Get the most accurate RBSE Solutions for Class 6 Mathematics Chapter 4 Negative Numbers and Integers here. Updated for the 2026-27 academic session, these solutions are based on the latest RBSE textbooks for Class 6 Mathematics. Our expert-created answers for Class 6 Mathematics are available for free download in PDF format.
Detailed Chapter 4 Negative Numbers and Integers RBSE Solutions for Class 6 Mathematics
For Class 6 students, solving RBSE textbook questions is the most effective way to build a strong conceptual foundation. Our Class 6 Mathematics solutions follow a detailed, step-by-step approach to ensure you understand the logic behind every answer. Practicing these Chapter 4 Negative Numbers and Integers solutions will improve your exam performance.
Class 6 Mathematics Chapter 4 Negative Numbers and Integers RBSE Solutions PDF
Question 1. Subtract the following.
(i) \( + 32 - (+12) \)
(ii) \( + 7 - (+15) \)
(iii) \( (-14) - (-20) \)
(iv) \( (-30) - (-15) \)
(v) \( 23 - (-10) \)
(vi) \( (-27) - 22 \)
Answer:
(i) \( + 32 - (+12) = 32 - 12 = 20 \)
(ii) \( + 7 - (+15) = 7 - 15 = -8 \)
(iii) \( (-14) - (-20) = -14 + 20 = 6 \)
(iv) \( (-30) - (-15) = -30 + 15 = -15 \)
(v) \( 23 - (-10) = 23 + 10 = 33 \)
(vi) \( (-27) - 22 = -27 - 22 = -49 \) When subtracting a negative number, it is the same as adding the positive version of that number.
In simple words: For each problem, change the subtraction of a positive number to adding a negative number, or change the subtraction of a negative number to adding a positive number, then do the math.
🎯 Exam Tip: Remember that subtracting a positive number is like moving left on the number line, while subtracting a negative number is like moving right.
Question 2. Fill in the blanks.
(i) \( -5 + \text{____} = 0 \)
(ii) \( 7 + \text{____} = 0 \)
(iii) \( 11 + (-11) = \text{____} \)
(iv) \( (-3) + \text{____} = -7 \)
(v) \( 14 - \text{____} = 16 \)
(vi) \( (-4) + \text{____} = -8 \)
Answer:
(i) \( -5 + 5 = 0 \) The number that makes an equation equal to zero when added is called the additive inverse.
(ii) \( 7 + (-7) = 0 \)
(iii) \( 11 + (-11) = 0 \)
(iv) \( (-3) + (-4) = -7 \)
(v) \( 14 - (-2) = 16 \)
(vi) \( (-4) + (-4) = -8 \)
In simple words: Find the number that completes each math sentence. For example, to get zero, you need to add the opposite number.
🎯 Exam Tip: For fill-in-the-blank questions involving integers, think about what number would balance the equation to make it true.
Question 3. Fill in the blanks with the sign >, < or =
(i) \( (-2) + (-9) \text{...............} (-2) + (-4) \)
(ii) \( (-21) + (-10) \text{...........} (-10) + (-21) \)
(iii) \( 45 - (-12) \text{...............} (-12) + 45 \)
(iv) \( (-14) + (14) \text{............} (-7) + (1) \)
Answer:
(i) First, calculate both sides:
\( (-2) + (-9) = -2 - 9 = -11 \)
\( (-2) + (-4) = -2 - 4 = -6 \)
Since \( -11 \) is less than \( -6 \) (it is further left on the number line), the sign is \( < \).
\( (-2) + (-9) < (-2) + (-4) \)
(ii) First, calculate both sides:
\( (-21) + (-10) = -21 - 10 = -31 \)
\( (-10) + (-21) = -10 - 21 = -31 \)
Since both sides are equal, the sign is \( = \).
\( (-21) + (-10) = (-10) + (-21) \)
(iii) First, calculate both sides:
\( 45 - (-12) = 45 + 12 = 57 \)
\( (-12) + 45 = 33 \)
Since \( 57 \) is greater than \( 33 \), the sign is \( > \).
