Biology Objective Questions and Answers: Molecular Basis of Inheritance
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Multiple Choice Questions
(a) (A) and (B)
(b) (B) and (C)
(c) (A) and (D)
(d) (A) and (C)
Show Answer & Explanation
Answer: (c) (A) and (D)
Explanation:
1. RNA is believed to be the first genetic material.
2. The RNA primer anneals at the 3' end of the template strand.
Teacher's Note:
1. 5-methyl uracil (thymine) is in DNA, and DNA polymerase needs a primer to begin synthesis.
(a) 87.5% light and 12.5% hybrid
(b) 75% light and 25% hybrid
(c) 25% light and 75% hybrid
(d) 12.5% light and 87.5% hybrid
Show Answer & Explanation
Answer: (a) 87.5% light and 12.5% hybrid
Explanation:
1. In 80 minutes there are 4 generations, giving 16 DNA molecules.
2. Two are hybrid (N15-N14) and 14 are light, so hybrid is 12.5% and light is 87.5%.
Teacher's Note:
1. Heavy DNA disappears after the first generation.
(a) Deoxyribose sugar
(b) 5-methyl uracil
(c) Demethylated thymine
(d) H3PO4
Show Answer & Explanation
Answer: (c) Demethylated thymine
Explanation:
1. Thymine is 5-methyl uracil, so it is present in DNA.
2. Demethylated thymine is uracil, which is found only in RNA.
Teacher's Note:
1. Deoxyribose and phosphate are parts of DNA nucleotides.
(a) A-i, B-ii, C-iii, D-iv, E-x
(b) A-ii, B-i, C-iii, D-iv, E-x
(c) A-iii, B-iv, C-ii, D-i, E-x
(d) A-iv, B-iii, C-ii, D-i, E-x
Show Answer & Explanation
Answer: (d) A-iv, B-iii, C-ii, D-i, E-x
Explanation:
1. Replication is DNA to DNA, transcription is DNA to mRNA, translation is mRNA to protein and reverse transcription is RNA to DNA.
2. The ribosome is made of rRNA and protein.
Teacher's Note:
1. Option (d) matches all five pairs.
(a) 20,000
(b) 40,000
(c) 10,000
(d) 5,000
Show Answer & Explanation
Answer: (b) 40,000
Explanation:
1. Each base pair has two nucleotides, one on each strand, and each nucleotide has one phosphate.
2. So 20,000 bp have 40,000 phosphates.
Teacher's Note:
1. Count nucleotides, not base pairs.
(a) 800
(b) 400
(c) 100
(d) 200
Show Answer & Explanation
Answer: (b) 400
Explanation:
1. In double-stranded DNA A = T and G = C, so A = T = 200 and G = C = 200, a total of 800 bases.
Teacher's Note:
1. Purines (A + G) are half of the total, which is 400.
(a) Base ratio is constant for a given species
(b) Base ratio is variable for different species
(c) Base ratio does not depend on the age of the organism
(d) Base ratio is different for different tissues of an organism
Show Answer & Explanation
Answer: (d) Base ratio is different for different tissues of an organism
Explanation:
1. The base composition of DNA is characteristic of a species, and does not change with age, tissue or environment.
2. All cells of an organism carry the same DNA.
Teacher's Note:
1. So statement (d) is false.
(a) One
(b) Two
(c) Three
(d) Four
Show Answer & Explanation
Answer: (c) Three
Explanation:
1. The octamer has 4 types of histones (H2A, H2B, H3 and H4), two of each, so (A) is wrong.
2. The other three statements are correct.
Teacher's Note:
1. Histones are basic because they are rich in lysine and arginine.
(a) 5'-OH of one sugar and 2'-OH of the next sugar
(b) 3'-OH of one sugar and 5'-OH of the next sugar
(c) 3'-OH of one sugar and 2'-OH of the next sugar
(d) 5'-OH of one sugar and 1'-OH of the next sugar
Show Answer & Explanation
Answer: (b) 3'-OH of one sugar and 5'-OH of the next sugar
Explanation:
