Download NEET MCQs for NEET Biology: Molecular Basis of Inheritance
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Chapter-wise Objective Questions: Molecular Basis of Inheritance
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Multiple Choice Questions
(a) 3' end
(b) 5' end
(c) both ends
(d) neither end
Show Answer & Explanation
Answer: (b) 5' end
Explanation:
1. The 5' end has a free phosphate on the 5' carbon of the sugar, and the 3' end has a free 3'-OH.
Teacher's Note:
1. Chains are written 5' to 3'.
(a) thymine
(b) cytosine
(c) adenine
(d) guanine
Show Answer & Explanation
Answer: (a) thymine
Explanation:
1. Thymine is uracil with a methyl group at position 5.
Teacher's Note:
1. Thymine occurs in DNA; uracil in RNA.
(a) two purines pair together
(b) two pyrimidines pair together
(c) phosphates pair with sugars
(d) each purine pairs with a pyrimidine
Show Answer & Explanation
Answer: (d) each purine pairs with a pyrimidine
Explanation:
1. Purine-pyrimidine pairing (A with T, G with C) keeps the helix diameter constant at about 2 nm.
Teacher's Note:
1. Hydrogen bonds hold the pairs.
(a) translation
(b) transcription
(c) reverse transcription
(d) replication
Show Answer & Explanation
Answer: (c) reverse transcription
Explanation:
1. Retroviruses use reverse transcriptase to make DNA from an RNA template (Temin and Baltimore).
Teacher's Note:
1. The central dogma is DNA to RNA to protein, with this exception.
(a) aspartic acid and glutamic acid
(b) lysine and arginine
(c) glycine and alanine
(d) cysteine and methionine
Show Answer & Explanation
Answer: (b) lysine and arginine
Explanation:
1. Lysine and arginine carry positive charges that bind the negatively charged DNA.
Teacher's Note:
1. Histone octamer: H2A, H2B, H3, H4 (two each).
(a) cistron
(b) codon
(c) operator
(d) replicon
Show Answer & Explanation
Answer: (a) cistron
Explanation:
1. A cistron is a DNA segment coding for a polypeptide chain.
Teacher's Note:
1. Monocistronic: one cistron per mRNA.
(a) RNA polymerase I
(b) RNA polymerase III
(c) DNA polymerase
(d) RNA polymerase II
Show Answer & Explanation
Answer: (d) RNA polymerase II
Explanation:
1. RNA pol I makes rRNAs (28S, 18S, 5.8S), pol II makes hnRNA, and pol III makes tRNA, 5S rRNA and snRNAs.
Teacher's Note:
1. Remember I, II, III as rRNA, mRNA, tRNA.
(a) Har Gobind Khorana
(b) Marshall Nirenberg
(c) George Gamow
(d) Francis Crick
Show Answer & Explanation
Answer: (c) George Gamow
Explanation:
1. Gamow reasoned that 4 bases taken three at a time give 64 codons, enough for 20 amino acids.
Teacher's Note:
1. Crick later gave experimental support with frame-shift mutants.
(a) 35S and 32P respectively
(b) 32P and 35S respectively
(c) 14C and 15N respectively
(d) 3H and 14C respectively
Show Answer & Explanation
Answer: (b) 32P and 35S respectively
Explanation:
1. DNA contains phosphorus but no sulphur, whereas protein contains sulphur but no phosphorus.
Teacher's Note:
1. Only 32P entered the bacteria, proving DNA is genetic material.
(a) Complete immutability
(b) Replicability
(c) Stability
(d) Expressibility
Show Answer & Explanation
Answer: (a) Complete immutability
Explanation:
1. Genetic material must replicate, be stable, express itself as phenotype and be capable of mutation for evolution; so it is not absolutely immutable.
Teacher's Note:
1. Mutations provide variation.
(a) Paper chromatography
(b) X-ray diffraction
(c) Gel electrophoresis
(d) Caesium chloride density gradient centrifugation
Show Answer & Explanation
Answer: (d) Caesium chloride density gradient centrifugation
Explanation:
1. They grew E. coli in 15N medium, then transferred to 14N, and separated heavy and light DNA by CsCl density gradient centrifugation.
