, while weight is the force of gravity acting on an object and changes with gravitational acceleration.

 

Question 9. If the Earth shrinks to 50% of its real radius its mass remaining the same, the weight of a body on the Earth will:
(a) decrease by 50%
(b) increase by 50%
(c) decrease by 25%
(d) increase by 300%
Answer: (d) increase by 300%
In simple words: If the Earth gets smaller but keeps the same amount of mass, gravity on its surface would get much stronger. This means an object's weight would increase a lot because gravity would be pulling it with more force.

๐ŸŽฏ Exam Tip: Recall the formula for gravitational acceleration \( g = \frac{GM}{R^2} \). If R is halved (50%), then \( R^2 \) becomes \( (R/2)^2 = R^2/4 \). So \( g \) would become \( \frac{GM}{R^2/4} = 4 \frac{GM}{R^2} = 4g \). Weight \( W = mg \), so new weight \( W' = m(4g) = 4W \). This is an increase of 300% (4 times the original value means an increase of 3 times the original value, or 300%).

 

Question 10. To project the rockets which of the following principle(s) is / (are) required?
(a) Newton's third law of motion
(b) Newton's law of gravitation
(c) law of conservation of linear momentum
(d) both a and c.
Answer: (d) both a and c.
In simple words: Rockets work because of two main physics rules. First, they push hot gas out one way, and the gas pushes the rocket the other way (Newton's third law). Second, the total push, or momentum, stays the same before and after the gas is expelled (conservation of linear momentum).

๐ŸŽฏ Exam Tip: Rocket propulsion is a classic example of Newton's third law in action, where the action of expelling gas causes an equal and opposite reaction force on the rocket. This also directly demonstrates the conservation of linear momentum for the rocket-gas system.

 

II. Fill In The Blanks

 

Question 1. To produce a displacement ........ is required.
Answer: force
In simple words: You need a force to make something move from one place to another.

๐ŸŽฏ Exam Tip: Remember that force is what causes motion or changes in motion. Without force, an object at rest stays at rest, and an object in motion stays in motion.

 

Question 2. Passengers lean forward when the sudden brake is applied in a moving vehicle. This can be explained by ..........
Answer: inertia
In simple words: When a car stops suddenly, your body wants to keep moving forward because of inertia, making you lean ahead.

๐ŸŽฏ Exam Tip: Inertia is an object's resistance to any change in its state of motion. In this case, your body's inertia of motion makes it continue forward even when the car stops.

 

Question 3. By convention, the clockwise moments are taken as ..... and the anticlockwise moments are taken as ..........
Answer: negative, positive
In simple words: When something turns in a clockwise direction, we usually call that a negative turn. If it turns the other way, anti-clockwise, we call it a positive turn.

๐ŸŽฏ Exam Tip: This is a sign convention in physics. Consistently applying this convention (e.g., clockwise as negative, anti-clockwise as positive) is crucial for solving problems involving moments and torque.

 

Question 4. .......... is used to change the speed of the car.
Answer: Accelerator
In simple words: The accelerator pedal in a car is used to either speed up or slow down the vehicle. When you push it, the car goes faster, and when you release it, the car slows down.

๐ŸŽฏ Exam Tip: The accelerator controls the engine's power, which in turn changes the force applied to the wheels, altering the car's speed. It is responsible for making the car accelerate (speed up) or decelerate (slow down).

 

Question 5. A man of mass 100 kg has a weight of ........ at the surface of the Earth.
Answer: \( 980 \text{ N} \)
In simple words: To find a man's weight on Earth, you multiply his mass (100 kg) by the strength of Earth's gravity (9.8 m/sยฒ). This gives a weight of 980 Newtons.

๐ŸŽฏ Exam Tip: Always remember the formula \( \text{Weight} = \text{mass} \times \text{acceleration due to gravity} \). On Earth, 'g' is approximately \( 9.8 \text{ m/s}^2 \), so \( \text{Weight} = 100 \text{ kg} \times 9.8 \text{ m/s}^2 = 980 \text{ N} \).

 

III. State Whether The Following Statements Are True Or False. Correct The Statement If It Is False.

 

Question 1. The linear momentum of a system of particles is always conserved.
Answer: True
In simple words: In a group of particles, the total amount of linear momentum always stays the same, as long as no outside forces act on it.

๐ŸŽฏ Exam Tip: This is the law of conservation of linear momentum. It holds true only in an isolated system, meaning no external forces are acting on the system.

 

Question 2. Apparent weight of a person is always equal to his actual weight.
Answer: False - Apparent weight of a person is not always equal to his actual weight.
In simple words: How heavy you feel (apparent weight) is not always the same as your actual weight. For example, in an elevator, you might feel lighter or heavier depending on its movement.

๐ŸŽฏ Exam Tip: Apparent weight can differ from actual weight in accelerating frames of reference, such as an elevator moving up or down, or in free fall. It only matches actual weight when the person is at rest or moving at a constant velocity.

 

Question 3. Weight of a body is greater at the equator and less at the polar region.
Answer: False โ€“ Weight of a body is minimum at the equator. It is maximum at the poles.
In simple words: An object feels heavier at the Earth's poles and lighter at the equator. This is because the Earth bulges slightly at the equator and spins, causing a small outward force that reduces gravity's effect there.

๐ŸŽฏ Exam Tip: The value of 'g' (acceleration due to gravity) is slightly less at the equator due to two factors: Earth's rotation (centrifugal effect) and its equatorial bulge (greater distance from the center). Therefore, weight, which is \( mg \), is minimum at the equator and maximum at the poles.

 

Question 4. Turning a nut with a spanner having a short handle is so easy than one with a long handle.
Answer: False โ€“ Turning a nut with a spanner having a longer handle is so easy than one with a short handle.
In simple words: It is easier to turn a nut using a spanner with a long handle than with a short one. A longer handle gives you more leverage, making it simpler to apply the turning force.

๐ŸŽฏ Exam Tip: The turning effect of a force (torque) is directly proportional to the perpendicular distance from the pivot point to the line of action of the force. A longer handle increases this distance, requiring less force to produce the same torque.

 

Question 5. Astronauts are falling freely around the earth due to their huge orbital velocity.
Answer: True
In simple words: Astronauts in orbit are constantly falling towards Earth but moving sideways so fast that they keep missing it. This continuous 'free fall' makes them feel weightless.

๐ŸŽฏ Exam Tip: The feeling of weightlessness in orbit is not due to a lack of gravity, but because both the astronauts and their spacecraft are continually accelerating towards Earth at the same rate, effectively being in a state of free fall.

 

IV. Match The Following.

 

Question 1. Match the column A with column B.

Column AColumn B
A Newton's I law(i) Propulsion of a rocket
B Newton's II law(ii) Stable equilibrium of a body
C Newton's III law(iii) Law of force
D Law of conservation of Linear momentum.(iv) Flying nature of bird

Answer:
A. (ii) Stable equilibrium of a body
B. (iii) Law of force
C. (i) Propulsion of a rocket
D. (iv) Flying nature of bird
In simple words: Newton's first law explains why a balanced object stays balanced. The second law is about how force causes things to move. The third law explains why rockets move forward when they push gas backward. And the law of conservation of linear momentum helps understand how birds fly.

๐ŸŽฏ Exam Tip: Understand the core concept of each law: First law (inertia/equilibrium), Second law (F=ma/rate of change of momentum), Third law (action-reaction pairs), and Conservation of Momentum (total momentum constant in isolated system).

 

V. Assertion And Reasoning.

 

Question 1. Assertion: The sum of the clockwise moments is equal to the sum of the anticlockwise moments. Reason: The principle of conservation of momentum is valid if the external force on the system is zero.
Answer: (b) If both the assertion and the reason are true, but the reason is not the correct explanation of assertion.
In simple words: The first statement is about balance in turning forces. The second statement is about momentum being conserved if there are no outside pushes or pulls. Both are true physics rules, but the second one doesn't explain the first one.

๐ŸŽฏ Exam Tip: Recognize that while both statements are true physics principles, they relate to different concepts: the assertion describes rotational equilibrium (principle of moments), while the reason describes linear momentum conservation. There is no direct causal link between them.

 

Question 2. Assertion: The value of 'g' decreases as height and depth increases from the surface of the Earth. Reason: 'g' depends on the mass of the object and the Earth.
Answer: (c) Assertion is true, but the reason is false.
In simple words: It is true that gravity's pull ('g') gets weaker both as you go higher up from Earth and deeper down into it. However, 'g' does not depend on the mass of the object being pulled; it depends only on the mass of the Earth and the distance from its center.

๐ŸŽฏ Exam Tip: The acceleration due to gravity 'g' decreases with both altitude and depth. Crucially, 'g' is independent of the mass of the falling object; it only depends on the mass of the planet and the distance from its center (\( g = \frac{GM}{R^2} \)).

 

VI. Answer Briefly.

 

Question 1. Define inertia. Give its classification.
Answer: Inertia is the natural tendency of a body to resist any change in its state of rest or of uniform motion, unless an outside unbalanced force acts on it. It means an object will stay put or keep moving at the same speed and direction unless something pushes or pulls it. There are three types of inertia:
1. Inertia of rest: An object at rest wants to stay at rest.
2. Inertia of motion: An object in motion wants to keep moving.
3. Inertia of direction: An object moving in a certain direction wants to keep going in that direction.
In simple words: Inertia is an object's resistance to change its movement or lack of movement. It comes in three kinds: staying still, keeping moving, or staying in the same direction.

๐ŸŽฏ Exam Tip: Clearly state the definition of inertia. For classification, give each type a name and a one-sentence description or example.

 

Question 2. Classify the types of force based on their application.
Answer: Based on the direction in which forces act, they can be grouped into two main types:
1. Like parallel forces: These are two or more forces, whether equal or unequal in strength, that act in the same direction and are parallel to each other. For example, two people pushing a box together in the same direction.
2. Unlike parallel forces: These are two or more forces, either equal or unequal in strength, that act in opposite directions but are still parallel to each other. For example, two people pushing a box from opposite sides.
In simple words: Forces can be grouped by how they act. "Like parallel forces" mean they push or pull in the same direction, like two people pushing a car forward. "Unlike parallel forces" mean they push or pull in opposite directions, like two people pushing a door from different sides.

๐ŸŽฏ Exam Tip: When classifying forces, remember that "parallel" refers to their lines of action, and "like" or "unlike" refers to whether they are in the same or opposite directions, respectively.

 

Question 3. If a 5 N and a 15 N forces are acting opposite to one another. Find the resultant force and the direction of action of the resultant force.
Answer:
Given:
First force \( F_1 = 5 \text{ N} \)
Second force \( F_2 = 15 \text{ N} \)
Since the forces act in opposite directions, the resultant force is found by subtracting the smaller force from the larger force.
Resultant force \( F_{\text{R}} = F_1 - F_2 \)
\( F_{\text{R}} = 5 \text{ N} - 15 \text{ N} = -10 \text{ N} \). The negative sign indicates the direction.
The magnitude of the resultant force is \( 10 \text{ N} \).
The resultant force acts in the direction of the larger force, which is the \( 15 \text{ N} \) force.
In simple words: When two forces push in opposite ways, you find the total force by subtracting the smaller one from the bigger one. The total force will push in the same direction as the bigger original force. In this case, it is \( 10 \text{ N} \) in the direction of the \( 15 \text{ N} \) force.

๐ŸŽฏ Exam Tip: When forces act in opposite directions, always subtract their magnitudes to find the resultant force, and the direction of the resultant force will be the same as that of the larger force.

 

Question 4. Differentiate mass and weight.
Answer: Mass is a measure of the amount of matter in an object, while weight is the force of gravity acting on that object. Mass remains constant regardless of location, whereas weight changes depending on the gravitational pull of the location. For example, an object's mass is the same on Earth and the moon, but its weight is less on the moon due to weaker gravity. Mass is measured in kilograms (kg), and weight is measured in Newtons (N).
In simple words: Mass is how much material is in something, and it never changes. Weight is how hard gravity pulls on that material, so it changes depending on where you are, like on Earth or the Moon.

๐ŸŽฏ Exam Tip: Highlight the key distinction: mass is scalar (amount of matter), weight is vector (force due to gravity). Emphasize that mass is constant, but weight varies with 'g'.

 

Question 5. Define the moment of a couple.
Answer: A couple is formed when two forces that are equal in strength, opposite in direction, and parallel to each other are applied at two different points on an object. These forces work together to make the object rotate. The turning effect created by these two forces is called the moment of a couple. It describes the tendency of the couple to cause rotation.
In simple words: A "couple" is two equal forces pushing in opposite directions at different spots on an object. This makes the object spin. The strength of this spin is called the moment of a couple.

๐ŸŽฏ Exam Tip: For a couple, emphasize that the two forces are equal in magnitude, opposite in direction, parallel, and have different lines of action. The moment of a couple is what causes pure rotational motion.

 

Question 6. State the principle of moments.
Answer: The principle of moments states that if a rigid body is balanced (in equilibrium) under the influence of several forces, the total turning effect caused by forces trying to turn it clockwise is equal to the total turning effect caused by forces trying to turn it anti-clockwise. In simpler terms, for an object to be perfectly balanced, all the forces making it turn one way must be exactly matched by forces making it turn the other way.
In simple words: For an object to stay balanced and not turn, the total turning force in one direction must be exactly the same as the total turning force in the opposite direction.

๐ŸŽฏ Exam Tip: The principle of moments is fundamental for understanding rotational equilibrium. Ensure you define it clearly, stating the equality of clockwise and anticlockwise moments about a pivot point.

 

Question 7. State Newton's second law.
Answer: Newton's second law states that the force acting on an object is directly proportional to the rate at which its linear momentum changes. This change in momentum always happens in the same direction as the force applied. Simply put, a larger force causes a greater and faster change in an object's movement, and this change follows the direction of the push or pull. This law is often summarized by the formula \( F = ma \), where F is force, m is mass, and a is acceleration.
In simple words: Newton's second law says that when you push or pull an object, it moves faster if you push harder, and it moves in the direction you push. How much faster it moves depends on its mass.

๐ŸŽฏ Exam Tip: Remember that Newton's second law connects force, mass, and acceleration (\( F=ma \)). It also emphasizes that force is the cause of a change in momentum over time.

 

Question 8. Why a spanner with a long handle is preferred to tighten screws in heavy vehicles?
Answer: A spanner with a long handle is preferred for tightening screws in heavy vehicles because it creates a greater turning effect (torque) with less effort. When the spanner has a long handle, the distance from the point where the force is applied to the fixed pivot point (the nut) is increased. According to the principle of moments, a larger distance for the applied force means a greater turning effect for the same amount of force. This extra leverage helps to apply the significant torque needed to tighten large, heavy-duty screws securely.
In simple words: A long spanner handle makes it easier to tighten tough screws because it gives you more leverage. This means you need less strength to make the screw turn tightly.

๐ŸŽฏ Exam Tip: Link this directly to the concept of torque (moment of force). Torque is calculated as Force \( \times \) Perpendicular Distance. A longer handle increases the perpendicular distance, thus maximizing torque for a given force.

 

Question 9. While catching a cricket ball the fielder lowers his hands backwards. Why?
Answer: When a fielder catches a cricket ball and lowers their hands backward, they increase the time over which the ball's high speed decreases to zero. By increasing this time, the force of impact on their hands is greatly reduced. Newton's second law tells us that force is related to the change in momentum divided by the time taken. So, a longer time for the momentum to change means a smaller force is felt, which helps prevent injury to the fielder's hands. This technique spreads the impact over a longer duration, reducing the peak force.
In simple words: A cricket fielder moves their hands back when catching a ball to give the ball more time to slow down. This makes the force on their hands less strong, so it does not hurt as much.

๐ŸŽฏ Exam Tip: This is an application of the impulse-momentum theorem (\( F \Delta t = \Delta p \)). By increasing \( \Delta t \) (the time of impact), the force \( F \) experienced by the hands is reduced for the same change in momentum \( \Delta p \).

 

Question 10. How does an astronaut float in a space shuttle?
Answer: Astronauts inside a space shuttle are not actually floating due to an absence of gravity; instead, they are continuously falling freely around the Earth. The space shuttle itself is also falling around the Earth at the same rate, thanks to its very high orbital velocity. Since both the astronauts and the shuttle have the same acceleration towards Earth, they are under a continuous "free fall" condition. This state, where the relative acceleration between the astronaut and the shuttle is zero, results in the sensation of weightlessness. It is similar to the feeling you would get if you were in a falling elevator.
In simple words: Astronauts "float" in a space shuttle because both they and the shuttle are constantly falling around the Earth at the same speed. This steady fall makes them feel weightless, even though Earth's gravity is still pulling them.

๐ŸŽฏ Exam Tip: Explain that weightlessness in orbit is a result of continuous free fall, not the absence of gravity. The orbital velocity ensures they continually miss the Earth while falling.

 

VII. Solve The Given Problems.

 

Question 1. Two bodies have a mass ratio of 3 : 4 The force applied on the bigger mass produces an acceleration of 12 msยฒ. What could be the acceleration of the other body, if the same force acts on it.
Answer:
Given:
Ratio of masses \( m_1 : m_2 = 3 : 4 \)
Let \( m_1 = 3x \) and \( m_2 = 4x \). The bigger mass is \( m_2 \).
Acceleration of bigger mass \( a_2 = 12 \text{ m/s}^2 \)
According to Newton's second law, Force \( F = ma \).
Force acting on \( m_2 \) is \( F_2 = m_2 a_2 \)
\( F_2 = (4x) \times (12 \text{ m/s}^2) = 48x \text{ N} \)
The problem states that the same force acts on the other body, so \( F_1 = F_2 \).
Thus, force acting on \( m_1 \) is \( F_1 = 48x \text{ N} \).
Now, we find the acceleration of \( m_1 \):
\( F_1 = m_1 a_1 \)
\( 48x = (3x) a_1 \)
\( a_1 = \frac{48x}{3x} \)
\( a_1 = 16 \text{ m/s}^2 \)
The acceleration of the other body \( m_1 \) is \( 16 \text{ m/s}^2 \).
In simple words: We have two objects, one is heavier than the other. If the same push is given to both, the lighter object will speed up more than the heavier one. Here, the lighter object (mass ratio 3) will accelerate at \( 16 \text{ m/s}^2 \) compared to the heavier object (mass ratio 4) which accelerates at \( 12 \text{ m/s}^2 \).

๐ŸŽฏ Exam Tip: Remember that force is directly proportional to acceleration and inversely proportional to mass (\( a = F/m \)). If the force is constant, a smaller mass will experience a larger acceleration.

 

Question 2. A ball of mass 1 kg moving with a speed of 10 ms\(^{-1}\) rebounds after a perfect elastic collision with the floor. Calculate the change in linear momentum of the ball.
Answer:
Given:
Mass of the ball \( m = 1 \text{ kg} \)
Initial speed \( u = 10 \text{ m/s} \)
Since it's a perfect elastic collision, the speed remains the same after rebounding, but the direction reverses. So, the final speed is \( v = -10 \text{ m/s} \).
Initial momentum \( p_{\text{initial}} = mu = 1 \text{ kg} \times 10 \text{ m/s} = 10 \text{ kg m/s} \)
Final momentum \( p_{\text{final}} = mv = 1 \text{ kg} \times (-10 \text{ m/s}) = -10 \text{ kg m/s} \)
Change in momentum \( \Delta p = p_{\text{final}} - p_{\text{initial}} \)
\( \Delta p = (-10 \text{ kg m/s}) - (10 \text{ kg m/s}) \)
\( \Delta p = -20 \text{ kg m/s} \)
The change in linear momentum of the ball is \( -20 \text{ kg m/s} \). The negative sign indicates the change is in the opposite direction to the initial motion.
In simple words: When a ball bounces perfectly, it hits and comes back with the same speed but in the opposite direction. The total change in its moving force (momentum) will be double its original momentum, but in the reverse direction.

๐ŸŽฏ Exam Tip: For elastic collisions, the speed is conserved, but the direction of velocity reverses. When calculating change in momentum, always assign a positive direction to initial velocity and a negative direction to final (rebounding) velocity.

 

Question 3. A mechanic unscrew a nut by applying a force of 140 N with a spanner of length 40 cm. What should be the length of the spanner if a force of 40 N is applied to unscrew the same nut?
Answer:
Given:
First force applied \( F_1 = 140 \text{ N} \)
Length of the first spanner \( d_1 = 40 \text{ cm} = 40 \times 10^{-2} \text{ m} \)
Second force applied \( F_2 = 40 \text{ N} \)
Let the length of the second spanner be \( d_2 \).
According to the principle of moments, for the same nut (meaning the same required turning effect or torque), the moments must be equal:
\( F_1 \times d_1 = F_2 \times d_2 \)
\( 140 \text{ N} \times (40 \times 10^{-2} \text{ m}) = 40 \text{ N} \times d_2 \)
\( 140 \times 40 = 40 \times d_2 \)
\( d_2 = \frac{140 \times 40}{40} \)
\( d_2 = 140 \text{ cm} = 1.4 \text{ m} \)
The length of the spanner required for the second force is \( 140 \text{ cm} \).
In simple words: If you need to turn a nut with a certain amount of force (torque), and you use less force, you will need a longer spanner handle to get the job done. If you push with less force, you need a longer lever to make it turn.

๐ŸŽฏ Exam Tip: This problem illustrates the inverse relationship between force and the lever arm length (distance) for a constant torque. \( \text{Torque} = F \times d \). If torque is constant, then \( F_1 d_1 = F_2 d_2 \).

 

Question 4. The ratio of masses of two planets is 2 : 3 and the ratio of their radii is 4 : 7. Find the ratio of their accelerations due to gravity.
Answer:
Given:
Ratio of masses \( m_1 : m_2 = 2 : 3 \)
Ratio of radii \( R_1 : R_2 = 4 : 7 \)
The acceleration due to gravity on a planet is given by the formula \( g = \frac{GM}{R^2} \), where G is the gravitational constant, M is the mass of the planet, and R is its radius.
For planet 1: \( g_1 = \frac{GM_1}{R_1^2} \)
For planet 2: \( g_2 = \frac{GM_2}{R_2^2} \)
To find the ratio \( g_1 : g_2 \), we divide \( g_1 \) by \( g_2 \):
\( \frac{g_1}{g_2} = \frac{\frac{GM_1}{R_1^2}}{\frac{GM_2}{R_2^2}} \)
\( \implies \frac{g_1}{g_2} = \frac{M_1}{R_1^2} \times \frac{R_2^2}{M_2} \)
\( \implies \frac{g_1}{g_2} = \left(\frac{M_1}{M_2}\right) \times \left(\frac{R_2}{R_1}\right)^2 \)
Substitute the given ratios:
\( \frac{M_1}{M_2} = \frac{2}{3} \)
\( \frac{R_2}{R_1} = \frac{7}{4} \)
\( \implies \frac{g_1}{g_2} = \left(\frac{2}{3}\right) \times \left(\frac{7}{4}\right)^2 \)
\( \implies \frac{g_1}{g_2} = \left(\frac{2}{3}\right) \times \left(\frac{49}{16}\right) \)
\( \implies \frac{g_1}{g_2} = \frac{2 \times 49}{3 \times 16} \)
\( \implies \frac{g_1}{g_2} = \frac{98}{48} \)
\( \implies \frac{g_1}{g_2} = \frac{49}{24} \)
Thus, the ratio of their accelerations due to gravity is \( 49 : 24 \).
In simple words: Gravity on a planet depends on its mass and how big it is. If we compare two planets with different masses and sizes, we can calculate how much stronger or weaker gravity is on each. In this case, even though one planet is heavier, the other has a smaller radius, making its gravity stronger.

๐ŸŽฏ Exam Tip: The acceleration due to gravity \( g \) is directly proportional to mass \( M \) and inversely proportional to the square of the radius \( R \). When dealing with ratios, remember to invert the radius ratio if it's \( R_1:R_2 \) and you need \( R_2:R_1 \).

