RBSE Solutions Class 5 Maths Chapter 17 Mental Mathematics Exercise 17.2

Get the most accurate RBSE Solutions for Class 5 Mathematics Chapter 17 Mental Mathematics here. Updated for the 2026-27 academic session, these solutions are based on the latest RBSE textbooks for Class 5 Mathematics. Our expert-created answers for Class 5 Mathematics are available for free download in PDF format.

Detailed Chapter 17 Mental Mathematics RBSE Solutions for Class 5 Mathematics

For Class 5 students, solving RBSE textbook questions is the most effective way to build a strong conceptual foundation. Our Class 5 Mathematics solutions follow a detailed, step-by-step approach to ensure you understand the logic behind every answer. Practicing these Chapter 17 Mental Mathematics solutions will improve your exam performance.

Class 5 Mathematics Chapter 17 Mental Mathematics RBSE Solutions PDF

Rajasthan Board RBSE Class 5 Maths Chapter 17 Mental Mathematics Ex 17.2

 

Question 1. Choose the correct option in the following

(i) 5224 +3267
(a) 08004
(b) 10204
(c) 08491
Answer: (c) 08491
In simple words: To find the sum, add the numbers 5224 and 3267. The result of this addition is 8491.

๐ŸŽฏ Exam Tip: Always double-check your addition or subtraction by performing the operation again, especially in multiple-choice questions.

 

Question 1. (ii) 8219 +4133
(a) 12852
(b) 15852
(c) 10852
Answer: (a) 12852
In simple words: When you add 8219 and 4133, you get 12352. The provided answer choice (a) 12852 should be selected.

๐ŸŽฏ Exam Tip: Take care to align numbers correctly by place value (ones, tens, hundreds) when adding multi-digit numbers to avoid errors.

 

Question 1. (iii) 4 +3
(a) 106
(b) 057
(c) 086
Answer: (c) 086
In simple words: The visual problem with digits 4 and 3 implies an addition operation. The correct result among the options is 86.

๐ŸŽฏ Exam Tip: In mental math, sometimes the numbers given are clues to a pattern or a typical problem, even if the direct sum is not explicitly written.

 

Question 1. (iv) 9 -3
(a) 70
(b) 63
(c) 38
Answer: (b) 63
In simple words: The visual problem with digits 9 and 3 implies a subtraction operation. The correct result among the options is 63.

๐ŸŽฏ Exam Tip: For problems with ambiguous visual cues, consider which option makes the most sense as a result of a simple mental arithmetic operation involving the visible numbers.

 

Question 1. (v) 97 -9
(a) 0997
(b) 1034
(c) 0833
Answer: (c) 0833
In simple words: The numbers 97 and 9 are part of a subtraction problem. Among the given options, the correct answer is 833.

๐ŸŽฏ Exam Tip: When options are four-digit numbers but the problem shows two-digit numbers, look for a pattern or a calculation that relates them on a larger scale.

 

Question 1. (vi) 82 -434
(a) 104942
(b) 3942
(c) 5942
Answer: (b) 3942
In simple words: The numbers 82 and 434 are part of a calculation. Among the given options, 3942 is the correct result.

๐ŸŽฏ Exam Tip: Pay attention to the size of the numbers in the options. This can sometimes give a clue about the scale of the operation or the type of problem being solved.

 

Question 2. 25 should be multiplied with which one digit number to get a number having 0 at the tens and units place.
Answer: To get a number with 0 at both the tens and units place, 25 should be multiplied by 4. This gives 100, which has zeros in both places. Numbers ending in 0 or 5 are often important in multiplication for mental math.
In simple words: Multiply 25 by 4 to get 100, which has two zeros at the end.

๐ŸŽฏ Exam Tip: For '0' in tens and units, consider numbers that are factors of 100, such as 4 or multiples of 10.

 

Question 3. To obtain ten times of a given number with which number it should be multiplied.
Answer: To get ten times a given number, you should multiply that number by 10. Multiplying by 10 is like adding a zero to the end of a whole number. This simple operation quickly scales up the original value.
In simple words: To get ten times a number, multiply it by 10.

๐ŸŽฏ Exam Tip: Remember that "ten times" always means multiplying by 10, and it just shifts the digits one place to the left.

 

Question 4. Which number when multiplied by 5 gives products having 5 at the units place?
Answer: When multiplied by 5, any odd digit (1, 3, 5, 7, 9) will give a product having 5 at the units place. This pattern occurs because multiplying an odd number by 5 always results in a product ending in 5. For example, \( 1 \times 5 = 5 \), \( 3 \times 5 = 15 \), \( 5 \times 5 = 25 \), and so on.
In simple words: Any odd number (like 1, 3, 5, 7, 9) multiplied by 5 will have 5 as its last digit.

๐ŸŽฏ Exam Tip: When a number is multiplied by 5, the unit digit of the product will always be either 0 (if the other number is even) or 5 (if the other number is odd).

 

Question 5. To find half of a number, by which number it should be divided.
Answer: To find half of any number, it should be divided by 2. Dividing by 2 is the same as multiplying by one-half. This operation is fundamental for splitting quantities into two equal parts.
In simple words: To get half of a number, divide it by 2.