1. The phosphate links the 3' carbon of one nucleotide to the 5' carbon of the next.
2. This gives a sugar-phosphate backbone with 5' to 3' polarity.
Teacher's Note:
1. DNA polymerase adds nucleotides to a free 3'-OH.
(a) Universal nature
(b) Degeneracy
(c) Unambiguous nature
(d) Comma-less or continuous reading
Show Answer & Explanation
Answer: (b) Degeneracy
Explanation:
1. Different codons can code for the same amino acid, which is degeneracy.
2. Mostly the third base differs.
Teacher's Note:
1. This makes the code robust to some mutations.
(a) A polymer of amino acids to a polymer of carbohydrates
(b) A polymer of deoxynucleotides to a polymer of nucleotides
(c) A polymer of nucleotides to a polymer of amino acids
(d) A polymer of amino acids to proteins
Show Answer & Explanation
Answer: (c) A polymer of nucleotides to a polymer of amino acids
Explanation:
1. In translation the nucleotide sequence of mRNA is decoded into an amino acid sequence.
2. This is a polymer of nucleotides to a polymer of amino acids.
Teacher's Note:
1. Option (b) describes transcription.
(a) It is the basis of DNA fingerprinting
(b) It is due to variable length of restriction fragments
(c) It is due to variable number of minisatellites
(d) It is the same for all human beings
Show Answer & Explanation
Answer: (d) It is the same for all human beings
Explanation:
1. RFLP shows individual differences in fragment lengths, caused by variable tandem repeats.
2. It is the basis of DNA fingerprinting, so it cannot be the same for all humans.
Teacher's Note:
1. Identical twins are the exception.
(a) Frequency greater than 0.01
(b) Frequency less than 0.01
(c) Frequency greater than 1.0
(d) Frequency less than 0.01%
Show Answer & Explanation
Answer: (a) Frequency greater than 0.01
Explanation:
1. DNA polymorphism requires that the variant allele be present in more than 1% (frequency greater than 0.01) of the population.
2. Rarer variants are called mutations.
Teacher's Note:
1. A frequency cannot exceed 1.0.
(a) There is a single promoter for the three structural genes lac z, lac y and lac a
(b) It forms polycistronic mRNA
(c) Glucose results in induction of the lac operon
(d) The repressor protein shows negative control
Show Answer & Explanation
Answer: (c) Glucose results in induction of the lac operon
Explanation:
1. The lac operon is induced by lactose (allolactose), not by glucose.
2. Glucose does not induce it.
Teacher's Note:
1. The operon has one promoter and gives polycistronic mRNA, and the repressor exerts negative control.
(a) A substitution, B transition
(b) A point mutation, B transversion
(c) A frameshift mutation, B transversion
(d) Both (b) and (c)
Show Answer & Explanation
Answer: (a) A substitution, B transition
Explanation:
1. A base replaced by another is a substitution (a type of point mutation).
2. Adenine to guanine is a purine-to-purine change, called a transition.
Teacher's Note:
1. A transversion is a purine-to-pyrimidine change.
(a) Promoter
(b) Structural gene
(c) Terminator
(d) Coding strand
Show Answer & Explanation
Answer: (c) Terminator
Explanation:
1. A transcription unit has a promoter at the 5' end, the structural gene, and the terminator at the 3' end of the coding strand.
2. The terminator signals the end of transcription.
Teacher's Note:
1. The promoter is the RNA polymerase binding site.
(a) Dystrophin is the largest gene of the human genome
(b) Chromosome Y has a minimum of 231 genes
(c) SNPs have been identified at about 2.4 million locations
(d) The functions of over 50% of discovered genes are unknown
Show Answer & Explanation
Answer: (c) SNPs have been identified at about 2.4 million locations
Explanation:
1. NCERT states that about 1.4 million SNPs were identified, so 2.4 million is incorrect.
Teacher's Note:
1. Dystrophin is the largest gene, chromosome Y has the fewest genes (231) and the function of over 50% of genes was unknown at that time.
Molecular Basis of Inheritance Objective Questions & Solutions for NEET Biology
Download Multiple Choice Questions: Molecular Basis of Inheritance (NEET Biology)
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FAQs
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