 

Question 3. Deduce the equation of a force using Newton's second law of motion.
Answer:
Let's consider an object with mass 'm' moving in a straight line with an initial velocity \( V \). After a time period 't', an unbalanced external force 'F' acts on the object, causing its velocity to change to \( v \).
The initial momentum of the body is \( P_{\text{initial}} = m \times V \).
The final momentum of the body is \( P_{\text{final}} = m \times v \).
The change in momentum \( \Delta p = P_{\text{final}} - P_{\text{initial}} = mv - mV = m(v - V) \).
Newton's second law states that force is directly proportional to the rate of change of linear momentum.
So, Force \( F \propto \text{rate of change of momentum} \)
\( \implies F \propto \frac{\text{change in momentum}}{\text{time}} \)
\( \implies F \propto \frac{m(v - V)}{t} \)
We know that acceleration \( a = \frac{\text{change in velocity}}{\text{time}} = \frac{v - V}{t} \).
Substituting 'a' into the proportionality:
\( F \propto ma \)
To convert this proportionality into an equation, we introduce a constant 'k'.
\( F = kma \)
In the SI system of units, the constant \( k \) is equal to 1. This means a unit force produces a unit acceleration in a unit mass.
Therefore, the equation of force is \( F = ma \). This is the mathematical form of Newton's second law, showing that force is equal to mass times acceleration.
In simple words: Newton's second law explains that a push or pull (force) makes an object speed up or slow down (accelerate). The stronger the push and the lighter the object, the more it speeds up. So, Force equals mass times acceleration.

๐ŸŽฏ Exam Tip: Start with the definition of Newton's second law in terms of momentum change. Clearly show the steps, defining initial and final momentum, change in momentum, and how this leads to \( F=ma \).

 

Question 4. State and prove the law of conservation of linear momentum.
Answer:
**Statement of Law:** The law of conservation of linear momentum states that if no external force acts on a system of two or more interacting objects, their total linear momentum remains constant (conserved). This means that the total momentum before any interaction (like a collision) is equal to the total momentum after the interaction.

**Proof:**
Consider two bodies, A and B, with masses \( m_1 \) and \( m_2 \), respectively. They are moving along a straight line with initial velocities \( u_1 \) and \( u_2 \). Let's assume \( u_1 > u_2 \), so body A will eventually collide with body B.
During the collision, which lasts for a time interval 't' seconds:
Body A exerts a force \( F_A \) on body B.
Body B exerts a force \( F_B \) on body A.
After the collision, the bodies move with final velocities \( v_1 \) and \( v_2 \) along the same straight line.

From Newton's second law, the force is the rate of change of momentum:
Force on body B due to A: \( F_{\text{AB}} = \frac{m_2(v_2 - u_2)}{t} \)
Force on body A due to B: \( F_{\text{BA}} = \frac{m_1(v_1 - u_1)}{t} \)

According to Newton's third law of motion, for every action, there is an equal and opposite reaction. So, the force exerted by A on B is equal in magnitude and opposite in direction to the force exerted by B on A.
Action force \( = - \) Reaction force
\( F_{\text{AB}} = -F_{\text{BA}} \)
\( \implies \frac{m_2(v_2 - u_2)}{t} = -\frac{m_1(v_1 - u_1)}{t} \)
We can cancel 't' from both sides:
\( m_2(v_2 - u_2) = -m_1(v_1 - u_1) \)
\( m_2 v_2 - m_2 u_2 = -m_1 v_1 + m_1 u_1 \)
Rearranging the terms to group initial and final momenta:
\( m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2 \)
This equation shows that the total momentum before the collision (left side) is equal to the total momentum after the collision (right side). This proof confirms that in the absence of any external force, the total linear momentum of the system is conserved.
In simple words: The law of conservation of momentum means that in a closed group of objects, the total "push" or "movement energy" always stays the same. If two objects bump into each other, their total movement before the bump is the same as their total movement after. This happens because for every push one object gives, it gets an equal and opposite push back.

๐ŸŽฏ Exam Tip: Clearly state the law first, emphasizing the "isolated system" condition. In the proof, correctly apply Newton's second and third laws, and ensure your algebraic steps logically lead to the equality of total initial and final momentum.

 

Question 5. Describe rocket propulsion.
Answer: Rocket propulsion works based on two main ideas: the law of conservation of linear momentum and Newton's third law of motion. Rockets carry fuel, which can be liquid or solid, in a special tank. When the rocket is launched, this fuel burns, and hot gas shoots out from the back (the nozzle) at a very high speed. This creates a large push, or momentum. To balance this push, an equal and opposite force, called a reaction force, is created inside the engine's burning chamber, which pushes the rocket forward. As the rocket moves, its total mass gets lighter because it uses up its fuel. This leads to a gradual increase in the rocket's speed as it goes higher. Eventually, the rocket reaches a speed called escape velocity, which is fast enough for it to break free from Earth's gravity. This continuous ejection of mass helps the rocket gain speed and move against gravity.
In simple words: Rockets move forward by burning fuel and pushing hot gas out very fast, following Newton's laws of motion. This push creates an equal and opposite reaction that makes the rocket fly.

๐ŸŽฏ Exam Tip: When describing rocket propulsion, always mention both the conservation of linear momentum and Newton's third law as the underlying principles, as they are crucial for a complete answer.

 

Question 6. State the universal law of gravitation and derive its mathematical expression.
Answer: Newton's universal law of gravitation states that every single particle of matter in the universe pulls every other particle towards itself with a force. This force is directly proportional to the product of their masses, meaning if the masses are larger, the force is stronger. The force is also inversely proportional to the square of the distance between the centers of these masses, meaning if they are further apart, the force quickly becomes much weaker. The direction of this force always acts along the straight line that connects the centers of the two masses. This gravitational force is always attractive and does not depend on what material is between the objects.

**Mathematical Expression:**
Let \( m_1 \) and \( m_2 \) be the masses of two bodies, A and B.
Let \( r \) be the distance between their centers.

According to the law of gravitation:
Force \( F \propto m_1 \times m_2 \) (Directly proportional to the product of masses)
Force \( F \propto \frac{1}{r^2} \) (Inversely proportional to the square of the distance)

Combining these two expressions:
\( F \propto \frac{m_1 m_2}{r^2} \)
To change this proportionality into an equation, we introduce a constant \( G \):
\( F = \frac{G m_1 m_2}{r^2} \)

Here, \( G \) is the universal gravitational constant. Its value in the SI unit system is approximately \( 6.674 \times 10^{-11} \text{ Nm}^2 \text{ kg}^{-2} \). The strength of gravity is often visualized as a field around massive objects, influencing other objects within that field.
In simple words: The law says that all objects with mass pull on each other. This pull is stronger if the objects are heavier and weaker if they are farther apart. The formula \( F = \frac{G m_1 m_2}{r^2} \) calculates this pulling force.

๐ŸŽฏ Exam Tip: When deriving the formula, clearly state the proportionalities first, then combine them, and finally introduce the gravitational constant G. Remember to also define G and its value.

 

Question 7. Give the applications of gravitation.
Answer: Here are some applications of the law of gravitation:
1. We can measure the sizes of celestial bodies, like the mass and radius of the Earth, and even the acceleration due to gravity with great accuracy. This helps us understand our planet and other planets better.
2. The law helps scientists find new stars and planets in space, as their gravitational pull can affect the motion of other known celestial bodies.
3. It helps explain certain unusual movements of stars, sometimes called 'wobbles'. By studying these wobbles, scientists can figure out the mass of nearby planets that cause these disturbances.
4. Gravitation explains why plant roots grow downwards, a process called geotropism. Roots respond to Earth's gravity and always grow in that direction to find water and nutrients.
5. This law is also used to predict exactly where astronomical bodies will move in space, helping us track planets, moons, and even comets.
In simple words: Gravity helps us measure planets, find new stars, understand why roots grow down, and predict how objects move in space.

๐ŸŽฏ Exam Tip: Focus on distinct applications that showcase the broad impact of gravitation, from planetary motion to everyday phenomena like root growth.

 

IX. HOT Questions

 

Question 1. Two blocks of masses 8 kg and 2 kg respectively lie on a smooth horizontal surface in contact with one other. They are pushed by a horizontally applied force of 15 N. Calculate the force exerted on the 2 kg mass.
Answer:
Mass of first block \( m_1 = 8 \text{ kg} \)
Mass of second block \( m_2 = 2 \text{ kg} \)
Total mass \( M = m_1 + m_2 = 8 + 2 = 10 \text{ kg} \)
Force applied \( F = 15 \text{ N} \)
First, find the acceleration of the system:
\( \text{Acceleration } a = \frac{F}{M} \)
\( a = \frac{15}{10} = 1.5 \text{ m/s}^2 \)
Now, calculate the force exerted *on* the 2 kg mass, which is \( m_2 \). This force is what makes \( m_2 \) accelerate.
Force exerted on the 2 kg mass, \( F_2 = m_2 a \)
\( F_2 = 2 \times 1.5 = 3 \text{ N} \)
Therefore, the 8 kg block exerts a 3 N force on the 2 kg block, pushing it forward.
In simple words: When a force pushes two blocks together, both blocks accelerate at the same rate. We first find this acceleration, then use it to figure out how much force the first block pushes on the second, lighter block.

๐ŸŽฏ Exam Tip: For problems involving blocks in contact, always find the common acceleration of the system first. Then, apply Newton's second law to the specific block on which the force is being exerted.

 

Question 2. A heavy truck and bike are moving with the same kinetic energy. If the mass of the truck is four times that of the bike, then calculate the ratio of their momenta.
Answer:
Let the mass of the truck be \( m_1 \)
Let the mass of the bike be \( m_2 \)
Given: mass of truck \( m_1 = 4m_2 \)
This means \( \frac{m_1}{m_2} = 4 \)
Also given: Kinetic energy of truck \( K.E_1 = K.E_2 \) Kinetic energy of bike
We know the relation between kinetic energy (KE) and momentum (P): \( K.E = \frac{P^2}{2m} \)
So, \( \frac{P_1^2}{2m_1} = \frac{P_2^2}{2m_2} \)
\( \frac{P_1^2}{m_1} = \frac{P_2^2}{m_2} \)
\( \frac{P_1^2}{P_2^2} = \frac{m_1}{m_2} \)
Taking the square root of both sides:
\( \frac{P_1}{P_2} = \sqrt{\frac{m_1}{m_2}} \)
Substitute the given mass ratio:
\( \frac{P_1}{P_2} = \sqrt{4} \)
\( \frac{P_1}{P_2} = 2 \)
Therefore, the ratio of their momenta is \( 2:1 \). This shows that even with the same kinetic energy, a heavier object will have more momentum.
In simple words: Even if a heavy truck and a light bike have the same energy when moving, the truck will have twice as much "moving force" or momentum because it is much heavier.

๐ŸŽฏ Exam Tip: Remember the relationship \( KE = \frac{P^2}{2m} \) for connecting kinetic energy and momentum problems. It's a quick way to solve such ratio questions efficiently.

 

Question 3. "Wearing helmet and fastening the seat belt is highly recommended for safe journey" Justify your answer using Newton's laws of motion.
Answer: Wearing a helmet and using a seat belt are very important for safety because of Newton's laws of motion:
(i) **Newton's First Law (Inertia) & Second Law:** When a car stops suddenly, the passengers inside continue to move forward due to inertia (Newton's First Law). If they hit the dashboard or windshield, the impact force is very large because their momentum changes very quickly over a short time (Newton's Second Law, \( F = \frac{\Delta P}{\Delta t} \)). A seat belt prevents the person from hitting these hard surfaces. Instead, it applies a force over a longer time, reducing the impact force. Similarly, if a bike rider falls, their head continues to move forward due to inertia. A helmet provides a soft, protective layer that spreads the impact force over a larger area and longer time, reducing the pressure and injury to the head. This extended impact time reduces the overall force.
(ii) **Newton's Third Law:** In a collision, if you hit a surface, that surface will hit you back with an equal and opposite force. For example, if your head hits the road during a fall, the road exerts a large force back on your head. Helmets and seat belts work to reduce the harmful effects of these reaction forces. They either absorb some of the energy or spread the force over a larger area, making it less dangerous. They effectively turn a sharp, damaging impact into a more cushioned, less harmful one.
In simple words: Helmets and seat belts keep you safe by reducing the force of impact during a sudden stop or crash. They do this by making the time of impact longer and spreading the force over a bigger area, which lessens the injury according to Newton's laws.

๐ŸŽฏ Exam Tip: Clearly link each safety measure (helmet, seat belt) to the relevant Newton's laws (inertia, force and momentum change, action-reaction) and explain *how* they reduce injury by increasing impact time or spreading force.

 

I. Choose the correct answer

 

Question 1. When a force is exerted on an object, it can change its:
(a) state
(b) shape
(c) position
(d) all the options
Answer: (d) all the options
In simple words: When you push or pull an object, you can make it start moving or stop (change state), squish it (change shape), or move it from one place to another (change position).

๐ŸŽฏ Exam Tip: Remember that force can cause multiple effects, not just motion. Consider all physical changes a force can induce.

 

Question 2. When the train stops, the passenger moves forward, It is due to
(a) Inertia of passenger
(b) Inertia of train
(c) gravitational pull by the earth
(d) None of the options
Answer: (a) Inertia of passenger
In simple words: When the train stops suddenly, your body wants to keep moving forward because of its inertia, making you lean ahead.

๐ŸŽฏ Exam Tip: This is a classic example of inertia of motion. Always identify which object's inertia is relevant to the observation.

 

Question 3. Force is a ........ quantity.
(a) vector
(b) fundamental
(c) scalar
(d) none
Answer: (a) vector
In simple words: Force is a vector because it has both a size (how strong it is) and a direction (which way it pushes or pulls).

๐ŸŽฏ Exam Tip: Clearly distinguish between scalar quantities (only magnitude) and vector quantities (magnitude and direction).

 

Question 4. The force of gravitation is _________.
(a) repulsive
(b) conservative
(c) electrostatic
(d) non-conservative.
Answer: (b) conservative
In simple words: Gravity is a conservative force, which means the work it does on an object only depends on the start and end positions, not on the path taken.

๐ŸŽฏ Exam Tip: Understand that a conservative force, like gravity, allows for the definition of potential energy, which is path-independent.

 

Question 5. The laws of motion of a body is given by _________.
(a) Galileo
(b) Archimedes
(c) Einstein
(d) Newton
Answer: (d) Newton
In simple words: Isaac Newton is the scientist who gave us the main laws that explain how things move and interact with forces.

๐ŸŽฏ Exam Tip: This is a direct recall question. Be sure to associate key scientific laws with their discoverers.

 

Question 6. A bodyweight 700 N on earth. What will be its weight on a planet having 1/7 of earth's mass and half of the earth's radius?
(a) 400 N
(b) 300 N
(c) 200 N
(d) 400 N
Answer: (a) 400 N
In simple words: If a body weighs 700 N on Earth, its weight on a planet with 1/7 the Earth's mass and half the Earth's radius will be 400 N. This is because gravity depends on both mass and radius.

๐ŸŽฏ Exam Tip: To solve this, remember the formula for acceleration due to gravity \( g = \frac{GM}{R^2} \) and weight \( W = mg \). Calculate the new 'g' first, then the new weight.
**Calculation:**
Weight on Earth \( W_E = mg_E = 700 \text{ N} \)
\( g_E = \frac{GM_E}{R_E^2} \)
On the new planet:
\( M_P = \frac{1}{7} M_E \)
\( R_P = \frac{1}{2} R_E \)
\( g_P = \frac{GM_P}{R_P^2} = \frac{G (\frac{1}{7} M_E)}{(\frac{1}{2} R_E)^2} = \frac{\frac{1}{7} G M_E}{\frac{1}{4} R_E^2} = \frac{4}{7} \frac{G M_E}{R_E^2} = \frac{4}{7} g_E \)
Weight on planet \( W_P = m g_P = m (\frac{4}{7} g_E) = \frac{4}{7} (m g_E) = \frac{4}{7} W_E \)
\( W_P = \frac{4}{7} \times 700 \text{ N} = 4 \times 100 \text{ N} = 400 \text{ N} \)

 

Question 7. From the following statements write down that which is not applicable to mass of an object:
(a) It is a fundamental quantity
(b) It is measured using physical balance
(c) It is measured using spring balance
(d) It is the amount of matter.
Answer: (c) It is measured using spring balance
In simple words: Mass is how much 'stuff' an object has and is a basic measurement, found using a physical balance. A spring balance measures weight, not mass.

๐ŸŽฏ Exam Tip: Remember that a physical balance (like a beam balance) compares masses, while a spring balance measures weight, which can change with gravity, unlike mass.

 

Question 8. Newton's first law of motion defines:
(a) inertia
(b) force
(c) acceleration
(d) both inertia and force
Answer: (d) both inertia and force
In simple words: Newton's first law talks about inertia, which is how objects resist changes in motion, and it also hints at what a force is by saying what happens if there's no net force.

๐ŸŽฏ Exam Tip: Newton's First Law is often called the Law of Inertia, describing an object's tendency to resist changes in its state of motion. It implies the definition of force as an external agent causing such a change.

 

Question 9. Mechanics is divided into ________ types.
(a) one
(b) two
(c) three
(d) four.
Answer: (b) two
In simple words: The study of how things move and forces work (mechanics) is split into two main parts: statics (things that don't move) and dynamics (things that do move).

๐ŸŽฏ Exam Tip: Recall the two main branches of mechanics: statics (study of forces on objects at rest or in uniform motion) and dynamics (study of forces on objects in motion, considering the cause).

 

Question 10. When an object undergoes acceleration:
(a) its velocity increases
(b) its speed increases
(c) its motion is uniform
(d) a force always acts on it
Answer: (d) a force always acts on it
In simple words: When an object is accelerating, it means its speed or direction of movement is changing, and this change can only happen if a force is pushing or pulling it.

๐ŸŽฏ Exam Tip: Remember Newton's Second Law, which states that acceleration is directly proportional to the net force and inversely proportional to mass (\( F = ma \)). Thus, acceleration always requires a net force.

 

Question 11. On what factor does inertia of a body depend?
(a) volume
(b) area
(c) mass
(d) density
Answer: (c) mass
In simple words: Inertia, which is an object's resistance to changing its motion, directly depends on how much mass it has; heavier objects have more inertia.

๐ŸŽฏ Exam Tip: Mass is the fundamental measure of inertia. The more mass an object has, the harder it is to start it moving or stop it once it's in motion.

 

Question 12. _________ deals with the motion of bodies without considering the cause of motion.
(a) Inertia
(b) Force
(c) Kinematics
(d) kinetics.
Answer: (c) Kinematics
In simple words: Kinematics is the part of science that studies how things move (like speed and distance) without caring about what forces are making them move.

๐ŸŽฏ Exam Tip: Differentiate between kinematics (describes motion) and dynamics (explains motion with forces). This distinction is fundamental in mechanics.

 

Question 13. If mass of an object is m, velocity v, acceleration a and applied force is F, then momentum P is given by:
(a) \( P = m \times v \)
(b) \( P = m \times a \)
(c) \( P = \frac{m}{v} \)
(d) \( P = \frac{v}{m} \)
Answer: (a) P = m x v
In simple words: Momentum is a measure of how much "oomph" a moving object has, calculated by multiplying its mass by its velocity.

๐ŸŽฏ Exam Tip: This is a definition-based question. Ensure you know the basic formulas for momentum (\( P=mv \)), force (\( F=ma \)), and kinetic energy (\( KE = \frac{1}{2}mv^2 \)).

 

Question 14. Which of the following is a vector quantity?
(a) speed
(b) distance
(c) momentum
(d) time
Answer: (c) momentum
In simple words: Momentum is a vector quantity because it tells us both how much an object is moving (its magnitude) and in what direction it is moving.

๐ŸŽฏ Exam Tip: Remember that vector quantities have both magnitude and direction (e.g., momentum, velocity, force), while scalar quantities only have magnitude (e.g., speed, distance, time, mass).

 

Question 15. Unit of momentum in SI system is _________.
(a) ms-1
(b) Kg ms-2
(c) Kg ms-1
(d) ms-2
Answer: (c) Kg ms-1
In simple words: Since momentum is mass times velocity, its standard unit is kilograms (for mass) multiplied by meters per second (for velocity).

๐ŸŽฏ Exam Tip: Always derive the unit from the formula (\( P = mv \)), using SI units for each component. \( \text{mass (kg)} \times \text{velocity (m/s)} = \text{kg m/s} \).

 

Question 16. Force is measured based on:
(a) Newton's first law
(b) Newton's second law
(c) Newton's third law
(d) All the options
Answer: (b) Newton's second law
In simple words: Newton's second law (\( F=ma \)) is the one that actually tells us how to measure force, connecting it to an object's mass and how much it accelerates.

๐ŸŽฏ Exam Tip: While all three laws describe aspects of force, Newton's Second Law (\( F=ma \)) provides the quantitative definition and method for measuring force.

 

Question 17. Force measures rate of change of:
(a) acceleration
(b) velocity
(c) momentum
(d) distances
Answer: (c) momentum
In simple words: Force directly measures how fast an object's momentum changes over time, as stated by Newton's second law.

๐ŸŽฏ Exam Tip: This is a direct statement from Newton's Second Law: Force is equal to the rate of change of momentum (\( F = \frac{\Delta P}{\Delta t} \)).

 

Question 18. The rotating or turning effect of a force about a fixed point or fixed axis is called _________.
(a) Force
(b) momentum
(c) torque
(d) couples.
Answer: (c) torque
In simple words: Torque is the turning power of a force that makes an object spin around a central point, like how you turn a doorknob.

๐ŸŽฏ Exam Tip: Distinguish torque from force; force causes linear motion, while torque causes rotational motion. Moment of force is another name for torque.

 

Question 19. The physical quantity which is equal to the rate of change of momentum is:
(a) displacement
(b) acceleration
(c) force
(d) velocity
Answer: (c) force
In simple words: When an object's momentum changes quickly, it means a strong force is acting on it, so force is directly related to how fast momentum changes.

๐ŸŽฏ Exam Tip: Newton's Second Law in its most general form defines force as the rate of change of momentum. This is a fundamental definition.

 

Question 20. The momentum of a massive object at rest is:
(a) very large
(b) very small
(c) zero
(d) infinity
Answer: (c) zero
In simple words: Momentum is mass times velocity, so if an object is not moving (velocity is zero), its momentum will also be zero, no matter how heavy it is.

๐ŸŽฏ Exam Tip: Recall the momentum formula \( P = mv \). If velocity (\( v \)) is zero, then momentum (\( P \)) must also be zero, regardless of mass (\( m \)).

 

Question 21. The velocity which is sufficient to just escape from the gravitational pull of the earth is _________.
(a) drift velocity
(b) escape velocity
(c) gradual velocity
(d) final velocity
Answer: (b) escape velocity
In simple words: Escape velocity is the specific speed an object needs to reach to break free from the gravity of a planet or moon and fly into space without falling back.

๐ŸŽฏ Exam Tip: Escape velocity is a critical concept in space physics, representing the minimum velocity required for an object to overcome the gravitational attraction of a celestial body.

 

Question 22. A force applied on an object is equal to:
(a) product of mass and velocity
(b) sum of mass and velocity of an object
(c) product of mass and acceleration
(d) sum of mass and acceleration
Answer: (c) product of mass and acceleration
In simple words: The force acting on an object is found by multiplying its mass by its acceleration, which is Newton's second law.

๐ŸŽฏ Exam Tip: This question directly tests Newton's Second Law (\( F = ma \)), which is central to understanding forces and motion.

 

Question 23. Action and reaction do not balance each other because they:
(a) act on the same body
(b) do not act on the same body
(c) are in opposite direction
(d) are unequal
Answer: (b) do not act on the same body
In simple words: Action and reaction forces don't cancel each other out because they push or pull on two different objects, not just one.

๐ŸŽฏ Exam Tip: A common misconception is that action-reaction pairs cancel. Emphasize that these forces always act on *different* bodies, making cancellation impossible for a single body.

 

Question 24. The value of variation of acceleration due to gravity (g) is _________ at the centre of the earth.
(a) one
(b) zero
(c) \( \infty \)
(d) \( \frac{1}{\infty} \)
Answer: (b) zero
In simple words: If you could go right to the very center of the Earth, the pull of gravity would be zero because all the mass of the Earth would be pulling you equally in every direction.

๐ŸŽฏ Exam Tip: Remember that inside a uniform spherical shell, gravitational force is zero. At the Earth's center, all mass pulls equally in all directions, leading to a net gravitational acceleration of zero.

