Maharashtra Board Class 5 Maths Chapter 16 Preparation for Algebra Set 55 Solutions

Preparation For Algebra Class 5 Problem Set 55 Question Answer Maharashtra Board

Balbharti Maharashtra Board Class 5 Maths Solutions Chapter 16 Preparation for Algebra Problem Set 55 Textbook Exercise Important Questions and Answers.

Std 5 Maths Chapter 16 Preparation For Algebra

Question 1. Say whether right or wrong. (1) \( (23 + 4) = 4 + 23 ) \)
Answer: \( 27 = 27 \) is right
In simple words: This statement checks if the sum of 23 and 4 is equal to the sum of 4 and 23, which is true due to the commutative property of addition.

🎯 Exam Tip: When evaluating equations, perform operations on both sides to check for equality or inequality.

Question 1. Say whether right or wrong. (2) \( (9 + 4) > 12 \)
Answer: \( 13 > 12 \) is right
In simple words: This statement tests if the sum of 9 and 4 is greater than 12. Since 13 is greater than 12, the statement is correct.

🎯 Exam Tip: Always calculate the value of expressions on both sides before making a comparison.

Question 1. Say whether right or wrong. (3) \( (9 + 4) < 12 \)
Answer: \( 13 < 12 \) is wrong
In simple words: This statement claims that 13 is less than 12, which is false.

🎯 Exam Tip: Accuracy in calculations is crucial to correctly determine the truthfulness of mathematical statements.

Question 1. Say whether right or wrong. (4) \( 138 > 138 \)
Answer: Wrong
In simple words: This statement suggests that 138 is strictly greater than itself, which is incorrect as 138 is equal to 138.

🎯 Exam Tip: Understand the difference between 'greater than' (>) and 'greater than or equal to' (>=) symbols.

Question 1. Say whether right or wrong. (5) \( 138 < 138 \)
Answer: Wrong
In simple words: This statement implies that 138 is strictly less than itself, which is false.

🎯 Exam Tip: Remember that a number cannot be both strictly less than and strictly greater than itself.

Question 1. Say whether right or wrong. (6) \( 138 = 138 \)
Answer: right
In simple words: This statement asserts that 138 is equal to 138, which is true.

🎯 Exam Tip: The equality symbol (=) indicates that the values on both sides are exactly the same.

Question 1. Say whether right or wrong. (7) \( (4 \times 7) = 30 - 2 \)
Answer: \( 28 = 28 \) is right
In simple words: This statement checks if the product of 4 and 7 equals the result of 30 minus 2; both sides evaluate to 28, making the statement true.

🎯 Exam Tip: Perform multiplication and subtraction carefully to ensure the accuracy of the comparison.

Question 1. Say whether right or wrong. (8) \( \frac{25}{5} > 5 \)
Answer: \( 5 > 5 \) is wrong.
In simple words: This statement claims that 25 divided by 5 is strictly greater than 5, which simplifies to 5 > 5, a false statement.

🎯 Exam Tip: Be precise with inequality symbols; 5 is equal to 5, not greater than it.

Question 1. Say whether right or wrong. (9) \( (5 \times 8) = (8 \times 5) \)
Answer: \( 40 = 40 \) is right
In simple words: This statement illustrates the commutative property of multiplication, showing that changing the order of factors does not change the product.

🎯 Exam Tip: Understanding fundamental properties like commutativity simplifies verification of such statements.

Question 1. Say whether right or wrong. (10) \( (16 + 0) = 0 \)
Answer: \( 16 + 0 = 16 \)
\( 16 = 0 \) is wrong
In simple words: This statement incorrectly equates 16 plus 0 to 0, when the sum is actually 16.

🎯 Exam Tip: Remember that adding zero to any number results in the number itself (additive identity property).

Question 1. Say whether right or wrong. (11) \( (16 + 0) = 16 \)
Answer: \( 16 = 16 \) is right.
In simple words: This statement correctly shows that adding zero to 16 results in 16, demonstrating the additive identity property.

🎯 Exam Tip: The additive identity property is a basic arithmetic rule to remember for evaluation.

Question 1. Say whether right or wrong. (12) \( (9 + 4) = 12 \)
Answer: \( 13 = 12 \) is wrong.
In simple words: This statement incorrectly claims that the sum of 9 and 4 is 12, when the actual sum is 13.

🎯 Exam Tip: Always double-check your addition to ensure the accuracy of equality statements.