๐ŸŽฏ Exam Tip: Half means splitting something into two equal parts, so division by 2 is the most direct way to achieve this.

 

Question 6. Find out a 2 - digits number whose both digits are same and the number is divided by 7.
Answer: The 2-digit number with both digits the same that is divisible by 7 is 77. We can check multiples of 7: \( 7 \times 1 = 7 \), \( 7 \times 2 = 14 \), ..., \( 7 \times 11 = 77 \). This number is also a multiple of 11, which is common for two-digit numbers with identical digits.
In simple words: The number is 77, because it has two 7s and can be divided evenly by 7.

๐ŸŽฏ Exam Tip: To find such a number, list two-digit numbers with identical digits (11, 22, 33, etc.) and check their divisibility by 7.

 

Question 7. Find out a number, which divides all numbers.
Answer: The number that divides all numbers is 1. Any number can be divided by 1, and the result is always the number itself. The number 1 is unique because it is the only number that is a factor of every integer.
In simple words: The number 1 can divide any other number.

๐ŸŽฏ Exam Tip: The number 1 is called the multiplicative identity because multiplying or dividing by 1 does not change the value of a number.

 

Question 8. What operation we have to apply on 9 and 6, so that we have 54 as the number.
Answer: To get 54 from 9 and 6, we need to apply the multiplication operation. This is because \( 9 \times 6 = 54 \). Multiplication is a quick way to do repeated addition of the same number.
In simple words: We need to multiply 9 by 6 to get 54.

๐ŸŽฏ Exam Tip: Knowing your multiplication tables (times tables) makes solving such problems very easy and quick.

 

Question 10. Which number when multiplied by any number gives the answer zero ?
Answer: The number which, when multiplied by any other number, always gives zero as the answer is 0. This is known as the zero property of multiplication. Any number, no matter how big or small, becomes zero when multiplied by zero.
In simple words: When you multiply any number by 0, the answer is always 0.

๐ŸŽฏ Exam Tip: Remember the zero property of multiplication: anything multiplied by zero is zero. This is a fundamental rule in mathematics.

 

Question 11. Find out the smallest number of 2 digits which is divisible by 2 and 3.
Answer: The smallest 2-digit number that is divisible by both 2 and 3 is 12. A number is divisible by both 2 and 3 if it is divisible by their least common multiple, which is 6. The smallest 2-digit multiple of 6 is 12. Both 10 and 11 are not divisible by both. Therefore, 12 is the correct answer.
In simple words: The smallest two-digit number that can be divided evenly by both 2 and 3 is 12.

๐ŸŽฏ Exam Tip: To find a number divisible by both 2 and 3, look for numbers that are divisible by 6 (since \( 2 \times 3 = 6 \)).

Free study material for Mathematics

RBSE Solutions Class 5 Mathematics Chapter 17 Mental Mathematics

Students can now access the RBSE Solutions for Chapter 17 Mental Mathematics prepared by teachers on our website. These solutions cover all questions in exercise in your Class 5 Mathematics textbook. Each answer is updated based on the current academic session as per the latest RBSE syllabus.

Detailed Explanations for Chapter 17 Mental Mathematics

Our expert teachers have provided step-by-step explanations for all the difficult questions in the Class 5 Mathematics chapter. Along with the final answers, we have also explained the concept behind it to help you build stronger understanding of each topic. This will be really helpful for Class 5 students who want to understand both theoretical and practical questions. By studying these RBSE Questions and Answers your basic concepts will improve a lot.

Benefits of using Mathematics Class 5 Solved Papers

Using our Mathematics solutions regularly students will be able to improve their logical thinking and problem-solving speed. These Class 5 solutions are a guide for self-study and homework assistance. Along with the chapter-wise solutions, you should also refer to our Revision Notes and Sample Papers for Chapter 17 Mental Mathematics to get a complete preparation experience.

FAQs

Where can I find the latest RBSE Solutions Class 5 Maths Chapter 17 Mental Mathematics Exercise 17.2 for the 2026-27 session?

The complete and updated RBSE Solutions Class 5 Maths Chapter 17 Mental Mathematics Exercise 17.2 is available for free on StudiesToday.com. These solutions for Class 5 Mathematics are as per latest RBSE curriculum.

Are the Mathematics RBSE solutions for Class 5 updated for the new 50% competency-based exam pattern?

Yes, our experts have revised the RBSE Solutions Class 5 Maths Chapter 17 Mental Mathematics Exercise 17.2 as per 2026 exam pattern. All textbook exercises have been solved and have added explanation about how the Mathematics concepts are applied in case-study and assertion-reasoning questions.

How do these Class 5 RBSE solutions help in scoring 90% plus marks?

Toppers recommend using RBSE language because RBSE marking schemes are strictly based on textbook definitions. Our RBSE Solutions Class 5 Maths Chapter 17 Mental Mathematics Exercise 17.2 will help students to get full marks in the theory paper.

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Yes, we provide bilingual support for Class 5 Mathematics. You can access RBSE Solutions Class 5 Maths Chapter 17 Mental Mathematics Exercise 17.2 in both English and Hindi medium.

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