Download NEET MCQs for NEET Biology: Cell Biology Plant Kingdom and Plant Physiology
Access targeted multiple-choice questions for Cell Biology Plant Kingdom and Plant Physiology designed to align with the latest NEET academic syllabus for NEET Biology. These objective practice sets help students evaluate their conceptual understanding and improve exam readiness.
Chapter-wise Objective Questions: Cell Biology Plant Kingdom and Plant Physiology
Access the complete set of multiple-choice questions for Cell Biology Plant Kingdom and Plant Physiology below. This focused format allows students to isolate specific topics for thorough review and uninterrupted practice alongside official NEET textbooks.
Multiple Choice Questions
(a) Algae : sex organs are unicellular and jacketless
(b) Bryophytes : the sporophyte is dependent on the gametophyte
(c) Pteridophytes : non-vascular cryptogams
(d) Gymnosperms : the endosperm is formed before fertilisation
Show Answer & Explanation
Answer: (c) Pteridophytes : non-vascular cryptogams
Explanation:
1. Pteridophytes are the first terrestrial plants with vascular tissues (xylem and phloem), so they are vascular cryptogams, not non-vascular ones.
2. The other three matches are correct: algal sex organs are unicellular and jacketless, a bryophyte sporophyte depends on the gametophyte, and the gymnosperm endosperm (female gametophyte) forms before fertilisation.
Teacher's Note:
1. Cryptogams are plants with hidden reproductive organs, and they include algae, bryophytes and pteridophytes.
2. Only bryophytes among them lack vascular tissue (non-vascular).
(a) Lichens are not very good pollution indicators.
(b) Viroids are larger than viruses.
(c) Viruses are made up of either DNA or RNA and proteins.
(d) Prions cause the potato spindle tuber disease.
Show Answer & Explanation
Answer: (c) Viruses are made up of either DNA or RNA and proteins.
Explanation:
1. A virus has one kind of nucleic acid, either DNA or RNA, enclosed in a protein coat (capsid).
2. Lichens are very good pollution indicators because they do not grow in polluted air, viroids are much smaller than viruses (free RNA only), and the potato spindle tuber disease is caused by a viroid, not a prion.
Teacher's Note:
1. Viroids have only RNA and no protein coat.
2. Prions are infectious proteins that cause diseases such as mad cow disease.
(a) two different species but both belong to the same genus
(b) two different species and they belong to different genera
(c) two different genera but both have the same specific epithet
(d) two different families but both have the same genus
Show Answer & Explanation
Answer: (a) two different species but both belong to the same genus
Explanation:
1. Potato is \(\textit{Solanum tuberosum}\) and brinjal is \(\textit{Solanum melongena}\).
2. They share the genus \(\textit{Solanum}\) but have different species names, so they are two different species of the same genus.
Teacher's Note:
1. In a binomial name the first word is the genus and the second is the species epithet.
2. Same genus implies the same family.
(a) 6
(b) 8
(c) 5
(d) 7
Show Answer & Explanation
Answer: (a) 6
Explanation:
1. Independent, free-living gametophytes are found in bryophytes and pteridophytes.
2. Sphagnum, Equisetum, Polytrichum, Funaria, Adiantum and Marchantia are 6 such examples.
3. In gymnosperms (Cedrus, Ginkgo, Pinus, Cycas) the gametophyte is dependent on the sporophyte.
Teacher's Note:
1. In gymnosperms and angiosperms the gametophyte is highly reduced and retained on the sporophyte.
2. In bryophytes the gametophyte is the dominant phase.
(a) Liliaceae
(b) Solanaceae
(c) Fabaceae
(d) Cruciferae
Show Answer & Explanation
Answer: (b) Solanaceae
Explanation:
1. Solanaceae have bisexual, actinomorphic flowers with a bicarpellary, obliquely placed syncarpous ovary and a swollen placenta bearing many ovules.
2. Liliaceae have a tricarpellary ovary, Fabaceae have a monocarpellary ovary, and Cruciferae have a bicarpellary ovary with a replum and a false septum.
Teacher's Note:
1. Potato, tomato, brinjal and tobacco belong to Solanaceae.
2. The fruit is a berry or a capsule.
(a) Liliaceae
(b) Solanaceae
(c) Fabaceae
(d) Cruciferae
Show Answer & Explanation
Answer: (a) Liliaceae
Explanation:
1. \(\textit{Gloriosa}\) (glory lily), \(\textit{Asparagus}\), \(\textit{Allium}\) and \(\textit{Aloe}\) are monocots of the family Liliaceae.