 

Question 25. Action and reaction forces are:
(a) equal in magnitude
(b) equal in direction
(c) opposite in direction
(d) both equal in magnitude and opposite in direction
Answer: (d) both equal in magnitude and opposite in direction
In simple words: Action and reaction forces are always the same strength but always push or pull in exact opposite directions.

๐ŸŽฏ Exam Tip: This directly states Newton's Third Law. It is crucial to remember both aspects: equal magnitude and opposite direction.

 

Question 26. If mass of a body is doubled then its acceleration becomes:
(a) halved
(b) doubled
(c) thrice
(d) zero
Answer: (a) halved
In simple words: If you double the mass of an object but keep the same pushing force, the object will accelerate only half as much because it's heavier.

๐ŸŽฏ Exam Tip: Apply Newton's Second Law (\( F=ma \)). If force (\( F \)) is constant, then acceleration (\( a \)) is inversely proportional to mass (\( m \)). So, if \( m \) doubles, \( a \) halves.

 

Question 27. The principle involved in the working of a jet plane is:
(a) Newton's first law
(b) Conservation of momentum
(c) Law of inertia
(d) Newton's second law
Answer: (b) Conservation of momentum
In simple words: Jet planes work by pushing out hot gas in one direction, which makes the plane move in the opposite direction, following the rule that total momentum stays the same.

๐ŸŽฏ Exam Tip: Jet propulsion, like rocket propulsion, is a prime example of the conservation of linear momentum. The expulsion of mass at high velocity in one direction creates momentum, which is balanced by the momentum gained by the plane in the opposite direction.

 

Question 28. _________ of a body is defined as the quantity of matter contained in the object.
(a) weight
(b) mass
(c) force
(d) momentum.
Answer: (b) mass
In simple words: Mass is simply how much material or 'stuff' an object is made of.

๐ŸŽฏ Exam Tip: Understand that mass is an intrinsic property of an object, representing the amount of matter, and is distinct from weight, which is the force of gravity acting on that mass.

 

Question 29. A gun gets kicked back when a bullet is fired. It is a good example of Newton's:
(a) first law
(b) first law
(c) second law
(d) third law
Answer: (d) third law
In simple words: When a bullet is fired, it pushes forward, and the gun pushes back on your shoulder with the same force, which is an example of Newton's third law of action and reaction.

๐ŸŽฏ Exam Tip: Recoil of a gun is a classic illustration of Newton's Third Law (action-reaction pairs) and also the conservation of momentum. When the gun exerts a force on the bullet, the bullet exerts an equal and opposite force on the gun.

 

Question 30. To change the state or position of an object, force is essential.
(a) balanced
(b) unbalanced
(c) electric
(d) elastic
Answer: (b) unbalanced
In simple words: To make something start moving, stop moving, or change its direction, you always need an unbalanced force acting on it. A balanced force results in no change in motion.

๐ŸŽฏ Exam Tip: Remember that balanced forces cause no change in motion, only unbalanced forces can make an object accelerate or change its state.

 

Question 31. When a bus starts suddenly, the passengers in the standing position are pushed backwards, this action is due to:
(a) first law of motion
(b) second law of motion
(c) third law of motion
(d) conservation of momentum
Answer: (a) first law of motion
In simple words: When the bus suddenly moves, your body wants to stay still because of inertia. This resistance to change in motion makes you feel pushed backward relative to the bus.

๐ŸŽฏ Exam Tip: Newton's first law, also known as the law of inertia, explains why objects resist changes in their state of motion or rest.

 

Question 32. When a body at rest breaks into two pieces of equal masses, then the parts will move:
(a) in same direction
(b) along different directions
(c) with unequal speeds
(d) in opposite directions with equal speeds
Answer: (d) in opposite directions with equal speeds
In simple words: If something breaks into two equal parts while sitting still, the parts will fly off in exact opposite ways, both moving at the same speed. This is because the total push (momentum) before and after must stay the same.

๐ŸŽฏ Exam Tip: This scenario is a classic example of the conservation of linear momentum, where the total momentum of a system remains constant if no external forces act on it.

 

Question 33. The principle of function of a jet aeroplane is based on:
(a) first law of motion
(b) second law of motion
(c) third law of motion
(d) all of the options
Answer: (c) third law of motion
In simple words: Jet planes work because they push hot gas backward very fast. As a reaction, the plane gets pushed forward with an equal force.

๐ŸŽฏ Exam Tip: Rocket and jet propulsion are primary real-world applications of Newton's third law, where action and reaction forces drive movement.

 

Question 34. Which of the following has the largest inertia?
(a) pin
(b) book
(c) pen
(d) table
Answer: (d) table
In simple words: Inertia is how much an object resists changing its motion. Heavier objects have more inertia. A table is usually the heaviest among the choices, so it has the most inertia.

๐ŸŽฏ Exam Tip: Inertia is directly proportional to mass; the more mass an object has, the harder it is to start it moving or stop it from moving.

 

Question 35. An athlete runs a long path before taking a long jump to increase:
(a) energy
(b) inertia
(c) momentum
(d) force
Answer: (c) momentum
In simple words: Running before a jump helps an athlete gain speed and mass in motion, which increases their momentum. This extra momentum helps them travel a longer distance in the air.

๐ŸŽฏ Exam Tip: Momentum is a crucial concept in sports like long jump, as it directly influences how far an athlete can travel after leaving the ground.

 

Question 36. The weight of a person is 50 kg. The weight of that person on the surface
(a) 50 N
(b) 35 N
(c) 380 N
(d) 490 N
Answer: (d) 490 N
In simple words: To find the weight of the person on Earth, you multiply their mass (50 kg) by the acceleration due to gravity (about 9.8 m/sยฒ). This calculation gives you 490 Newtons.

๐ŸŽฏ Exam Tip: Always remember the difference between mass (measured in kg) and weight (measured in N), and use \( W = mg \) to calculate weight on Earth where \( g \approx 9.8 \text{ m/s}^2 \).

 

Question 37. Which is incorrect statement about the action and reaction referred to Newton's third law of motion?
(a) They are equal
(b) They are opposite
(c) They act on the same object
(d) They act on two different objects
Answer: (c) They act on the same object
In simple words: Newton's third law says that for every action, there is an equal and opposite reaction. These forces always act on two different objects, not on the same one.

๐ŸŽฏ Exam Tip: A common mistake is to think action-reaction pairs cancel out because they are equal and opposite, but they can't cancel if they act on different objects.

 

Question 38. The tendency of a force to rotate a body about a given axis is called:
(a) turning effect of a force
(b) moment of force
(c) torque
(d) all of the options
Answer: (d) all of the options
In simple words: All these words โ€” turning effect of a force, moment of force, and torque โ€” mean the same thing. They all describe how a force can make something spin or twist.

๐ŸŽฏ Exam Tip: These terms are often used interchangeably in physics to describe the rotational effect produced by a force.

 

Question 39. The moment of force is:
(a) product of force and the perpendicular distance
(b) product of force and velocity
(c) ratio of force to the acceleration
(d) ratio of force to the perpendicular distance
Answer: (a) product of force and the perpendicular distance
In simple words: The moment of force is calculated by multiplying the force by the shortest distance from the pivot point to where the force is applied. This distance must be at a right angle to the force.

๐ŸŽฏ Exam Tip: Always ensure the distance used in the calculation is the perpendicular distance from the pivot to the line of action of the force for an accurate moment of force.

 

Question 40. If the force rotates the body in the anticlockwise direction, then the moment is called:
(a) clockwise moment
(b) anticlockwise moment
(c) couple
(d) torque
Answer: (b) anticlockwise moment
In simple words: When a force makes something turn against the direction a clock's hands move, we call it an anticlockwise moment. This is a specific way to describe the turning effect.

๐ŸŽฏ Exam Tip: In many physics conventions, anticlockwise moments are considered positive, while clockwise moments are considered negative.

 

Question 41. Anticlockwise moment is:
(a) positive
(b) negative
(c) opposite
(d) zero
Answer: (a) positive
In simple words: In physics, we usually say that a turning force (moment) that goes against the clock's direction is a positive value. This helps us keep track of direction in calculations.

๐ŸŽฏ Exam Tip: Consistency in sign convention for moments is crucial in problems involving rotational equilibrium or net torque calculations.

 

Question 42. Clockwise moment or torque is:
(a) zero
(b) always one
(c) negative
(d) positive
Answer: (c) negative
In simple words: Following the common rule in physics, a turning force (moment or torque) that spins something in the same direction as a clock's hands is given a negative sign. This is just a way to show its direction.

๐ŸŽฏ Exam Tip: Understanding the sign convention for moments is key to correctly solving problems involving rotational dynamics and equilibrium.

 

Question 43. SI unit of moment of force is:
(a) Nm\(^{-2}\)
(b) Nm\(^{-1}\)
(c) Ns
(d) Nm
Answer: (d) Nm
In simple words: Since moment of force is calculated by multiplying force (Newtons) by distance (meters), its standard unit is Newton-meter (Nm). This unit measures how much twisting force is applied.

๐ŸŽฏ Exam Tip: Be careful not to confuse Newton-meter (Nm) for torque with Joules (J) for energy, although they have the same units, they represent different physical quantities.

 

Question 44. Moment of force produces:
(a) acceleration
(b) linear motion
(c) velocity
(d) angular acceleration
Answer: (d) angular acceleration
In simple words: A moment of force, or torque, is what makes an object start to spin faster or slower. It creates a change in how quickly something rotates, which we call angular acceleration.

๐ŸŽฏ Exam Tip: Just as force causes linear acceleration, torque causes angular acceleration, indicating a change in rotational velocity.

 

Question 45. Two equal and opposite forces whose lines of action do not coincide are said to constitute a:
(a) couple
(b) torque
(c) unlike force
(d) parallel force
Answer: (a) couple
In simple words: When two forces are exactly the same size but pull in opposite directions, and they are not on the same line, they create a 'couple'. This couple makes an object twist or rotate.

๐ŸŽฏ Exam Tip: A couple is unique because it only produces a rotational effect (torque) and no translational (linear) motion.

 

Question 46. Couple produces:
(a) translatory motion
(b) rotatory motion
(c) translatory as well as rotatory motion
(d) neither translatory nor rotatory
Answer: (b) rotatory motion
In simple words: A couple of forces always makes an object spin around a point or axis. It does not make the object move in a straight line, only rotate.

๐ŸŽฏ Exam Tip: The net force of a couple is zero, so it cannot cause linear acceleration; its sole effect is to cause angular acceleration or rotation.

 

Question 47. ....... is an example of couple.
(a) opening or closing a tap
(b) turning of a key in a lock
(c) steering wheel of car
(d) all of the options
Answer: (d) all of the options
In simple words: All these actions involve two forces acting in opposite directions but not on the same line, which creates a twisting motion called a couple. When you turn a tap, key, or steering wheel, you're applying a couple.

๐ŸŽฏ Exam Tip: Common everyday actions like twisting a screwdriver or turning a bicycle handlebar also demonstrate the concept of a couple.

 

Question 48. Force of attraction between any two objects in the universe is called:
(a) gravitational force
(b) mechanical force
(c) magnetic force
(d) electrostatic force
Answer: (a) gravitational force
In simple words: Gravity is the special force that pulls any two objects together just because they have mass. It's the reason an apple falls from a tree and why planets orbit the sun.

๐ŸŽฏ Exam Tip: Gravitational force is one of the four fundamental forces of nature and always acts as an attractive force between objects with mass.

 

Question 49. Universal law of gravitation was given by:
(a) Archimedes
(b) Aryabhatta
(c) Kepler
(d) Newton
Answer: (d) Newton
In simple words: Sir Isaac Newton was the scientist who first explained the universal law of gravitation, describing how all objects in the universe attract each other. Kepler's laws described planetary motion, while Newton explained *why* they moved that way.

๐ŸŽฏ Exam Tip: Newton's law of universal gravitation is a foundational concept in physics, explaining phenomena from falling objects to planetary orbits.

 

Question 50. The force of gravitation between two bodies does not depend on:
(a) product of their masses
(b) their separation
(c) sum of their masses
(d) gravitational constant
Answer: (c) sum of their masses
In simple words: The strength of gravity between two objects depends on how much mass each object has, how far apart they are, and a special number called the gravitational constant. It does not depend on simply adding their masses together.

๐ŸŽฏ Exam Tip: Newton's law of gravitation states that \( F = \frac{Gm_1m_2}{r^2} \), clearly showing dependence on the product of masses, distance squared, and G, but not the sum of masses.

 

Question 51. Law of gravitation is applicable to:
(a) heavy bodies only
(b) small sized objects
(c) light bodies
(d) objects of any size
Answer: (d) objects of any size
In simple words: The law of gravitation works for all objects, no matter how big or small they are. Everything with mass attracts everything else with mass.

๐ŸŽฏ Exam Tip: The term "universal" in Newton's law of universal gravitation signifies its applicability to all masses, regardless of their size, composition, or location.

 

Question 52. The value of gravitational constant (G) is:
(a) different at different places
(b) same at all places in the universe
(c) different only at all the places of earth
(d) same only at all the places of earth
Answer: (b) same at all places in the universe
In simple words: The gravitational constant (G) is a special number that is always the same, no matter where you are in the universe. It helps us calculate the force of gravity between any two objects.

๐ŸŽฏ Exam Tip: Unlike 'g' (acceleration due to gravity), which varies with location and altitude, 'G' is a fundamental physical constant with a fixed value.

 

Question 53. The unit of gravitational constant is:
(a) Nm\(^2\) kg
(b) kgms\(^{-2}\)
(c) Nm\(^2\) kg\(^{-2}\)
(d) ms\(^{-2}\)
Answer: (c) Nm\(^2\) kg\(^{-2}\)
In simple words: The unit for the gravitational constant (G) is Newton meters squared per kilogram squared. This unit comes from the formula for gravitational force, \( F = \frac{Gm_1m_2}{r^2} \).

๐ŸŽฏ Exam Tip: You can derive the unit of G by rearranging the gravitational force formula: \( G = \frac{Fr^2}{m_1m_2} \), which gives \( \frac{\text{N} \cdot \text{m}^2}{\text{kg} \cdot \text{kg}} = \text{Nm}^2\text{kg}^{-2} \).

 

Question 54. The weight of an object is:
(a) the quantity of matter it contains
(b) its inertia
(c) same as its mass
(d) the force with which it is attracted by the earth
Answer: (d) the force with which it is attracted by the earth
In simple words: Weight is the force of gravity pulling an object towards a planet, usually the Earth. It's different from mass, which is just how much 'stuff' an object has.

๐ŸŽฏ Exam Tip: Weight is a force, so it has direction (always downwards) and is measured in Newtons (N), whereas mass is a scalar quantity measured in kilograms (kg).

 

Question 55. In vacuum, all freely falling objects have the same:
(a) speed
(b) velocity
(c) force
(d) acceleration
Answer: (d) acceleration
In simple words: If there's no air to slow things down, all objects, no matter how heavy or light, fall with the same increasing speed towards the Earth. This constant rate of speeding up is called acceleration.

๐ŸŽฏ Exam Tip: This principle, famously demonstrated by Galileo, shows that in the absence of air resistance, the acceleration due to gravity 'g' is constant for all falling objects.

 

Question 56. The acceleration due to gravity:
(a) has the same value everywhere in space
(b) has the same value everywhere on earth
(c) varies with the latitude on earth
(d) is greater on moon due to its smaller diameter
Answer: (c) varies with the latitude on earth
In simple words: The force that pulls things down (gravity) is not exactly the same everywhere on Earth. It changes a little bit depending on how far you are from the equator or the poles.

๐ŸŽฏ Exam Tip: The acceleration due to gravity 'g' varies with latitude because Earth is not a perfect sphere (it bulges at the equator) and due to the Earth's rotation.

 

Question 57. When an object is thrown up, the force of gravity:
(a) is opposite to the direction of motion
(b) is in the same direction as direction of motion
(c) decreases as it rises up
(d) increases as it rises up
Answer: (a) is opposite to the direction of motion
In simple words: When you throw something into the air, the force of gravity always pulls it downwards. This downward pull goes against the object's upward movement, causing it to slow down.

๐ŸŽฏ Exam Tip: Gravity is a constant downward force near the Earth's surface, acting against upward motion and with downward motion.

 

Question 58. The SI unit of acceleration due to gravity 'g' is:
(a) ms\(^{-1}\)
(b) ms
(c) ms\(^{-2}\)
(d) ms\(^2\)
Answer: (c) ms\(^{-2}\)
In simple words: The standard way to measure acceleration due to gravity is in meters per second squared. This tells us how much an object's speed changes each second as it falls.

๐ŸŽฏ Exam Tip: The unit for acceleration due to gravity is the same as for any other acceleration, indicating a rate of change of velocity.

 

Question 59. What happens to the value of 'g' as we go higher from surface of earth?
(a) decreases
(b) increases
(c) no change
(d) zero
Answer: (a) decreases
In simple words: As you go further away from the Earth's surface, the pull of gravity gets weaker. This means the value of 'g' (acceleration due to gravity) becomes smaller at higher altitudes.

๐ŸŽฏ Exam Tip: The acceleration due to gravity is inversely proportional to the square of the distance from the Earth's center, so 'g' decreases with increasing altitude.

 

Question 60. Mass of a body on moon is:
(a) the same as that on the earth
(b) \( \frac{1}{6} \)th of that at the surface of the earth
(c) 6 times as that on the earth
(d) none of the options
Answer: (a) the same as that on the earth
In simple words: The amount of 'stuff' an object is made of, called its mass, stays the same no matter where it is. So, a body's mass on the Moon is the same as its mass on Earth.

๐ŸŽฏ Exam Tip: Mass is an intrinsic property of an object and is independent of gravity or location, while weight changes depending on the gravitational field.

 

Question 61. At which place is the value of 'g' is zero?
(a) at poles
(b) at centre of the earth
(c) at equator
(d) above the earth
Answer: (b) at centre of the earth
In simple words: The acceleration due to gravity becomes zero right at the very middle of the Earth. This is because all the gravitational pulls from different parts of the Earth cancel each other out at the center.

๐ŸŽฏ Exam Tip: At the Earth's center, an object would experience weightlessness, as the net gravitational force on it would be zero due to symmetry.

 

Question 62. The weight of the body is maximum:
(a) at the centre of the earth
(b) on the surface of earth
(c) above the surface of earth
(d) none of the options
Answer: (b) on the surface of earth
In simple words: A body's weight is heaviest right on the surface of the Earth. As you go higher up or deeper down towards the center, the weight decreases because the gravitational pull changes.

๐ŸŽฏ Exam Tip: The maximum value of 'g' (and thus weight) occurs at the Earth's surface, specifically at the poles, due to a combination of distance and Earth's rotation.

 

Question 63. A rock is brought from the surface of the moon to the earth, then its:
(a) weight will change
(b) mass will change
(c) both mass and weight will change.
(d) mass and weight will remain the same
Answer: (a) weight will change
In simple words: When a rock is moved from the Moon to the Earth, its mass (the amount of material in it) stays the same. However, its weight changes because the Earth has a much stronger gravitational pull than the Moon.

๐ŸŽฏ Exam Tip: Mass is an intrinsic property, while weight is a force that depends on the local gravitational field.

 

Question 64. Why is the acceleration due to gravity on the surface of the moon is lesser than that on the surface of earth?
(a) because mass of moon is less
(b) radius of moon is less
(c) mass and radius of moon is large
(d) mass and radius of moon is less
Answer: (d) mass and radius of moon is less
In simple words: The Moon has a weaker pull of gravity than Earth because both its total mass and its size (radius) are smaller. The combination of these two factors makes gravity less on the Moon's surface.

๐ŸŽฏ Exam Tip: The formula for acceleration due to gravity is \( g = \frac{GM}{R^2} \), which shows that 'g' depends on both the mass (M) and the radius (R) of the celestial body.

 

Question 65. If the distance between two bodies is doubled, then the gravitational force between them is:
(a) halved
(b) doubled
(c) reduced to one-fourth
(d) increased by one fourth
Answer: (c) reduced to one-fourth
In simple words: The force of gravity gets weaker very quickly as objects move apart. If you double the distance between them, the gravitational pull becomes four times smaller.

๐ŸŽฏ Exam Tip: Gravitational force follows an inverse square law, meaning it is inversely proportional to the square of the distance between the centers of the two masses.

 

Question 66. The unit newton can also be written as:
(a) kgm
(b) kgms\(^{-1}\)
(c) kgms\(^{-2}\)
(d) kgm\(^{-2}\)s
Answer: (c) kgms\(^{-2}\)
In simple words: A Newton is the standard unit of force. It can also be expressed as kilograms times meters per second squared, which comes from Newton's second law, Force = mass \( \times \) acceleration.

๐ŸŽฏ Exam Tip: This derived unit for force (kg m/s\(^2\)) is fundamental in understanding the relationship between mass, acceleration, and force.

 

Question 67. A bus starts for rest and moves after 4 seconds. Its velocity is 100 ms\(^{-1}\). Its uniform acceleration is:
(a) 10 ms\(^{-2}\)
(b) 25 ms\(^{-2}\)
(c) 400 ms\(^{-2}\)
(d) 2.5 ms\(^{-2}\)
Answer: (b) 25 ms\(^{-2}\)
In simple words: The bus starts from still, then reaches a speed of 100 meters per second in 4 seconds. To find how fast it sped up (acceleration), you divide the change in speed by the time taken, which gives 25 meters per second squared.

๐ŸŽฏ Exam Tip: Remember the formula for acceleration, \( a = \frac{v-u}{t} \), where 'v' is final velocity, 'u' is initial velocity, and 't' is time. Starting from rest means \( u = 0 \).

 

Question 68. A body of mass 10 kg increases its velocity from 2 m/s to 8 m/s within 4 second by the application of a constant force. The magnitude of the applied force is:
(a) 1.5 N
(b) 30 N
(c) 15 N
(d) 150 N
Answer: (c) 15 N
In simple words: First, find how fast the body sped up (acceleration) using the change in velocity over time. Then, multiply this acceleration by the body's mass to find the force that was applied.

๐ŸŽฏ Exam Tip: This problem requires two steps: first calculating acceleration using kinematic equations, and then applying Newton's second law, \( F = ma \), to find the force.

 

Question 70. Which one of the following is scalar quantity?
(a) momentum
(b) moment of force
(c) speed
(d) velocity
Answer: (c) speed
In simple words: A scalar quantity only has a size (magnitude), but no direction. Speed is scalar because it only tells you how fast something is moving, not where it is going.

๐ŸŽฏ Exam Tip: Distinguish between scalar quantities (like speed, mass, time) and vector quantities (like velocity, momentum, force) which have both magnitude and direction.

 

Question 71. Which of the following changes the direction of motion of a body?
(a) momentum
(b) force
(c) energy
(d) mass
Answer: (b) force
In simple words: A force is a push or a pull that can make an object speed up, slow down, or change the direction it is moving in. Without a force, an object keeps going in a straight line at a steady speed.

๐ŸŽฏ Exam Tip: Newton's first law of motion states that an object's velocity (which includes direction) changes only if an external force acts on it.

 

Question 72. When one makes a sharp turns while driving a car he tends to lean sideways due to:
(a) inertia of rest
(b) inertia of motion
(c) inertia of direction
(d) all of the options
Answer: (c) inertia of direction
In simple words: When a car turns sharply, your body wants to keep moving in the original straight line. This resistance to changing direction is called inertia of direction, and it makes you feel like you're leaning sideways.

๐ŸŽฏ Exam Tip: Inertia is an object's resistance to any change in its state of motion, whether that's stopping, starting, or changing direction.

 

Question 73. The unit of momentum is:
(a) kg m
(b) m/s\(^2\)
(c) kg m/s
(d) joule
Answer: (c) kg m/s
In simple words: Momentum is calculated by multiplying an object's mass (in kilograms) by its velocity (in meters per second). So, its standard unit is kilogram meters per second.

๐ŸŽฏ Exam Tip: Momentum is a vector quantity, meaning it has both magnitude and direction, and its unit reflects both mass and velocity.