Question 13. Fill in the blanks with the right symbol from <, > or =. (1) \( (45 \div 9) \) [ ] \( (9 - 4) \)
Answer: \( 45 \div 9 = 5 \),
\( 9 - 4 = 5 \)
So, \( (45 \div 9) = (9 - 4) \)
In simple words: By evaluating both expressions, we find that 45 divided by 9 is 5, and 9 minus 4 is also 5, therefore the correct symbol to fill the blank is equals (=).

🎯 Exam Tip: Simplify both sides of the expression first to easily determine the correct comparison symbol.

Question 14. Fill in the blanks with the right symbol from <, > or =. (2) \( (6 + 1) \) [ ] \( (3 \times 2) \)
Answer: \( 6 + 1 = 7 \),
\( 3 \times 2 = 6 \)
So, \( (6 + 1) > (3 \times 2) \)
In simple words: Calculating the expressions, 6 plus 1 is 7, and 3 times 2 is 6, indicating that 7 is greater than 6, so the symbol should be greater than (>).

🎯 Exam Tip: Perform addition and multiplication operations accurately to identify the correct relational symbol.

Question 15. Fill in the blanks with the right symbol from <, > or =. (3) \( (12 \times 2) \) [ ] \( (25 + 10) \)
Answer: \( 12 \times 2 = 24 \),
\( 25 + 10 = 35 \)
So, \( (12 \times 2) < (25 + 10) \)
In simple words: After calculating, 12 multiplied by 2 is 24, and 25 plus 10 is 35, showing that 24 is less than 35, so the symbol is less than (<).

🎯 Exam Tip: Verify all calculations thoroughly to ensure the correct inequality or equality is chosen.

Question 16. Fill in the blanks in the expressions with the proper numbers. (1) \( (1 \times 7) = ( \text{ [ ] } \times 1) \)
Answer: \( 1 \times 7 = 7 \),
\( 7 \times 1 = 7 \)
So, \( (1 \times 7) = (7 \times 1) \)
In simple words: To maintain equality, since 1 times 7 is 7, the blank on the right side must be 7 to make 7 times 1 also 7, illustrating the commutative property of multiplication.

🎯 Exam Tip: Recognize the commutative property of multiplication, which states that changing the order of factors does not change the product.

Question 17. Fill in the blanks in the expressions with the proper numbers. (2) \( (5 \times 4) > (7 \times \text{ [ ] }) \)
Answer: \( 5 \times 4 = 20 \). For \( (7 \times \text{ [ ] }) \) to be less than 20, the blank must be 2.
\( 7 \times 2 = 14 \)
So, \( (5 \times 4) > (7 \times 2) \)
In simple words: Since 5 times 4 is 20, we need 7 times the blank to be less than 20; the largest whole number that satisfies this is 2, making 7 times 2 equal to 14.

🎯 Exam Tip: When filling blanks in inequalities, test values that make the statement true while considering whole number constraints.

Question 18. Fill in the blanks in the expressions with the proper numbers. (3) \( (48 \div 3) < ( \text{ [ ] } \times 5) \)
Answer: \( 48 \div 3 = 16 \). We need \( ( \text{ [ ] } \times 5) \) to be greater than 16.
If the blank is 4, \( 5 \times 4 = 20 \). If the blank is 3, \( 5 \times 3 = 15 \).
Since \( 16 < 20 \), the smallest whole number that makes the statement true is 4.
So, \( (48 \div 3) < (4 \times 5) \)
In simple words: Since 48 divided by 3 is 16, the blank multiplied by 5 must be greater than 16; the smallest whole number that fits this condition is 4, making 4 multiplied by 5 equal to 20.

🎯 Exam Tip: Identify the range of values that satisfy the inequality by testing nearby numbers around the calculated value.

Question 19. Fill in the blanks in the expressions with the proper numbers. (4) \( (0 + 1) > (5 \times \text{ [ ] }) \)
Answer: \( 0 + 1 = 1 \). We need \( (5 \times \text{ [ ] }) \) to be less than 1.
If the blank is 1, \( 5 \times 1 = 5 \). If the blank is 0, \( 5 \times 0 = 0 \).
Since \( 1 > 0 \), the number that makes the statement true is 0.
So, \( (0 + 1) > (5 \times 0) \)
In simple words: As 0 plus 1 is 1, we need 5 times the blank to be less than 1; the only whole number that satisfies this condition is 0, making 5 times 0 equal to 0.