\( 45 - (-12) > (-12) + 45 \)
(iv) First, calculate both sides:
\( (-14) + (14) = 0 \)
\( (-7) + (1) = -6 \) Comparing numbers is easier after performing the operations on both sides.
Since \( 0 \) is greater than \( -6 \) (it is further right on the number line), the sign is \( > \).
\( (-14) + (14) > (-7) + (1) \)
In simple words: Solve each side of the blank separately. Then, compare the two answers to see if the first is greater than, less than, or equal to the second.
🎯 Exam Tip: Always solve both sides of the expression completely before deciding which comparison sign (>, <, or =) to use.
Question 4. Find the value of the following.
(i) \( (-7) + (-4) + 11 \)
(ii) \( (-12) + (-3) - (-4) \)
(iii) \( 14 - 8 - (-2) \)
(iv) \( (-24) + (-12) - (-8) \)
Answer:
(i) We need to find the sum of \( (-7) \), \( (-4) \), and \( 11 \).
First, add the negative numbers:
\( (-7) + (-4) = -11 \)
Then add \( 11 \) to the result:
\( -11 + 11 = 0 \)
So the value is \( 0 \).
(ii) We need to find the value of \( (-12) + (-3) - (-4) \).
First, combine the additions and subtractions:
\( (-12) + (-3) - (-4) \)
\( = -12 - 3 + 4 \)
\( = -15 + 4 \)
\( = -11 \)
So the value is \( -11 \).
(iii) We need to find the value of \( 14 - 8 - (-2) \).
First, perform the subtraction from left to right:
\( 14 - 8 = 6 \)
Then subtract the negative number:
\( 6 - (-2) = 6 + 2 = 8 \)
So the value is \( 8 \).
(iv) We need to find the value of \( (-24) + (-12) - (-8) \).
First, add the negative numbers:
\( (-24) + (-12) = -36 \)
Then subtract the negative number: Remember that subtracting a negative number is the same as adding its positive counterpart.
\( -36 - (-8) = -36 + 8 = -28 \)
So the value is \( -28 \).
In simple words: Calculate each expression by following the rules for adding and subtracting positive and negative numbers. Remember that subtracting a negative number changes to adding a positive number.
🎯 Exam Tip: When solving expressions with multiple operations, combine numbers with the same sign first, then perform the remaining additions and subtractions carefully. Pay close attention to the rules of signs.
Free study material for Mathematics
RBSE Solutions Class 6 Mathematics Chapter 4 Negative Numbers and Integers
Students can now access the RBSE Solutions for Chapter 4 Negative Numbers and Integers prepared by teachers on our website. These solutions cover all questions in exercise in your Class 6 Mathematics textbook. Each answer is updated based on the current academic session as per the latest RBSE syllabus.
Detailed Explanations for Chapter 4 Negative Numbers and Integers
Our expert teachers have provided step-by-step explanations for all the difficult questions in the Class 6 Mathematics chapter. Along with the final answers, we have also explained the concept behind it to help you build stronger understanding of each topic. This will be really helpful for Class 6 students who want to understand both theoretical and practical questions. By studying these RBSE Questions and Answers your basic concepts will improve a lot.
Benefits of using Mathematics Class 6 Solved Papers
Using our Mathematics solutions regularly students will be able to improve their logical thinking and problem-solving speed. These Class 6 solutions are a guide for self-study and homework assistance. Along with the chapter-wise solutions, you should also refer to our Revision Notes and Sample Papers for Chapter 4 Negative Numbers and Integers to get a complete preparation experience.
FAQs
The complete and updated RBSE Solutions Class 6 Maths Chapter 4 Negative Numbers and Integers Exercise 4.3 is available for free on StudiesToday.com. These solutions for Class 6 Mathematics are as per latest RBSE curriculum.
Yes, our experts have revised the RBSE Solutions Class 6 Maths Chapter 4 Negative Numbers and Integers Exercise 4.3 as per 2026 exam pattern. All textbook exercises have been solved and have added explanation about how the Mathematics concepts are applied in case-study and assertion-reasoning questions.
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