Maharashtra Board Class 8 Maths Chapter 9 Discount and Commission Set 9.1 Solutions

Get the most accurate MSBSHSE Solutions for Class 8 Maths Chapter 9 Discount and Commission Set 9.1 here. Updated for the 2026-27 academic session, these solutions are based on the latest MSBSHSE textbooks for Class 8 Maths. Our expert-created answers for Class 8 Maths are available for free download in PDF format.

Detailed Chapter 9 Discount and Commission Set 9.1 MSBSHSE Solutions for Class 8 Maths

For Class 8 students, solving MSBSHSE textbook questions is the most effective way to build a strong conceptual foundation. Our Class 8 Maths solutions follow a detailed, step-by-step approach to ensure you understand the logic behind every answer. Practicing these Chapter 9 Discount and Commission Set 9.1 solutions will improve your exam performance.

Class 8 Maths Chapter 9 Discount and Commission Set 9.1 MSBSHSE Solutions PDF

Question 1. If marked price = Rs 1700, selling price = Rs 1540, then find the discount.
Answer: Solution:
Here, Marked price = Rs 1700,
selling price = Rs 1540
Selling price = Marked price - Discount
.:. 1540 = 1700 - Discount
.:. Discount = 1700 - 1540
= Rs 160
.:. The amount of discount is Rs 160.
In simple words: Discount is calculated as the difference between the marked price and the selling price. In this case, subtracting the selling price from the marked price directly gives the discount amount.

🎯 Exam Tip: Remember the basic formula: Discount = Marked Price - Selling Price. This is a fundamental concept for profit and loss calculations.

 

Question 2. If marked price Rs 990 and percentage of discount is 10, then find the selling price.
Answer: Solution:
Here, marked price = Rs 990,
discount = 10%
Let the percentage of discount be x
.:. x = 10%
i. Discount
\( = \frac{\text{Marked price} \times x}{100} \)
\( = \frac{990 \times 10}{100} \)
= Rs 99
ii. Selling price = Marked price - Discount
= 990 - 99
= Rs 891
.:. The selling price is Rs 891.
In simple words: First, calculate the amount of discount by finding 10% of the marked price. Then, subtract this discount amount from the marked price to get the final selling price.

🎯 Exam Tip: Always calculate the actual discount amount before determining the selling price when a percentage discount is given.

 

Question 3. If selling price Rs 900, discount is 20%, then find the marked price.
Answer: Solution:
Here, selling price = Rs 900, discount = 20%
Let the marked price be Rs 100
Since, the discount given = 20%
.:. Amount of discount = Rs 20
.:. Selling price = 100 - 20 = Rs 80
Let actual marked price be Rs x
.:. For marked price of Rs x, selling price is Rs 900
\( \frac{80}{100} = \frac{900}{x} \)
.:. 80 x x = 100 × 900
\( x = \frac{100 \times 900}{80} \)
.:. x = Rs 1125
.:. The marked price is Rs 1125.
In simple words: If a 20% discount means the selling price is 80% of the marked price, then you can use a proportion to find the original marked price when the selling price is known.

🎯 Exam Tip: When working backward from selling price and discount percentage to find the marked price, assume a base marked price (e.g., Rs 100) to set up a ratio or proportion.

 

Question 4. The marked price of the fan is Rs 3000. Shopkeeper gave 12% discount on it. Find the total discount and selling price of the fan.
Answer: Solution:
Here, Marked price = Rs 3000, discount = 12%
Let the percentage of discount be x.
.:. x = 12%
i. Discount
\( = \frac{\text{Marked price} \times x}{100} \)
\( = \frac{3000 \times 12}{100} \)
= 30 × 12
= Rs 360
ii. Selling price = Marked price - Discount
= 3000 - 360
= Rs 2640
.:. The total discount is Rs 360 and the selling price of the fan is Rs 2640.
In simple words: Calculate the 12% discount on the marked price of Rs 3000 to find the discount amount. Then, subtract this discount from the marked price to find the final selling price.

🎯 Exam Tip: This question requires two calculations: first, the discount amount, and second, the selling price. Ensure both are clearly presented for full marks.