 

Question 74. Moment of a force is given by \( \tau = \)
(a) \( \frac{F}{d} \)
(b) \( F \times 2d \)
(c) \( F \times d \)
(d) \( \frac{F}{d} \)
Answer: (c) \( F \times d \)
In simple words: The twisting power of a force, also known as torque or moment of force, is found by multiplying the size of the force by the perpendicular distance from the pivot point. This formula helps calculate how much an object will rotate.

๐ŸŽฏ Exam Tip: Ensure that 'd' represents the perpendicular distance from the axis of rotation to the line of action of the force; using any other distance will lead to an incorrect calculation.

 

Question 75. Which of the following work on the principle of torque?
(a) Gears
(b) Seasaw
(c) all of the options
Answer: (c) all of the options
In simple words: Both gears and seesaws use the idea of torque, or twisting force, to work. Gears transfer turning power, and seesaws balance forces around a pivot point to create movement.

๐ŸŽฏ Exam Tip: The principle of moments (or torque) is widely applied in simple machines like levers, wheels and axles, and pulleys to achieve mechanical advantage.

 

Question 76. The SI unit of gravitational constant
(a) Nmยฒ/g
(b) Nmยฒkgยฒ
(c) Nmยฒkg-2
(d) Nmkg
Answer: (c) Nmยฒkg-2
In simple words: The unit for the universal gravitational constant, often written as G, shows how it relates force, mass, and distance. It helps us calculate the gravitational pull between any two objects.

๐ŸŽฏ Exam Tip: Remember the SI units for fundamental constants like gravitational constant (G) as they are frequently tested in objective questions.

 

Question 77. What is the value of gravitational constant?
(a) \( 6.674 \times 10^{-11} \) Nmยฒg-2
(b) \( 9.8 \times 10^{-11} \) Nmยฒg-2
(c) \( 6.647 \times 10^{-11} \) Nmยฒg-2
(d) \( 13.28 \times 10^{-11} \) Nmยฒg-2
Answer: (a) \( 6.674 \times 10^{-11} \) Nmยฒg-2
In simple words: The gravitational constant (G) is a fixed number used in physics to figure out how strong the gravity is between two objects. It is a very small number, meaning gravity is a weak force unless masses are very large.

๐ŸŽฏ Exam Tip: Memorize the precise value and unit of the universal gravitational constant (G), as small variations can lead to incorrect answers in MCQs.

 

Question 78. The value of mass of the Earth is:
(a) \( 6.972 \times 10^{24} \) kg
(b) \( 6.792 \times 10^{24} \) kg
(c) \( 5.972 \times 10^{24} \) kg
(d) \( 2.936 \times 10^{24} \) kg
Answer: (c) \( 5.972 \times 10^{24} \) kg
In simple words: The Earth has a very large mass, which is a key factor in how strongly it pulls objects towards its surface due to gravity. This immense mass creates the gravitational field we experience.

๐ŸŽฏ Exam Tip: Keep in mind the approximate values of major physical constants and astronomical data, as they are often required in calculations or multiple-choice questions.

 

Question 79. At poles of the Earth, weight of the body is:
(a) minimum
(b) maximum
(c) zero
(d) infinity
Answer: (b) maximum
In simple words: A body weighs the most at the Earth's poles because they are slightly closer to the Earth's center and the Earth's rotation has less effect there. This makes the pull of gravity strongest at the poles.

๐ŸŽฏ Exam Tip: Understand that the Earth's shape (bulging at the equator) and rotation influence the effective gravitational acceleration, leading to maximum weight at the poles and minimum at the equator.

 

Question 80. Where will the value of acceleration due to gravity be minimum?
(a) poles of the earth
(b) centre of the earth
(c) equator of the earth
(d) space
Answer: (d) space
In simple words: The acceleration due to gravity becomes very, very small, almost zero, when you are far away from Earth in space. This is because the gravitational pull lessens greatly with distance.

๐ŸŽฏ Exam Tip: Remember that 'g' is minimum at the Earth's equator (due to centrifugal force and larger radius) compared to poles, and zero at the Earth's center. However, the question asks for the absolute minimum value, which is in space, far from any significant mass.

 

Question 81. When an elevator is at rest:
(a) Apparent weight is greater than the actual weight
(b) Apparent weight is less than the actual weight
(c) Apparent weight is equal to the actual weight
(d) None of the options
Answer: (c) Apparent weight is equal to the actual weight
In simple words: When an elevator is not moving, the scale inside it will show your normal weight. This is because there is no extra force pushing you up or down.

๐ŸŽฏ Exam Tip: In elevator problems, the apparent weight equals actual weight when the elevator is at rest or moving with constant velocity (zero acceleration).

 

Question 82. In a lift, apparent weight of a body is equal to zero when the lift is;
(a) moving upwards
(c) moving downwards
(d) falling down freely
Answer: (d) falling down freely
In simple words: If a lift falls without anything stopping it, you would feel weightless inside it. This happens because the lift and everything in it are accelerating downwards at the same rate as gravity.

๐ŸŽฏ Exam Tip: Apparent weight becomes zero (weightlessness) when the elevator is in free fall, meaning its downward acceleration is equal to 'g'.

 

Question 83. When the lift is moving upward with an acceleration 'a' the apparent weight of the body is:
(a) lesser than actual weight
(b) greater than actual weight
(c) equal to actual weight
(d) zero
Answer: (b) greater than actual weight
In simple words: When an elevator speeds up while going up, you feel heavier than usual. This is because the floor pushes harder on you to make you accelerate upwards along with the lift.

๐ŸŽฏ Exam Tip: When a lift accelerates upwards, the apparent weight is \( W_{apparent} = m(g+a) \), which is greater than the actual weight \( mg \).

 

Question 84. When an elevator is moving downward, the apparent weight of a person who is in that elevator is:
(a) maximum
(b) zero
(c) minimum
(d) infinity
Answer: (c) minimum
In simple words: When an elevator speeds up while going down, you feel lighter than usual. This is because the floor does not need to push as hard on you to make you accelerate downwards.

๐ŸŽฏ Exam Tip: When a lift accelerates downwards, the apparent weight is \( W_{apparent} = m(g-a) \), which is less than the actual weight \( mg \). If \( a = g \), apparent weight becomes zero.

 

Question 85. Which law helps to predict the path of the astronomical bodies?
(a) Newton's law of motion
(b) Newton's law of gravitation
(c) Pascal's law
Answer: (b) Newton's law of gravitation
In simple words: Newton's law of gravitation helps us understand and predict how planets and other space objects move around each other. It explains the pull that keeps them in their orbits.

๐ŸŽฏ Exam Tip: Newton's Law of Universal Gravitation is foundational for understanding orbital mechanics and predicting the motion of celestial bodies.

 

II. Fill In The Blanks

 

Question 1. To produce a displacement ........ is required.
Answer: force
In simple words: You need a push or a pull, called force, to make something move from its place. Without force, an object will stay where it is.

๐ŸŽฏ Exam Tip: Remember that force is the agent that can cause or change motion (displacement) of an object.

 

Question 2. Passengers lean forward when the sudden brake is applied in a moving vehicle. This can be explained by ........
Answer: inertia
In simple words: When a moving vehicle stops suddenly, the passengers keep moving forward because of inertia. Inertia is the tendency of objects to keep doing what they are already doing.

๐ŸŽฏ Exam Tip: This phenomenon is a classic example of Newton's First Law of Motion, which describes inertia.

 

Question 3. By convention, the clockwise moments are taken as ..... and the anticlockwise moments are taken as ........
Answer: negative, positive
In simple words: In physics, turning forces that go clockwise are usually given a minus sign, and those that go counter-clockwise get a plus sign. This helps keep track of their direction.

๐ŸŽฏ Exam Tip: Establish a consistent sign convention (e.g., clockwise negative, anticlockwise positive) when dealing with moments or torques to avoid errors in calculations.

 

Question 4. ........ is used to change the speed of the car.
Answer: Accelerator
In simple words: The accelerator in a car is the pedal you push to make the car go faster or change its speed. It controls the amount of power from the engine.

๐ŸŽฏ Exam Tip: Identify common tools and their functions in everyday physics contexts to answer such practical questions.

 

Question 5. A man of mass 100 kg has a weight of ........ at the surface of the Earth.
Answer: \( 980 \text{ N} \)
In simple words: To find a person's weight on Earth, you multiply their mass (how much 'stuff' they are made of) by the force of gravity (about 9.8). So, a 100 kg person weighs 980 Newtons.

๐ŸŽฏ Exam Tip: Always remember the formula for weight: Weight = mass ร— acceleration due to gravity (W = mg), and use \( g \approx 9.8 \text{ m/s}^2 \).

 

Question 6. Force: vector then momentum: ......(i)...... ......... Balanced force: resultant of the two forces is zero then......(ii)........ : resultant forces are responsible for change in position or state.
Answer: (i) vector, (ii) imbalanced force
In simple words: Momentum is like force, it also has a direction, making it a vector quantity. When forces on an object do not cancel each other out, they are called unbalanced forces, and these are what cause movement.

๐ŸŽฏ Exam Tip: Clearly distinguish between scalar and vector quantities. Unbalanced forces cause acceleration, while balanced forces result in zero net force and thus no change in motion.

 

Question 7. Momentum is the product of ........ and ........
Answer: mass, velocity
In simple words: Momentum is calculated by multiplying an object's mass (how much matter it has) by its velocity (how fast it is moving and in what direction). It tells us how much "oomph" a moving object has.

๐ŸŽฏ Exam Tip: The formula for momentum is \( p = mv \). Always remember that momentum is a vector quantity, meaning it has both magnitude and direction.

 

Question 8. To produce an acceleration of 1 m/sยฒ in an object of mass 1 kg. The force required is ........ and for 3 kg of mass to produce same acceleration, the force required is ........
Answer: 1 N, 3 N
In simple words: If you want to make a 1 kg object speed up by 1 m/sยฒ, you need a force of 1 Newton. To make a 3 kg object speed up at the same rate, you would need three times that force, which is 3 Newtons, because force is directly related to mass and acceleration.

๐ŸŽฏ Exam Tip: Apply Newton's Second Law of Motion \( F = ma \). For a constant acceleration, force is directly proportional to mass.

 

Question 9. Two or more forces are acting in an object and does not change its position, the forces are ........ and it is essential to act some ........ force, to change the state or position of an object.
Answer: balanced, unbalanced
In simple words: If multiple forces act on an object but it stays still, those forces are balanced. To make the object move or change its state, you need an unbalanced force.

๐ŸŽฏ Exam Tip: Balanced forces result in zero net force and no acceleration, while unbalanced forces cause acceleration and a change in the object's state of motion.

 

Question 10. ......... deals with bodies that are at rest under the action of force.
Answer: Statics
In simple words: Statics is the part of physics that studies objects that are not moving, even when forces are pushing or pulling on them. It looks at how these forces balance out.

๐ŸŽฏ Exam Tip: Distinguish between statics (study of bodies at rest or in equilibrium) and dynamics (study of bodies in motion, considering forces).

 

Question 11. A branch of mechanics that deals with the motion of the bodies considering the cause of motion is called .........
Answer: kinetics
In simple words: Kinetics is a field of study that looks at how things move and also why they move, focusing on the forces that cause the motion. It answers both "how" and "why" things change their movement.

๐ŸŽฏ Exam Tip: Remember that kinetics focuses on the causes of motion (forces), while kinematics describes motion without considering its causes.

 

Question 12. If m is the mass of a body moving with velocity v then its momentum is given by ........
Answer: mv
In simple words: An object's momentum is found by multiplying its mass (how much material it has) by its velocity (how fast it is moving). This calculation tells us how much "push" the moving object carries.

๐ŸŽฏ Exam Tip: The formula for linear momentum is \( p = mv \), where 'p' is momentum, 'm' is mass, and 'v' is velocity. This is a fundamental concept in mechanics.

 

Question 13. A system of forces can be brought to equilibrium by applying .......... in opposite direction.
Answer: equilibriant
In simple words: To make a set of forces balance out, you can add a single force that is equal in strength but points in the exact opposite direction. This added force is called an equilibriant.

๐ŸŽฏ Exam Tip: An equilibriant is a single force that, when added to a system of forces, results in zero net force, bringing the system into equilibrium.

 

Question 14. Torque is a ......... quantity.
Answer: vector
In simple words: Torque is a turning force, and it is a vector quantity, meaning it has both a strength and a direction (which way it is turning). It tells us how effective a force is at making something spin.

๐ŸŽฏ Exam Tip: Understand that torque, like force, is a vector quantity, as its effect (rotation) has a specific direction.

 

Question 15. Steering wheel transfers a torque to the wheels with ........
Answer: less effort
In simple words: A steering wheel helps you turn the car's wheels easily because it uses the idea of torque. By giving you a larger turning radius, it allows a small force from your hands to create a large turning effect on the wheels.

๐ŸŽฏ Exam Tip: The steering wheel is an application of the principle of moments or torque, where a larger radius (from the center of the wheel to where you apply force) requires less force to produce the same turning effect.

 

Question 16. The mathematical form of the principle of moments is ........
Answer: \( F_1 \times d_1 = F_2 \times d_2 \)
In simple words: The principle of moments says that for something to be balanced, the turning force on one side (force times distance) must be equal to the turning force on the other side. This formula helps us calculate those forces.

๐ŸŽฏ Exam Tip: This equation is critical for solving problems involving equilibrium and levers. Ensure you know what each variable represents.

 

Question 17. Change in momentum takes place in the ........ of ........
Answer: direction, force
In simple words: When an object's momentum changes, it means its speed or direction of movement has changed. This change always happens in the same direction as the force that caused it.

๐ŸŽฏ Exam Tip: Recall Newton's Second Law, which states that the rate of change of momentum is directly proportional to the applied force and occurs in the direction of the force.

 

Question 18. 1 Newton = ........
Answer: \( 10^5 \) dyne
In simple words: One Newton is a unit of force in the metric system. It is equal to \( 100,000 \) dynes, which is a smaller unit of force.

๐ŸŽฏ Exam Tip: Remember this conversion factor between Newton (SI unit of force) and dyne (CGS unit of force).

 

Question 19. If a force F acts on a body for a time t's then the impulse is ........
Answer: \( F \times t \)
In simple words: Impulse is what happens when a force pushes on an object for a certain amount of time. You find it by multiplying the force by the time it acts.

๐ŸŽฏ Exam Tip: The impulse-momentum theorem states that impulse (Force ร— time) is equal to the change in momentum. This is a crucial concept for understanding collisions.

 

Question 20. 1 kg f = ........
Answer: 9.8 N
In simple words: One kilogram-force (kgf) is a unit that measures weight, or the force of gravity on one kilogram of mass. It is equal to about 9.8 Newtons.

๐ŸŽฏ Exam Tip: Understand that kilogram-force (kgf) is a unit of force, not mass. It represents the weight of 1 kg mass under standard gravity conditions.

 

Question 21. The force of attraction between two objects is directly proportional to the product of their ... and inversely proportional to the square of the .......... between them.
Answer: masses, distance
In simple words: The force that pulls two objects together (gravity) gets stronger if their masses are bigger, and it gets weaker very quickly if they are farther apart. This is how gravity works in the universe.

๐ŸŽฏ Exam Tip: This is a key statement of Newton's Law of Universal Gravitation. Make sure to recall "product of their masses" and "square of the distance" accurately.

 

Question 22. The value of g varies with ........ and ........
Answer: altitude, depth
In simple words: The strength of gravity, 'g', changes depending on how high you are above the Earth or how deep you go inside it. It is strongest at the surface and changes as you move away or towards the center.

๐ŸŽฏ Exam Tip: The acceleration due to gravity (g) is not constant; it decreases both as you go higher (altitude) and as you go deeper into the Earth (depth), becoming zero at the Earth's center.

 

Question 23. The value of gravitational constant is ...... at all places but the value of acceleration due to gravity ........
Answer: same, differs
In simple words: The gravitational constant (G) is always the same everywhere in the universe. However, the acceleration due to gravity (g) changes depending on factors like location and height.

๐ŸŽฏ Exam Tip: Differentiate between the universal gravitational constant (G), which is a fundamental constant, and the acceleration due to gravity (g), which is a local variable.

 

Question 24. The relation between g and G is ........
Answer: \( g = \frac{GM}{R^2} \)
In simple words: This formula connects the local gravity (g) with the universal gravitational constant (G), the mass of the planet (M), and its radius (R). It shows how a planet's size and mass determine the gravity on its surface.

๐ŸŽฏ Exam Tip: This is the derived expression for acceleration due to gravity, crucial for solving problems involving gravitational fields.

 

III. State whether the following statements are true or false. Correct the statement if it is false.

 

Question 1. Newton's first law explains inertia:
Answer: True
In simple words: Newton's first law tells us that objects tend to keep doing what they are doing (staying still or moving steadily) unless a force acts on them. This tendency is called inertia.

๐ŸŽฏ Exam Tip: Newton's First Law is often called the Law of Inertia because it directly describes this property of matter.

 

Question 2. If a motion depends on force then it is called as natural motion.
Answer: False - If a motion does not depend on force then it is called as natural motion.
In simple words: Natural motion is when something moves on its own without needing a constant push or pull, like a ball rolling until friction stops it. Motion that needs a force to keep it going is not natural motion.

๐ŸŽฏ Exam Tip: Aristotle's concept of "natural motion" contrasted with "violent motion" (requiring an external force). Newton's laws redefined this, stating that uniform motion in a straight line is "natural" and requires no net force.

 

Question 3. The resistance of a body to change its state of rest or the state of uniform motion is known as inertia of motion.
Answer: True
In simple words: Inertia is an object's natural resistance to any change in its movement, whether it is sitting still or moving at a steady speed. It means objects want to keep doing what they are already doing.

๐ŸŽฏ Exam Tip: Understand that inertia applies to both the state of rest and the state of uniform motion, representing an object's resistance to any change in its velocity.

 

Question 4. Linear momentum = mass ร— acceleration.
Answer: False - Linear momentum = mass ร— velocity
In simple words: Linear momentum is found by multiplying an object's mass by its speed, not by how fast its speed is changing. The formula is mass times velocity.

๐ŸŽฏ Exam Tip: The formula for linear momentum is \( p = mv \), whereas \( F = ma \) is for force. Confusing velocity and acceleration in this context is a common mistake.

 

Question 5. Two equal force acting in opposite directions are called unlike parallel forces.
Answer: True
In simple words: When two forces are of the same strength but pull in exact opposite directions, and they act along lines that are parallel, they are called unlike parallel forces.

๐ŸŽฏ Exam Tip: Remember the definitions of various force types, especially parallel forces (like and unlike), which are crucial in understanding rotational motion and equilibrium.

 

Question 6. If the resultant force of three force acting on body is zero then the forces are called balanced forces.
Answer: True
In simple words: If all the forces pushing and pulling on an object add up to nothing, then those forces are considered balanced. This means the object will either stay still or keep moving at a constant speed.

๐ŸŽฏ Exam Tip: Balanced forces imply that the net force on an object is zero, leading to either static equilibrium (at rest) or dynamic equilibrium (constant velocity).

 

Question 7. Torque is a scalar quantity.
Answer: False - Torque is a vector quantity
In simple words: Torque is a turning force that has both a strength and a direction (like clockwise or counter-clockwise). Because it has direction, it is a vector, not just a scalar quantity that only has strength.

๐ŸŽฏ Exam Tip: Torque is a vector because its effect (rotation) occurs about a specific axis and in a specific direction (clockwise or counter-clockwise), which can be represented by a vector perpendicular to the plane of rotation.

 

Question 8. Moment of couple = Force ร— \( \perp \) r distance between line of action of forces
Answer: True
In simple words: The "moment of a couple" describes the turning effect created by two equal and opposite forces. You calculate it by multiplying the force by the shortest distance between their lines of action.

๐ŸŽฏ Exam Tip: The moment of a couple (torque) is calculated as the magnitude of one force multiplied by the perpendicular distance between the lines of action of the two forces. This produces pure rotational motion.

 

Question 9. Principle of moments states that moment in clockwise direction = Moment in anti clockwise direction.
Answer: True
In simple words: The principle of moments says that for an object to be balanced and not turn, the total turning force in the clockwise direction must be exactly equal to the total turning force in the counter-clockwise direction.

๐ŸŽฏ Exam Tip: This principle is essential for understanding rotational equilibrium, particularly in problems involving levers and balances.

 

Question 10. 1 Newton = 1 g cm s-2
Answer: False - 1 Newton = 1 kg ms-2
In simple words: One Newton is the force needed to make a 1 kilogram object speed up by 1 meter per second every second. It is not the force needed for a 1 gram object in centimeters.

๐ŸŽฏ Exam Tip: Carefully distinguish between SI units (Newton, kg, m, s) and CGS units (dyne, g, cm, s). 1 Newton = 1 kg m/sยฒ, while 1 dyne = 1 g cm/sยฒ.

 

Question 11. Impulse = Change in momentum
Answer: True
In simple words: Impulse is how much a force changes an object's momentum over a period of time. It means a big force for a short time, or a small force for a long time, can cause the same change in an object's movement.

๐ŸŽฏ Exam Tip: This is a direct statement of the impulse-momentum theorem, a fundamental concept in collision analysis.

 

Question 12. Propulsion of rockets is based Newton's third law of motion and conservation of momentum.
Answer: True
In simple words: Rockets move forward by pushing gas backward very fast. This works because for every action (gas pushed back), there is an equal and opposite reaction (rocket pushed forward). This also keeps the total "movement" of the system the same.

๐ŸŽฏ Exam Tip: Rocket propulsion is an excellent real-world application illustrating both Newton's Third Law (action-reaction pairs) and the Law of Conservation of Linear Momentum.

 

Question 13. The value of universal gravitational constant is \( 6.674 \times 10^{-11} \) Nmยฒ kg-2
Answer: True
In simple words: The universal gravitational constant, often written as G, has a fixed numerical value of \( 6.674 \times 10^{-11} \) with specific units. This constant is used to calculate the gravitational force between any two objects in the universe.

๐ŸŽฏ Exam Tip: Always remember the exact value and correct units for the universal gravitational constant, G, as it is a crucial constant in physics problems.

 

Question 14. The relation between g and G is \( g = \frac{Gm}{R^2} \)
Answer: True
In simple words: This formula shows how the acceleration due to gravity (g) on a planet depends on the universal gravitational constant (G), the planet's mass (m), and its radius (R). It means larger, denser planets have stronger gravity.

๐ŸŽฏ Exam Tip: This equation links the local acceleration due to gravity 'g' to the universal gravitational constant 'G', the mass of the celestial body 'M', and its radius 'R'.

 

Question 15. The value of acceleration due to gravity decreases as the altitude of the body increases.
Answer: True
In simple words: As you go higher above the Earth, the pull of gravity (and thus the acceleration due to gravity) becomes weaker. This is because you are getting farther away from the Earth's center.

๐ŸŽฏ Exam Tip: Gravitational force follows an inverse square law, so 'g' decreases with increasing distance from the center of the Earth (i.e., with increasing altitude).

 

Question 16. In a 'free fall' motion acceleration of the body is equal to the acceleration due to gravity.
Answer: True
In simple words: When an object is in free fall, it means only gravity is acting on it. So, its acceleration is exactly the same as the acceleration caused by gravity alone, which is 'g'.

๐ŸŽฏ Exam Tip: Free fall is defined as motion under the influence of gravity alone, meaning air resistance and other forces are negligible, and the acceleration is 'g'.

 

IV. Match The Following

 

Question 1. Match the column A with column B.

Column AColumn B
A Relation between 'g' and 'G'(i) \( F=G \frac{m_1 m_2}{r^2} \)
B Universal gravitational law(ii) \( W = mg \)
C Mass of an object is measured by(iii) Physical balance
D Unit of g(iv) \( g = \frac{GM}{R^2} \)
E Relation between mass and weight(v) m/sยฒ
Answer:
A. (iv)
B. (i)
C. (iii)
D. (v)
E. (ii)
In simple words: This match-up connects different physics ideas: how gravity (g) relates to the gravitational constant (G), the law of how objects attract each other, how to measure mass, the unit for gravity's acceleration, and how mass and weight are linked. Each pair correctly matches a concept with its definition or formula.

๐ŸŽฏ Exam Tip: For matching questions, systematically go through each item in Column A and find its corresponding match in Column B. Knowing key definitions and formulas is essential.

