RBSE Solutions Class 5 Maths Chapter 14 Perimeter and Area Important Questions

Get the most accurate RBSE Solutions for Class 5 Mathematics Chapter 14 Perimeter and Area here. Updated for the 2026-27 academic session, these solutions are based on the latest RBSE textbooks for Class 5 Mathematics. Our expert-created answers for Class 5 Mathematics are available for free download in PDF format.

Detailed Chapter 14 Perimeter and Area RBSE Solutions for Class 5 Mathematics

For Class 5 students, solving RBSE textbook questions is the most effective way to build a strong conceptual foundation. Our Class 5 Mathematics solutions follow a detailed, step-by-step approach to ensure you understand the logic behind every answer. Practicing these Chapter 14 Perimeter and Area solutions will improve your exam performance.

Class 5 Mathematics Chapter 14 Perimeter and Area RBSE Solutions PDF

Multiple Choice Questions

 

Question 1. Area means
(a) Space occupied by object in air
(b) Space occupied by object in water
(c) Space occupied by object in plane
(d) Space occupied by object in any liquid
Answer: (c) Space occupied by object in plane
In simple words: Area is how much flat space an object takes up on a surface. It helps us measure the size of flat things.

๐ŸŽฏ Exam Tip: Remember that area specifically refers to the amount of two-dimensional space a shape covers, usually on a flat surface or a plane.

 

Question 2. Space occupied by any shape on grid paper is find out by
(a) By drawing ray diagram of object
(b) By counting number of squares covered by object
(c) By cutting graph paper of size of object
(d) None of the options
Answer: (b) By counting number of squares covered by object
In simple words: To find the area of a shape on grid paper, you simply count how many small squares it covers. Each square represents a unit of area.

๐ŸŽฏ Exam Tip: When counting squares, remember to count half-squares and nearly full squares carefully to get the most accurate estimate of the area.

 

Question 3. External measurement of given figure

7 cm. 7 cm. 4 cm. 2 cm. 7 cm. 3 cm. 2 cm. 3 cm. 2 cm.
(a) 24 cm.
(b) 44 cm.
(c) 54 cm.
(d) 36 cm.
Answer: (d) 36 cm.
In simple words: The external measurement means the perimeter of the shape. Even with steps, if a figure can be made into a simple rectangle by pushing in the steps, its perimeter is the same as that rectangle. Here, the total length is 14 cm (7+7) and the total height is 4 cm. So, the perimeter is 2 times (length + height).

๐ŸŽฏ Exam Tip: For complex shapes made of straight lines, you can often find the perimeter by summing all horizontal segments and all vertical segments separately. If the shape can be conceptually "unfolded" into a rectangle, the perimeter will be twice the sum of its overall length and height.

 

Question 5. The length of an envelop is 15 cm. and width is 20 cm. then external measurement of the envelop is
(a) 60 cm.
(b) 70 cm.
(c) 80 cm.
(d) 90 cm.
Answer: (b) 70 cm.
In simple words: The external measurement of the envelop means its perimeter. For a rectangle, we add up all four sides, or use the formula: 2 times (length plus width).

๐ŸŽฏ Exam Tip: Always remember that "external measurement" or "distance around" typically refers to the perimeter of a shape. Be careful with units; ensure all measurements are in the same unit before calculating.

 

Question 6. Unit of Area in meter is
(a) Square meter
(b) Meter
(c) Meter cube
(d) Kilometer
Answer: (a) Square meter
In simple words: Area measures flat space, so its unit is always squared. If we measure length in meters, area is measured in square meters.

๐ŸŽฏ Exam Tip: Always include the correct units with your answer. For area, the unit is always "square" followed by the length unit (e.g., square cm, square m), and for perimeter, it's just the length unit (e.g., cm, m).

 

Question 7. Formula to find perimeter of square
(a) Side ร— Side
(b) Length + Width
(c) Length ร— Width
(d) 4 ร— Side
Answer: (d) 4 ร— Side
In simple words: A square has four sides that are all the same length. So, to find the total distance around it (perimeter), you just multiply the length of one side by four.

๐ŸŽฏ Exam Tip: Distinguish clearly between the formula for perimeter (sum of sides) and the formula for area (side ร— side for a square, length ร— width for a rectangle). Knowing the properties of each shape helps in recalling the correct formula.