Teacher's Note:
1. Liliaceae flowers are trimerous with six tepals.
2. Many members are used as ornamentals, vegetables and medicinal plants.
(a) dicot root
(b) monocot root
(c) dicot stem
(d) monocot stem
Show Answer & Explanation
Answer: (b) monocot root
Explanation:
1. Monocot roots are polyarch, with usually more than six xylem bundles, and the xylem is exarch.
2. Dicot roots usually have two to four (diarch to tetrarch) xylem bundles, and stems have endarch xylem.
Teacher's Note:
1. Roots have exarch xylem and stems have endarch xylem.
2. Monocot roots also have a large pith.
(a) leptotene
(b) zygotene
(c) pachytene
(d) diplotene
Show Answer & Explanation
Answer: (b) zygotene
Explanation:
1. Prophase I has five substages. In zygotene homologous chromosomes pair up in a process called synapsis, forming the synaptonemal complex.
2. Crossing over takes place later in pachytene, and chiasmata become visible in diplotene.
Teacher's Note:
1. The order is leptotene, zygotene, pachytene, diplotene, diakinesis.
2. The paired chromosomes at zygotene are called bivalents or tetrads.
(a) 0.05 to 1 \(\mu\)m
(b) 0.2 to 1.0 \(\mu\)m
(c) 0.05 to 10 \(\mu\)m
(d) 1 to 4.1 \(\mu\)m
Show Answer & Explanation
Answer: (b) 0.2 to 1.0 \(\mu\)m
Explanation:
1. Mitochondria are sausage-shaped or cylindrical with a diameter of 0.2 to 1.0 \(\mu\)m (average 0.5 \(\mu\)m) and a length of 1.0 to 4.1 \(\mu\)m.
Teacher's Note:
1. Note that 1 to 4.1 micrometres is the length, not the diameter.
2. These values are easy to confuse in the NCERT text.
(a) it is a component of the endomembrane system
(b) it is bounded by the tonoplast
(c) in animals it occupies about 90% of the volume of the cell
(d) it contains water, sap, excretory products etc.
Show Answer & Explanation
Answer: (c) in animals it occupies about 90% of the volume of the cell
Explanation:
1. The vacuole is bound by a single membrane called the tonoplast, is part of the endomembrane system, and contains water, sap and excretory products.
2. In plant cells the vacuole can occupy up to 90% of the cell volume. In animal cells vacuoles are small, so statement (c) is incorrect.
Teacher's Note:
1. The tonoplast regulates the movement of ions into the vacuole.
2. Contractile and food vacuoles are the animal examples.
(a) Anything less than a complete structure of all cells does not ensure independent living.
(b) Anton von Leeuwenhoek first saw and described a living cell.
(c) Robert Brown discovered the cell.
(d) The cell is the basic unit of structure and function of all organisms.
Show Answer & Explanation
Answer: (c) Robert Brown discovered the cell.
Explanation:
1. Robert Hooke discovered the cell in 1665 by examining cork slices. Robert Brown discovered the nucleus in 1831.
2. So (c) is incorrect. The other three statements are correct.
Teacher's Note:
1. Leeuwenhoek was the first to see a living cell.
2. Schleiden and Schwann formulated the cell theory, and Virchow added that new cells arise from pre-existing cells.
(a) maltose
(b) lactose
(c) sucrose
(d) glycogen
Show Answer & Explanation
Answer: (c) sucrose
Explanation:
1. Sucrose is made of \(\alpha\)-D-glucose and \(\beta\)-D-fructose.
2. Maltose is two glucose units and lactose is glucose plus galactose. Glycogen is a polysaccharide, not a disaccharide.
Teacher's Note:
1. Sucrose is a non-reducing sugar because both anomeric carbons are involved in the bond.
2. Invertase hydrolyses sucrose into glucose and fructose.
(a) nucleic acids
(b) glycogen
(c) lecithin
(d) ribose
Show Answer & Explanation
Answer: (b) glycogen
Explanation:
1. The bond joining monosaccharides in glycogen is an O-glycosidic bond (\(\ce{C-O-C}\)).
2. Nucleic acids join the sugar and base through an N-glycosidic bond, and nucleotides are joined by phosphodiester bonds. Lecithin has ester bonds, and ribose is a monosaccharide with no glycosidic bond.
Teacher's Note:
1. A glycosidic bond joins the anomeric carbon of a sugar to another group.
2. The name of the bond depends on the atom it is linked to (O or N).
(a) glucose
(b) ribose
(c) fructose
(d) arabinose
Show Answer & Explanation
Answer: (c) fructose
Explanation:
1. Fructose has six carbons and a ketone group at C-2, so it is a ketohexose.
2. Glucose is an aldohexose, and ribose and arabinose are aldopentoses.
Teacher's Note:
1. Ketoses end with the suffix -ulose in the systematic naming.
2. Fructose is the sweetest naturally occurring sugar.
(a) \(\beta\)-galactosidase
(b) permease
(c) transacetylase
(d) repressor
Show Answer & Explanation
Answer: (d) repressor
Explanation:
1. The \(i\) gene (inhibitor gene) codes for the repressor protein, which binds the operator and blocks transcription in the absence of the inducer.
