JEE Mathematics Circles MCQs Set C

Practice JEE Mathematics Circles MCQs Set C provided below. The MCQ Questions for JEE Circles Mathematics with answers and follow the latest JEE (Main)/ NCERT and KVS patterns. Refer to more Chapter-wise MCQs for JEE (Main) JEE Mathematics and also download more latest study material for all subjects

MCQ for JEE Mathematics Circles

JEE Mathematics students should review the 50 questions and answers to strengthen understanding of core concepts in Circles

Circles MCQ Questions JEE Mathematics with Answers

Question. The angle between the pair of tangents from the point (1, 1/2) to the circle \( x^2 + y^2 + 4x + 2y – 4 = 0 \) is
(a) \( \cos^{-1}(4/5) \)
(b) \( \sin^{-1}(4/5) \)
(c) \( \sin^{-1}(3/5) \)
(d) None of the options
Answer: (b) \( \sin^{-1}(4/5) \)

Question. The chords of contact of the pair of tangents to the circle \( x^2 + y^2 = 1 \) drawn from any point on the line \( 2x + y = 4 \) pass through the point
(a) (1/2, 1/4)
(b) (1/4, 1/2)
(c) (1, 1/2)
(d) (1/2, 1)
Answer: (a) (1/2, 1/4)

Question. A foot of the normal from the point (4, 3) to a circle is (2, 1) and a diameter of the circle has the equation \( 2x – y = 2 \). Then the equation of the circle is
(a) \( x^2 + y^2 + 2x – 1 = 0 \)
(b) \( x^2 + y^2 - 2x – 1 = 0 \)
(c) \( x^2 + y^2 - 2y – 1 = 0 \)
(d) None of the options
Answer: (b) \( x^2 + y^2 - 2x – 1 = 0 \)

Question. The line \( \lambda x + \mu y = 1 \) is a normal to the circle \( 2x^2 + 2y^2 – 5x + 6y – 1 = 0 \) if
(a) \( 5\lambda - 6\mu = 2 \)
(b) \( 4 + 5\mu = 6\lambda \)
(c) \( 5\lambda - 6\mu = 4 \)
(d) None of the options
Answer: (c) \( 5\lambda - 6\mu = 4 \)

Question. The number of feet of normals from the point (7, -4) to the circle \( x^2 + y^2 = 5 \) is
(a) 1
(b) 2
(c) 3
(d) 4
Answer: (b) 2

Question. The equation of a chord of the circle \( x^2 + y^2 – 4x = 0 \) which is bisected at the point (1, 1) is
(a) \( x + y = 2 \)
(b) \( 3x – y = 2 \)
(c) \( x – 2y + 1 = 0 \)
(d) \( x – y = 0 \)
Answer: (d) \( x – y = 0 \)

Question. Lines are drawn through the point P(-2, -3) to meet the circle \( x^2 + y^2 – 2x – 10y + 1 = 0 \). The length of the line segment PA, A being the point on the circle where the line meets the circle sat coincident points, is
(a) 16
(b) \( 4\sqrt{3} \)
(c) 48
(d) None of the options
Answer: (b) \( 4\sqrt{3} \)

Question. The equations of two circles are \( x^2 + y^2 + 2\lambda x + 5 = 0 \) and \( x^2 + y^2 + 2\lambda y + 5 = 0 \). P is any point on the line \( x - y = 0 \). If PA and PB are then lengths of the tangents from P to the two circles and PA = 3 then PB is equal to
(a) 1.5
(b) 6
(c) 3
(d) None of the options
Answer: (c) 3

Question. The common chord of the circle \( x^2 + y^2 + 6x + 8y – 7 = 0 \) and a circle passing through the origin, touching the line \( y = x \), always passes through the point
(a) (-1/2, 1/2)
(b) (1, 1)
(c) (1/2, 1/2)
(d) None of the options
Answer: (c) (1/2, 1/2)