 

Question 8. If the side of a square is 5 meter then area of square in the following is
(a) 10 meter
(b) 25 meter
(c) 25 square meter
(d) 15 square meter
Answer: (c) 25 square meter
In simple words: To find the area of a square, you multiply the length of one side by itself. Since the side is 5 meters, the area is 5 meters multiplied by 5 meters, which is 25 square meters.

๐ŸŽฏ Exam Tip: Pay close attention to the units. Area is always in "square units" (e.g., square meter), while perimeter is in "units" (e.g., meter). Mixing them up is a common mistake.

 

Fill in the blanks of the following

 

Question 1. Fill in the blanks of the following
1. Area of rectangle = ......... ร— Width
2. Space covered by an object is called ......... of this object.
3. ......... of open shapes can not be determined
4. Perimeter of regular shapes = ......... ร— measurement of side.
5. Perimeter of rectangle = 2 ร— (......... + width)
Answer:
1. Area of rectangle = Length ร— Width
2. Space covered by an object is called Area of this object.
3. Perimeter of open shapes can not be determined
4. Perimeter of regular shapes = No. of sides ร— measurement of side.
5. Perimeter of rectangle = 2 ร— (Length + width)
In simple words: These blanks help us remember the main formulas for calculating area and perimeter of different shapes. Area is about space covered, perimeter is about distance around the edge.

๐ŸŽฏ Exam Tip: Make sure to learn all the basic formulas for area and perimeter. Understanding the definition of each term (like "area" and "perimeter") will help you fill in these blanks correctly.

 

Very Short Answer Type Questions

 

Question 1. Measurement of three sides of a triangle is 4 cm, 5 cm and 6 cm. Write external measurement of the triangle.
Answer: The external measurement of a triangle is its perimeter. To find this, we add the lengths of all three sides together. So, \( 4 \text{ cm} + 5 \text{ cm} + 6 \text{ cm} = 15 \text{ cm} \). The total distance around the triangle is 15 cm.
In simple words: The external measurement of a triangle means adding all its sides. Here, it is \( 4 + 5 + 6 = 15 \) cm.

๐ŸŽฏ Exam Tip: Always sum all sides of any polygon to find its perimeter. For a triangle, it's the sum of its three sides.

 

Question 2. Length of a packet of biscuit is 8 cm. and width is 4 cm. then many squares it cover?
Answer: To find out how many 1 cm ร— 1 cm squares a biscuit packet covers, we need to calculate its area. The packet is a rectangle with a length of 8 cm and a width of 4 cm. The area is calculated by multiplying length by width. So, \( 8 \text{ cm} \times 4 \text{ cm} = 32 \) square cm. This means it covers 32 small squares. This is a practical use of finding area.
In simple words: The biscuit packet covers 32 squares. We get this by multiplying its length (8 cm) by its width (4 cm) to find the area.

๐ŸŽฏ Exam Tip: When a question asks how many unit squares an object covers, it's asking for the object's area. Remember to use the formula length ร— width for rectangles.

 

Question 3. Find out external measurement of the shape given below.

5 cm. 3 cm. 2 cm. 2 cm. 10 cm. 2 cm. 3 cm. 2 cm. 3 cm. 2 cm. 16 cm.
Answer: The external measurement refers to the perimeter of the given shape. We need to sum the lengths of all the outer edges. By carefully tracing the shape and adding up all the segments shown in the diagram, we get:
\( 16 \text{ cm} \text{ (bottom)} + 2 \text{ cm} \text{ (right-most vertical)} + 10 \text{ cm} \text{ (horizontal left from right-most vertical)} + 3 \text{ cm} \text{ (vertical above 10cm horizontal)} + 2 \text{ cm} \text{ (horizontal left from 3cm vertical)} + 3 \text{ cm} \text{ (vertical above 2cm horizontal)} + 2 \text{ cm} \text{ (horizontal left from 3cm vertical)} + 3 \text{ cm} \text{ (vertical on the left, above 5cm)} + 2 \text{ cm} \text{ (top horizontal, right segment)} + 5 \text{ cm} \text{ (far left vertical)} = 48 \text{ cm} \).
In simple words: Add up the length of every line segment that forms the outside edge of the figure. When you sum all these parts, the total perimeter is 48 cm.

