Find trusted MSBSHSE Solutions for Class 7 Maths Chapter 14 Set 53 Algebraic Formulae Expansion of Squares below, updated for the 2026-27 term. Following standard MSBSHSE textbook editions for Class 7 Maths, these professional answers for Class 7 Maths give students complete explanations and are downloadable as free PDFs.
Detailed Chapter 14 Set 53 Algebraic Formulae Expansion of Squares MSBSHSE Solutions for Class 7 Maths
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Question 1. Factorize the following expressions:
(i) p² - q²
(ii) 4x² - 25y²
(iii) y² - 4
(iv) p² - \( \frac{1}{25} \)
(v) 9x² - \( \frac{1}{16} \)y²
(vi) x² - \( \frac{1}{x^2} \)
(vii) a²b - ab
(viii) 4x²y - 6x²
(ix) \( \frac{1}{2} \)y² - 8z²
(x) 2x² - 8y²
Answer:
(i) p² - q²
Here, a = p, b = q
\( \implies \) p² - q² = (p + q)(p - q)
....[(a² - b²) = (a + b)(a - b)]
(ii) 4x² - 25y²
= (2x)² - (5y)²
Here, a = 2x, b = 5y
\( \implies \) (2x)² - (5y)² = (2x + 5y)(2x - 5y)
....[(a² - b²) = (a + b)(a - b)]
(iii) y² - 4
= y² - 2²
Here, a = y, b = 2
\( \implies \) y² - 2² = (y + 2)(y - 2)
....[(a² - b²) = (a + b)(a - b)]
(iv) p² - \( \frac{1}{25} \)
Here a = p, b = \( \frac{1}{5} \)
\( \implies \) p² - \( (\frac{1}{5})^2 \) = \( (p + \frac{1}{5}) (p - \frac{1}{5}) \)
....[(a² - b²) = (a + b)(a - b)]
(v) 9x² - \( \frac{1}{16} \)y²
Here a = 3x, b = \( \frac{1}{4} \)y
\( \implies \) (3x)² - \( (\frac{1}{4}y)^2 \) = \( (3x + \frac{1}{4}y) (3x - \frac{1}{4}y) \)
....[(a² - b²) = (a + b)(a - b)]
(vi) x² - \( \frac{1}{x^2} \)
Here a = x, b = \( \frac{1}{x} \)
\( \implies \) x² - \( (\frac{1}{x})^2 \) = \( (x + \frac{1}{x})(x - \frac{1}{x}) \)
....[(a² - b²) = (a + b)(a - b)]
(vii) a²b - ab
= a (ab - b)
= ab (a - 1)
(viii) 4x²y - 6x²
= 2 (2x²y - 3x²)
= 2x² (2y - 3)
(ix) \( \frac{1}{2} \)y² - 8z²
= \( \frac{1}{2} \)y² - \( \frac{2 \times 8}{2} \)z²
= \( \frac{1}{2} \)y² - \( \frac{16}{2} \)z²
= \( \frac{1}{2} \)(y² - 16z²)
= \( \frac{1}{2} \)[y² - (4z)²]
= \( \frac{1}{2} \)[(y + 4z)(y - 4z)]
(x) 2x² - 8y²
= 2 (x² - 4y²)
= 2 [x² - (2y)²]
= 2(x + 2y)(x - 2y)
....[(a² - b²) = (a + b)(a - b)]
In simple words: This question asks to factorize algebraic expressions by identifying common factors or applying the difference of squares formula, \( (a^2 - b^2) = (a - b)(a + b) \), to simplify each given expression into its factors.
🎯 Exam Tip: Mastering the difference of squares formula and identifying common factors is crucial for scoring well in factorization problems. Show each step clearly, especially the identification of 'a' and 'b' terms.
MSBSHSE Solutions for Class 7 Maths Chapter 14 Set 53 Algebraic Formulae Expansion of Squares
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