Question. A tangent to the circle \( x^2 + y^2 = 1 \) through the point (0, 5) cuts the circle \( x^2 + y^2 = 4 \) at A and B. The tangents to the circle \( x^2 + y^2 = 4 \) at A and B meet at C. The coordinates of C are
(a) \( ( \frac{8}{5}\sqrt{6}, \frac{4}{5} ) \)
(b) \( ( \frac{8}{5}\sqrt{6}, -\frac{4}{5} ) \)
(c) \( ( -\frac{8}{5}\sqrt{6}, -\frac{4}{5} ) \)
(d) None of the options
Answer: (a) \( ( \frac{8}{5}\sqrt{6}, \frac{4}{5} ) \)

Question. If the common chord of the circles \( x^2 + (y - \lambda)^2 = 16 \) and \( x^2 + y^2 = 16 \) subtend a right angle at the origin then \( \lambda \) is equal to
(a) 4
(b) \( 4\sqrt{2} \)
(c) \( \pm 4\sqrt{2} \)
(d) 8
Answer: (c) \( \pm 4\sqrt{2} \)

Question. The equation of the smallest circle passing through the intersection of the line \( x + y = 1 \) and the circle \( x^2 + y^2 = 9 \) is
(a) \( x^2 + y^2 + x + y – 8 = 0 \)
(b) \( x^2 + y^2 – x – y – 8 = 0 \)
(c) \( x^2 + y^2 – x + y – 8 = 0 \)
(d) None of the options
Answer: (b) \( x^2 + y^2 – x – y – 8 = 0 \)

Question. The equation of a circle is \( x^2 + y^2 = 4 \). The centre of the smallest circle touching this circle and the line \( x + y = 5\sqrt{2} \) has the coordinates
(a) \( ( \frac{7}{2\sqrt{2}}, \frac{7}{2\sqrt{2}} ) \)
(b) \( ( 3/2, 3/2 ) \)
(c) \( ( -\frac{7}{2\sqrt{2}}, -\frac{7}{2\sqrt{2}} ) \)
(d) None of the options
Answer: (a) \( ( \frac{7}{2\sqrt{2}}, \frac{7}{2\sqrt{2}} ) \)

Question. The members of a family of circles are given by the equation \( 2(x^2 + y^2) + \lambda x – (1 + \lambda^2)y – 10 = 0 \). The number of circles belonging to the family that are cut orthogonally by the fixed circle \( x^2 + y^2 + 4x + 6y + 3 = 0 \) is
(a) 2
(b) 1
(c) 0
(d) None of the options
Answer: (a) 2

Question. The equation of the circle with the chord \( y = 2x \) of the circle \( x^2 + y^2 – 10x = 0 \) as its diameter is
(a) \( x^2 + y^2 – 2x – 4y – 5 = 0 \)
(b) \( x^2 + y^2 = 2x + 4y \)
(c) \( x^2 + y^2 = 4x + 2y \)
(d) None of the options
Answer: (b) \( x^2 + y^2 = 2x + 4y \)

Question. A circle of radius 2 touches the coordinate axes in the first quadrant. If the circle makes a complete rotation on the x-axis along the positive direction of the x-axis then the equation of the circle in the new position is
(a) \( x^2 + y^2 - 4(x + y) - 8\pi x + (2 + 4\pi)^2 = 0 \)
(b) \( x^2 + y^2 – 4x – 4y + (2 + 4\pi)^2 = 0 \)
(c) \( x^2 + y^2 - 8\pi x – 4y + (2 + 4\pi)^2 = 0 \)
(d) None of the options
Answer: (a) \( x^2 + y^2 - 4(x + y) - 8\pi x + (2 + 4\pi)^2 = 0 \)