 

Question 2. Match the column A with column B.

Column AColumn B
A Resultant of the forces is zero(i) Law of conservation of momentum
B Newton's first law(ii) Vector
C Force(iii) Quantitative definition of force
D Newton's third law(iv) Balanced force
E Newton's second law(v) Inertia
Answer:
A. (iv)
B. (v)
C. (ii)
D. (i)
E. (iii)
In simple words: This matching exercise connects basic physics principles: when forces balance out, Newton's first law explains inertia, force is a quantity with direction (vector), Newton's third law links to momentum staying the same, and Newton's second law defines force numerically.

๐ŸŽฏ Exam Tip: Review Newton's three laws of motion, their implications, and associated concepts like inertia, balanced forces, and conservation of momentum. Also, know the types of physical quantities.

 

Question 3. Match the column A with column B.

Column AColumn B
A Liquid Helium(i) Lunar Laser Ranging Instrument
B Sky lab(ii) Magnetic resonance imaging
C Liquid nitrogen(iii) lunar probe
D LLRI(iv) space station
E Chandrayaan - I(v) Freezing
Answer:
A. (ii)
B. (iv)
C. (v)
D. (i)
E. (iii)
In simple words: This matching helps link scientific substances and space projects to their uses or types. Liquid helium is used in MRI, Sky Lab was a space station, liquid nitrogen is for freezing, LLRI is a laser tool for moon measurement, and Chandrayaan-I was a probe sent to the moon.

๐ŸŽฏ Exam Tip: This question tests general scientific knowledge and current affairs related to science and technology. Staying updated on such topics is beneficial.

 

Question 4. Match the column A with column B.

Column AColumn B
A Force(i) \( F \times d \)
B Moment of a couple(ii) \( F \times t \)
C Torque(iii) \( F \times a \)
D Impulse(iv) \( ma \)
(v) \( F \times s \)
Answer:
A. (iv)
B. (v)
C. (i)
D. (ii)
In simple words: This matching exercise connects different physics terms with their correct formulas. Force is mass times acceleration, moment of a couple is force times distance, torque is also force times distance, and impulse is force times time.

๐ŸŽฏ Exam Tip: Memorize the fundamental formulas for force, torque, moment of a couple, and impulse. Understanding the units and dimensions of each quantity also helps in matching.

 

V. Assertion and Reasoning.

 

Question 1. Assertion: While travelling in a motor car we tend to remain at rest with respect to the seat. Reason: While travelling in a motor car we tend to move along the car with respect to the ground.
(a) Both Assertion and Reason are false.
(b) Assertion is true but Reason is false.
(c) Assertion is false but Reason is true.
(d) Both Assertion and Reason are true.
Answer: (d) Both Assertion and Reason are true.
In simple words: The assertion is true because our bodies resist changes in motion (inertia), so we feel at rest with the car's seat. The reason is also true, as our motion is compared to the ground outside the car, showing that we are indeed moving.

๐ŸŽฏ Exam Tip: Carefully read both the assertion and reason. Evaluate each statement for its truthfulness and then determine if the reason correctly explains the assertion. This question relates to the concept of relative motion and inertia.

 

Question 2. Assertion: When we kick a football it will roll over; when we kick a stone of the size of the football, it remains unmoved. Reason: Inertia of a body depends mainly on its mass.
(a) Both Assertion and Reason are true and Reason explains Assertion.
(b) Both Assertion and Reason are true but Reason doesn't explain Assertion.
(c) Both Assertion and Reason are false.
(d) Assertion is true but Reason is false.
Answer: (a) Both Assertion and Reason are true and Reason explains Assertion.
In simple words: The assertion is true: a football moves easily because it is light, but a stone of the same size does not because it is heavy. This happens because inertia, which makes things resist movement, is mainly determined by how much mass something has. The heavier the object, the more it resists moving.

๐ŸŽฏ Exam Tip: This question clearly demonstrates how inertia is directly proportional to mass. A heavier object has greater inertia and thus requires a larger force to change its state of motion.

 

Question 3. Assertion: In a gun-bullet experiment, the acceleration of the gun is much lesser than the acceleration of the bullet. Reason: The gun has much smaller mass than the bullet.
(c) Assertion is true, but the reason is false.
(d) Assertion is false, but the reason is true.
Answer: (c) Assertion is true, but the reason is false.
In simple words: The assertion is true because the bullet speeds up much more than the gun. However, the reason is false; the gun is actually much heavier than the bullet. This is why the gun has less acceleration even though the force on both is equal and opposite.

๐ŸŽฏ Exam Tip: Remember Newton's Third Law (equal and opposite forces) and Second Law (\( F=ma \)). For equal force, the object with larger mass will have smaller acceleration. The gun has a larger mass, not smaller, than the bullet.

 

Question 4. Assertion: When a bullet is fired from a gun, the bullet moves forward, the gun moves backward. Reason: Total momentum before collision is equal to the total momentum after collision.
(a) Both Assertion and Reason are true and Reason explains Assertion.
(b) Both Assertion and Reason are true but Reason doesn't explain Assertion.
(c) Assertion is true but Reason is false.
(d) Assertion is false but Reason is true.
Answer: (a) Both Assertion and Reason are true and Reason explains Assertion.
In simple words: The assertion is true because the gun recoils backward as the bullet shoots forward, which is Newton's third law. The reason is also true, as the total momentum of the gun-bullet system stays the same before and after firing, explaining why the gun must move backward to balance the bullet's forward motion.

๐ŸŽฏ Exam Tip: This scenario is a classic example of both Newton's Third Law (action-reaction) and the Law of Conservation of Momentum. The recoil occurs to conserve the total momentum of the system.

 

Question 5. Assertion: A person whose mass on earth is 125 kg will have his mass on moon as 250 kg. Reason: Mass varies from place to place.
(c) Both Assertion and Reason are false.
(d) Assertion is true but Reason is false.
Answer: (c) Both Assertion and Reason are false.
In simple words: The assertion is false because a person's mass stays the same whether they are on Earth or the Moon. Mass does not change. The reason is also false because mass is a basic property of matter and does not change depending on where you are.

๐ŸŽฏ Exam Tip: Clearly differentiate between mass and weight. Mass is an intrinsic property of an object and is constant everywhere, while weight is a force that changes with gravitational acceleration.

 

Question 6. Assertion: While turning a cyclist negotiates of the curve, while a man sitting in the car leans outwards of the curve. Reason: An acceleration is acting towards the centre of the curve.
(a) If both the assertion and the reason are true and the reason is the correct explanation of assertion.
(b) If both the assertion and the reason are true, but the reason is not the correct explanation of assertion.
(c) Assertion is true, but the reason is false.
(d) Assertion is false, but the reason is true.
Answer: (c) Assertion is true, but the reason is false.
In simple words: The assertion is true because a cyclist leans inward to turn, but a person in a car feels pushed outward. However, the reason is false because when moving in a circle, the acceleration is directed towards the center, not necessarily pushing outwards.

๐ŸŽฏ Exam Tip: Centripetal acceleration (towards the center) is required for circular motion. The outward leaning in a car is due to inertia, as the body tends to continue in a straight line while the car turns. The cyclist leans to provide the necessary centripetal force.

 

Question 7. Assertion: On a rainy day, it is difficult to drive a car at high speed. Reason: The valve of coefficient of friction is lowered due to polishing of the surface.
(a) If both the assertion and the reason are true and the reason is the correct explanation of assertion.
(b) If both the assertion and the reason are true, but the reason is not the correct explanation of assertion.
(c) Assertion is true, but the reason is false.
(d) Assertion is false, but the reason is true.
Answer: (a) If both the assertion and the reason are true and the reason is the correct explanation of assertion.
In simple words: It is hard to drive fast on a rainy day because the wet road has less friction, which means tires cannot grip as well. This reduced grip is because water acts like a lubricant, making the surface "smoother" and reducing the friction coefficient.

๐ŸŽฏ Exam Tip: Understand that water on a road reduces friction, which is essential for vehicle control (braking, turning). A lower coefficient of friction makes it difficult to maintain grip and control, increasing the risk of skidding.

 

Question 8. Assertion: A rocket moves forward by pushing the air backwards. Reason: It derives the necessary thrust to move forwarded according to Newton's third law of motion.
(a) If both the assertion and the reason are true and the reason is the correct explanation of assertion.
(b) If both the assertion and the reason are true, but the reason is not the correct explanation of assertion.
(c) Assertion is true, but the reason is false.
(d) Assertion is false, but the reason is true.
Answer: (d) Assertion is false, but the reason is true.
In simple words: The assertion is false; rockets move forward by pushing hot gas backward, not air. The reason is true because this forward movement (thrust) follows Newton's third law, where the action of pushing gas backward causes an equal and opposite reaction pushing the rocket forward.

๐ŸŽฏ Exam Tip: Rockets operate on the principle of expelling mass (hot gases) backward, not by pushing against external air. This is why they work in the vacuum of space. The thrust is a direct application of Newton's Third Law and conservation of momentum.

 

Question 9. Assertion: A mass in the elevator which is falling freely, does not experience gravity. Reason: Inertial and gravitational masses have equivalence.
(c) Assertion is true, but the reason is false.
(d) Assertion is false, but the reason is true.
Answer: (c) Assertion is true, but the reason is false.
In simple words: The assertion is true because a mass in a freely falling elevator experiences weightlessness, feeling as if there is no gravity, even though gravity is still acting on it. The reason is false because the equivalence of inertial and gravitational masses is a principle of general relativity, but it does not mean that gravity is absent in free fall.

๐ŸŽฏ Exam Tip: An object in free fall still experiences gravity; it just feels weightless because it is accelerating with the same rate as the elevator. The equivalence principle is about how gravity and acceleration are indistinguishable, not about the absence of gravity.

 

Question 10. Assertion: The intensity of gravitational field varies with respect to height and depth of a body on the Earth. Reason: The value of gravitational field intensity depends on height and depth of a body.
(a) If both the assertion and the reason are true and the reason is the correct explanation of assertion.
(b) If both the assertion and the reason are true, but the reason is not the correct explanation of assertion.
(c) Assertion is true, but the reason is false.
(d) Assertion is false, but the reason is true.
Answer: (a) If both the assertion and the reason are true and the reason is the correct explanation of assertion.
In simple words: The assertion is true because the strength of gravity changes as you go higher or deeper into the Earth. The reason is also true and explains why: the actual value of gravity's strength is affected by how far you are from the Earth's center, whether up in the sky or down in a mine.

๐ŸŽฏ Exam Tip: The gravitational field intensity (which is equivalent to acceleration due to gravity, 'g') varies significantly with both altitude (decreasing) and depth (decreasing, becoming zero at the center). The reason accurately explains this dependency.

 

VI. Answer Briefly.

 

Question 1. What is meant by mechanics? How can it be classified?
Answer: Mechanics is a part of physics that studies how forces affect bodies. It looks at how objects move or stay still when forces act on them. This field of study is divided into two main areas: statics and dynamics. Statics deals with objects that are not moving, while dynamics looks at objects that are in motion. A deeper understanding reveals that dynamics further splits into kinematics (describing motion) and kinetics (explaining the causes of motion).
In simple words: Mechanics is about how things move or stay still because of forces. It has two main parts: statics (for things that are still) and dynamics (for things that are moving).

๐ŸŽฏ Exam Tip: Define mechanics clearly and then outline its primary classifications (statics and dynamics). Briefly explaining what each classification studies will earn full marks.

 

Question 2. What is statics?
Answer: Statics is a branch of mechanics that focuses on bodies that are at rest. It studies how different forces act on these objects in such a way that they remain stationary. In statics, all forces acting on an object are balanced, resulting in no net force and no acceleration. It is important for understanding the stability of structures like buildings and bridges.
In simple words: Statics is the study of objects that are not moving. It looks at how forces balance each other to keep things still.

๐ŸŽฏ Exam Tip: Emphasize that in statics, objects are in equilibrium (at rest) and the net force acting on them is zero.

 

Question 3. What is dynamics?
Answer: Dynamics is the part of mechanics that studies moving bodies. It not only describes their motion but also investigates the forces that cause this motion. Dynamics helps us understand why objects start moving, stop moving, or change their direction. This field is crucial for designing vehicles, machinery, and predicting the movement of celestial bodies.
In simple words: Dynamics is the study of how and why things move. It looks at the forces that make objects change their speed or direction.

๐ŸŽฏ Exam Tip: Highlight that dynamics deals with both the description of motion and the forces causing it, distinguishing it from statics and kinematics.

 

Question 4. What is Kinematics?
Answer: Kinematics is a part of dynamics that describes the motion of bodies. It focuses on aspects like position, velocity, and acceleration, without considering the forces that cause the motion. It provides the mathematical tools to analyze movement, such as how fast an object is going or how quickly its speed is changing. For example, plotting the path of a projectile is a kinematics problem.
In simple words: Kinematics describes how objects move, like their speed and direction, but it does not care about what forces make them move.

๐ŸŽฏ Exam Tip: Ensure you differentiate kinematics (describing motion without cause) from kinetics (describing motion with cause, i.e., forces).

 

Question 5. What is Kinetics?
Answer: Kinetics is the study of how forces cause bodies to move. It focuses on why objects start moving or change their motion. This area helps us understand the fundamental reasons behind movement.
In simple words: Kinetics looks at how forces make things move. It explains the causes of motion.

๐ŸŽฏ Exam Tip: Remember that kinetics explains the 'why' of motion (forces involved), while kinematics describes the 'how' (motion itself, without forces).

 

Question 6. Define momentum. State its unit.
Answer: Momentum is a measure of the quantity of motion an object has. It is found by multiplying an object's mass by its velocity. The direction of the momentum is always the same as the direction of the object's velocity. It is a key concept in understanding collisions. Its S.I. unit is \( \text{kg m s}^{-1} \).
In simple words: Momentum tells us how much 'oomph' a moving object has. We find it by multiplying its mass and speed. Its unit is kilograms times meters per second.

๐ŸŽฏ Exam Tip: Always remember that momentum is a vector quantity, meaning it has both magnitude and direction.

 

Question 7. What is meant by a force?
Answer: Force is an influence that can change or try to change the state of rest or uniform motion of a body. It can make an object start moving, stop moving, or change its direction. Force is fundamental to all interactions in physics.
In simple words: Force is a push or a pull that can make things move or stop moving.

๐ŸŽฏ Exam Tip: Forces always come in pairs and result from interactions between objects.

 

Question 8. State the effects of force.
Answer: A force can have several effects on a body:
1. It can make a body that is not moving start to move.
2. It can make a moving body stop or try to stop it.
3. It can make a moving body change its direction of motion or try to change it. Force can also change the shape or size of an object, like squeezing a sponge.
In simple words: A force can start things moving, stop them, or change their direction.

๐ŸŽฏ Exam Tip: When describing the effects of force, remember to mention both starting/stopping motion and changing direction, as well as deformation if applicable.

 

Question 9. What is resultant force?
Answer: When several forces act on the same body at the same time, their combined effect can be represented by a single force. This single force is called the 'resultant force'. It is like finding one overall push or pull from many different pushes and pulls. The resultant force tells us the net effect on the object.
In simple words: If many forces push or pull an object, the resultant force is one single force that shows their total effect.

๐ŸŽฏ Exam Tip: The resultant force determines the acceleration of an object according to Newton's second law.

 

Question 10. What are balanced forces?
Answer: Balanced forces are forces acting on an object where the resultant force is zero. This means that if an object is at rest, it will stay at rest, and if it is moving, it will continue to move at a constant speed in a straight line. Balanced forces do not cause a change in motion. For example, a book resting on a table experiences balanced forces.
In simple words: Balanced forces happen when all the pushes and pulls on an object cancel each other out, so the object does not speed up or slow down.

๐ŸŽฏ Exam Tip: An object under balanced forces is said to be in equilibrium, whether it's stationary or moving at a constant velocity.

 

Question 11. What are unbalanced forces?
Answer: Unbalanced forces are forces acting on an object where the resultant force is not zero. When unbalanced forces act on an object, they cause it to accelerate, meaning its speed or direction of motion changes. These forces are responsible for all changes in motion. For instance, kicking a ball applies an unbalanced force, causing it to move.
In simple words: Unbalanced forces are when the pushes and pulls on an object are not equal, making the object speed up, slow down, or change direction.

๐ŸŽฏ Exam Tip: Unbalanced forces are directly linked to acceleration and are described by Newton's second law of motion.

 

Question 12. What is meant by equilibriant?
Answer: An equilibriant is a single force that, when applied to a system of forces, brings the system into equilibrium. This force is equal in magnitude to the resultant force but acts in the exact opposite direction. It effectively cancels out all other forces, leading to no net change in motion. It's the balancing force.
In simple words: An equilibriant is a force that perfectly balances out all other forces, making an object steady.

๐ŸŽฏ Exam Tip: The equilibriant is always equal and opposite to the resultant force, ensuring the net force on the object becomes zero.

 

Question 13. What is meant by couple? State few examples.
Answer: A couple is formed when two forces that are equal in size, act in opposite directions, and are parallel to each other, are applied at two different points on a body. These forces do not meet at a single point, causing a rotating effect without any net linear movement. This rotational effect is crucial in many mechanical systems. Examples include:
- Turning a tap on or off.
- Winding or unwinding a screw.
- Spinning a top.
- The action of a steering wheel in a car.
In simple words: A couple is two equal but opposite forces that make an object spin, like turning a screw or a car's steering wheel.

๐ŸŽฏ Exam Tip: A key characteristic of a couple is that it produces pure rotational motion without causing any translational (straight-line) motion.

 

Question 14. A sudden application of brakes may cause injury to passengers in a car by collision with panels in front?
Answer: When a car suddenly brakes, the car itself slows down quickly. However, due to inertia, our bodies tend to keep moving forward at the original speed. This resistance to change in motion can cause passengers to collide with the panels in front, leading to injuries. Seatbelts help to counteract this inertia.
In simple words: When a car stops fast, our bodies want to keep moving forward because of inertia, which can cause us to hit the front of the car.

๐ŸŽฏ Exam Tip: Always relate sudden stops or starts to the concept of inertia, which is a body's resistance to changes in its state of motion.

 

Question 15. When we are standing in a bus which begins to move suddenly, we tend to fall backwards. Why?
Answer: When a bus suddenly starts moving forward, the bus itself and our feet (which are in contact with the bus floor) gain motion. However, the upper part of our body tends to stay at rest due to inertia. This difference in motion causes us to fall backwards relative to the bus. It shows how our body resists a change from rest to motion.
In simple words: We fall backward when a bus starts suddenly because our feet move with the bus, but our upper body tries to stay still due to inertia.

๐ŸŽฏ Exam Tip: This is a classic example of inertia of rest โ€“ the tendency of an object to resist changes to its state of rest.

 

Question 16. While travelling through a curved path, passengers in a bus tend to get thrown to one side. Justify.
Answer: When a bus takes a sharp turn on a curved path, an unbalanced force is applied by the engine to change the bus's direction. Due to inertia of direction, the passengers' bodies tend to continue moving in the original straight-line path. This tendency to maintain their original direction causes them to be thrown sideways, away from the center of the curve. This is why you feel pushed to the side.
In simple words: When a bus turns, passengers lean sideways because their bodies want to keep moving in a straight line due to inertia.

๐ŸŽฏ Exam Tip: This illustrates inertia of direction, where objects resist changes in their path of motion, even if their speed remains constant.

 

Question 17. Define momentum of an object.
Answer: The momentum of an object is defined as the product of its mass and velocity. It is a vector quantity, meaning it has both magnitude and direction, and its direction is the same as the object's velocity. Momentum is a measure of how hard it is to stop a moving object. For example, a heavy truck moving slowly can have more momentum than a small car moving fast.
In simple words: Momentum is how much an object moves, calculated by multiplying its mass by its speed.

๐ŸŽฏ Exam Tip: Understand that momentum is directly proportional to both mass and velocity; changing either will change momentum.

 

Question 18.
Answer:
In simple words:

๐ŸŽฏ Exam Tip: Always double-check if all parts of a question are present in the source. If a question is incomplete, make a note or flag it for review if allowed.

 

Question 19. Define one dyne.
Answer: One dyne is defined as the amount of force required to give a mass of 1 gram an acceleration of 1 centimeter per second squared (\( \text{1 cm s}^{-2} \)). It is a unit of force in the CGS (centimeter-gram-second) system. The dyne is a very small unit of force compared to the Newton. We know that \( \text{1 N} = \text{10}^5 \text{ dyne} \).
In simple words: A dyne is a small unit of force that makes a 1-gram object speed up by 1 centimeter per second, every second.

๐ŸŽฏ Exam Tip: When defining units, always specify the mass and acceleration they cause. Remember the conversion factor between Newtons and dynes.

 

Question 20. What is unit force?
Answer: A unit force is the amount of force required to produce an acceleration of \( \text{1 m s}^{-2} \) in a body of mass 1 kg. This unit force is known as 1 Newton (N). It represents the standard measure for force in the International System of Units. This definition helps standardize force measurements across science and engineering.
In simple words: Unit force is the force needed to make a 1 kg object accelerate by 1 meter per second, every second.

๐ŸŽฏ Exam Tip: The definition of a unit force (1 Newton) is directly derived from Newton's second law, \( F = ma \).

 

Question 21. What are the values of 1 kg f and 1 g f.
Answer:
1 kilogram-force (\( \text{1 kg f} \)) is the force due to gravity on a 1 kg mass. It is equal to \( \text{1 kg} \times \text{9.8 m s}^{-2} = \text{9.8 N} \).
1 gram-force (\( \text{1 g f} \)) is the force due to gravity on a 1 g mass. It is equal to \( \text{1 g} \times \text{980 cm s}^{-2} = \text{980 dyne} \).
These units represent the weight of an object under standard gravity. It's important to differentiate these from mass units.
In simple words: 1 kg f is the weight of 1 kg, which is 9.8 Newtons. 1 g f is the weight of 1 gram, which is 980 dynes.

๐ŸŽฏ Exam Tip: Distinguish between mass (a measure of inertia) and weight (a measure of gravitational force). Kilogram-force and gram-force are units of weight, not mass.

 

Question 22. What is meant by impulsive force?
Answer: An impulsive force is a very large force that acts on a body for a very short period of time. Even though the time is short, this force causes a significant change in the body's momentum. Examples include hitting a baseball with a bat or a car colliding with a wall. Such forces are often associated with impacts.
In simple words: An impulsive force is a big push that happens for only a tiny moment, like a hit or a sudden bump.

๐ŸŽฏ Exam Tip: Impulsive forces cause a change in momentum (impulse), which is why impulse is often defined as force multiplied by time.

 

Question 23. What is meant by impulse?
Answer: Impulse is a measure of the change in momentum of an object. It is calculated by multiplying the force applied to an object by the time duration for which that force acts. Impulse is represented by 'J' and its unit is \( \text{kg m s}^{-1} \) or Newton-second (\( \text{N s} \)). Impulse is a vector quantity, having both magnitude and direction, same as the force applied.
In simple words: Impulse is how much an object's movement changes when a force pushes it for a certain time.

๐ŸŽฏ Exam Tip: Remember the impulse-momentum theorem: Impulse is equal to the change in momentum. This is a crucial relationship in physics.

 

Question 24. Prove that impulse is equal to the magnitude of change in momentum.
Answer:
According to Newton's second law of motion, the force \( F \) acting on a body is directly proportional to the rate of change of linear momentum \( \Delta P \) of the body.
\( F = \frac{\Delta P}{t} \)
Now, we can rearrange this equation to find the change in momentum:
\( \Delta P = F \times t \)
By definition, impulse \( J \) is the product of force and time:
\( J = F \times t \)
Comparing these two equations, we can see that:
\( J = \Delta P \)
This proves that impulse is equal to the magnitude of the change in momentum. The unit of impulse is \( \text{kg m s}^{-1} \) or \( \text{N s} \). This relationship is very useful for analyzing collisions.
In simple words: Newton's second law tells us that force changes momentum over time. Impulse is defined as force times time. So, impulse is the same as the total change in an object's momentum.

๐ŸŽฏ Exam Tip: When proving relationships, always start with the fundamental laws (like Newton's second law) and clearly define all variables used.

