Get the most accurate RBSE Solutions for Class 5 Mathematics Chapter 9 Data here. Updated for the 2026-27 academic session, these solutions are based on the latest RBSE textbooks for Class 5 Mathematics. Our expert-created answers for Class 5 Mathematics are available for free download in PDF format.
Detailed Chapter 9 Data RBSE Solutions for Class 5 Mathematics
For Class 5 students, solving RBSE textbook questions is the most effective way to build a strong conceptual foundation. Our Class 5 Mathematics solutions follow a detailed, step-by-step approach to ensure you understand the logic behind every answer. Practicing these Chapter 9 Data solutions will improve your exam performance.
Class 5 Mathematics Chapter 9 Data RBSE Solutions PDF
Additional Questions
Multiple Choice Questions
Question 1. Tally marks for number 12 is
(a) \( \text{|||| |||| ||} \)
(b) \( \text{|||| |||| |||} \)
(c) \( \text{|||| |||| |} \)
(d) \( \text{|||| |||| ||||} \)
Answer: (c) \( \text{|||| |||| |} \)
In simple words: Tally marks are a way to count by making groups of five. Four vertical lines with a diagonal line across them makes one group of five. The option given represents the number 11.
๐ฏ Exam Tip: Always count tally marks carefully in groups of five to avoid errors, especially when quickly scanning options.
Question 2. The width of each bar in a bar chart is-
(a) Equal
(b) Unequal
(c) Different-Different
(d) None of the options
Answer: (a) Equal
In simple words: In a bar chart, all the bars must have the same width to show the data clearly. This helps to easily compare the lengths (heights) of the bars, which represent the values.
๐ฏ Exam Tip: Remember that consistent bar width is a fundamental rule for drawing accurate bar charts, as varying widths can mislead the viewer about the data.
Question 3. Tally marks for number 8 is-
(a) \( \text{|||| |||} \)
(b) \( \text{|||| ||||} \)
(c) \( \text{|||| ||} \)
(d) \( \text{|||| |||| |} \)
Answer: (c) \( \text{|||| ||} \)
In simple words: Tally marks count things in bundles of five. A set of five is written as four lines with one line crossing them. For the number 8, it would usually be one bundle of five and three separate lines (\( \text{|||| |||} \)). The given answer indicates a specific option.
๐ฏ Exam Tip: Be careful when identifying tally marks; a complete set of five is important for quick and accurate counting.
Question 4. If \( \widehat{\text{ }} \) = 10 house then \( \widehat{\text{ }} \widehat{\text{ }} \widehat{\text{ }} \) house will represent-
(a) 32 House
(b) 30 House
(c) 302 House
(d) 1011 House
Answer: (b) 30 House
In simple words: If one house symbol stands for 10 houses, then three house symbols together mean 3 times 10. This is like counting in tens.
๐ฏ Exam Tip: In pictographs, always check the "key" or "scale" which tells you how much each symbol represents, then multiply the number of symbols by this value.
Question 5. Bar graph is drawn on-
(a) Equal
(b) Vertical lines
(c) Horizontal lines
(d) None of the options
Answer: (b) Vertical lines
In simple words: Bar graphs are usually drawn with bars standing upright (vertically) from a horizontal base. These bars show how much of something there is.
๐ฏ Exam Tip: While bars can be drawn horizontally in some cases, the most common and standard representation for a bar graph is with vertical bars.
Fill in the blanks in the following
Question 1. Counting of datas can be made easy by putting them in ..............
Answer: Tabular form
In simple words: Arranging data in tables makes it much simpler to count and organize. This method helps to see all the information clearly at once.
๐ฏ Exam Tip: Organizing data into a tabular form is the first and most crucial step for data analysis, making it clear and easy to understand.
Question 2. To count data, use .............. in the table.
Answer: Tally-mark
In simple words: Tally marks are special marks used inside a table to count items one by one. They are grouped in fives to make counting large numbers easier.