 

Question 5. The marked price of a mixer is Rs 2300. A customer purchased it for Rs 1955. Find percentage of discount offered to the customer.
Answer: Solution:
Here, marked price = Rs 2300,
selling price = Rs 1955
i. Selling price = Marked price - Discount
.:. 1955 = 2300 - Discount
.:. Discount = 2300 - 1955
= Rs 345
ii. Let the percentage of discount be x
\( \frac{x}{100} = \frac{\text{Discount}}{\text{Marked price}} \)
\( \frac{x}{100} = \frac{345}{2300} \)
\( \text{.: } x = \frac{345}{2300} \times 100 \)
\( = \frac{345}{23} \)
.:. x = 15%
.:. The percentage of discount offered to the customer is 15%.
In simple words: First, find the discount amount by subtracting the selling price from the marked price. Then, express this discount as a percentage of the original marked price.

🎯 Exam Tip: Percentage discount is always calculated on the Marked Price. Use the formula: \(\frac{\text{Discount}}{\text{Marked Price}} \times 100\%\).

 

Question 6. A shopkeeper gives 11% discount on a television set, hence the cost price of it is Rs 22,250. Then find the marked price of the television set.
Answer: Solution:
Here, selling price = Rs 22,250, discount = 11%
Let marked price be Rs 100
Since, the discount given = 11%
.:. Amount of discount = Rs 11
.:. Selling price = 100 - 11 = Rs 89
.:. Let actual marked price be Rs x
.:. For marked price of Rs x, selling price is Rs 22,250
\( \frac{89}{100} = \frac{22,250}{x} \)
.:. x × 89 = 100 × 22,250
\( \text{.: } x = \frac{100 \times 22,250}{89} \)
= 100 × 250
.:. x = Rs 25,000
.:. The marked price of the television set is Rs 25,000.
In simple words: Since an 11% discount means the selling price is 89% of the marked price, you can use a proportion to find the original marked price given the selling price.

🎯 Exam Tip: When the selling price and discount percentage are known, and you need to find the marked price, consider what percentage of the marked price the selling price represents (100% - discount%).

 

Question 7. After offering discount of 10% on marked price, a customer gets total discount of Rs 17. To find the cost price for the customer, fill in the following boxes with appropriate numbers and complete the activity.
Answer: Solution:
Suppose, marked price of the item = Rs 100 Therefore, for customer that item costs 100 - 10 = Rs 90.
Hence, when the discount is [10] then the selling price is [90] rupees.
Suppose when the discount is [17] rupees, the selling price is x rupees.
\( \frac{x}{17} = \frac{90}{10} \)
\( \text{.: } x = \frac{90 \times 17}{10} \)
.:. x = 9 × 17
.:. x = 153
.:. The customer will get the item for Rs 153.
In simple words: By setting up a proportion based on the relationship between discount and selling price, you can find the customer's cost price for a different discount amount.

🎯 Exam Tip: For fill-in-the-blanks activities, ensure your calculations for the initial assumed values (e.g., marked price Rs 100) are correct as they form the basis for the proportion.

 

Question 8. A shopkeeper decides to sell a certain item at a certain price. He tags the price on the item by increasing the decided price by 25%. While selling the item, he offers 20% discount. Find how many more or less percent he gets on the decided price.
Answer: Solution:
Here, price increase = 25%,
discount offered = 20%
Let the decided price be Rs 100
.:. Increase in price = Rs 25
.:. Shopkeeper marks the price = 100 + 25
= Rs 125
.:. marked price = Rs 125
Let the percentage of discount be x
.:. x = 20%
.:. Discount \( = \frac{\text{marked price} \times x}{100} \)
\( = \frac{125 \times 20}{100} \)
\( = \frac{2500}{100} \)
= Rs 25
.:. Selling price = Marked price - Discount
= 125 - 25
= Rs 100
.:. If the decided price is Rs 100, then shopkeeper gets Rs 100.
.:. The shopkeeper gets neither more nor less than the decided price i.e. he gets 0% more / less.
In simple words: Despite increasing the price by 25% and then offering a 20% discount, the final selling price turns out to be exactly the same as the original decided price, resulting in no net gain or loss percentage for the shopkeeper.

🎯 Exam Tip: When a price is first increased by a percentage and then discounted by another percentage, always calculate the new marked price first, and then apply the discount on that new marked price. Do not simply add and subtract percentages.