 

Question 25. How can the change in momentum be achieved?
Answer: A change in momentum can be achieved in two main ways, as described by the impulse-momentum theorem:
1. By applying a large force for a very short period of time. This is common in impacts, like hitting a golf ball.
2. By applying a smaller force for a longer period of time. This is seen when catching a cricket ball and moving your hands back, spreading the force over a longer time. Both methods result in the same total impulse. This principle is used in safety features like airbags.
In simple words: You can change momentum by using a big force for a short time, or a small force for a long time.

๐ŸŽฏ Exam Tip: Emphasize the inverse relationship between force and time duration for a given change in momentum โ€“ if time increases, force decreases, and vice-versa.

 

Question 26. State an example for change in momentum.
Answer: A good example of how changes in momentum are managed is in automobiles. Cars are fitted with springs and shock absorbers. These components increase the time over which a force acts when the car goes over uneven roads. By extending this time, they reduce the sudden large forces (jerks) felt by passengers, making the ride smoother. This helps to protect the car's components and the passengers from harsh impacts.
In simple words: Car shock absorbers stretch out the time of impact when driving over bumps, which makes the force smaller and the ride smoother.

๐ŸŽฏ Exam Tip: When explaining real-world examples, clearly link the change in momentum to the duration of the force application and its resulting effect.

 

Question 27. A spring balance is fastened to a wall and another spring balance is attached to its hole and is pulled steadily. Do both the spring balances show different readings on their scales. Give reason.
Answer: No, both spring balances will show the exact same reading. This is because, according to Newton's third law of motion, for every action, there is an equal and opposite reaction. The force applied to the second spring balance (action) creates an equal and opposite reaction force on the first spring balance, which is attached to the wall. Both balances are measuring the magnitude of this action-reaction pair. This principle ensures consistency in force measurements.
In simple words: Both spring balances will show the same reading because, according to Newton's third law, the forces they measure are equal and opposite.

๐ŸŽฏ Exam Tip: Always relate questions about interacting objects or forces to Newton's third law; it's the fundamental principle governing such scenarios.

 

Question 28. When a gun is fired it recoils, Give reason.
Answer: A gun recoils when fired due to Newton's third law of motion. When the gun is fired, it exerts a forward force on the bullet, pushing it out (this is the action). In response, the bullet exerts an equal and opposite force backward on the gun (this is the reaction). This backward force causes the gun to move backward, which is known as recoil. The law ensures that momentum is conserved.
In simple words: A gun kicks back (recoils) because it pushes the bullet forward, and the bullet pushes the gun backward with equal force, as per Newton's third law.

๐ŸŽฏ Exam Tip: Explain action-reaction pairs clearly: the action is the force on the bullet, and the reaction is the force on the gun. Also, mention conservation of momentum.

 

Question 29. Action and reaction are equal and opposite. But they do not cancel each other. Give reason.
Answer: Action and reaction forces are indeed equal in magnitude and opposite in direction, as stated by Newton's third law. However, they do not cancel each other out because they always act on *different* bodies. For example, when you push a wall, you exert a force on the wall (action), and the wall exerts an equal and opposite force on you (reaction). Since these forces are on different objects, they cannot cancel each other and thus affect the motion of each respective body. This is a critical distinction in understanding forces.
In simple words: Action and reaction forces don't cancel because they push on different objects, not the same one.

๐ŸŽฏ Exam Tip: The crucial point is that action and reaction forces *always* act on different bodies. If they acted on the same body, they would indeed cancel, and no motion would ever occur due to such pairs.

 

Question 30. Why does a cricket player, pulls his arms back with the ball while catching a ball?
Answer: A cricket player pulls his arms back while catching a ball for two key reasons related to impulse and momentum:
(i) The player is trying to reduce the ball's high velocity to zero. By pulling their arms back, they increase the time over which the ball's momentum changes. This extended time means the force exerted by the ball on the player's hands is spread out, making it smaller.
(ii) A smaller force acting over a longer time reduces the impact on the player's palms, preventing injury and making the catch less painful. This is an application of the impulse-momentum theorem, where \( \text{Impulse} = \text{Force} \times \text{Time} \).
In simple words: A cricket player moves their hands back to increase the time it takes to stop the ball. This makes the force on their hands smaller and prevents injury.

๐ŸŽฏ Exam Tip: Emphasize the inverse relationship: increasing the time of impact reduces the force of impact for the same change in momentum.

 

Question 31. When a sailor jumps forward, the boat moves backward. State the action and reaction in the above case.
Answer: This scenario is a classic example of Newton's third law of motion and the conservation of momentum:
- **Action:** The sailor exerts a force on the boat, pushing it backward as they jump forward.
- **Reaction:** The boat exerts an equal and opposite force on the sailor, pushing the sailor forward. This propels the sailor into the air, while the boat moves backward in response. This interaction highlights how forces always come in pairs.
In simple words: The sailor pushes the boat backward (action) to jump, and the boat pushes the sailor forward (reaction), causing the boat to move backward.

๐ŸŽฏ Exam Tip: Clearly identify which object exerts the "action" force and which object experiences the "reaction" force. Remember they are always on different bodies.

 

Question 32. It is easier to stop a tennis ball than a cricket ball moving with the same velocity.
Answer: It is easier to stop a tennis ball than a cricket ball moving at the same velocity because of their difference in mass. A cricket ball has a significantly larger mass than a tennis ball. Since momentum is calculated as mass multiplied by velocity (\( P = mv \)), the cricket ball will have a greater momentum. To bring an object to a stop, its momentum must be reduced to zero, which requires applying a larger force for the more massive cricket ball, even if both are moving at the same speed. This is a direct consequence of the impulse-momentum theorem.
In simple words: It's easier to stop a tennis ball because it's lighter than a cricket ball, so it has less momentum, even if both are moving at the same speed.

๐ŸŽฏ Exam Tip: Relate this directly to the definition of momentum and how a greater mass results in greater momentum for the same velocity.

 

Question 33. Define moment of force.
Answer: The moment of force, also known as torque, is defined as the turning effect of a force about a fixed point or axis. It is calculated as the product of the magnitude of the force and the perpendicular distance from the pivot point to the line of action of the force. This turning effect is what causes objects to rotate. For instance, tightening a bolt involves applying a moment of force.
In simple words: Moment of force is how much a force makes something spin around a point. We find it by multiplying the force by the distance from that point.

๐ŸŽฏ Exam Tip: Emphasize "perpendicular distance" as it is crucial for calculating the moment of force correctly.

 

Question 34. Draw the diagram of a couple.
Answer: O F X F Y
The diagram above shows two equal and opposite parallel forces, F, acting at points X and Y on a rigid body, creating a rotational effect around the pivot O. This setup causes the body to rotate without any linear motion. A couple always creates a turning effect.
In simple words: This picture shows two forces pushing in opposite directions on different parts of an object, making it spin.

๐ŸŽฏ Exam Tip: Ensure your diagram clearly shows two equal, parallel, and opposite forces acting at different points, causing rotation without translation.

 

Question 35. What do you know about moment of a couple?
Answer: The moment of a couple is the measure of its turning effect. It is calculated as the product of the magnitude of one of the forces in the couple and the perpendicular distance between the lines of action of the two forces. This distance is often called the arm of the couple. The moment of a couple is a vector quantity and determines the angular acceleration of the body. For a couple with force F and perpendicular distance S, the moment M is given by \( M = F \times S \). This moment always produces rotation.
In simple words: The moment of a couple is how strong its spinning effect is. You find it by multiplying one of the forces by the distance between the two forces.

๐ŸŽฏ Exam Tip: Emphasize that the moment of a couple is calculated using *one* force and the *perpendicular* distance between them, not the distance to a pivot.

 

Question 36. It is easier to open a door by applying the force at the free end. Justify.
Answer: It is easier to open a door by applying force at its free end, furthest from the hinges, because of the concept of moment of force (torque).
(i) The moment of force is the product of the force and the perpendicular distance from the pivot (hinges) to the line of action of the force. When you apply the force at the handle (free end), this perpendicular distance is maximized.
(ii) A larger perpendicular distance means a larger turning effect (moment of force) for the same amount of force. Therefore, only a small force is needed at the free end to create enough torque to open the door, making it feel easier. This is a practical application of physics in everyday life.
In simple words: It's easier to open a door by pushing on the handle because it's far from the hinges. This creates a bigger turning force with less effort.

๐ŸŽฏ Exam Tip: Clearly link "easier" to "larger perpendicular distance" and "smaller force required" to achieve the same turning effect (torque).

 

Question 37. A force can rotate a nut when applied by a wrench.
(a) What is meant by moment of force?
(b) Name the factors on which the turning effect of a force depend on.

Answer:
(a) The moment of force, also called torque, is the turning effect that a force produces on a body around a fixed axis. It causes rotation. For example, when you turn a doorknob, you are applying a moment of force.
(b) The turning effect of a force depends on two main factors:
1. The magnitude of the force applied.
2. The perpendicular distance of the line of action of the force from the axis of rotation.
A greater force or a longer perpendicular distance will result in a larger turning effect. This is why longer wrenches make it easier to loosen tight nuts.
In simple words: (a) Moment of force means how much a force makes something spin. (b) It depends on how strong the push is and how far away from the spinning point the push is applied.

๐ŸŽฏ Exam Tip: Always remember that the distance involved in calculating torque must be the *perpendicular* distance to the line of action of the force.

 

Question 38. What is meant by weightlessness?
Answer: Weightlessness is a condition where a body or a person experiences effectively zero weight. This happens when the only force acting on the body is Earth's gravitational force, and there are no other contact forces supporting it. In such a state, the body is in continuous free fall. Astronauts in orbit experience weightlessness because they are constantly falling around the Earth. This feeling is not due to an absence of gravity, but rather the absence of normal contact forces.
In simple words: Weightlessness means feeling like you have no weight because you are constantly falling without anything pushing you up.

๐ŸŽฏ Exam Tip: Emphasize that weightlessness is a *sensation* due to the absence of a normal force, not the absence of gravity itself.

 

Question 39. What is meant by moment of a force?
Answer: The moment of a force, also known as torque, is the measure of its tendency to cause rotation about a specific point or axis. It quantifies the effectiveness of a force in producing a turning effect. A larger moment of force means a greater tendency for the object to spin. This concept is vital in understanding how levers and gears work. For example, using a longer wrench increases the moment of force, making it easier to turn a bolt.
In simple words: Moment of force means how much a push or pull makes something spin around a pivot point.

๐ŸŽฏ Exam Tip: Torque is a vector quantity, meaning it has both magnitude and direction (clockwise or anti-clockwise). Always consider the pivot point.

 

Question 40. What is meant by gravitational force?
Answer: Gravitational force is the natural force of attraction that exists between any two objects in the universe that have mass. The strength of this force depends on the masses of the objects and the distance between them. The more massive the objects, or the closer they are, the stronger the gravitational pull. This force is responsible for keeping planets in orbit around the sun and for objects falling to Earth. It's one of the four fundamental forces of nature.
In simple words: Gravitational force is the pull between any two things that have weight, like Earth pulling an apple.

๐ŸŽฏ Exam Tip: Remember that gravitational force is always attractive and acts along the line connecting the centers of the two masses.

 

Question 41. In which direction does gravitational force act?
Answer: The gravitational force always acts along the line joining the centers of the two interacting objects. For example, the Earth's gravity pulls objects directly towards the center of the Earth. It's a force that pulls things together, never pushes them apart. This directionality is what makes objects fall downwards.
In simple words: Gravitational force pulls two objects straight towards each other's centers.

๐ŸŽฏ Exam Tip: Visualize the line connecting the centers of masses to correctly determine the direction of the gravitational force.

 

Question 42. (a) When a horse suddenly starts running, the rider falls backward. Give reason.
(b) Why doesn't earth move towards an apple?

Answer:
(a) When a horse suddenly starts running, its lower part (in contact with the horse) comes into motion instantly. However, the rider's upper body tends to remain at rest due to inertia. This difference causes the rider's upper body to lag behind, making them fall backward. It is a clear demonstration of the inertia of rest.
(b) According to Newton's second law of motion (\( F = ma \)), for a given force, acceleration is inversely proportional to mass (\( a \propto \frac{1}{m} \)). While an apple exerts an equal and opposite gravitational force on the Earth, the Earth's mass is extremely large compared to the apple's mass. Therefore, the acceleration produced in the Earth is negligibly small, making its movement towards the apple undetectable. This shows that while forces are equal, their effects can differ greatly due to mass.
In simple words: (a) A rider falls backward when a horse starts fast because their body wants to stay still due to inertia. (b) The Earth doesn't move towards an apple because the Earth is too heavy; even with equal pull, the apple's pull can't make the Earth noticeably move.

๐ŸŽฏ Exam Tip: For part (a), focus on inertia of rest. For part (b), emphasize Newton's third law (equal and opposite forces) combined with Newton's second law (acceleration inversely proportional to mass) to explain the different effects.

 

Question 43. (a) Why it is difficult to walk on a slippery floor or sand?
(b) State the law related to this.

Answer:
(a) It is difficult to walk on a slippery floor or sand because we rely on friction to move forward. When we walk, we push the ground backward (action). The ground, in turn, pushes us forward (reaction) due to friction. On a slippery surface or loose sand, the friction is insufficient to provide a strong enough forward reaction force. This makes it hard to get a grip and push off effectively, leading to slipping or sinking.
(b) This phenomenon is directly related to **Newton's Third Law of Motion**, which states that for every action, there is an equal and opposite reaction. Without a sufficient action force (pushing the ground back) that can be met with an equal and opposite reaction force (friction pushing us forward), efficient locomotion becomes challenging.
In simple words: (a) It's hard to walk on slippery floors or sand because there isn't enough friction for the ground to push us forward when we push it backward. (b) This is explained by Newton's Third Law, which says pushes always come with equal and opposite pushes.

๐ŸŽฏ Exam Tip: When explaining friction and walking, remember to articulate the action-reaction pair and how the lack of sufficient friction hinders the reaction force needed for movement.

 

Question 44. State the numerical value and unit of gravitational constant.
Answer: The numerical value of the universal gravitational constant (\( G \)) is approximately \( \text{6.674} \times \text{10}^{-11} \). Its unit is \( \text{N m}^2 \text{ kg}^{-2} \). This constant is a fundamental constant of nature, used in Newton's law of universal gravitation to calculate the attractive force between any two masses. The value of G remains the same throughout the universe.
In simple words: The gravitational constant is about \( \text{6.674} \times \text{10}^{-11} \), and its unit is Newtons times meters squared per kilogram squared.

๐ŸŽฏ Exam Tip: It's important to differentiate the universal gravitational constant (\( G \)) from the acceleration due to gravity (\( g \)). Their values, units, and contexts are different.

 

Question 45. What is meant by acceleration due gravity?
Answer: Acceleration due to gravity is the acceleration experienced by an object solely because of the force of Earth's gravity. When an object is in free fall, ignoring air resistance, it accelerates downwards at a constant rate. This acceleration is denoted by \( g \), and its average value on Earth's surface is approximately \( \text{9.8 m s}^{-2} \). This constant acceleration makes all objects fall at the same rate regardless of their mass in a vacuum.
In simple words: Acceleration due to gravity is how fast objects speed up when they fall because of Earth's pull, which is about 9.8 meters per second squared.

๐ŸŽฏ Exam Tip: Remember that acceleration due to gravity (\( g \)) is a specific case of acceleration caused by the gravitational force of a celestial body, most commonly Earth.

 

Question 46. Write the expression of acceleration due to gravity.
Answer: The expression for acceleration due to gravity (\( g \)) on the surface of a celestial body (like Earth) is given by:
\[ g = \frac{GM}{R^2} \]
Where:
\( G \) is the universal gravitational constant.
\( M \) is the mass of the Earth (or the celestial body).
\( R \) is the radius of the Earth (or the celestial body).
This formula shows how gravity's pull depends on the mass and size of the planet. For instance, on the Moon, \( M \) and \( R \) would be the Moon's mass and radius, resulting in a smaller \( g \) than on Earth.
In simple words: The formula for gravity's acceleration is \( g = \frac{GM}{R^2} \), where \( G \) is a constant, \( M \) is the planet's mass, and \( R \) is the planet's radius.

๐ŸŽฏ Exam Tip: Understand that \( g \) depends on the mass and radius of the planet, not on the mass of the falling object. This is a common misconception.

 

Question 47. Deduce the value of mass of earth.
Answer: To deduce the value of Earth's mass (\( M \)), we can use the formula for acceleration due to gravity:
\[ g = \frac{GM}{R^2} \]
Rearranging this formula to solve for \( M \), we get:
\[ M = \frac{gR^2}{G} \]
Now, we plug in the known values:
\( g = \text{9.8 m s}^{-2} \) (acceleration due to gravity on Earth's surface)
\( R = \text{6.38} \times \text{10}^6 \text{ m} \) (average radius of Earth)
\( G = \text{6.673} \times \text{10}^{-11} \text{ N m}^2 \text{ kg}^{-2} \) (universal gravitational constant)
Substitute these values into the equation:
\( M = \frac{(9.8 \text{ m s}^{-2}) \times (6.38 \times 10^6 \text{ m})^2}{6.673 \times 10^{-11} \text{ N m}^2 \text{ kg}^{-2}} \)
\( M = \frac{9.8 \times (6.38)^2 \times 10^{12}}{6.673 \times 10^{-11}} \)
\( M = \frac{9.8 \times 40.7044 \times 10^{12}}{6.673 \times 10^{-11}} \)
\( M \approx \frac{398.903}{6.673} \times 10^{12 - (-11)} \)
\( M \approx 59.78 \times 10^{23} \text{ kg} \)
\( M \approx 5.978 \times 10^{24} \text{ kg} \)
Thus, the approximate mass of the Earth is \( \text{5.98} \times \text{10}^{24} \text{ kg} \). This is how scientists calculate the mass of planets. The result is a very large number, as expected for a planet.
In simple words: We find Earth's mass by using the gravity formula. We put in values for Earth's gravity, its size, and the gravitational constant, then do the math. This shows Earth weighs about \( \text{5.98} \times \text{10}^{24} \) kilograms.

๐ŸŽฏ Exam Tip: Show all steps clearly when deriving a value. Pay close attention to unit consistency and scientific notation in calculations.

 

Question 48. What happens to the gravitational force between two objects if the masses of both objects are doubled?
Answer: According to Newton's law of universal gravitation, the gravitational force (\( F \)) between two objects is directly proportional to the product of their masses (\( F \propto m_1 m_2 \)). If the masses of *both* objects are doubled, say \( m_1 \) becomes \( 2m_1 \) and \( m_2 \) becomes \( 2m_2 \), then the new product of masses will be \( (2m_1) \times (2m_2) = 4m_1 m_2 \). This means the gravitational force between them will increase by a factor of four. The relationship is always proportional to the product of masses.
In simple words: If you double the mass of both objects, the pull of gravity between them becomes four times stronger.

๐ŸŽฏ Exam Tip: Remember the formula \( F = \frac{Gm_1 m_2}{r^2} \). If \( m_1 \to 2m_1 \) and \( m_2 \to 2m_2 \), then \( F \to \frac{G(2m_1)(2m_2)}{r^2} = 4 \frac{Gm_1 m_2}{r^2} \). Always show your reasoning based on the formula.

 

Question 49. The mass of a body is 60 kg. What will be its mass when it is placed on the moon?
Answer: The mass of a body is a fundamental property that measures the amount of matter it contains. It is an intrinsic property and does not change regardless of its location in the universe. Therefore, if a body has a mass of 60 kg on Earth, its mass will remain 60 kg when it is placed on the Moon. What would change on the Moon is its *weight*, because the Moon has less gravity than Earth.
In simple words: The mass of a body will still be 60 kg on the Moon because mass is how much stuff is in an object, and that doesn't change with location.

๐ŸŽฏ Exam Tip: Clearly differentiate between mass (a scalar quantity, constant everywhere) and weight (a vector quantity, dependent on gravity and thus location).

 

Question 50. When an object is taken to the moon, is there any change in weight?
Answer: Yes, when an object is taken to the Moon, there will be a significant change in its weight. Weight is the measure of the gravitational force acting on an object, calculated as mass times the acceleration due to gravity (\( W = mg \)). Since the Moon has a much smaller mass and radius compared to Earth, its acceleration due to gravity is approximately one-sixth that of Earth's. Consequently, an object's weight on the Moon will be about one-sixth of its weight on Earth. This is why astronauts can jump higher on the Moon.
In simple words: Yes, an object's weight changes on the Moon because the Moon's gravity is much weaker than Earth's, making the object weigh less.

๐ŸŽฏ Exam Tip: Explain that weight is a force and depends on the local gravitational field, unlike mass, which is a constant measure of matter.

 

Question 51. Gravitational force acts on all objects is proportional to their masses. But a heavy object falls slower than a light object. Give reason.
Answer: The statement that a heavy object falls slower than a light object is incorrect. While it is true that gravitational force is proportional to an object's mass, meaning a heavier object experiences a greater gravitational pull, this doesn't mean it falls slower. In a vacuum, all objects, regardless of their mass, fall at the same rate of acceleration (acceleration due to gravity, \( g \)). This is because the greater gravitational force on a heavier object is precisely balanced by its greater inertia (resistance to acceleration), resulting in the same acceleration for all. Air resistance, however, can make lighter, larger objects appear to fall slower in the real world.
In simple words: Heavy objects do not fall slower than light objects in a vacuum. Even though gravity pulls heavier things harder, heavier things also resist moving more, so they fall at the same speed.

๐ŸŽฏ Exam Tip: Clarify the role of air resistance in real-world scenarios versus the theoretical concept of free fall in a vacuum. Emphasize that acceleration due to gravity is independent of mass.

 

Question 52. A falling apple is attracted towards the earth.
(a) Does the apple attract the earth?
(b) Why doesn't earth move towards an apple?

Answer:
(a) Yes, according to Newton's Third Law of Motion and the Law of Universal Gravitation, the apple *does* attract the Earth with an equal and opposite force. Gravitational attraction is always a mutual force between two masses.
(b) The Earth does not appear to move towards an apple because of its extremely large mass. While the force exerted by the apple on the Earth is equal in magnitude to the force exerted by the Earth on the apple, the acceleration produced in an object is inversely proportional to its mass (\( a = \frac{F}{m} \)). Since the Earth's mass is astronomically larger than the apple's mass, the acceleration of the Earth due to the apple's pull is negligible and virtually undetectable. The Earth does accelerate, but by an immeasurably small amount.
In simple words: (a) Yes, the apple pulls on the Earth just as much as the Earth pulls on the apple. (b) The Earth doesn't visibly move towards the apple because it's too big; even though the pull is equal, the Earth's mass makes its movement tiny.

๐ŸŽฏ Exam Tip: This question combines Newton's third law (equal and opposite forces) with the second law (acceleration depends on mass) to explain why the effect on different masses varies.

 

Question 53. Observe the figure and write the answer:
(a) The force which balance A exerts on balance B is called
(b) The force of balance B on balance A is called

Answer: Based on the principles of forces and interactions:
(a) The force which balance A exerts on balance B is called **action**. This is the initial force applied or observed in an interaction.
(b) The force of balance B on balance A is called **opposite reaction**. According to Newton's third law, this reaction force is equal in magnitude and opposite in direction to the action force. The diagram visually represents this interaction, often used to illustrate spring balance readings.
In simple words: (a) The push from balance A to balance B is called action. (b) The push from balance B back to balance A is called reaction.

๐ŸŽฏ Exam Tip: Clearly define action and reaction forces as an interacting pair, emphasizing that they are always equal and opposite and act on different bodies.

 

Question 54. What is meant by apparent weight?
Answer: Apparent weight is the weight that a person or object *seems* to have, which is determined by the normal force acting on them. It can be different from an object's actual weight (the true gravitational force) if there are other forces acting on it, such as in an accelerating lift or while in orbit. For example, in a lift accelerating upwards, your apparent weight feels greater than your actual weight. It reflects the net force exerted by the supporting surface.
In simple words: Apparent weight is how heavy you feel, which can change if you are moving up or down in a lift, unlike your real weight.

๐ŸŽฏ Exam Tip: Apparent weight is essentially the reading on a weighing scale, and it changes with acceleration (or lack thereof) in a non-inertial frame of reference.