๐ŸŽฏ Exam Tip: For complex polygons, identify and list all individual line segments that form the outer boundary. Be methodical in adding them to avoid missing any segment and always double-check your sum.

 

Question 4. Which is called perimeter?
Answer: Perimeter is the total length of the external boundary of any closed two-dimensional shape. It's like walking around the edge of a field and measuring the total distance covered. For shapes made of straight lines, we find it by adding the lengths of all its sides. Understanding this basic concept helps in daily life, like fencing a garden.
In simple words: Perimeter is the total distance around the outside edge of a shape. You find it by adding up all the lengths of its sides.

๐ŸŽฏ Exam Tip: Clearly define perimeter as the "total distance around the boundary" or "sum of the lengths of all sides" of a closed figure to score full marks.

 

Question 5. If the length of sitting is 30 cm width 25 cm. then how much space it occupied on floor?
Answer: To find out how much space something occupies on a floor, we need to calculate its area. Here, the "sitting" (likely a mat or rug) has a length of 30 cm and a width of 25 cm. For a rectangular shape, the area is found by multiplying the length by the width. So, \( 30 \text{ cm} \times 25 \text{ cm} = 750 \) square cm. This means the sitting occupies 750 square centimeters of space.
In simple words: To find the space occupied, we calculate the area. Length (30 cm) multiplied by width (25 cm) gives 750 square cm of space.

๐ŸŽฏ Exam Tip: Recognize that "space occupied" on a flat surface refers to area. Always state the correct unit for area, which is "square" units (e.g., square cm, square m).

 

Short Answer and Essay type Questions

 

Question 1. The length of a mobile is 9 cm. and width is 4 cm. then calculate the space occupied by mobile. [Use 1 cm. ร— 1 cm. square grid paper.]
Answer: To find the space occupied by the mobile, we need to calculate its area. The mobile has a length of 9 cm and a width of 4 cm. We use the formula for the area of a rectangle, which is length multiplied by width. So, \( 9 \text{ cm} \times 4 \text{ cm} = 36 \) square cm. This means the mobile would cover 36 squares on a 1 cm ร— 1 cm grid paper. Calculating area helps us understand how much surface a flat object covers.
In simple words: The mobile's area is length times width. So, \( 9 \text{ cm} \times 4 \text{ cm} = 36 \) square cm. It covers 36 squares.

๐ŸŽฏ Exam Tip: When given dimensions and asked for "space occupied," calculate the area. Visualizing it on a grid helps confirm that area is the count of unit squares.

 

Question 2. Draw the given shapes on 1 cm ร— 1 cm square grid paper and find out. If the length of paper is 8 cm and width is 3 cm. then space occupied by paper is equal to how many squares?
Answer: To find the space occupied by the paper, we calculate its area. The paper is a rectangle with a length of 8 cm and a width of 3 cm. The area of a rectangle is found by multiplying its length by its width. So, \( 8 \text{ cm} \times 3 \text{ cm} = 24 \) square cm. This means the paper would cover 24 squares if drawn on a 1 cm ร— 1 cm grid paper. Grid paper helps us visualize and count these squares directly.
In simple words: The paper's area is its length (8 cm) times its width (3 cm). This makes \( 8 \times 3 = 24 \) square cm. So, it covers 24 squares.

๐ŸŽฏ Exam Tip: Remember that area calculations directly tell you how many unit squares fit into a given shape. Always ensure your calculation uses the correct formula for the shape (e.g., length ร— width for a rectangle).

 

Question 3. Some shapes are given below on grid paper. Answer the following questions given below.