 

Maharashtra Board Class 8 Maths Chapter 9 Discount And Commission Practice Set 9.1 Intext Questions And Activities

 

Question 1. Write the appropriate numbers in the following boxes. (Textbook pg. no. 51)
Answer: Solution:
1. \( \frac{12}{100} \) = 12 percent = 12%
2. 47% = \( \frac{47}{100} \)
3. 86% = \( \frac{86}{100} \)
4. 4% of 300 = 300 × \( \frac{4}{100} \) = 12
5. 15% of 1700 = 1700 × \( \frac{15}{100} \) = 255
In simple words: This exercise reinforces the conversion between fractions, percentages, and calculating percentages of numbers. A percentage is simply a fraction out of 100.

🎯 Exam Tip: Practice converting between fractions and percentages regularly, as this forms the foundation for many percentage-based problems. Understanding that 'x% of a number' means \(\frac{x}{100} \times \text{number}\) is key.

 

Question 2. You may have seen advertisements like 'Monsoon Sale', 'Stock Clearance Sale' etc offering different discount. In such a sale, a discount is offered on various goods. Generally in the month of July, sales of clothes are declared. Find and discuss the purpose of such sales. (Textbook pg. no. 51)
Answer: Solution:
(Students should attempt the above activity on their own)
In simple words: Sales like 'Monsoon Sale' or 'Stock Clearance Sale' are often conducted by businesses to clear out old inventory, make space for new stock, attract more customers, and boost sales during specific periods.

🎯 Exam Tip: For descriptive questions or activities, focus on providing a clear and logical explanation. Think about the economic reasons behind sales and how they benefit both businesses and consumers.

MSBSHSE Solutions Class 8 Maths Chapter 9 Discount and Commission Set 9.1

Students can now access the MSBSHSE Solutions for Chapter 9 Discount and Commission Set 9.1 prepared by teachers on our website. These solutions cover all questions in exercise in your Class 8 Maths textbook. Each answer is updated based on the current academic session as per the latest MSBSHSE syllabus.

Detailed Explanations for Chapter 9 Discount and Commission Set 9.1

Our expert teachers have provided step-by-step explanations for all the difficult questions in the Class 8 Maths chapter. Along with the final answers, we have also explained the concept behind it to help you build stronger understanding of each topic. This will be really helpful for Class 8 students who want to understand both theoretical and practical questions. By studying these MSBSHSE Questions and Answers your basic concepts will improve a lot.

Benefits of using Maths Class 8 Solved Papers

Using our Maths solutions regularly students will be able to improve their logical thinking and problem-solving speed. These Class 8 solutions are a guide for self-study and homework assistance. Along with the chapter-wise solutions, you should also refer to our Revision Notes and Sample Papers for Chapter 9 Discount and Commission Set 9.1 to get a complete preparation experience.

FAQs

Where can I find the latest Maharashtra Board Class 8 Maths Chapter 9 Discount and Commission Set 9.1 Solutions for the 2026-27 session?

The complete and updated Maharashtra Board Class 8 Maths Chapter 9 Discount and Commission Set 9.1 Solutions is available for free on StudiesToday.com. These solutions for Class 8 Maths are as per latest MSBSHSE curriculum.

Are the Maths MSBSHSE solutions for Class 8 updated for the new 50% competency-based exam pattern?

Yes, our experts have revised the Maharashtra Board Class 8 Maths Chapter 9 Discount and Commission Set 9.1 Solutions as per 2026 exam pattern. All textbook exercises have been solved and have added explanation about how the Maths concepts are applied in case-study and assertion-reasoning questions.

How do these Class 8 MSBSHSE solutions help in scoring 90% plus marks?

Toppers recommend using MSBSHSE language because MSBSHSE marking schemes are strictly based on textbook definitions. Our Maharashtra Board Class 8 Maths Chapter 9 Discount and Commission Set 9.1 Solutions will help students to get full marks in the theory paper.

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Yes, we provide bilingual support for Class 8 Maths. You can access Maharashtra Board Class 8 Maths Chapter 9 Discount and Commission Set 9.1 Solutions in both English and Hindi medium.

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