 

Question 55. What is meant by free fall?
Answer: Free fall is a state of motion where an object is accelerating solely under the influence of gravity, with no other forces (like air resistance) acting upon it. In free fall, the apparent weight of the object (or person inside a falling lift) becomes zero because there is no normal contact force supporting it. This condition is observed when the acceleration of an object (\( a \)) is equal to the acceleration due to gravity (\( g \)), meaning \( R = m(g - g) = 0 \). This is the condition experienced by astronauts in orbit.
In simple words: Free fall means an object is only falling because of gravity, and nothing else is pushing or holding it up, making it feel weightless.

๐ŸŽฏ Exam Tip: Emphasize that free fall implies *only* gravity is acting, and it's the condition where apparent weight is zero.

 

VII. Solve the given problems.

 

Question 1. The ratio of masses of two bodies is 1 : 3 and the ratio of applied forces on them is 4: 9. Calculate the ratio of their accelerations.
Answer:
Given:
Ratio of masses \( m_1 : m_2 = 1 : 3 \)
Ratio of applied forces \( F_1 : F_2 = 4 : 9 \)
We know from Newton's second law that acceleration \( a = \frac{F}{m} \).
For the first body, acceleration \( a_1 = \frac{F_1}{m_1} \)
For the second body, acceleration \( a_2 = \frac{F_2}{m_2} \)
To find the ratio of their accelerations, \( a_1 : a_2 \):
\( \frac{a_1}{a_2} = \frac{\frac{F_1}{m_1}}{\frac{F_2}{m_2}} \)
\( \frac{a_1}{a_2} = \frac{F_1}{m_1} \times \frac{m_2}{F_2} \)
\( \frac{a_1}{a_2} = \left(\frac{F_1}{F_2}\right) \times \left(\frac{m_2}{m_1}\right) \)
Substitute the given ratios:
\( \frac{a_1}{a_2} = \left(\frac{4}{9}\right) \times \left(\frac{3}{1}\right) \)
\( \frac{a_1}{a_2} = \frac{4 \times 3}{9 \times 1} \)
\( \frac{a_1}{a_2} = \frac{12}{9} \)
\( \frac{a_1}{a_2} = \frac{4}{3} \)
The ratio of their accelerations is \( 4 : 3 \). This shows how both force and mass influence acceleration.
In simple words: We used Newton's law to find that if masses are 1:3 and forces are 4:9, then their accelerations will be in a ratio of 4:3.

๐ŸŽฏ Exam Tip: Remember to set up ratios carefully, especially when dealing with inverse relationships (like acceleration and mass) in combined ratios.

 

Question 2. What is acceleration produced by a force of 12 N exerted on an object of mass 3 kg?
Answer:
Given:
Force exerted, \( F = \text{12 N} \)
Mass of the object, \( m = \text{3 kg} \)
We need to find the acceleration produced, \( a \).
According to Newton's second law of motion, \( F = ma \).
To find acceleration, we can rearrange the formula: \( a = \frac{F}{m} \)
Substitute the given values:
\( a = \frac{12 \text{ N}}{3 \text{ kg}} \)
\( a = 4 \text{ m s}^{-2} \)
Therefore, the acceleration produced in the object is \( \text{4 m s}^{-2} \). This is a straightforward application of the fundamental force equation.
In simple words: If a 12 Newton force pushes a 3 kg object, it will speed up by 4 meters per second, every second.

๐ŸŽฏ Exam Tip: Always state the formula used, show substitution of values, and include correct units in the final answer for full marks.

 

Question 3. A certain force exerted for 1.2 s raises the speed of an object from 1.8 m/s to 4.2 m/s. Later, the same force is applied for 2 s. How much does the speed change in 2 s.
Answer:
First, let's find the acceleration from the first part of the problem.
Given:
Time, \( t_1 = \text{1.2 s} \)
Initial velocity, \( u = \text{1.8 m/s} \)
Final velocity, \( v = \text{4.2 m/s} \)
Acceleration, \( a = \frac{\text{change in velocity}}{\text{time}} = \frac{v - u}{t_1} \)
\( a = \frac{4.2 \text{ m/s} - 1.8 \text{ m/s}}{1.2 \text{ s}} \)
\( a = \frac{2.4 \text{ m/s}}{1.2 \text{ s}} \)
\( a = 2 \text{ m s}^{-2} \)
Now, the problem states that the *same force* is applied, which means the acceleration remains \( \text{2 m s}^{-2} \).
For the second part:
Time, \( t_2 = \text{2 s} \)
We need to find the change in speed (or change in velocity), \( \Delta v \).
Change in speed \( = \text{acceleration} \times \text{time} \)
\( \Delta v = a \times t_2 \)
\( \Delta v = \text{2 m s}^{-2} \times \text{2 s} \)
\( \Delta v = 4 \text{ m/s} \)
Therefore, the speed changes by \( \text{4 m/s} \) when the same force is applied for 2 s. This problem combines kinematics and dynamics principles.
In simple words: First, we found how fast the object was speeding up, which was 2 meters per second, every second. Then, we used this same speed-up rate to find that if it speeds up for 2 seconds, its speed will change by 4 meters per second.

๐ŸŽฏ Exam Tip: Break down multi-part problems into logical steps. First calculate acceleration, then use that acceleration with new parameters. Pay attention to units.

 

Question 4. A constant force acts on an object of mass 10 kg for a duration of 4 s. It increases the objects velocity from 2 ms\(^{-1}\) to 8 ms\(^{-1}\). Find the magnitude of the applied force.
Answer: First, let's list what we know:
Mass of the object \(m = 10\) kg
Initial velocity \(u = 2\) ms\(^{-1}\)
Final velocity \(v = 8\) ms\(^{-1}\)
Time taken \(t = 4\) s
We use Newton's second law, which states that force is equal to the rate of change of momentum.
So, force \(F = \frac{m(v-u)}{t}\)
\(F = \frac{10(8-2)}{4}\)
\(F = \frac{10 \times 6}{4}\)
\(F = \frac{60}{4}\)
\(F = 15\) N
The applied force on the object is 15 N. This force causes the object to speed up over a short period.
In simple words: A force of 15 N was used to make the 10 kg object go faster, changing its speed from 2 ms\(^{-1}\) to 8 ms\(^{-1}\) in 4 seconds.

๐ŸŽฏ Exam Tip: Remember to clearly write down all given values and the formula before substituting to avoid errors in calculations.

 

Question 5. Which would require a greater force for accelerating a 2 kg of mass at 4 ms\(^{-2}\) or a 3 kg mass at 2 ms\(^{-2}\)?
Answer: We use the formula \(F = ma\), where F is force, m is mass, and a is acceleration.
For the first case:
Mass \(m_1 = 2\) kg
Acceleration \(a_1 = 4\) ms\(^{-2}\)
Force \(F_1 = m_1 a_1 = 2 \times 4 = 8\) N
For the second case:
Mass \(m_2 = 3\) kg
Acceleration \(a_2 = 2\) ms\(^{-2}\)
Force \(F_2 = m_2 a_2 = 3 \times 2 = 6\) N
Since \(F_1 = 8\) N and \(F_2 = 6\) N, we can see that \(F_1 > F_2\). Therefore, accelerating the 2 kg mass at 4 ms\(^{-2}\) requires a greater force. The higher acceleration for a smaller mass still needs more push in this comparison.
In simple words: It takes a bigger push (8 N) to make a 2 kg object speed up by 4 ms\(^{-2}\) than it does (6 N) to make a 3 kg object speed up by 2 ms\(^{-2}\).

๐ŸŽฏ Exam Tip: When comparing forces, always calculate each force separately using \(F=ma\) and then compare the numerical values.

 

Question 6. A bullet of mass 15 g is horizontally fired with a velocity 100 ms\(^{-1}\) from a pistol of mass 2 kg. What is the recoil velocity of the pistol?
Answer: This problem uses the law of conservation of momentum. First, convert all units to SI.
Mass of the bullet, \(m_1 = 15\) g \( = 0.015\) kg
Mass of the pistol, \(m_2 = 2\) kg
Initial velocity of the bullet, before firing, \(u_1 = 0\) ms\(^{-1}\)
Initial velocity of the pistol, before firing, \(u_2 = 0\) ms\(^{-1}\)
Final velocity of the bullet, after firing, \(v_1 = + 100\) ms\(^{-1}\) (we take forward direction as positive)
Let the recoil velocity of the pistol be \(v_2\).
According to the law of conservation of momentum, the total momentum before firing is equal to the total momentum after firing. Before firing, both are at rest, so the total momentum is 0.
Total momentum before firing \( = m_1 u_1 + m_2 u_2 = (0.015 \times 0) + (2 \times 0) = 0\)
Total momentum after firing \( = m_1 v_1 + m_2 v_2\)
Substituting the values:
\(0 = (0.015 \times 100) + (2 \times v_2)\)
\(0 = 1.5 + 2v_2\)
Now, solve for \(v_2\):
\(2v_2 = -1.5\)
\(v_2 = \frac{-1.5}{2}\)
\(v_2 = -0.75\) ms\(^{-1}\)
The negative sign indicates that the pistol moves in the opposite direction to the bullet. This is why a gun 'kicks back' when fired.
In simple words: When a 15 g bullet is shot forward from a 2 kg gun at 100 ms\(^{-1}\), the gun moves backward at a speed of 0.75 ms\(^{-1}\). This happens because momentum must stay the same before and after firing.

๐ŸŽฏ Exam Tip: Always remember to convert all given masses to kilograms (kg) before performing calculations involving momentum and to correctly interpret the sign of the final velocity.

 

Question 7. A 10 g bullet is shot from a 5 kg gun with a velocity of 400 m/s. what is the speed of recoil of the gun?
Answer: We will use the law of conservation of momentum. First, convert the bullet's mass to kilograms.
Mass of the bullet, \(m_1 = 10\) g \( = 10 \times 10^{-3}\) kg \( = 0.01\) kg
Mass of the gun, \(m_2 = 5\) kg
Initial velocity of bullet and gun before firing, \(u_1 = u_2 = 0\) m/s (they are at rest)
Velocity of the bullet after firing, \(v_1 = 400\) m/s
Let the speed of recoil of the gun be \(v_2\).
Total momentum before firing \( = m_1 u_1 + m_2 u_2 = (0.01 \times 0) + (5 \times 0) = 0\)
Total momentum after firing \( = m_1 v_1 + m_2 v_2\)
By the law of conservation of momentum:
\(m_1 v_1 + m_2 v_2 = 0\)
\( (0.01 \times 400) + (5 \times v_2) = 0\)
\(4 + 5v_2 = 0\)
\(5v_2 = -4\)
\(v_2 = \frac{-4}{5}\)
\(v_2 = -0.8\) m/s
The speed of recoil of the gun is 0.8 m/s. The negative sign shows that the gun moves in the opposite direction to the bullet. This recoil is a clear example of Newton's third law in action.
In simple words: When a 10 g bullet is shot forward at 400 m/s from a 5 kg gun, the gun pushes back at 0.8 m/s. This is because the total push (momentum) must stay the same before and after the bullet is fired.

๐ŸŽฏ Exam Tip: Pay close attention to unit conversions (grams to kilograms) and remember that recoil velocity will always have the opposite sign to the bullet's velocity.

 

Question 8. The figure represents two bodies of masses 10 kg and 20 kg, moving with an initial velocity of 10 ms\(^{-1}\) and 5 ms\(^{-1}\) respectively. They collide with each other. After collision, they move with velocities 12 ms\(^{-1}\) and 4 ms\(^{-1}\) respectively. The time of collision is 2 s. Now calculate F\(_{2}\) and F\(_{2}\).
Answer: We need to calculate the forces F\(_{1}\) and F\(_{2}\) exerted during the collision. The figure depicts two objects colliding and then moving apart, illustrating conservation of momentum and Newton's laws.
Initial conditions:
Mass of first object \(m_1 = 10\) kg
Mass of second object \(m_2 = 20\) kg
Initial velocity of first object \(u_1 = 10\) ms\(^{-1}\)
Initial velocity of second object \(u_2 = 5\) ms\(^{-1}\)
Final conditions:
Final velocity of first object \(v_1 = 12\) ms\(^{-1}\)
Final velocity of second object \(v_2 = 4\) ms\(^{-1}\)
Time of collision, \(t = 2\) s

First, let's find the force acting on the 20 kg object (\(m_2\)):
This force is F\(_{1}\). We use the formula \(F = \frac{m(v-u)}{t}\).
\(F_1 = m_2 \frac{(v_2 - u_2)}{t}\)
\(F_1 = 20 \frac{(4 - 5)}{2}\)
\(F_1 = 20 \frac{(-1)}{2}\)
\(F_1 = -10\) N
The negative sign means the force acting on the 20 kg object is in the opposite direction to its initial motion. The force from the 10 kg object slowed it down.

Next, let's find the force acting on the 10 kg object (\(m_1\)):
This force is F\(_{2}\).
\(F_2 = m_1 \frac{(v_1 - u_1)}{t}\)
\(F_2 = 10 \frac{(12 - 10)}{2}\)
\(F_2 = 10 \frac{(2)}{2}\)
\(F_2 = 10\) N
The positive sign means the force acting on the 10 kg object is in the same direction as its initial motion. The force from the 20 kg object sped it up.
Notice that F\(_{1}\) = -F\(_{2}\), which is consistent with Newton's third law of motion (action-reaction forces are equal in magnitude and opposite in direction).
In simple words: During the collision, the 10 kg object pushed the 20 kg object with a force of 10 N backward (F\(_{1}\)), causing it to slow down. At the same time, the 20 kg object pushed the 10 kg object with a force of 10 N forward (F\(_{2}\)), causing it to speed up.

๐ŸŽฏ Exam Tip: Remember to apply Newton's second law for each object separately during the collision, paying attention to the signs of velocity changes to correctly determine force direction.

 

Question 9. The mass of an object is 5 kg. What is its weight on the earth?
Answer: We use the formula for weight, which is \(W = m \times g\), where \(W\) is weight, \(m\) is mass, and \(g\) is the acceleration due to gravity.
Given:
Mass of the object \(m = 5\) kg
Acceleration due to gravity on Earth \(g = 9.8\) ms\(^{-2}\)
Substitute the values into the formula:
\(W = 5 \times 9.8\)
\(W = 49\) N
So, the weight of the 5 kg object on the surface of the Earth is 49 N. Weight is a force, so its unit is Newtons.
In simple words: An object that has a mass of 5 kg will have a weight of 49 N on Earth, because Earth's gravity pulls on it.

๐ŸŽฏ Exam Tip: Always remember that mass is a measure of the amount of matter, while weight is the force of gravity on that mass. Ensure you use the correct value for \(g\) (9.8 ms\(^{-2}\) for Earth) in your calculations.

 

Question 10. Calculate the force of gravitation between two objects of masses 80 kg and 120 kg kept at a distance of 10 m from each other. Given, G = 6.67 \(\times\) 10\(^{-11}\) Nm\(^{2}\) / kg\(^{2}\).
Answer: We use Newton's law of universal gravitation, which is \(F = \frac{Gm_1 m_2}{r^2}\).
Given:
Mass of the first object \(m_1 = 80\) kg
Mass of the second object \(m_2 = 120\) kg
Distance between the objects \(r = 10\) m
Gravitational constant \(G = 6.67 \times 10^{-11}\) Nm\(^2\)kg\(^{-2}\)
Now, substitute these values into the formula:
\(F = \frac{(6.67 \times 10^{-11}) \times 80 \times 120}{(10)^2}\)
\(F = \frac{(6.67 \times 10^{-11}) \times 9600}{100}\)
\(F = (6.67 \times 10^{-11}) \times 96\)
\(F = 640.32 \times 10^{-11}\)
\(F = 6.4032 \times 10^{-9}\) N
The force of gravitation between the two objects is approximately \(6.4032 \times 10^{-9}\) N. This force is usually very small unless the masses are very large, like planets.
In simple words: The tiny gravitational pull between an 80 kg object and a 120 kg object, placed 10 meters apart, is about \(6.4 \times 10^{-9}\) Newtons.

๐ŸŽฏ Exam Tip: Be careful with scientific notation and squaring the distance in the denominator. Double-check your calculations for powers of 10.

 

Question 11. Calculate the value of acceleration due to gravity on moon. Given mass of moon = 7.4 \(\times\) 10\(^{22}\) kg. radius of moon = 1740 km.
Answer: We use the formula for acceleration due to gravity \(g = \frac{GM}{R^2}\). First, convert the radius to meters.
Given:
Mass of the moon \(M = 7.4 \times 10^{22}\) kg
Radius of the moon \(R = 1740\) km \( = 1740 \times 1000\) m \( = 1.740 \times 10^6\) m
Gravitational constant \(G = 6.67 \times 10^{-11}\) Nm\(^2\)kg\(^{-2}\)
Now, substitute these values into the formula:
\(g = \frac{(6.67 \times 10^{-11}) \times (7.4 \times 10^{22})}{(1.740 \times 10^6)^2}\)
\(g = \frac{(6.67 \times 7.4) \times (10^{-11} \times 10^{22})}{(1.740)^2 \times (10^6)^2}\)
\(g = \frac{49.358 \times 10^{11}}{3.0276 \times 10^{12}}\)
\(g = \frac{49.358}{30.276} \times 10^{(11-12)}\)
\(g \approx 1.630 \times 10^{-1}\)
\(g \approx 0.163\) ms\(^{-2}\)
The acceleration due to gravity on the moon is approximately \(1.63\) ms\(^{-2}\). This value is much less than on Earth, which is why astronauts can jump higher on the Moon.
In simple words: On the Moon, gravity makes things fall slower, with an acceleration of about 1.63 ms\(^{-2}\). This is calculated using the Moon's mass and radius, and it's much weaker than Earth's gravity.

๐ŸŽฏ Exam Tip: Always ensure the radius is in meters and remember to square the entire radius term, including its power of 10, in the denominator.

 

Question 12. State Newton's law of gravitation. Write an expression for acceleration due to gravity on the surface of the earth. If the ratio of acceleration due to gravity of two heavenly bodies is 1 : 4 and the ratio of their radii is 1 : 3, what will be the ratio of their masses?
Answer:
**Newton's Law of Universal Gravitation:**
Newton's law of gravitation states that every object in the universe attracts every other object with a force. This force is directly proportional to the product of their masses and inversely proportional to the square of the distance between the centers of these masses. The direction of the force acts along the line joining the masses.
The mathematical expression for this force is \(F = \frac{Gm_1 m_2}{d^2}\), where \(G\) is the universal gravitational constant, \(m_1\) and \(m_2\) are the masses of the two objects, and \(d\) is the distance between their centers.

**Expression for acceleration due to gravity (\(g\)) on the surface of the Earth:**
The acceleration due to gravity (\(g\)) on the surface of a planet (like Earth) is given by the formula \(g = \frac{GM}{R^2}\), where \(G\) is the universal gravitational constant, \(M\) is the mass of the planet, and \(R\) is the radius of the planet. This formula shows how gravity pulls objects downwards.

**Ratio of masses calculation:**
Given:
Ratio of acceleration due to gravity for two heavenly bodies: \(\frac{g_1}{g_2} = \frac{1}{4}\)
Ratio of their radii: \(\frac{R_1}{R_2} = \frac{1}{3}\)
We know the formula for acceleration due to gravity: \(g = \frac{GM}{R^2}\)
For the first body: \(g_1 = \frac{GM_1}{R_1^2}\)
For the second body: \(g_2 = \frac{GM_2}{R_2^2}\)
Now, let's find the ratio of \(g_1\) to \(g_2\):
\( \frac{g_1}{g_2} = \frac{\frac{GM_1}{R_1^2}}{\frac{GM_2}{R_2^2}} \)
\( \frac{g_1}{g_2} = \frac{GM_1}{R_1^2} \times \frac{R_2^2}{GM_2} \)
The gravitational constant \(G\) cancels out:
\( \frac{g_1}{g_2} = \frac{M_1}{M_2} \times \frac{R_2^2}{R_1^2} \)
Rearranging to find the ratio of masses \(\frac{M_1}{M_2}\):
\( \frac{M_1}{M_2} = \frac{g_1}{g_2} \times \frac{R_1^2}{R_2^2} \)
\( \frac{M_1}{M_2} = \frac{g_1}{g_2} \times \left(\frac{R_1}{R_2}\right)^2 \)
Substitute the given ratios:
\( \frac{M_1}{M_2} = \frac{1}{4} \times \left(\frac{1}{3}\right)^2 \)
\( \frac{M_1}{M_2} = \frac{1}{4} \times \frac{1}{9} \)
\( \frac{M_1}{M_2} = \frac{1}{36} \)
So, the ratio of their masses \(M_1 : M_2 = 1 : 36\). This means the second body is much more massive than the first one to have a larger surface gravity despite its larger radius.
In simple words: Newton's law says all things pull on each other. The acceleration due to gravity on a planet depends on its mass and radius. If one planet has 1/4th the gravity of another, and 1/3rd its radius, then its mass must be 1/36th of the other planet's mass.

๐ŸŽฏ Exam Tip: When dealing with ratios in gravitation problems, always write out the full formula for each body, set up the ratio, and cancel out common terms like \(G\) before substituting numerical ratios.

 

Question 13. A bomb of mass 3 kg, initially at rest, explodes into two parts of 2 kg and 1 kg. The 2 kg mass travels with a velocity of 3 m/s. At what velocity will the 1 kg mass travel?
Answer: This problem uses the principle of conservation of linear momentum. Since the bomb is initially at rest, its total momentum before explosion is zero.
Given:
Total mass of the bomb \(m = 3\) kg
Initial velocity of the bomb \(v = 0\) m/s
Mass of the first part \(m_1 = 2\) kg
Velocity of the first part \(v_1 = 3\) m/s
Mass of the second part \(m_2 = 1\) kg (since \(3\) kg \( - 2\) kg \( = 1\) kg)
Let the velocity of the second part be \(v_2\).
According to the law of conservation of momentum, the total momentum before the explosion is equal to the total momentum after the explosion.
Total momentum before explosion \( = m \times v = 3 \times 0 = 0\)
Total momentum after explosion \( = m_1 v_1 + m_2 v_2\)
So,
\(m_1 v_1 + m_2 v_2 = 0\)
Substitute the known values:
\( (2 \times 3) + (1 \times v_2) = 0\)
\(6 + v_2 = 0\)
Now, solve for \(v_2\):
\(v_2 = -6\) m/s
The velocity of the 1 kg mass will be -6 m/s. The negative sign indicates that it moves in the opposite direction to the 2 kg mass, which is expected in an explosion. This is a common effect observed when objects break apart.
In simple words: A 3 kg bomb, sitting still, breaks into two pieces. If the 2 kg piece flies off at 3 m/s, the 1 kg piece will fly off in the exact opposite direction at 6 m/s, keeping the total motion (momentum) balanced.

๐ŸŽฏ Exam Tip: For problems involving explosions or collisions where the initial momentum is zero, remember that the final momentum of all parts added together must also be zero. The parts will move in opposite directions to balance out.

 

Question 14. Two ice skaters of weight 60 kg and 50 kg are holding the two ends of a rope. The rope is taut. The 60 kg man pulls the rope with 20 N force. What will be the force exerted by the rope on the other person? What will be their respective acceleration?
Answer:
**Force exerted on the other person:**
According to Newton's Third Law of Motion, for every action, there is an equal and opposite reaction. If the 60 kg man pulls the rope with a 20 N force, then the rope will exert an equal and opposite force of 20 N on the 50 kg person. This fundamental law explains how forces always come in pairs.

**Respective acceleration:**
We use Newton's Second Law, \(F = ma\), to find the acceleration of each skater.
For the first skater (60 kg man):
Mass \(m_1 = 60\) kg
Force exerted on him by the rope \(F_1 = 20\) N (in the direction he is pulled)
Acceleration \(a_1 = \frac{F_1}{m_1} = \frac{20}{60} = \frac{1}{3} \approx 0.33\) ms\(^{-2}\)
So, the acceleration of the 60 kg man is approximately 0.33 ms\(^{-2}\).