Question. A ray of light incident at the point (-2, -1) gets reflected from the tangent at (0, -1) to the circle \( x^2 + y^2 = 1 \). The reflected ray touches the circle. The equation of the line along which the incident ray moved is
(a) \( 4x – 3y + 11 = 0 \)
(b) \( 4x + 3y + 11 = 0 \)
(c) \( 3x + 4y + 11 = 0 \)
(d) None of the options
Answer: (b) \( 4x + 3y + 11 = 0 \)

Question. The locus of the centres of the circles for which one end of a diameter is (1, 1) while the other end is on the line \( x + y = 3 \) is
(a) \( x + y = 1 \)
(b) \( 2(x – y) = 5 \)
(c) \( 2x + 2y = 5 \)
(d) None of the options
Answer: (c) \( 2x + 2y = 5 \)

Question. The angle between a pair of tangents drawn from a point P to the curve \( x^2 + y^2 + 4x – 6y + 9\sin^2\alpha + 13\cos^2\alpha = 0 \) is \( 2\alpha \). The locus of P is
(a) \( x^2 + y^2 + 4x – 6y + 4 = 0 \)
(b) \( x^2 + y^2 + 4x – 6y – 9 = 0 \)
(c) \( x^2 + y^2 + 4x – 6y – 4 = 0 \)
(d) \( x^2 + y^2 + 4x – 6y + 9 = 0 \)
Answer: (d) \( x^2 + y^2 + 4x – 6y + 9 = 0 \)

Question. The point P moves in the plane of a regular hexagon such that the sum of the squares of its distances from the vertices of the hexagon is \( 6a^2 \). If the radius of the circumcircles of the hexagon is \( r(< a) \) then the locus of P is
(a) a pair of straight lines
(b) an ellipse
(c) a circle of radius \( \sqrt{a^2 – r^2} \)
(d) an ellipse of major axis a and minor axis r
Answer: (c) a circle of radius \( \sqrt{a^2 – r^2} \)

Question. The locus of the middle points of chords of length 4 of the circle \( x^2 + y^2 = 16 \) is
(a) a straight line
(b) a circle of radius 2
(c) a circle of radius \( 2\sqrt{3} \)
(d) an ellipse
Answer: (c) a circle of radius \( 2\sqrt{3} \)

Question. The equation of the locus of the middle point of a chord of the circle \( x^2 + y^2 = 2(x + y) \) such that the pair of lines joining the origin to the point of intersection of the chord and the circle are equally inclined to the x-axis is
(a) \( x + y = 2 \)
(b) \( x – y = 2 \)
(c) \( 2x – y = 1 \)
(d) None of the options
Answer: (a) \( x + y = 2 \)

Question. The locus of the centres of circles passing through the origin and intersecting the fixed circle \( x^2 + y^2 - 5x + 3y – 1 = 0 \) orthogonally is
(a) a straight line of the slope 3/5
(b) a circle
(c) a pair of straight lines
(d) None of the options
Answer: (d) None of the options

Question. The equation of a circle \( C_1 \) is \( x^2 + y^2 – 4x – 2y – 11 = 0 \). A circle \( C_2 \) of radius 1 rolls on the outside of the circle \( C_1 \). The locus of the centre of \( C_2 \) has the equation
(a) \( x^2 + y^2 – 4x – 2y – 20 = 0 \)
(b) \( x^2 + y^2 + 4x + 2y – 20 = 0 \)
(c) \( x^2 + y^2 – 3x – y – 11 = 0 \)
(d) None of the options
Answer: (a) \( x^2 + y^2 – 4x – 2y – 20 = 0 \)

Question. Circles are drawn through the point (3, 0) to cut an intercept of length 6 units on the negative direction of the x-axis. The equation of the locus of their centres is
(a) the x-axis
(b) \( x – y = 0 \)
(c) the y-axis
(d) \( x + y = 0 \)
Answer: (c) the y-axis

Question. The locus of the centre of a circle touching the line \( x + 2y = 0 \) and \( x – 2y = 0 \) is
(a) \( xy = 0 \)
(b) \( x = 0 \)
(c) \( y = 0 \)
(d) None of the options
Answer: (a) \( xy = 0 \)