2. The structural genes \(z\), \(y\) and \(a\) code for \(\beta\)-galactosidase, permease and transacetylase.
Teacher's Note:
1. Lactose (allolactose) is the inducer that binds the repressor and frees the operator.
2. The \(i\) gene is expressed continuously (constitutively).
(a) a facultative and permanent formation
(b) an obligatory and permanent formation
(c) an obligatory and transient formation
(d) a facultative and transient formation
Show Answer & Explanation
Answer: (c) an obligatory and transient formation
Explanation:
1. The substrate must bind the active site for the reaction to take place, so ES complex formation is obligatory.
2. The complex breaks down to give the product and the free enzyme, so it is only transient.
Teacher's Note:
1. The enzyme is regenerated unchanged at the end of the reaction.
2. Transient means that it lasts only for a short time.
(a) cooling of the leaf surface
(b) water supply to leaves for photosynthesis
(c) transport of minerals from the root to the leaves
(d) active absorption of minerals by the root
Show Answer & Explanation
Answer: (d) active absorption of minerals by the root
Explanation:
1. Transpiration cools the leaf, supplies water for photosynthesis and carries the minerals in the xylem sap upward with the transpiration pull.
2. Absorption of minerals by roots is largely active and needs energy. It is not a function of transpiration.
Teacher's Note:
1. Transpiration pull is the main force for the ascent of sap in tall trees.
2. Mineral uptake depends on ATP in the root cells.
(a) loss of chlorophyll
(b) inhibition of cell division
(c) death of tissues
(d) delay in flowering
Show Answer & Explanation
Answer: (c) death of tissues
Explanation:
1. Necrosis is the death of tissue, usually in the leaf tips and margins.
2. Loss of chlorophyll is chlorosis, and inhibition of cell division and delayed flowering are other deficiency symptoms.
Teacher's Note:
1. Chlorosis and necrosis are the two main deficiency symptoms.
2. Ca, Mg, Cu and K deficiencies all show necrosis.
(a) Joseph Priestley with his experiment on an aquatic plant
(b) T. W. Engelmann with his experiment on a green alga
(c) C. B. van Niel with his experiment on purple and green sulphur bacteria
(d) Jan Ingenhousz with his experiment on an aquatic plant
Show Answer & Explanation
Answer: (d) Jan Ingenhousz with his experiment on an aquatic plant
Explanation:
1. Jan Ingenhousz showed, using an aquatic plant (\(\textit{Hydrilla}\)) in a transparent jar, that sunlight is essential and that only the green parts of the plant release oxygen.
2. Priestley showed that plants restore air, Engelmann described the action spectrum, and van Niel showed that oxygen comes from water.
Teacher's Note:
1. Priestley discovered the role of plants in restoring air, but not the need for sunlight.
2. Engelmann used the alga \(\textit{Cladophora}\) and aerobic bacteria.
(a) A = 9.45 kcal/g, B = 4.0 kcal/g
(b) A = 9.0 kcal/g, B = 5.65 kcal/g
(c) A = 9.45 kcal/g, B = 9.0 kcal/g
(d) A = 4.1 kcal/g, B = 4.0 kcal/g
Show Answer & Explanation
Answer: (c) A = 9.45 kcal/g, B = 9.0 kcal/g
Explanation:
1. The gross calorific value of fat is 9.45 kcal/g and the physiological value (energy available to the body) is 9.0 kcal/g.
2. Carbohydrates give 4.1 kcal/g (gross) and 4.0 kcal/g (physiological), and proteins give 5.65 and 4.0 kcal/g.
Teacher's Note:
1. Physiological value is slightly lower than gross because digestion and absorption are not 100 percent efficient.
2. Fat gives more than twice the energy of carbohydrate per gram.
(a) abscisic acid
(b) ethylene
(c) cytokinin
(d) gibberellin
Show Answer & Explanation
Answer: (c) cytokinin
Explanation:
1. Auxin from the apical bud suppresses the growth of the lateral (axillary) buds.
2. Cytokinins promote the growth of lateral buds, so they oppose the effect of auxin and are antagonistic to it in apical dominance.
Teacher's Note:
1. Removing the apical bud (decapitation) releases the lateral buds, so hedges are pruned.
2. Cytokinins also delay senescence and promote cytokinesis.
(a) bryophytes
(b) psilophytons
(c) tracheophytes
(d) chlorophytes
Show Answer & Explanation
Answer: (b) psilophytons
Explanation:
1. Psilophytons (the early vascular plants such as \(\textit{Rhynia}\)) were the ancestors of the ferns, and through progymnosperms the conifers arose from them.
Teacher's Note:
1. Psilophytes are extinct early land plants and Psilotum is a living relative.
2. Bryophytes are a separate side branch and did not give rise to vascular plants.
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