For the second skater (50 kg person):
Mass \(m_2 = 50\) kg
Force exerted on her by the rope \(F_2 = 20\) N (in the direction she is pulled)
Acceleration \(a_2 = \frac{F_2}{m_2} = \frac{20}{50} = \frac{2}{5} = 0.4\) ms\(^{-2}\)
So, the acceleration of the 50 kg person is 0.4 ms\(^{-2}\).
The lighter person has a greater acceleration because the same force acts on a smaller mass.
In simple words: When a 60 kg person pulls a rope with 20 N force, the 50 kg person at the other end also feels a 20 N pull. This makes the 60 kg person speed up at 0.33 ms\(^{-2}\), and the lighter 50 kg person speed up faster at 0.4 ms\(^{-2}\).

๐ŸŽฏ Exam Tip: Clearly state Newton's Third Law for the force interaction, and then apply Newton's Second Law to each object separately, remembering that acceleration is inversely proportional to mass for a constant force.

 

VIII. Answer in detail.

 

Question 1. Explain the types of forces.
Answer: Forces can be classified based on the direction in which they act. There are two main types:
1. **Like parallel forces:** These are two or more forces that act along the same direction and are parallel to each other. They can be of equal or unequal strength. For example, if two people push a box from behind in the same direction, those are like parallel forces. These forces work together to move an object.
2. **Unlike parallel forces:** These are two or more forces that are parallel to each other but act in opposite directions. They can also be of equal or unequal strength. For example, if two people push a box from opposite sides, those are unlike parallel forces. These forces tend to oppose each other's effects. If they are equal, they might cancel out; if unequal, the object moves in the direction of the stronger force.
In simple words: Forces can push or pull in the same direction (like parallel forces) or in opposite directions (unlike parallel forces).

๐ŸŽฏ Exam Tip: Clearly define each type of force and provide a simple, easy-to-understand example for each to illustrate the concept.

 

Question 2. Tabulate the action of forces with their resultant and diagram.
Answer: Here is a table showing different types of force actions, their diagrams, and how to find the resultant force. The resultant force is the single force that produces the same effect as all the individual forces acting together.

Action of forcesDiagramResultant force (F\(_{net}\))
Parallel forces are acting in the same directionF\(_{1}\)F\(_{2}\)F\(_{net}\) = F\(_{1}\) + F\(_{2}\)
Parallel unequal forces are acting in opposite directionsF\(_{1}\)F\(_{2}\)F\(_{net}\) = F\(_{1}\) - F\(_{2}\) (if F\(_{1}\) > F\(_{2}\))
F\(_{net}\) = F\(_{2}\) - F\(_{1}\) (if F\(_{2}\) > F\(_{1}\))
F\(_{net}\) is directed along the greater force.
Parallel equal forces are acting in opposite directions in the same line of action (F\(_{1}\) = F\(_{2}\))F\(_{1}\)F\(_{2}\)F\(_{net}\) = F\(_{1}\) - F\(_{2}\) (F\(_{1}\) = F\(_{2}\))
F\(_{net}\) = 0

In simple words: This table shows how forces combine. If forces push in the same direction, they add up. If they push in opposite directions, they subtract. If equal and opposite, they cancel out completely.

๐ŸŽฏ Exam Tip: When drawing diagrams for forces, use arrows to indicate direction and length to represent magnitude. Always label your forces clearly (F\(_{1}\), F\(_{2}\), etc.).

 

Question 3. Explain the applications of torque.
Answer: Torque is a twisting force that causes rotation. It is used in many everyday machines and tools. Here are some examples of where torque is applied:
1. **Gears:** Gears are wheels with teeth that fit together. They are used to change how fast a wheel spins by adjusting the torque. They also help to transfer power from one part of a machine to another, like in a bicycle or a car gearbox. Gears allow us to control speed and power effectively.
2. **Seesaw:** On a seesaw, a heavier person can lift a lighter person if the heavier person sits closer to the middle pivot point. This is because bringing them closer reduces the distance from the pivot, thus changing the torque. The lighter person can then be lifted more easily because the torque from the heavier person is balanced by the torque from the lighter person, allowing them to balance the twisting forces.
3. **Steering Wheel:** A small steering wheel in a car makes it easy to turn the car. When you turn the steering wheel, you apply a force at its rim, creating torque. This torque is then transferred to the car's wheels, making them turn with less effort. This mechanical advantage helps drivers control large vehicles with ease.
In simple words: Torque is a turning force. It's used in gears to change how fast things spin, in seesaws to balance weights, and in steering wheels to turn a car easily.

๐ŸŽฏ Exam Tip: When explaining applications of torque, focus on how the force is applied and how the distance from the pivot point (or axis of rotation) affects the turning effect.

 

Question 4. State and explain principle of moments.
Answer:
**Principle of Moments:**
The principle of moments states that if a rigid body is balanced (in equilibrium) and many forces are acting on it, then the total turning effect (or moment) in the clockwise direction is equal to the total turning effect in the anticlockwise direction. In simpler words, for an object to be perfectly balanced, all the forces trying to turn it one way must be exactly equal to all the forces trying to turn it the other way.

**Explanation:**
Consider a bar balanced at a pivot point (fulcrum). If forces F\(_{1}\) and F\(_{2}\) are applied at distances d\(_{1}\) and d\(_{2}\) from the pivot, as shown in the diagram: The force F\(_{1}\) creates a turning effect (moment) that tries to rotate the bar in the anticlockwise direction. This moment is \(M_1 = F_1 \times d_1\). The force F\(_{2}\) creates a turning effect (moment) that tries to rotate the bar in the clockwise direction. This moment is \(M_2 = F_2 \times d_2\). For the bar to be in equilibrium (balanced and not rotating), the anticlockwise moment must be equal to the clockwise moment.
So, according to the principle of moments:
Moment of clockwise direction = Moment of anticlockwise direction
\(F_1 \times d_1 = F_2 \times d_2\)
This principle is widely used in levers, beams, and other systems where balancing turning effects is crucial. It ensures stability and proper functioning of mechanical systems.
In simple words: The principle of moments means that for an object to be balanced, the total turning force in one direction must be equal to the total turning force in the opposite direction.

P F\(_{1}\) d\(_{1}\) F\(_{2}\) d\(_{2}\) anticlockwise moment clockwise moment

๐ŸŽฏ Exam Tip: Always define "moment" (Force x Perpendicular Distance) before explaining the principle. Clearly label your diagram to show forces, distances, and the pivot point.

 

Question 5. Explain the illustrations for Newton's third law of motion briefly.
Answer: Newton's third law of motion states that for every action, there is an equal and opposite reaction. This means that whenever one object pushes or pulls on another, the second object pushes or pulls back with the same strength but in the opposite direction. These forces always act on two different bodies. Here are some examples:
(i) **Birds flying:** When a bird flies, it pushes the air downwards with its wings (this is the action force). In return, the air pushes the bird upwards with an equal force (this is the reaction force). This upward push from the air is what keeps the bird flying in the sky.
(ii) **Swimming:** When a person swims, they push the water backwards with their hands and feet (this is the action force). The water then pushes the swimmer forwards with an equal and opposite force (this is the reaction force). This forward push helps the swimmer move through the water.
(iii) **Firing a gun:** When a gun is fired, it pushes the bullet forward with a strong force (this is the action force). At the same time, the bullet pushes the gun backwards with an equal force (this is the reaction force), causing the gun to "recoil" or kick back. This is why a shooter feels a push when a gun is fired. These simple examples help us understand how forces always work in pairs in the natural world.
In simple words: Newton's third law says that for every push or pull, there's an equal and opposite push or pull. Like a bird pushing air down and the air pushing the bird up, or a gun pushing a bullet forward and the bullet pushing the gun backward.

๐ŸŽฏ Exam Tip: When providing illustrations for Newton's third law, make sure to clearly identify both the "action" and "reaction" forces and specify which body each force acts upon.

 

Question 6. Derive the relation between acceleration due to gravity (g) and Gravitational constant G.
Answer: We can derive the relationship between the acceleration due to gravity (\(g\)) and the universal gravitational constant (\(G\)) by considering an object on the surface of the Earth. This derivation combines Newton's laws of motion and gravitation.
Assume a body of mass \(m\) is on the surface of the Earth. The Earth has a mass \(M\) and a radius \(R\). The entire mass of the Earth can be considered to be concentrated at its center for this calculation.

**1. Gravitational Force (F\(_{g}\))**
According to Newton's Law of Universal Gravitation, the force of attraction between the Earth (mass \(M\)) and the body (mass \(m\)) on its surface is given by:
\(F_g = \frac{GMm}{R^2}\)
Here, \(R\) is the distance between the center of the Earth and the center of the body. Since the body is on the surface, this distance is approximately the radius of the Earth itself.

**2. Force due to Gravity (Weight)**
According to Newton's Second Law of Motion, the force acting on an object is equal to its mass times its acceleration. When a body falls freely near the Earth's surface, the acceleration it experiences is the acceleration due to gravity (\(g\)). This force is also known as the weight of the object.
\(F = ma\)
So, the force acting on the body due to Earth's gravity (its weight) is:
\(F = mg\)

**3. Relating the two expressions**
Since both expressions represent the same force (the gravitational force acting on the object), we can set them equal to each other:
\(mg = \frac{GMm}{R^2}\)
We can cancel out the mass of the small body (\(m\)) from both sides of the equation:
\(g = \frac{GM}{R^2}\)
This is the relation between the acceleration due to gravity (\(g\)) and the universal gravitational constant (\(G\)). This formula shows that the acceleration due to gravity depends only on the mass and radius of the planet, not on the mass of the object falling. This means a feather and a stone fall with the same acceleration (in a vacuum).
In simple words: We can find out how fast things fall to Earth (g) by comparing the Earth's pull (gravity formula) with how force makes things move (F=ma). Both calculations lead to the formula \(g = \frac{GM}{R^2}\), showing that gravity's pull depends on the planet's size and mass.

M Earth m Object F R

๐ŸŽฏ Exam Tip: Clearly show the steps by first writing the gravitational force formula, then the \(F=ma\) (weight) formula, and finally equating them to derive \(g = \frac{GM}{R^2}\). Remember to state that \(m\) cancels out.

 

Question 7. Tabulate the apparent weight of person moving in a lift when lift is
(i) moving upwards
(ii) moving downwards
(iii) at rest
(iv) falling down freely.

Answer: The apparent weight of a person in a lift changes depending on the lift's acceleration. This table summarizes how your weight feels in different lift situations.

CaseConditionsAcceleration (\(a\))Apparent Weight (R) FormulaApparent Weight (R) compared to Actual Weight (W)
1Lift moving upward with an acceleration '\(a\)'\(a\) is positive (upwards)\(R = m(g+a)\)\(R > W\)
Apparent weight is greater than the actual weight.
2Lift moving downward with an acceleration '\(a\)'\(a\) is negative (downwards)\(R = m(g-a)\)\(R < W\)
Apparent weight is less than the actual weight.
3Lift is at rest or moving with uniform velocity\(a = 0\)\(R = mg\)\(R = W\)
Apparent weight is equal to the actual weight.
4Lift is falling down freely\(a = g\)\(R = m(g-g) = 0\)\(R = 0\)
Apparent weight is equal to zero.

In simple words: Your weight feels heavier when a lift goes up fast, lighter when it goes down fast, normal when it's still or moving steadily, and zero if it's falling freely.

๐ŸŽฏ Exam Tip: Remember the basic formula \(R = m(g \pm a)\). Use \(+a\) for upward acceleration and \(-a\) for downward acceleration. For uniform velocity or rest, \(a=0\).

 

IX. HOT Questions

 

Question 1. What gives the measure of inertia?
Answer: The mass of an object is what gives the measure of its inertia. Inertia is the natural tendency of an object to resist changes in its state of motion. A heavier object has more inertia, meaning it is harder to start moving, stop moving, or change its direction. For example, it is much harder to push a heavy car than a light bicycle. This is because the car has more mass, and thus more inertia.
In simple words: An object's mass tells us how much inertia it has; more mass means more inertia, making it harder to change its movement.

๐ŸŽฏ Exam Tip: Always associate mass directly with inertia. The greater the mass, the greater the inertia, and the more resistance there is to changes in motion.

 

Question 2. Is any external force required to keep a body in uniform motion?
Answer: No, according to Newton's First Law of Motion (the law of inertia), an external force is not required to keep a body in uniform motion. An object in uniform motion (moving at a constant velocity in a straight line) will continue to do so unless an unbalanced external force acts upon it. This means that if there's no friction or air resistance, a ball rolling on a flat surface would just keep rolling forever without any extra pushes. In reality, we apply force to overcome friction and maintain uniform motion.
In simple words: No, if there's no friction or air stopping it, an object will keep moving at the same speed by itself without needing any more pushes.

๐ŸŽฏ Exam Tip: Referencing Newton's First Law (Law of Inertia) is key here. Emphasize that force is only needed to *change* motion, not to *maintain* uniform motion.

 

Question 3. Which law of motion gives the measure of force?
Answer: Newton's Second Law of Motion gives the measure of force. This law states that the force acting on an object is equal to the product of its mass and acceleration (\(F = ma\)). It provides a quantitative way to calculate force, explaining how a force causes an object to speed up or slow down. For example, if you push a toy car, the harder you push (more force), the faster it speeds up (more acceleration). This law is central to understanding dynamics.
In simple words: Newton's Second Law, which says that force equals mass times acceleration (\(F = ma\)), is used to measure force.

๐ŸŽฏ Exam Tip: Always remember the formula \(F=ma\) and specify "Newton's Second Law of Motion" when asked about the measure of force.

 

Question 4. Write the second law of motion in vector form.
Answer: Newton's Second Law of Motion states that the net force acting on an object is equal to the rate of change of its linear momentum. In vector form, this law is expressed as:
\( \vec{F} = m \vec{a} \)
Where:
\( \vec{F} \) is the net force vector acting on the object.
\( m \) is the mass of the object (a scalar quantity).
\( \vec{a} \) is the acceleration vector of the object.
This vector notation means that the force and acceleration have the same direction. It is a powerful way to represent how forces cause changes in motion in a specific direction.
In simple words: Newton's second law, in its vector form, simply says that the push or pull (\( \vec{F} \)) on an object is equal to its mass (\(m\)) times how fast its speed and direction change (\( \vec{a} \)). The arrows show that force and acceleration point in the same direction.

๐ŸŽฏ Exam Tip: Ensure you use vector notation (\( \vec{} \)) for force and acceleration and understand that mass is a scalar. The direction of the net force is always the same as the direction of the acceleration.

 

Question 5. What is the net force acting on a cork that floats on water? Why?
Answer: The net force acting on a cork that floats on water is zero. This is because the weight of the cork (gravitational force pulling it downwards) is exactly balanced by the upthrust force from the water (buoyant force pushing it upwards). When these two forces are equal in magnitude and opposite in direction, they cancel each other out, resulting in a zero net force. Since there is no net force, the cork remains at rest, floating on the surface of the water, which is an example of equilibrium.
In simple words: The total force on a floating cork is zero because the water pushes it up with the same strength that gravity pulls it down, keeping it still.

๐ŸŽฏ Exam Tip: For floating objects, remember that the upthrust (buoyant force) exactly equals the object's weight, leading to zero net force and equilibrium.

 

Question 6. What is the relation between newton and dyne?
Answer: The newton (N) and dyne are both units of force, but they belong to different systems of units. The newton is the SI unit of force, while the dyne is the unit of force in the CGS (centimeter-gram-second) system. The relationship between them is that one newton is equal to 100,000 dynes.
\(1 \text{ newton (N)} = 10^5 \text{ dynes}\)
This means that a newton is a much larger unit of force than a dyne. This conversion is useful when working with different measurement systems in physics.
In simple words: A newton is a unit of force, and one newton is equal to 100,000 dynes.

๐ŸŽฏ Exam Tip: Clearly state that Newton is an SI unit and dyne is a CGS unit. Remember the conversion factor: \(1 \text{ N} = 10^5 \text{ dynes}\).

 

Question 7. A person is standing on a weighing machine placed nearly a door. What will be the effect of the reading of the machine if a person presses the edge of the door upward?
Answer: If a person standing on a weighing machine presses the edge of the door upward, the reading of the machine will increase. When the person pushes the door upward, according to Newton's Third Law, the door pushes back on the person downward with an equal and opposite force. This additional downward force from the door adds to the person's actual weight, making the weighing machine show a higher reading. This is similar to someone standing on a scale and pressing down on the counter - the scale reading increases.
In simple words: If someone on a weighing machine pushes a door upwards, the door pushes back downwards. This extra downward push adds to their weight, making the machine show a higher reading.

๐ŸŽฏ Exam Tip: Apply Newton's Third Law: the upward action force on the door results in an equal and opposite downward reaction force on the person, increasing the apparent weight.

 

Question 8. A bomb explode in mid-air into two equal fragments. What is the relation between the direction of motion of the two fragments?
Answer: When a bomb explodes in mid-air into two equal fragments, the two fragments will fly off in exactly opposite directions. This is due to the principle of conservation of linear momentum. Since the bomb was initially at rest (or moving with a certain momentum) and exploded into two equal masses, the total momentum of the system must remain the same. To conserve momentum, if one fragment moves in one direction, the other fragment, being of equal mass, must move in the opposite direction with the same speed. This ensures the net change in momentum is zero, or maintains the original momentum if the bomb was already moving. This shows how forces internally within the bomb cause equal and opposite effects on its parts.
In simple words: If a bomb breaks into two equal parts while in the air, the pieces will fly away in exactly opposite directions to keep the total motion balanced.

๐ŸŽฏ Exam Tip: Emphasize the principle of conservation of linear momentum. For equal fragments from an explosion, they will have equal speeds in opposite directions.

 

Question 9. Which law explains the following situation, Athlete runs a certain distance before long jump.
Answer: This situation is best explained by the Law of Inertia, which is Newton's First Law of Motion. By running a certain distance before a long jump, the athlete builds up forward momentum. This momentum, due to inertia of motion, helps the athlete to travel a greater horizontal distance in the air. Their body naturally resists changing its state of motion (moving forward), allowing them to cover more ground even after leaving the earth. This initial velocity adds to the overall distance of the jump.
In simple words: An athlete runs before a long jump because of the Law of Inertia (Newton's First Law). Running helps them build up speed, and their body's tendency to keep moving forward helps them jump farther.

๐ŸŽฏ Exam Tip: Clearly link the athlete's action of running to building momentum and how inertia helps maintain that motion, leading to a longer jump.

 

Question 10. Is impulse a scalar?
Answer: No, impulse is not a scalar quantity; it is a vector quantity. Impulse is defined as the product of force and the time interval over which the force acts, and it is also equal to the change in momentum. Since force and momentum are both vector quantities (they have both magnitude and direction), impulse also has both magnitude and direction. For example, hitting a baseball with a bat imparts an impulse in a specific direction. This means that if you hit a ball, not only does its speed change, but also its direction. Hence, impulse is a vector.
In simple words: No, impulse is a vector because it has both a size (how strong the push or pull is and how long it lasts) and a direction.

๐ŸŽฏ Exam Tip: Remember that if force and momentum are vectors, then impulse, which is directly related to them, must also be a vector.

 

Question 11. When a lift moves with uniform velocity, what is its
(i) acceleration and
(ii) the apparent weight of the person standing inside the lift.

Answer:
(i) When a lift moves with uniform velocity, its acceleration is zero. Uniform velocity means the speed and direction are constant, so there is no change in velocity over time. This lack of change means zero acceleration.
(ii) The apparent weight of a person standing inside the lift is equal to their true weight. Since the acceleration is zero, the net force on the person is also zero. This means the normal force from the lift floor (apparent weight) is exactly equal to the person's actual weight. So, if you were on a scale in such a lift, it would show your normal weight.
In simple words: If a lift moves at a steady speed, it has no acceleration. In this case, a person inside the lift feels their normal weight.

๐ŸŽฏ Exam Tip: Uniform velocity always implies zero acceleration. When acceleration is zero, the apparent weight is equal to the actual weight (\(R=mg\)).

 

Question 12. When a lift falls freely, what happens to the apparent weight of a body in the lift.
Answer: When a lift falls freely, the apparent weight of a body in the lift becomes equal to zero. This is because in free fall, the lift (and everything inside it) is accelerating downwards at the same rate as gravity (\(a=g\)). In this situation, the normal force (the support force from the floor of the lift) acting on the person becomes zero. The formula for apparent weight in a lift moving downwards is \(R = m(g-a)\). If \(a=g\), then \(R = m(g-g) = 0\). This sensation is commonly called "weightlessness," as you feel no support from the surface you are standing on. It's like astronauts in space who are continuously falling around Earth.
In simple words: When a lift falls freely, you feel weightless because both you and the lift are falling at the same speed, so the floor doesn't push up on you.

๐ŸŽฏ Exam Tip: Understand that "free fall" means \(a=g\). Substituting this into the apparent weight formula \(R = m(g-a)\) directly shows that apparent weight becomes zero.

 

Question 13. When a body falls freely, it appears to have zero weight. Give reason.
Answer: When a body falls freely, it appears to have zero weight because it is acting under the action of gravitational force alone, with no other supporting force. In free fall, the body and its container (like a lift) both accelerate downwards at the same rate as gravity (\(g\)). There is no normal force pushing up on the body from the supporting surface (like a floor or scale). Since apparent weight is measured by this normal force, if there's no upward push, the apparent weight is zero. This experience is often described as weightlessness, where the body does not press against any supporting surface. This happens because all objects fall at the same rate regardless of their mass in a vacuum.
In simple words: A body falling freely feels like it has no weight because gravity is the only force acting on it, and there's no surface to push back and make it feel heavy.

๐ŸŽฏ Exam Tip: Focus on the absence of a normal (support) force during free fall as the reason for perceived weightlessness, rather than the absence of gravity itself.

There are no questions located between page 85 and page 86 in the provided content. The specified pages contain only introductory text, page metadata, and navigation elements.

TN Board Solutions Class 10 Science Chapter 01 Laws of Motion

Students can now access the TN Board Solutions for Chapter 01 Laws of Motion prepared by teachers on our website. These solutions cover all questions in exercise in your Class 10 Science textbook. Each answer is updated based on the current academic session as per the latest TN Board syllabus.

Detailed Explanations for Chapter 01 Laws of Motion

Our expert teachers have provided step-by-step explanations for all the difficult questions in the Class 10 Science chapter. Along with the final answers, we have also explained the concept behind it to help you build stronger understanding of each topic. This will be really helpful for Class 10 students who want to understand both theoretical and practical questions. By studying these TN Board Questions and Answers your basic concepts will improve a lot.

Benefits of using Science Class 10 Solved Papers

Using our Science solutions regularly students will be able to improve their logical thinking and problem-solving speed. These Class 10 solutions are a guide for self-study and homework assistance. Along with the chapter-wise solutions, you should also refer to our Revision Notes and Sample Papers for Chapter 01 Laws of Motion to get a complete preparation experience.

FAQs

Where can I find the latest Samacheer Kalvi Class 10 Science Solutions Chapter 1 Laws of Motion for the 2026-27 session?

The complete and updated Samacheer Kalvi Class 10 Science Solutions Chapter 1 Laws of Motion is available for free on StudiesToday.com. These solutions for Class 10 Science are as per latest TN Board curriculum.

Are the Science TN Board solutions for Class 10 updated for the new 50% competency-based exam pattern?

Yes, our experts have revised the Samacheer Kalvi Class 10 Science Solutions Chapter 1 Laws of Motion as per 2026 exam pattern. All textbook exercises have been solved and have added explanation about how the Science concepts are applied in case-study and assertion-reasoning questions.

How do these Class 10 TN Board solutions help in scoring 90% plus marks?

Toppers recommend using TN Board language because TN Board marking schemes are strictly based on textbook definitions. Our Samacheer Kalvi Class 10 Science Solutions Chapter 1 Laws of Motion will help students to get full marks in the theory paper.

Do you offer Samacheer Kalvi Class 10 Science Solutions Chapter 1 Laws of Motion in multiple languages like Hindi and English?

Yes, we provide bilingual support for Class 10 Science. You can access Samacheer Kalvi Class 10 Science Solutions Chapter 1 Laws of Motion in both English and Hindi medium.

Is it possible to download the Science TN Board solutions for Class 10 as a PDF?

Yes, you can download the entire Samacheer Kalvi Class 10 Science Solutions Chapter 1 Laws of Motion in printable PDF format for offline study on any device.