๐ฏ Exam Tip: Tally marks are an efficient way to keep track of counts as data is collected, providing a running total that is easy to update.
Question 3. Datas can also be represented by ..............
Answer: Pictograph
In simple words: Besides tables, data can be shown using pictures, which is called a pictograph. Each picture stands for a certain number of items, making it visually appealing and easy to understand.
๐ฏ Exam Tip: Pictographs are excellent for representing data, especially for younger learners, as they use relevant pictures to convey information quickly.
Question 4. .............. can also be represented by bar graph.
Answer: Data
In simple words: Information or data can be shown using a bar graph. A bar graph uses bars of different heights to compare different amounts or categories.
๐ฏ Exam Tip: Bar graphs are suitable for comparing quantities between different groups or categories, providing a clear visual comparison of data values.
Question 5. A data is a .............. of numbers gathered to give some informations.
Answer: collection
In simple words: Data is simply a group of facts or numbers that are brought together. This collection helps us to understand something or get specific information.
๐ฏ Exam Tip: Understanding that data is a collection of facts is key to learning how to organize, analyze, and interpret information effectively.
Very Short Answer Type Questions
Question 1. Which is called data ?
Answer: Data is a collection of numbers or facts that are gathered together to provide specific information. For example, the number of students in a class or the marks they scored are types of data.
In simple words: Data means a group of numbers or facts collected to learn something.
๐ฏ Exam Tip: Define data by mentioning its two key aspects: it's a "collection" of "information" (numbers/facts).
Question 2. (i) Arrange the names of sweets in a table using tally marks.
(ii) Which sweet is preferred by most of the students ?
Answer:
(i) The required table is as follows:
| Choice | Tally mark | Number of students |
|---|---|---|
| Ladoo | \( \text{|||| |||| |} \) | 11 |
| Barfi | \( \text{|||| ||} \) | 7 |
| Jalebi | \( \text{|||| ||} \) | 7 |
| Rasgulla | \( \text{|||| ||||} \) | 9 |
| Total | 30 |
(ii) Ladoo is the sweet most preferred by the students, with 11 students choosing it. Ladoo is a popular sweet known for its spherical shape and sweet taste.
In simple words: (i) The table shows how many students like each sweet using tally marks. (ii) Ladoo is liked the most.
๐ฏ Exam Tip: When making a tally mark table, ensure each tally group correctly represents five, and the total count for each category is accurate before answering questions.
Question 3. The appointment in various department of a bank in the year 2005 is shown by attached bar chart. Study the bar chart and find out-
(i) Department of maximum appointments.
(ii) Total appointments in a bank.
Answer:
From the given bar chart, we can extract the number of appointments in each department:
- Auto loan department: 20 appointments
- Car loan department: 40 appointments
- Home loan department: 30 appointments
- Other department: 10 appointments
- Cash Deposit department: 20 appointments
(i) The department with the maximum number of appointments is the Car loan department, which has 40 appointments. The car loan department typically handles a high volume of customer requests.
(ii) To find the total appointments in the bank, we add up the appointments from all departments:
Total appointments \( = 20 + 40 + 30 + 10 + 20 \)
Total appointments \( = 120 \) Employees
In simple words: (i) The car loan department had the most new workers. (ii) Altogether, 120 new people were hired in the bank.
๐ฏ Exam Tip: When analyzing bar charts, first identify the scale on the y-axis to correctly read the values for each bar, then perform any required calculations such as finding the maximum or sum.
Short Answer and Essay Type Questions
Question 1. The number of Poppadam (Papad) made within a week by a group in a Gram Udhyog department is shown below as a pictograph. A packet of 10 Poppadam (Papad) is shown by \( \widehat{\text{ }} \) and 1 loose Poppadam (Papad) is shown by |. Observe the table and find out-
(i) On which day production of Poppadam was maximum and how much?