Question. The locus of a point from which the lengths of the tangents to the circles \( x^2 + y^2 = 4 \) and \( 2(x^2 + y^2) – 10x + 3y – 2 = 0 \) are equal to
(a) a straight line inclined at \( \pi/4 \) with the line joining the centres of the circles
(b) a circles
(c) an ellipse
(d) a straight line perpendicular to the line joining the centres of the circles
Answer: (d) a straight line perpendicular to the line joining the centres of the circles

Question. The locus of the centres of the circles passing through the intersection of the circles \( x^2 + y^2 = 1 \) and \( x^2 + y^2 - 2x + y = 0 \) is
(a) a line whose equation is \( x + 2y = 0 \)
(b) a line whose equation is \( 2x – y = 1 \)
(c) a circle
(d) a pair of lines
Answer: (a) a line whose equation is \( x + 2y = 0 \)

Choose the correct options. One or more options may be correct.

Question. The point of contact of tangent from the point (1, 2) to the circle \( x^2 + y^2 = 1 \) has the coordinates
(a) \( ( \frac{1 - 2\sqrt{19}}{5}, \frac{2 + \sqrt{19}}{5} ) \)
(b) \( ( \frac{1 - 2\sqrt{19}}{5}, \frac{2 - \sqrt{19}}{5} ) \)
(c) \( ( \frac{1 + 2\sqrt{19}}{5}, \frac{2 + \sqrt{19}}{5} ) \)
(d) \( ( \frac{1 + 2\sqrt{19}}{5}, \frac{2 - \sqrt{19}}{5} ) \)
Answer: (a) and (d)

Question. The equation of a circle \( C_1 \) is \( x^2 + y^2= 4 \). The locus of the intersection of orthogonal tangents to the circle is the curve \( C_2 \) and the locus of the intersection of perpendicular tangents to the curve \( C_2 \) is the curve \( C_3 \). Then
(a) \( C_3 \) is a circle
(b) the area enclosed by the curve \( C_3 \) is \( 8\pi \)
(c) \( C_2 \) and \( C_3 \) are circles with the same centre
(d) None of the options
Answer: (a) \( C_3 \) is a circle and (c) \( C_2 \) and \( C_3 \) are circles with the same centre

Question. A line parallel to the line \( x – 3y = 2 \) touches the circle \( x^2 + y^2 – 4x + 2y – 5 = 0 \) at the point
(a) (1, -4)
(b) (1, 2)
(c) (3, -4)
(d) (3, 2)
Answer: (b) (1, 2) and (c) (3, -4)

Question. A point on the line \( x = 3 \) from which the tangents drawn to the circle \( x^2 + y^2 = 8 \) are at right angles is
(a) \( (3, -\sqrt{7}) \)
(b) \( (3, \sqrt{23}) \)
(c) \( (3, \sqrt{7}) \)
(d) \( (3, -\sqrt{23}) \)
Answer: (a) \( (3, -\sqrt{7}) \) and (c) \( (3, \sqrt{7}) \)

Question. Tangents drawn from (2, 0) to the circle \( x^2 + y^2 = 1 \) touches the circle at A and B. Then
(a) \( A = ( \frac{1}{2}, \frac{\sqrt{3}}{2} ), B = ( \frac{1}{2}, -\frac{\sqrt{3}}{2} ) \)
(b) \( A = ( -\frac{1}{2}, \frac{\sqrt{3}}{2} ), B = ( \frac{1}{2}, -\frac{\sqrt{3}}{2} ) \)
(c) \( A = ( \frac{1}{2}, \frac{\sqrt{3}}{2} ), B = ( \frac{1}{2}, -\frac{\sqrt{3}}{2} ) \)
(d) \( A = ( \frac{1}{2}, -\frac{\sqrt{3}}{2} ), B = ( \frac{1}{2}, \frac{\sqrt{3}}{2} ) \)
Answer: (c) and (d)