🎯 Exam Tip: Consider the properties of multiplication by zero when determining numbers for inequalities involving it.

Question 20. Fill in the blanks in the expressions with the proper numbers. (5) \( (35 \div 7) = (\text{ [ ] } + \text{ [ ] }) \)
Answer: \( 35 \div 7 = 5 \). We need two numbers that add up to 5.
For example, \( 3 + 2 = 5 \).
So, \( (35 \div 7) = (3 + 2) \)
In simple words: Since 35 divided by 7 equals 5, we need two numbers whose sum is 5; one possible pair is 3 and 2.

🎯 Exam Tip: When multiple blanks need to sum to a target value, remember that various combinations can be correct.

Question 21. Fill in the blanks in the expressions with the proper numbers. (6) \( (6 - \text{ [ ] }) < (2 + 3) \)
Answer: \( 2 + 3 = 5 \). We need \( (6 - \text{ [ ] }) \) to be less than 5.
If the blank is 2, then \( 6 - 2 = 4 \). Since \( 4 < 5 \), the number that makes the statement true is 2.
So, \( (6 - 2) < (2 + 3) \)
In simple words: Since 2 plus 3 is 5, we need 6 minus the blank to be less than 5; if the blank is 2, then 6 minus 2 is 4, which is less than 5.

🎯 Exam Tip: Test possible whole numbers for the blank to find one that satisfies the given inequality.

Using Letters

Symbols are frequently used in mathematical writing. The use of symbols makes the writing very short. For example, using symbols, 'Division of 75 by 15 gives us 5' can be written in short as ' \( 75 \div 15 = 5 \) '. It is also easier to grasp.

Letters can be used like symbols to make our writing short and simple.

While adding, subtracting or carrying out other operations on numbers, you must have discovered many properties of the operations.

For example, what properties do you see in sums like \( (9 + 4) \), \( (4 + 9) \)?

The sum of any two numbers and the sum obtained by reversing the order of the two numbers is the same.

Now see how much easier and faster it is to write this property using letters.

• Let us use a and b to represent any two numbers. Their sum will be ' \( a + b \) '. Changing the order of those numbers will make the addition ' \( b + a \) '. Therefore, the rule will be : 'For all values of a and b, \( (a + b) = (b + a) \). '

Let us see two more examples.

• Multiplying any number by 1 gives the number itself. In short, \( a \times 1 = a \).
• Given two unequal numbers, the division of the first by the second is not the same as the division of the second by the first. In short, if a and b are two different numbers, then \( (a \div b) \neq (b \div a) \).

Take the value of a as 8 and b as 4 and verify the property yourself.

Preparation For Algebra Problem Set 54 Additional Important Questions And Answers

Say Whether Right Or Wrong.

Question 1. (1) \( (15 \div 3) = 5 \)
Answer: \( 5 = 5 \) is right.
In simple words: This statement correctly shows that 15 divided by 3 equals 5.

🎯 Exam Tip: Confirm divisions and equalities to verify the truth of such statements.

Question 2. (2) \( (2 \times 1) = 1 \)
Answer: \( 2 = 1 \) is wrong.
In simple words: This statement incorrectly asserts that 2 multiplied by 1 is 1, when it should be 2.

🎯 Exam Tip: Recall the identity property of multiplication where any number multiplied by 1 is the number itself.

Question 3. (3) \( (16 \div 8) = (2 \times 2) \)
Answer: \( 2 = 4 \) is wrong.
In simple words: This statement incorrectly equates 16 divided by 8 (which is 2) with 2 multiplied by 2 (which is 4).

🎯 Exam Tip: Perform operations on both sides of the equation accurately before comparing the results.

Question 4. (4) \( (13 - 7) = 6 \)
Answer: \( 6 = 6 \) is right.
In simple words: This statement correctly indicates that 13 minus 7 equals 6.

🎯 Exam Tip: Basic subtraction facts are essential for quickly verifying such equations.

Question 5. (5) \( (1 \times 0) = 1 \)
Answer: \( 0 = 1 \) is wrong.
In simple words: This statement incorrectly claims that 1 multiplied by 0 is 1, when any number multiplied by 0 is 0.

🎯 Exam Tip: Remember the property of multiplication by zero: any number multiplied by zero is always zero.

Question 6. (6) \( (1 + 0) = 1 \)
Answer: \( 1 = 1 \) is right.
In simple words: This statement correctly shows that 1 plus 0 equals 1.

🎯 Exam Tip: The additive identity property states that adding zero to any number yields the number itself.