ABCD 4 cm. 3 cm. PQRS 6 cm. 2 cm.
(1) Area of rectangle ABCD is =
(2) Area of rectangle PQRS is =
(3) Are the area of both rectangles equal.
(4) Perimeter of rectangle ABCE is =
(5) Perimeter of rectangle PQRS =
(6) Perimeter of which rectangle is more? Name it.
Answer:
(1) For rectangle ABCD: Length = 4 cm, Breadth = 3 cm. Area = Length ร— Breadth = \( 4 \text{ cm} \times 3 \text{ cm} = 12 \) square cm.
(2) For rectangle PQRS: Length = 6 cm, Breadth = 2 cm. Area = Length ร— Breadth = \( 6 \text{ cm} \times 2 \text{ cm} = 12 \) square cm.
(3) Yes, the area of both rectangles (ABCD and PQRS) is equal, both are 12 square cm.
(4) For rectangle ABCD: Length = 4 cm, Breadth = 3 cm. Perimeter = 2 ร— (Length + Breadth) = \( 2 \times (4 \text{ cm} + 3 \text{ cm}) = 2 \times 7 \text{ cm} = 14 \) cm.
(5) For rectangle PQRS: Length = 6 cm, Breadth = 2 cm. Perimeter = 2 ร— (Length + Breadth) = \( 2 \times (6 \text{ cm} + 2 \text{ cm}) = 2 \times 8 \text{ cm} = 16 \) cm.
(6) The perimeter of rectangle PQRS is more (16 cm) compared to the perimeter of rectangle ABCD (14 cm).
In simple words: First, calculate the area of both rectangles by multiplying length and width. Then, calculate the perimeter of both by adding all their sides (or using 2 times length plus width). Compare the results to see which one has a larger perimeter.

๐ŸŽฏ Exam Tip: Always clearly identify the length and breadth of each rectangle from the grid before calculating area and perimeter. Be precise with units (square cm for area, cm for perimeter) and double-check your arithmetic.

 

Question 4. Length and width of a cloth is 10 cm. and 12 cm. How much long lace required to put on its edge? We have to put flower on it. On how much area flowers can be put? [Use 1 cm. x 1 cm. square grid]
Answer:
First, let's find the length of lace required. Lace is put on the edge, which means we need to calculate the perimeter of the cloth. The cloth has a length of 12 cm and a width of 10 cm. Perimeter = 2 ร— (Length + Width) = \( 2 \times (12 \text{ cm} + 10 \text{ cm}) = 2 \times 22 \text{ cm} = 44 \) cm. So, 44 cm of lace is needed.
Next, let's find the area where flowers can be put. Flowers are placed on the surface of the cloth, so we need to calculate the area. Area = Length ร— Width = \( 12 \text{ cm} \times 10 \text{ cm} = 120 \) square cm. This means flowers can be placed on an area of 120 square cm, which is equivalent to 120 squares on a 1 cm ร— 1 cm grid. Understanding the difference between perimeter and area is key here.
In simple words: To find the lace needed, calculate the perimeter (distance around the cloth): \( 2 \times (12 + 10) = 44 \) cm. To find the space for flowers, calculate the area: \( 12 \times 10 = 120 \) square cm.

๐ŸŽฏ Exam Tip: Remember that "on its edge" or "around" implies perimeter, while "on it" or "space occupied" implies area. Always clarify which measurement the question is asking for before you start calculating.

 

Question 5. Length and width of a pocket diary is 12 cm and 6 cm. Find its external measurement on drawing figure.
Answer: The external measurement of a pocket diary refers to its perimeter. The diary has a length of 12 cm and a width of 6 cm. To find the perimeter, we add up the lengths of all four sides. This means adding the length twice and the width twice. So, the external measurement is \( 12 \text{ cm} + 12 \text{ cm} + 6 \text{ cm} + 6 \text{ cm} = 36 \) cm. Alternatively, using the formula, Perimeter = 2 ร— (Length + Width) = \( 2 \times (12 \text{ cm} + 6 \text{ cm}) = 2 \times 18 \text{ cm} = 36 \) cm. Visualizing the rectangular shape helps in summing all its sides.
In simple words: The external measurement is the perimeter. It is \( 12 \text{ cm} + 12 \text{ cm} + 6 \text{ cm} + 6 \text{ cm} = 36 \) cm.

๐ŸŽฏ Exam Tip: When finding the external measurement of a rectangle, ensure you add all four sides (two lengths and two widths). Drawing the figure helps in visually confirming that all sides are included in the sum.

Free study material for Mathematics

RBSE Solutions Class 5 Mathematics Chapter 14 Perimeter and Area

Students can now access the RBSE Solutions for Chapter 14 Perimeter and Area prepared by teachers on our website. These solutions cover all questions in exercise in your Class 5 Mathematics textbook. Each answer is updated based on the current academic session as per the latest RBSE syllabus.

Detailed Explanations for Chapter 14 Perimeter and Area

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