Get the most accurate MSBSHSE Solutions for Class 5 Math Chapter 2 Number Work Set 5 here. Updated for the 2026-27 academic session, these solutions are based on the latest MSBSHSE textbooks for Class 5 Math. Our expert-created answers for Class 5 Math are available for free download in PDF format.
Detailed Chapter 2 Number Work Set 5 MSBSHSE Solutions for Class 5 Math
For Class 5 students, solving MSBSHSE textbook questions is the most effective way to build a strong conceptual foundation. Our Class 5 Math solutions follow a detailed, step-by-step approach to ensure you understand the logic behind every answer. Practicing these Chapter 2 Number Work Set 5 solutions will improve your exam performance.
Class 5 Math Chapter 2 Number Work Set 5 MSBSHSE Solutions PDF
Std 5 Maths Chapter 2 Number Work
Question 1. Write the place value of the underlined digit.
(1) 78, 95,210
(2) 14, 95,210
(3) 3,52,749
(4) 50,000
(5) 89, 99,988
Answer:
(1) Here, the underlined digit 7 is in ten lakhs place.
So, its place value is 70,00,000 (70 lakhs)
(2) Here, the underlined digit 4 is in lakhs place.
So, its place value is 4,00,000 (4 lakhs)
(3) Here, the underlined digit 5 in ten thousands place.
So, its place value is 50,000 (50 thousands)
(4) Here, the underlined digit '0' is in the unit place.
Hence, its place value is 0 (zero)
(5) Here, the underlined digit 9 is in ten thousands place
So, its place value is 90,000 (90 thousands)
In simple words: The place value of a digit is determined by its position in the number, indicating how much it represents. For underlined digits, we identify their position (e.g., units, tens, thousands, lakhs) and calculate the corresponding value.
🎯 Exam Tip: Always pay close attention to the position of the underlined digit and count the places correctly to determine its exact place value for full marks.
Question 2. Write the numbers in their expanded form.
(1) 56, 43, 215
(2) 70, 815
(3) 8, 35, 999
(4) 8, 88, 889
(5) 92, 32, 992
Answer:
(1) 56,43,215: 50,00,000 + 6,00,000 + 40,000 + 3,000 + 200 + 10 + 5
(2) 70,815 : 70,000 + 800 + 10 + 5
(3) 8,35,999 : 8,00,000 + 30,000 + 5,000 + 900 + 90 + 9
(4) 8,88,889 : 8,00,000 + 80,000 + 8,000 + 800 + 80 + 9
(5) 92,32,992: 90,00,000 + 2,00,000 + 30,000 + 2,000 + 900 + 90 + 2
In simple words: The expanded form of a number shows the sum of the place values of all its digits. Each digit is multiplied by its corresponding place value (e.g., 10, 100, 1000) and then added together.
🎯 Exam Tip: When writing numbers in expanded form, ensure each digit's place value is correctly identified and all terms are added together, paying special attention to zeros which represent their place value as 0.
Question 3. Write the place name and place value of each digit in the following numbers.
(1) 35, 705
Answer:
Digit 3 is in ten thousands place, its place value is 30,000
Digit 5 is in thousands place, its place value is 5,000
Digit 7 is in hundreds place, its place value is 700
Digit 0 is in ten place, its place value is 0
Digit 5 is in units place, its place value is 5
(2) 7, 82, 899
Answer:
Digit 7 is in lakhs place, its place value is 7,00,000
Digit 8 is in ten thousands place, its place value is 80,000
Digit 2 is in thousands place, its place value is 2,000
Digit 8 is in hundreds place, its place value is 800
Digit 9 is- in ten place, its place value is 90
Digit 9 is in units place, its place value is 9
(3) 82, 74, 508
Answer:
Digit 8 is in ten lakhs place, its place value is 80,00,000
Digit 2 is in lakhs place, its place value is 2,00,000
Digit 7 is in ten thousands place, its place value is 70,000
Digit 4 is in thousands place, its place value is 4,000
Digit 5 is in hundreds place, its place value is 500
Digit 0 is in ten place, its place value is 0
Digit 8 is in units place, its place value is 8
In simple words: To find the place name and place value, identify the position of each digit starting from the right (units, tens, hundreds, thousands, etc.) and then multiply the digit by the value of its position.
🎯 Exam Tip: Carefully list each digit, its correct place name, and its corresponding numerical place value to avoid errors, especially with zeros in different positions.
Question 4. The expanded form of the number is given. Write the number.
(1) 60, 000 + 4000 + 600 + 70 + 9
(2) 9, 00, 000 + 20,000 + 7000 + 800 + 5
(3) 20,00,000 + 3,00,000 + 60,000 + 9000 + 500 + 10 + 7
(4) 7,00,000 + 80,000 + 4000 + 500
(5) 80,00,000 + 50,000 + 1000 + 600 + 9
Answer:
(1) The number is 64,679
(2) The number is 9,27,805
(3) The number is 23,69,517
(4) The number is 7,84,500
(5) The number is 80,51,609
In simple words: To convert an expanded form back into a standard number, simply add all the given place values together, aligning them correctly by their decimal places if necessary, to form the complete number.
🎯 Exam Tip: When reconstructing a number from its expanded form, ensure all place values are included and correctly aligned; be especially careful to insert zeros for any missing place values (e.g., if tens place is missing, a zero must be in the tens position).
An Interesting Dice Game
Prepare a table with the name of each player, as shown below.