Fill In The Blanks With The Right Symbol From <, >, Or =.

Question 7. (1) \( (12 + 6) \) [ ] \( (10 \times 2) \)
Answer: \( 12 + 6 = 18 \),
\( 10 \times 2 = 20 \)
So, \( (12 + 6) < (10 \times 2) \)
In simple words: Comparing the values, 12 plus 6 is 18, and 10 times 2 is 20, thus 18 is less than 20, so the blank is filled with '<'.

🎯 Exam Tip: Always calculate both sides of the expression before comparing them with an inequality or equality symbol.

Question 8. (2) \( (4 \times 5) \) [ ] \( (10 \times 2) \)
Answer: \( 4 \times 5 = 20 \),
\( 10 \times 2 = 20 \)
So, \( (4 \times 5) = (10 \times 2) \)
In simple words: Since both 4 times 5 and 10 times 2 result in 20, the expressions are equal, so the blank is filled with '='.

🎯 Exam Tip: Ensure accurate multiplication to correctly identify whether expressions are equal or unequal.

Question 9. (3) \( (7 + 3) \) [ ] \( (3 \times 3) \)
Answer: \( 7 + 3 = 10 \),
\( 3 \times 3 = 9 \)
So, \( (7 + 3) > (3 \times 3) \)
In simple words: Calculating both sides, 7 plus 3 is 10, and 3 times 3 is 9, meaning 10 is greater than 9, so the blank is filled with '>'.

🎯 Exam Tip: Always perform addition and multiplication operations correctly to determine the accurate relationship between two expressions.

Fill In The Blanks In The Expressions With The Proper Numbers.

Question 10. (1) \( (8 + \text{ [ ] }) = (8 \times 1) \)
Answer: \( 8 \times 1 = 8 \). We need \( (8 + \text{ [ ] }) \) to be equal to 8.
So, the blank must be 0, as \( 8 + 0 = 8 \).
Thus, \( (8 + 0) = (8 \times 1) \)
In simple words: Since 8 times 1 is 8, the blank must be 0 for 8 plus the blank to also equal 8, demonstrating the additive identity property.

🎯 Exam Tip: Recognize the additive identity property to quickly determine the missing number in such equations.

Question 11. (2) \( (5 \times 6) > (14 \times \text{ [ ] }) \)
Answer: \( 5 \times 6 = 30 \). We need \( (14 \times \text{ [ ] }) \) to be less than 30.
If the blank is 1, \( 14 \times 1 = 14 \). If the blank is 2, \( 14 \times 2 = 28 \). If the blank is 3, \( 14 \times 3 = 42 \).
Since \( 30 > 28 \), the largest whole number that makes the statement true is 2.
So, \( (5 \times 6) > (14 \times 2) \)
In simple words: Given 5 times 6 is 30, we need 14 times the blank to be less than 30; the largest whole number fitting this is 2, making 14 times 2 equal to 28.

🎯 Exam Tip: When finding a missing number in an inequality, test values to determine the range that satisfies the condition.

Question 12. (3) \( (6 \times 7) < ( \text{ [ ] } \times 5) \)
Answer: \( 6 \times 7 = 42 \). We need \( ( \text{ [ ] } \times 5) \) to be greater than 42.
If the blank is 9, \( 9 \times 5 = 45 \). Since \( 42 < 45 \), the smallest whole number that makes the statement true is 9.
So, \( (6 \times 7) < (9 \times 5) \)
In simple words: Since 6 times 7 is 42, the blank multiplied by 5 must be greater than 42; the smallest whole number that fulfills this condition is 9, resulting in 45.

🎯 Exam Tip: Find the smallest whole number for the blank that makes the product greater than the value on the other side of the inequality.

Class 5 Maths Solution Maharashtra Board

• Three Dimensional Objects and Nets Problem Set 51 Class 5 maths Solutions
• Pictographs Problem Set 52 Class 5 maths Solutions
• Patterns Problem Set 53 Class 5 maths Solutions
• Preparation for Algebra Problem Set 54 Class 5 maths Solutions
• Preparation for Algebra Problem Set 55 Class 5 maths Solutions
• Preparation for Algebra Problem Set 56 Class 5 maths Solutions

Class 5

< Problem Set 9 Class 5 Maths Chapter 3 Addition and Subtraction Question Answer Maharashtra Board

> Problem Set 34 Class 5 Maths Chapter 8 Multiples and Factors Question Answer Maharashtra Board