Teacher's Note:
1. Hybrid DNA was seen after the first generation.
(a) monocistronic and split
(b) monocistronic and non-split
(c) polycistronic and non-split
(d) polycistronic and split
Show Answer & Explanation
Answer: (c) polycistronic and non-split
Explanation:
1. In bacteria genes are often arranged in operons giving polycistronic mRNA, and they lack introns.
Teacher's Note:
1. Most eukaryotic genes are monocistronic and split.
(a) Severo Ochoa
(b) H. G. Khorana
(c) George Gamow
(d) F. Sanger
Show Answer & Explanation
Answer: (b) H. G. Khorana
Explanation:
1. Khorana chemically synthesised RNA with repeating sequences that helped decode the genetic code.
Teacher's Note:
1. Ochoa's enzyme made RNA without a template.
(a) degenerate
(b) ambiguous
(c) overlapping
(d) non-universal
Show Answer & Explanation
Answer: (a) degenerate
Explanation:
1. Degeneracy: 61 sense codons for 20 amino acids.
Teacher's Note:
1. Each codon, however, codes for only one amino acid so the code is unambiguous.
(a) Down syndrome
(b) Turner syndrome
(c) albinism due to deletion of a chromosome
(d) sickle-cell anaemia
Show Answer & Explanation
Answer: (d) sickle-cell anaemia
Explanation:
1. Replacement of a single base (GAG to GUG) changes glutamic acid to valine in the beta chain of haemoglobin.
Teacher's Note:
1. Down syndrome is a chromosomal aberration.
(a) point mutation
(b) silent mutation
(c) frame-shift mutation
(d) missense mutation
Show Answer & Explanation
Answer: (c) frame-shift mutation
Explanation:
1. The reading frame is disturbed from the point of insertion or deletion, changing all later codons.
Teacher's Note:
1. Insertion of three bases keeps the frame.
(a) clover leaf
(b) inverted L
(c) straight rod
(d) double helix
Show Answer & Explanation
Answer: (b) inverted L
Explanation:
1. The cloverleaf of 2-D diagrams folds into an inverted L-shape.
Teacher's Note:
1. The anticodon loop and the amino acid acceptor end are at opposite ends.
(a) untranslated regions (UTRs)
(b) introns
(c) exons
(d) operators
Show Answer & Explanation
Answer: (a) untranslated regions (UTRs)
Explanation:
1. UTRs are required for efficient translation.
Teacher's Note:
1. They are present before the start codon and after the stop codon.
(a) Beadle and Tatum
(b) Hershey and Chase
(c) Meselson and Stahl
(d) Jacob and Monod
Show Answer & Explanation
Answer: (d) Jacob and Monod
Explanation:
1. Francois Jacob and Jacques Monod proposed the lac operon model of regulation in bacteria.
Teacher's Note:
1. They shared the 1965 Nobel prize with Lwoff.
(a) beta-galactosidase
(b) permease
(c) repressor
(d) transacetylase
Show Answer & Explanation
Answer: (c) repressor
Explanation:
1. The regulatory i gene produces a repressor protein that binds to the operator.
Teacher's Note:
1. The repressor is made all the time.
(a) permease
(b) transacetylase
(c) beta-galactosidase
(d) repressor
Show Answer & Explanation
Answer: (b) transacetylase
Explanation:
1. z codes for beta-galactosidase, y for permease and a for transacetylase.
Teacher's Note:
1. Z-Y-A order in the operon.
(a) inducer
(b) repressor
(c) operator
(d) promoter
Show Answer & Explanation
Answer: (a) inducer
Explanation:
1. Lactose (allolactose) binds the repressor and inactivates it, permitting transcription.
Teacher's Note:
1. Regulation of lac operon by repressor is negative regulation.
(a) maltose into glucose
(b) sucrose into glucose and fructose
(c) starch into maltose
(d) lactose into galactose and glucose
Show Answer & Explanation
Answer: (d) lactose into galactose and glucose
Explanation:
1. Beta-galactosidase breaks the beta-galactoside lactose into its monosaccharides.
Teacher's Note:
1. Permease increases permeability of cell to lactose.
(a) Frederick Sanger
(b) Kary Mullis
(c) Alec Jeffreys
(d) Hamilton Smith
Show Answer & Explanation
Answer: (c) Alec Jeffreys
Explanation:
1. Alec Jeffreys used variable repeats (VNTR) as probes.
Teacher's Note:
1. DNA fingerprinting depends on DNA polymorphism.
(a) micro-satellite
(b) mini-satellite
(c) macro-satellite
(d) telomeric DNA
Show Answer & Explanation
Answer: (b) mini-satellite
Explanation:
1. VNTR (variable number of tandem repeats) is a mini-satellite.
Teacher's Note:
1. Satellite DNA forms small peaks in density gradient.
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FAQs
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