In front of each name, there are boxes to make seven-digit numbers.
| Names | TL | L | TTH | TH | H | T | U | The number formed |
|---|---|---|---|---|---|---|---|---|
| Ajay | 1 | |||||||
| Megha | 3 | |||||||
| Pushkarni | 6 | |||||||
| Vijay | 2 |
Game 1: The first player throws the dice and writes that number in any one of the boxes in front of his/her name. You can write only one number in each box and once it is written, you cannot change its place. The other players do the same till all the boxes are filled and each one gets a seven-digit number. The one with the largest number is the winner.
Game 2: Use the same table, but you may write the number (you get on throwing the dice) in any box in front of anyone's name. The one with the largest number is the winner.
Game 3: The rules are the same as for game 2, but the one with the smallest number is the winner.
Bigger And Smaller Numbers
Hamid : How do we determine the smaller or bigger number when we are dealing with six- or seven-digit numbers ?
Teacher : You have learnt how to do that with five-digit numbers. The number with the bigger ten thousands digit is the bigger number. If they are the same, we look at the thousands digits to determine the smaller or bigger number.
Now, can you tell how to compare six- or seven-digit numbers ?
Hamid : Yes, I can. First, we'll look at the ten lakhs digits. If they are the same, we'll look at the digits in the lakhs place. If those are equal, we look at the ten thousands place to tell the smaller or bigger number and so on. Besides, we might be able to tell which of the numbers is bigger, just by looking at the number of digits in each number. Right ?
Teacher: Absolutely ! The number with more digits is the bigger number.
Roman Numerals Problem Set 5 Additional Important Questions And Answers
Question 1. Write the place value of the underlined digit.
(1) 81,67,303
Answer:
Here, the underlined digit 7 is in thousands place.
So, its place value is 7,000 (7 thousands)
(2) 41,35,062
Answer:
Here, the underlined digit 6 is in ten's place.
So, its place value is 60 (sixty)
(3) 90,31,265
Answer:
Here, the underlined digit 3 is in ten thousands place.
So, its place value is 30,000 (30 thousands)
In simple words: The place value indicates the worth of a digit based on its position within a number, making it essential to accurately identify the specific place of the underlined digit.
🎯 Exam Tip: When determining place value, always count positions from the right, starting with units, to accurately assign the correct value to the underlined digit.
Question 2. Write the numbers in their expanded form.
(1) 51,03,640: .50,00,000 + 1,00,000 + 3,000 + 600 + 40
(2) 60,60,600: 60,00,000 + 60,000 + 600
(3) 71,45,042 : 70,00,000 + 1,00,000 + 40,000 + 5,000 + 40 + 2
Answer:
(1) 51,03,640: 50,00,000 + 1,00,000 + 3,000 + 600 + 40
(2) 60,60,600: 60,00,000 + 60,000 + 600
(3) 71,45,042 : 70,00,000 + 1,00,000 + 40,000 + 5,000 + 40 + 2
In simple words: The expanded form shows a number as the sum of its digits, each multiplied by its respective place value.
🎯 Exam Tip: For expanded forms, always ensure that zeros in the number are represented by their place values (which would be zero), and all non-zero digits contribute their specific place value to the sum.
Question 3. Write the place name and place value of each digit in the following numbers.
(1) 1,88,919
Answer:
Digit 1 is in lakhs place, its place value is 1,00,000
Digit 8 is in ten thousands place, its place value is 80,000
Digit 8 is in thousands place, its place value is 8,000
Digit 9 is in hundreds place, its place value is 900
Digit 1 is in ten place, its place value is 10
Digit 9 is in units place, its place value is 9
In simple words: Each digit's place name (like lakhs, thousands, tens) and its place value (its numerical contribution based on position) must be identified.
🎯 Exam Tip: Be meticulous in assigning both the correct place name and its corresponding numerical value for each digit to avoid any calculation or conceptual errors.
Question 4. The expanded form write the number.
(1) 40,00,000 + 5,00,000 + 10,000 + 3,000 + 200 + 70+8
Answer:
The number is 45,13,278
(2) 80,000 + 300 + 40 + 1
Answer:
The number is 80,341
In simple words: To write the standard number from an expanded form, sum up all the given place value components, ensuring each digit occupies its correct place.
🎯 Exam Tip: When converting expanded form to standard numbers, arrange terms by decreasing place value and fill in any missing places with zeros to ensure accuracy.
MSBSHSE Solutions Class 5 Math Chapter 2 Number Work Set 5
Students can now access the MSBSHSE Solutions for Chapter 2 Number Work Set 5 prepared by teachers on our website. These solutions cover all questions in exercise in your Class 5 Math textbook. Each answer is updated based on the current academic session as per the latest MSBSHSE syllabus.
Detailed Explanations for Chapter 2 Number Work Set 5
Our expert teachers have provided step-by-step explanations for all the difficult questions in the Class 5 Math chapter. Along with the final answers, we have also explained the concept behind it to help you build stronger understanding of each topic. This will be really helpful for Class 5 students who want to understand both theoretical and practical questions. By studying these MSBSHSE Questions and Answers your basic concepts will improve a lot.
Benefits of using Math Class 5 Solved Papers
Using our Math solutions regularly students will be able to improve their logical thinking and problem-solving speed. These Class 5 solutions are a guide for self-study and homework assistance. Along with the chapter-wise solutions, you should also refer to our Revision Notes and Sample Papers for Chapter 2 Number Work Set 5 to get a complete preparation experience.
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The complete and updated Maharashtra Board Class 5 Maths Chapter 2 Number Work Set 5 Solutions is available for free on StudiesToday.com. These solutions for Class 5 Math are as per latest MSBSHSE curriculum.
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