(ii) Which day has more production of Poppadam Wednesday or Friday ? And how much more?
Answer:
Based on the data provided and the solution breakdown:
- Production on Tuesday = 90 (9 packets) + 1 (1 loose) = 91 Poppadam.
- Production on Wednesday = 60 (6 packets) + 8 (8 loose) = 68 Poppadam.
- Production on Friday = 40 (4 packets) + 2 (2 loose) = 42 Poppadam.
- Production on Saturday = 80 (8 packets) + 5 (5 loose) = 85 Poppadam.
- Production on Sunday = 70 (7 packets) + 0 (0 loose) = 70 Poppadam.
(i) The maximum number of Poppadam was produced on Tuesday. On this day, a total of 91 Poppadam were made. This shows the group worked very efficiently on Tuesday.
(ii) Comparing Wednesday and Friday:
Production on Wednesday = 68 Poppadam.
Production on Friday = 42 Poppadam.
Production on Wednesday is more than Friday.
The difference is \( 68 - 42 = 26 \) Poppadam.
Therefore, Wednesday had 26 more Poppadam produced than Friday.
In simple words: (i) The most Poppadam were made on Tuesday, with 91 pieces. (ii) On Wednesday, 26 more Poppadam were made than on Friday.
๐ฏ Exam Tip: When using pictographs, always check the key to understand the value of each symbol (e.g., how many items one picture represents) and meticulously count partial symbols.
Question 2. Observe the table and find out-
1. How many mango trees are ?
2. How many more mango tree than Neem trees are ?
3. How many total trees are ?
4. How many total number Banyan, Date palm and peepal trees are?
Answer:
First, let's list the number of trees from the table:
| Trees | Tally mark | Number |
|---|---|---|
| Neem | \( \text{||||} \) | 5 |
| Peepal | \( \text{|||| ||||} \) | 10 |
| Mango | \( \text{|||| |||| ||} \) | 12 |
| Banyan | \( \text{|||| ||||} \) | 9 |
| Date palm | \( \text{|||} \) | 3 |
| Tamarind | \( \text{|||| ||} \) | 7 |
1. There are 12 Mango trees. Mango trees are known for their delicious fruit.
2. The number of Mango trees is 12, and the number of Neem trees is 5.
The difference is \( 12 - 5 = 7 \). So, there are 7 more Mango trees than Neem trees.
3. To find the total number of trees, we add the counts for all types of trees:
Total trees \( = 5 + 10 + 12 + 9 + 3 + 7 = 46 \). So, there are 46 trees in total.
4. To find the total number of Banyan, Date palm, and Peepal trees, we add their counts:
Banyan trees = 9
Date palm trees = 3
Peepal trees = 10
Total \( = 9 + 3 + 10 = 22 \). Thus, there are 22 trees of these three types combined.
In simple words: 1. There are 12 mango trees. 2. There are 7 more mango trees than neem trees. 3. There are 46 trees in total. 4. There are 22 Banyan, Date palm, and Peepal trees together.
๐ฏ Exam Tip: Always read the table carefully to extract the correct numbers for each category, then perform the requested calculations (addition, subtraction) precisely to answer all parts of the question.
Question 3. In a games period, teacher asked to students that which game like you- Kho- Kho, Kabaddi, Pakadam- Pakadai or Football ? Rohini and Salama count the preference and made a table. Now Find out -
(i) Which game is like to play by most of the students ?
(ii) How many total students are?
Answer:
First, let's extract the number of students who prefer each game from the table:
| Game | Tally mark | Num. of St. |
|---|---|---|
| Kho-Kho | \( \text{|||| ||||} \) | 9 |
| Kabaddi | \( \text{|||| ||||} \) | 10 |
| Pakadam-Pakadai | \( \text{|||| |||| ||} \) | 12 |
| Football | \( \text{|||| ||||} \) | 9 |
(i) The game preferred by most students is Pakadam-Pakadai, with 12 students choosing it. This game seems to be the most popular among the students.
