Biology Objective Questions and Answers: Biotechnology Principles and Processes
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Multiple Choice Questions
(a) Positively charged
(b) Negatively charged
(c) Neutral
(d) Either positively or negatively charged depending on their size
Show Answer & Explanation
Answer: (b) Negatively charged
Explanation:
1. DNA fragments are negatively charged because of phosphate group.
(a) Bromophenol blue
(b) Acetocarmine
(c) Aniline blue
(d) Ethidium bromide
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Answer: (d) Ethidium bromide
Explanation:
1. Ethidium bromide is used to stain the DNA fragments and will appear as orange coloured bands under UV light.
(a) The larger the fragment size, the farther it moves
(b) The smaller the fragment size, the farther it moves
(c) Positively charged fragments move to farther end
(d) Negatively charged fragments do not move
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Answer: (b) The smaller the fragment size, the farther it moves
Explanation:
1. During gel electrophoresis, DNA fragments separate (resolve) according to their size through sieving effect provided by agarose gel.
(a) Purification of product
(b) Addition of preservatives to the product
(c) Availability of oxygen throughout the process
(d) Ensuring anaerobic conditions in the culture vessel
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Answer: (c) Availability of oxygen throughout the process
Explanation:
1. Stirred-tank bioreactor is provided with stirrer for availability of oxygen throughout the process.
(a) Eco RI
(b) Taq polymerase
(c) Polymerase III
(d) Ligase
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Answer: (d) Ligase
Explanation:
1. In DNA recombinant technology, linking of foreign DNA and plasmid is made possible by DNA ligase which is also called "molecular glue".
(a) Separation
(b) Purification
(c) Preservation
(d) Expression
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Answer: (d) Expression
Explanation:
1. After the completion of biosynthetic pathway, downstreaming processing includes all the steps involved in isolation, purification and preservation of products.
2. All the steps before the completion of pathway are included in upstreaming processing i.e., expression of genetic material.
(a) Sal I
(b) Eco RV
(c) Xho I
(d) Hind III
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Answer: (b) Eco RV
Explanation:
1. Eco RV cuts the DNA in the centre of restriction sites forming blunt ends.
2. The pallindromic sequence for Eco RV is 5 3 G AT AT C C T AT A G 3 5.
(a) Pseudomonas putida
(b) Thermus aquaticus
(c) Thiobacillus ferroxidans
(d) Bacillus subtilis
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Answer: (b) Thermus aquaticus
Explanation:
1. Taq polymerase is thermostable DNA polymerase obtained from Thermus aquaticus.
(a) RNase
(b) Hind II
(c) Protease
(d) DNase I
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Answer: (b) Hind II
Explanation:
1. Hind II is a restriction endonuclease.
(a) Carrier
(b) Transformer
(c) Vector
(d) Template
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Answer: (c) Vector
Explanation:
1. The DNA molecule to which the gene of interest is integrated for cloning is called vector.
(a) Ligases
(b) Restriction enzymes
(c) Probes
(d) Selectable markers
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Answer: (b) Restriction enzymes
Explanation:
1. The cutting of DNA at specific locations became possible with the discovery of restriction enzymes called molecular scissors or knife.
(a) DNA fingerprinting
(b) Disarming pathogen vectors
(c) Transformation of plant cells
(d) Constructing recombinant DNA by joining with vectors
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Answer: (c) Transformation of plant cells
Explanation:
1. This is so because gene gun inserts recombinant DNA into host cells which leads to transformation of plant cells.
(a) To keep the cultures free of infection
(b) As selectable markers
(c) To select healthy vectors
(d) As sequences from where replication starts
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Answer: (b) As selectable markers
Explanation:
1. The host cells must naturally be sensitive to the antibiotic in questions so that any vector molecule which transforms a host cell can confer antibiotic resistance.
2. By plating transformed cells on a medium containing the antibiotic, only those cells that have been transformed by vector molecules survive.