Question. The equations of four circles are \( (x \pm a)^2 + (y \pm a)^2 = a^2 \). The radius of a circle touching all the four circles is
(a) \( (\sqrt{2} - 1)a \)
(b) \( 2\sqrt{2}a \)
(c) \( (\sqrt{2} + 1)a \)
(d) \( (2 + \sqrt{2})a \)
Answer: (a) \( (\sqrt{2} - 1)a \) and (c) \( (\sqrt{2} + 1)a \)

Question. Let a line through the point P(5, 10) cut the line \( l \) whose equation is \( x + 2y = 5 \), at Q and the circle C whose equation is \( x^2 + y^2 = 25 \), at A and B. Then
(a) P is the pole of the line \( l \) with respect to the circle C
(b) \( l \) is the polar of the point P with respect to the circle C
(c) PA, PQ, PB are in AP
(d) PQ is the HM of PA and PB
Answer: (a), (b), and (d)

Question. The equation of a circle is \( x^2 + y^2 – 4x + 2y – 4 = 0 \). With respect to the circle
(a) the pole of the line \( x – 2y + 5 = 0 \) is (1, 1)
(b) the chord of contact of real tangents from (1, 1) is the line \( x – 2y + 5 = 0 \)
(c) the polar of the point (1, 1) is \( x – 2y + 5 = 0 \)
(d) None of the options
Answer: (a) the pole of the line \( x – 2y + 5 = 0 \) is (1, 1) and (c) the polar of the point (1, 1) is \( x – 2y + 5 = 0 \)

MCQs for Circles Mathematics JEE

Students can use these MCQs for Circles to quickly test their knowledge of the chapter. These multiple-choice questions have been designed as per the latest syllabus for JEE Mathematics released by JEE (Main). Our expert teachers suggest that you should practice daily and solving these objective questions of Circles to understand the important concepts and better marks in your school tests.

Circles NCERT Based Objective Questions

Our expert teachers have designed these Mathematics MCQs based on the official NCERT book for JEE. We have identified all questions from the most important topics that are always asked in exams. After solving these, please compare your choices with our provided answers. For better understanding of Circles, you should also refer to our NCERT solutions for JEE Mathematics created by our team.

Online Practice and Revision for Circles Mathematics

To prepare for your exams you should also take the JEE Mathematics MCQ Test for this chapter on our website. This will help you improve your speed and accuracy and its also free for you. Regular revision of these Mathematics topics will make you an expert in all important chapters of your course.

Where can I access latest JEE Mathematics Circles MCQs Set C?

You can get most exhaustive JEE Mathematics Circles MCQs Set C for free on StudiesToday.com. These MCQs for JEE Mathematics are updated for the 2025-26 academic session as per JEE (Main) examination standards.

Are Assertion-Reasoning and Case-Study MCQs included in the Mathematics JEE material?

Yes, our JEE Mathematics Circles MCQs Set C include the latest type of questions, such as Assertion-Reasoning and Case-based MCQs. 50% of the JEE (Main) paper is now competency-based.

How do practicing Mathematics MCQs help in scoring full marks in JEE exams?

By solving our JEE Mathematics Circles MCQs Set C, JEE students can improve their accuracy and speed which is important as objective questions provide a chance to secure 100% marks in the Mathematics.

Do you provide answers and explanations for JEE Mathematics Circles MCQs Set C?

Yes, Mathematics MCQs for JEE have answer key and brief explanations to help students understand logic behind the correct option as its important for 2026 competency-focused JEE (Main) exams.

Can I practice these Mathematics JEE MCQs online?

Yes, you can also access online interactive tests for JEE Mathematics Circles MCQs Set C on StudiesToday.com as they provide instant answers and score to help you track your progress in Mathematics.