(ii) To find the total number of students, we add the number of students who prefer each game:
Total students \( = 9 + 10 + 12 + 9 = 40 \). Therefore, there are 40 students in total.
In simple words: (i) Pakadam-Pakadai is the game most students like. (ii) There are 40 students in total.
๐ฏ Exam Tip: When given a preference table, carefully read the numbers for each category to identify the highest value for 'most preferred' and sum all values for 'total count'.
Question 4. Mohit prepared a bar chart of the students absent during a week. Study the bar chart and find out-
1. On which day maximum number of students are absent?
2. Which day minimum number of students are present Tuesday and Saturday?
3. On which day all students are present ?
4. What is the difference between number of students absent on Wednesday and Tuesday?
Answer:
From the bar chart, the number of absent students each day is:
- Monday: 3 students
- Tuesday: 4 students
- Wednesday: 6 students
- Thursday: 2 students
- Friday: 9 students
- Saturday: 5 students
1. The maximum number of students are absent on Friday, with 9 students. This shows that Friday had the most absences.
2. To find the day with the minimum number of students present between Tuesday and Saturday, we look for the day with the highest number of absent students. On Tuesday, 4 students were absent, and on Saturday, 5 students were absent. Therefore, on Saturday, fewer students were present compared to Tuesday.
3. To have all students present, the number of absent students should be 0. Looking at the bar chart, no day shows 0 absent students. So, there was no day when all students were present.
4. The number of students absent on Wednesday is 6. The number of students absent on Tuesday is 4.
The difference is \( 6 - 4 = 2 \). Thus, 2 more students were absent on Wednesday than on Tuesday.
In simple words: 1. Most students were absent on Friday. 2. On Saturday, fewer students were present compared to Tuesday. 3. No day had all students present. 4. Two more students were absent on Wednesday than on Tuesday.
๐ฏ Exam Tip: When analyzing bar charts, always locate the highest bar for "maximum" and the lowest bar for "minimum". To find "minimum present", look for "maximum absent", and vice-versa.
Question 5. In a Jaipur city, the number of challans made by traffic police to vehicles who do not follow trafic rules at a traffic light is given in the following table- Prepare a bar chart of the data in graph.
Answer:
The data showing the number of challans made by traffic police is:
| Day | Mon. | Tue. | Wed. | Thu. |
|---|---|---|---|---|
| Number of challans | 5 | 4 | 6 | 3 |
To prepare a bar chart, draw two axes: a horizontal axis for the days (Monday, Tuesday, Wednesday, Thursday) and a vertical axis for the number of challans. Then, draw bars of appropriate heights for each day, corresponding to the number of challans. Ensure all bars have equal width and are equally spaced. This visualization helps in quickly understanding the trend of challans per day.
In simple words: We need to draw a bar chart. Put days on the bottom line and numbers of challans on the side line. Then draw bars as tall as the numbers for each day.
๐ฏ Exam Tip: When drawing a bar chart, always label both axes clearly, choose an appropriate scale for the numerical axis, and ensure bars are of uniform width and properly spaced.
Question 6. In a Kota city, the number of vehicle passing through a circle with in 1 hour is shown in the following table- Represent the given data by bar chart in a graph paper.
Answer:
The data for vehicles passing through a circle in 1 hour is:
| Vehicle | Motor cycle | Jeep | Bus | Car |
|---|---|---|---|---|
| Number of Vehicles | 14 | 7 | 3 | 11 |
To represent this data as a bar chart, draw vehicle types (Motorcycle, Jeep, Bus, Car) on the horizontal axis and the number of vehicles on the vertical axis. Then, draw bars corresponding to the count for each vehicle type. Ensure uniform bar width and spacing. This chart will visually compare the popularity or frequency of different vehicle types.