(a) coli
(b) colon
(c) coelom
(d) coenzyme
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Answer: (a) coli
Explanation:
1. E co R I Order in which enzyme were isolated Escherichia Rough strain (RY13 strain) coli.
(a) Degrade sewage
(b) Produce methane
(c) Obtain antibiotics
(d) Purify enzymes
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Answer: (c) Obtain antibiotics
Explanation:
1. Conditions in which continuous addition of sugars in fed batch fermentation is done to obtain antibiotics.
(a) Retrovirus
(b) Baculovirus
(c) Salmonella typhimurium
(d) Rhizopus nigricans
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Answer: (a) Retrovirus
Explanation:
1. Retroviruses are most commonly used as they have a relatively high insert capacity.
(a) Identification of the DNA with desirable genes
(b) Cleaving DNA segments with ‘ligase’ and joining them with endonuclease
(c) Introduction of the identified DNA into the host
(d) Maintenance of introduced DNA in the host and transfer of DNA to its progeny
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Answer: (b) Cleaving DNA segments with ‘ligase’ and joining them with endonuclease
Explanation:
1. Cleaving DNA segments with endonuclease and joining them with 'ligase'.
(a) Plasmids are used widely in gene transfer
(b) These are found in viruses
(c) Plasmids contain genes for vital activities
(d) These are main part of chromosome
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Answer: (a) Plasmids are used widely in gene transfer
Explanation:
1. These are found in bacteria and some yeast cells.
2. Chromosomal DNA contains vital genes necessary for cell.
3. Plasmid is extra chromosomal DNA.
(a) Down stream processing
(b) Upstream processing
(c) Elution
(d) Insertional inactivation
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Answer: (c) Elution
Explanation:
1. Down streaming processing the recovery and purification of biosynthetic products, particularly pharmaceuticals, from natural sources such as animal or plant tissue or fermentation both, including the recycling of salvageable components.
2. Upstreaming processing process from cell isolation and cultivation to cell banking and culture expansion of the cells until final harvest.
3. Insertional inactivation is the inactivation of a gene upon insertion of another gene inside in its place or within its coding sequence.
(a) Blunt ends
(b) Sticky ends
(c) Staggered end
(d) Both (2) & (3)
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Answer: (d) Both (2) & (3)
Explanation:
1. In Blunt ends the cleavage point occur exactly on the axis of symmetry. 5'–G–A–T–A–T–C–3' EcoRV 5'–G–A–T A–T–C–3' 3'–C–T–A–T–A–G–5' 3'–C–T–A T–A–G–5' Blunt cut Cleavage site 5'–G–A–A–T–T–C–3' EcoRI 5'–G 5'–AA–T–T–C–3' 3'–C–T–T–A–A–G–3' 3'–C–T–T–A–A–5' G–5' Stick or staggered cut.
(a) Alkaline phosphatase
(b) Restriction endonuclease
(c) DNA ligase
(d) DNA polymerase
Show Answer & Explanation
Answer: (c) DNA ligase
Explanation:
1. DNA ligase: Catalyzes the joining of DNA strands together.
2. Alkaline phosphatase: Removes phosphate groups from the 5' ends of DNA molecules, which prevents these molecules from being ligated to one another.
3. Restriction endonuclease: Enzyme that cuts DNA at or near specific recognition nucleotide sequence.
4. DNA polymerase: Enzymes that create DNA molecules by assembling nucleotides, the building blocks of DNA.
(a) This will result in the inactivation of the enzyme
(b) The presence of chromogenic substrate will give blue coloured colonies
(c) The recombinant colonies do not produce any colour
(d) Both (1) & (3) are correct
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Answer: (d) Both (1) & (3) are correct
Explanation:
1. Blue coloured colonies are produced when plasmid does not have an insert.
(a) Formed by reverse transcriptase
(b) Cloned DNA
(c) Circular DNA
(d) Recombinant DNA
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Answer: (a) Formed by reverse transcriptase
Explanation:
1. cDNA (complementary DNA) is a double stranded DNA synthesized from a messenger RNA template in a reaction catalysed by enzyme reverse transcriptase.
2. Cloned DNA– DNA created by copying of DNA fragements, cells, or organisms.
3. Circular DNA is a form of DNA that is found in viruses, bacteria.
4. Recombinant DNA– DNA that has been formed artificially by combining constituents from different organisms.
Multiple Choice Questions (MCQs) for NEET Biology Biotechnology Principles and Processes
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FAQs
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