Python Strings, List, Tuple, Dictionary, Module MCQs with Answers Set 05

Question. What Will be The output Of the following code snippet?
\(myList = [1, 3, 3, 3, 3, 1]\)
\(max = myList[0]\)
\(indexOfMax = 0\)
\(for\ x\ in\ range(1, len(myList)):\)
\(\ \ \ \ if\ myList[x] > max:\)
\(\ \ \ \ \ \ \ \ max = myList[x]\)
\(\ \ \ \ \ \ \ \ indexOfMax = x\)
\(print(indexOfMax)\)
(a) 0
(b) 1
(c) 2
(d) 3
Answer: (b)

Question. Let list1 = [3, 4, 5, 20, 5, 25, 1, 3], what is list1.index(5)?
(a) 0
(b) 4
(c) 1
(d) 2
Answer: (d)

Question. What is list("pqrs")?
(a) ['p', 'q', 'r', 's']
(b) ['pq']
(c) ['rs']
(d) ['pqrs']
Answer: (a)

Question. What will be the output of the following code snippet?
\(myList = [0, 1, 2, 3, 4, 5]\)
\(for\ x\ in\ range(1, 5):\)
\(\ \ \ \ myList[x - 1] = myList[x]\)
\(for\ x\ in\ range(0, 5):\)
\(\ \ \ \ print(myList[x], end = "\ ")\)
(a) 2 3 4 5 6 1
(b) 1 1 2 3 4 5
(c) 6 1 2 3 4 5
(d) 1 2 3 4 4
Answer: (d)

Question. What is list("a#b#c#d".split('#'))?
(a) ['a', 'b', 'c', 'd']
(b) ['a b c d']
(c) ['a#b#c#d']
(d) ['abcd']
Answer: (a)

Question. To add 5 to the end of list1, use _______.
(a) list1.add(5)
(b) list1.append(5)
(c) list1.addLast(5)
(d) list1.addEnd(5)
Answer: (b)

Question. list1 = [11, 2, 23] and list2 = [11, 2, 2], list1 < list2 is ________
(a) True
(b) False
Answer: (b)

Question. What will be the output of the following code snippet?
\(def\ x(values):\)
\(\ \ \ \ values[0] = 33\)
\(v = [1, 2, 3]\)
\(x(v)\)
\(print(v)\)
(a) [1, 2, 3, 33]
(b) [1, 2, 3]
(c) [1, 33]
(d) [33, 2, 3]
Answer: (d)

Question. Let list1 = [0, 3, 2], what is sum(list1)?
(a) 5
(b) 4
(c) 6
(d) 2
Answer: (a)

Question. To remove string "red" from list1, use _______.
(a) list1.remove("red")
(b) list1.remove(red)
(c) list1.removeAll("red")
(d) list1.removeOne("red")
Answer: (a)

Question. What will be the output of the following code?
\(list1 = [12, 3, 25]\)
\(list2 = [12, 3, 2]\)
\(print(list1 > list2)\)
(a) False
(b) True
(c) Error
(d) None
Answer: (b)

Question. What will be the output of the following code?
\(numbers = [2, 4, 6]\)
\(numbers.append([1,2,3,4])\)
\(print(len(numbers))\)
(a) 6
(b) 7
(c) 4
(d) 22
Answer: (c)

Question. What will be the output of the following code?
\(names1 = ['Bertha', 'Davida', 'Monika']\)
\(names2 = [name.lower()\ for\ name\ in\ names1]\)
\(print(names2[2][0])\)
(a) b
(b) m
(c) d
(d) None
Answer: (b)

Question. What will be the output of the following code?
\(p="python"\)
\(q=list((f.upper(),len(f))\ for\ f\ in\ p)\)
\(print(q)\)
(a) [('P', 1), ('Y', 1), ('T', 1), ('H', 1), ('O', 1), ('N', 1)]
(b) [('PYTHON', 5)]
(c) [('P', 1), ('Y', 1), ('T', 1), ('H', 1), ('O', 1), ('N', 1)]
(d) Syntax error
Answer: (a)

Question. To which of the following the “in” operator can be used to check if an item is in it?
(a) Dictionary
(b) Set
(c) Lists
(d) All of the above
Answer: (d)

Question. What will be the output of the following code?
\(def\ x(values):\)
\(\ \ \ \ values[0] = 45\)
\(v = [2, 4, 6]\)
\(x(v)\)
\(print(v)\)
(a) [ 45, 6, 4,]
(b) [45, 4]
(c) [4, 6, 45 ]
(d) [45, 4, 6]
Answer: (d)

Question. Suppose list1 is [3, 4, 15, 15, 25, 15], what is list1.index(15)?
(a) 0
(b) 5
(c) 2
(d) 3
Answer: (c)

Question. What will be the output of the following code?
\(my\_List = [1, 2, 3, 4, 5]\)
\(for\ i\ in\ range(1, 5):\)
\(\ \ \ \ my\_List[i - 1] = my\_List[i]\)
\(for\ i\ in\ range(0, 5):\)
\(\ \ \ \ print(my\_List[i], end = "\ ")\)
(a) 2 2 3 4 3 3 6 3 3 4 5 2 3 4 4 5 4 5 5
(b) 2 2 3 4 3 3 4 5 4 4 5 2 3 4 2 3 3 4 5
(c) 2 2 3 4 5 2 3 3 4 5 2 3 4 4 5 2 3 4 5 5
(d) 2 2 2 3 4 5 2 2 2 2 3 4 5 3 4 5 2 3 4 5
Answer: (c)

Question. What will be the output of the following code?
\(my\_List = [2, 6, 6, 6, 6, 2]\)
\(max = my\_List[0]\)
\(indexOfMax = 0\)
\(for\ i\ in\ range(2, len(my\_List)):\)
\(\ \ \ \ if\ my\_List[i] > max:\)
\(\ \ \ \ \ \ \ \ max = my\_List[i]\)
\(\ \ \ \ \ \ \ \ indexOfMax = i\)
\(print(indexOfMax)\)
(a) 1
(b) 2
(c) 3
(d) 4
Answer: (b)

Question. What will be the output of the following code?
\(q=[5,6,7,8]\)
\(p=list(filter(lambda\ x:x\%2,q))\)
\(print(p)\)
(a) [5,8]
(b) [ ]
(c) [5, 7]
(d) Invalid arguments for filter function
Answer: (c)

Question. What will be the output of the following code?
\(x=[12,48,15]\)
\(x.append([77])\)
\(x.extend([40,60])\)
\(print(x)\)
(a) [12,48,15, [77]40,60]
(b) [12, 48, 15, [77], 40, 60]
(c) [12, 48, 15, 77,[ 40, 60]]
(d) [12,48,15,77,[ 40, 60]]
Answer: (b)