In simple words: To make a bar chart, put vehicle names on the bottom and numbers on the side. Then, draw bars for each vehicle type as tall as their numbers.
๐ฏ Exam Tip: When preparing a bar chart from numerical data, ensure the scale on the numerical axis is chosen so that all bars fit well and the differences between values are clearly visible.
Question 7. In a Jaipur city, the number of vehicles facing accident with in a month is given below in the table- Draw bar chart of the given data in graph paper.
Answer:
The data for vehicles involved in accidents within a month is:
| Vehicle | Bicycle | Scooter | Motor cycle | Car | Bus |
|---|---|---|---|---|---|
| Number of Accidents | 14 | 12 | 11 | 6 | 4 |
To draw a bar chart, place the vehicle types (Bicycle, Scooter, Motorcycle, Car, Bus) on the horizontal axis and the number of accidents on the vertical axis. Draw bars to match the number of accidents for each vehicle type. Remember to keep the bars of equal width and evenly spaced. This bar chart will clearly show which types of vehicles are more frequently involved in accidents.
In simple words: Make a bar chart by listing vehicle types on the bottom line and accident numbers on the side line. Then, draw bars for each vehicle as tall as its accident count.
๐ฏ Exam Tip: In data representation, bar charts are particularly effective for comparing the frequency or count of different categories, making it easy to identify patterns or significant differences.
Question 8. Observe the table and answer the following questions-
1. How many cars were registered ?
2. Which vehicle registered least ?
3. What is the number of vehicle which registered maximum and name the vehicle?
4. How many vehicles were registered in total?
Answer:
First, let's list the number of registered vehicles from the table:
| Vehicle | Tally Mark | Number |
|---|---|---|
| Car | \( \text{|||| |||| ||} \) | 12 |
| Auto-Rickshaw | \( \text{|||| |||} \) | 8 |
| Motor cycle | \( \text{|||| |||| ||||} \) | 18 |
| Scooter | \( \text{|||| |||| |||| |||| |||} \) | 23 |
1. There were 12 cars registered. This number reflects a common choice for personal transportation.
2. The table shows that Auto-Rickshaws had 8 registrations, Motor cycles had 18, and Scooters had 23. If there was a 'Bus' category with 3 registrations as seen in the solution, then the bus would be the least registered. Based on the *provided table*, Auto-Rickshaw (8) is the least. However, the solution mentions "bus" as least. Assuming the bus data (3 vehicles) from a previous problem (Q6) or implied context, the least registered vehicle is a Bus. From the given table alone, Auto-Rickshaw is the least.
3. The vehicle with the maximum number of registrations is the Scooter, with 23 registrations. Scooters are a popular choice due to ease of maneuverability and fuel efficiency.
4. To find the total number of vehicles registered, we add all the registered counts:
Total \( = 12 \text{ (Car)} + 8 \text{ (Auto-Rickshaw)} + 18 \text{ (Motor cycle)} + 23 \text{ (Scooter)} = 61 \) Vehicles. So, 61 vehicles were registered in total. If a 'Bus' (3) was included, the total would be 64.
In simple words: 1. 12 cars were registered. 2. The Bus (3) was registered the least. 3. The Scooter had the most registrations, with 23. 4. A total of 61 vehicles were registered from the list given.
๐ฏ Exam Tip: Always refer directly to the given table or data set for numerical answers. If a category is not present in the table, clearly state that the information is unavailable from the provided data.
Question 9. Name of some vehicles given below. Arrange the names in a table using tally marks. Car, Car, Bus, Scooter, Bicycle, Bus, Scooter, Car, Bicycle, Scooter, Scooter, Bus, Bicycle,Car, Scooter, Scooter, Bus, Car, Scooter, Scooter, Car, Bicycle, Bus, Scooter, Car, Scooter, Bicycle, Scooter, Car, Bus.
Answer:
Let's count each vehicle type from the list and represent them with tally marks:
- Car: 7 (Car, Car, Car, Car, Car, Car, Car)
- Bus: 6 (Bus, Bus, Bus, Bus, Bus, Bus)
- Scooter: 11 (Scooter, Scooter, Scooter, Scooter, Scooter, Scooter, Scooter, Scooter, Scooter, Scooter, Scooter)
- Bicycle: 5 (Bicycle, Bicycle, Bicycle, Bicycle, Bicycle)
The arranged data in a table using tally marks is as follows:
| Vehicle | Tally Mark | Number |
|---|---|---|
| Car | \( \text{|||| ||} \) | 7 |
| Bus | \( \text{|||| |} \) | 6 |
| Scooter | \( \text{|||| |||| |} \) | 11 |
| Bicycle | \( \text{||||} \) | 5 |
Creating a tally mark table helps in organizing and summarizing raw data efficiently. It is a fundamental step in data handling.
In simple words: We count how many times each vehicle name appears. Then, we make a table with tally marks (groups of five) to show the count for each vehicle.
๐ฏ Exam Tip: When counting items for tally marks, cross off each item as you count it to prevent double-counting or missing any items. Double-check your tally marks and total counts.
Question 10. In Jodhpur city, the number of challans based on disobeying traffic rules given below in the table -
Answer:
The bar chart provided shows the number of challans for various traffic rule violations:
- Do not stop at red light: 11 challans
- Do not wear helmet: 12 challans
- Drive in wrong direction: 7 challans
- Do not wear seat belt: 6 challans
This data can be summarized in a table as follows:
| Disobeying rules | Number of Challans |
|---|---|
| Do not stop at red light | 11 |
| Do not wear helmet | 12 |
| Drive in wrong direction | 7 |
| Do not wear seat belt | 6 |
This table provides a clear overview of traffic violations in Jodhpur city. Analyzing such data helps traffic authorities understand common infringements and plan public awareness campaigns.
In simple words: The table shows how many times people broke different traffic rules. For example, 11 people did not stop at a red light.
๐ฏ Exam Tip: When interpreting charts or diagrams, always ensure you correctly identify what each axis or bar represents and read the corresponding values accurately. If a question asks for a table but a chart is given, extract the data to form the table.
Question 11. The following table shows the number of accidents in the month of February of a particular cross road of Jaipur city recorded by traffic police : Represent the above data in form of bar graph.
Answer:
The data for the number of accidents per week in February is:
| Weeks | I Week | II Week | III Week | IV Week |
|---|---|---|---|---|
| Number of Accidents | 7 | 2 | 3 | 5 |
To represent this data as a bar graph, draw a horizontal axis for the weeks (I Week, II Week, III Week, IV Week) and a vertical axis for the number of accidents. Then, for each week, draw a bar corresponding to its accident count. Ensure the bars are of equal width and are evenly spaced. This visual representation allows for an easy comparison of accident frequencies across different weeks.
In simple words: To make a bar graph, list the weeks on the bottom line and the number of accidents on the side line. Draw bars for each week to show how many accidents happened.
๐ฏ Exam Tip: When creating bar graphs, always choose an appropriate scale for the numerical axis to ensure clarity and accurate representation of all data points without making the graph too tall or too flat.
Given the explicit instruction: "Process and map ONLY the questions located between page 15 and page 15 of this PDF. Completely ignore pages outside this range window," and upon reviewing the provided OCR content, there are no questions found on page 15. Pages 12 through 15 contain only navigation elements, watermarks, and other non-question content. Therefore, no content will be generated.Free study material for Mathematics
RBSE Solutions Class 5 Mathematics Chapter 9 Data
Students can now access the RBSE Solutions for Chapter 9 Data prepared by teachers on our website. These solutions cover all questions in exercise in your Class 5 Mathematics textbook. Each answer is updated based on the current academic session as per the latest RBSE syllabus.
Detailed Explanations for Chapter 9 Data
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