Maharashtra Board Class 5 Maths Chapter 11 Problems on Measurement Set 47 Solutions

Problems On Measurement Class 5 Problem Set 47 Question Answer Maharashtra Board

Std 5 Maths Chapter 11 Problems On Measurement

Question 1.For his birthday, Ajay gave 20 l 450 ml of milk to the children in an Ashramshala and 28 l 800 ml to the children in an orphanage. How much milk did Ajay donate? Solution:

l	ml
20	450
+ 28	800
49	250

450 ml + 800 ml
= 1250 ml
= 1 l + 250 ml
∴ Ajay donated 49 l 250 ml milk
Answer: Ajay donated 49 liters and 250 milliliters of milk in total.
In simple words: To find the total milk donated, add the milk given to the Ashramshala and the orphanage, remembering that 1000 ml equals 1 liter.

🎯 Exam Tip: Remember to convert milliliters to liters when the sum exceeds 1000 ml. Carry over the liters to the liter column for accurate total. This step is crucial for correct answers in measurement problems.

Question 2.Under the Rural Cleanliness Mission, college students cleaned 1 km 750m of a village road that is 2 km 575m long. How much remained to be cleaned? Solution:

km	m
1	1575
2	575
- 1	750
0	825

750 m cannot be subtracted from 575 m. So, convert 1 km = 1000 m.
∴ 825 m remained to be cleaned
Answer: 825 meters of the road remained to be cleaned.
In simple words: To find the remaining length, subtract the cleaned length from the total road length, borrowing 1 km (1000 m) when necessary.

🎯 Exam Tip: When subtracting measurements, ensure that the units are consistent. If the smaller unit (e.g., meters) in the minuend is less than in the subtrahend, borrow from the larger unit (e.g., kilometers), remembering its conversion value (1 km = 1000 m).

Question 3.Babhulgaon used 21,250 liters of treated waste water in the fields. Samvatsar used 31,350 litres of similar water. How much treated waste water was used in all? Solution: 21250 litres Babhulgaon used + 31350 litres Samvatsar used 52600
∴ 52,600 litres of waste water used in all
Answer: A total of 52,600 liters of treated waste water was used.
In simple words: Add the amount of water used by Babhulgaon and Samvatsar to find the total treated waste water used.

🎯 Exam Tip: For "in all" or "total" questions, the operation is usually addition. Double-check your column alignment and carrying when adding large numbers.

Question 4.If half a litre of milk costs 22 rupees, how much will 7 litres cost? Solution: \( \frac{1}{2} + \frac{1}{2} = \frac{1+1}{2} = \frac{2}{2} = 1 \) litre
22 + 22 = Rs. 44
That is, 1 litre cost Rs. 44
∴ 7 litres costs 44 x 7 = Rs. 308
∴ 7 litres costs 308
Answer: 7 litres of milk will cost Rs. 308.
In simple words: Since half a liter costs Rs. 22, a full liter costs Rs. 44. Multiply this cost by 7 to find the cost of 7 liters.

🎯 Exam Tip: Break down multi-step problems. First find the unit cost (cost per liter), then multiply by the total quantity required. Pay close attention to currency conversion and multiplication steps.

Question 5.If the speed of a motorcycle is 40 km per hour, how far will it travel in an hour and a quarter? Solution: Hour and quarter = \( 1 + \frac{1}{4} \) hours
= 40 km + \( \frac{1}{4} \) x 40 km
= 40 km + 10 km
= 50 km
∴ Motorcycle will travel in a hour and a quarter 50 km
Answer: The motorcycle will travel 50 km in an hour and a quarter.
In simple words: The motorcycle travels 40 km in one hour. For a quarter hour, it travels one-fourth of 40 km, which is 10 km. Add these distances to get the total.

🎯 Exam Tip: To calculate distance for a fractional time, first determine the distance covered in the full hour, then calculate the distance for the fraction of an hour, and finally add them up. Ensure the units for speed and time are compatible.

Question 6.If a man walks at a speed of 4 kmph, how long will it take him to walk 3 km? Solution: 1 km = 1000 m
4 km in 1 hour, 4 km in 60 minutes
That is
2 km in 30 minutes
+ 1 km in 15 minutes
3 km in 45 minutes

\( 4 \overline{) 60} \)
   15
   -4
    20
   -20
    00
That is 1 km in 15 minutes Hence, 3
km in 15 x 3 = 45 min
∴ 3 km in 15 x 3 = 45 min
Answer: It will take the man 45 minutes to walk 3 km.
In simple words: If 4 km takes 60 minutes, then 1 km takes 15 minutes (60/4). So, 3 km will take 3 times 15 minutes, which is 45 minutes.

🎯 Exam Tip: Convert hours to minutes for easier calculation when dealing with speeds and shorter distances. Use unit rates (e.g., time per 1 km) to solve for total time. Clearly show each step of your calculation.

Question 7.If a rickshaw travels at a speed of 30 kmph, how far will it travel in three quarters of an hour? Solution: 30 kmph means
In 60 minutes 30 km and 30 minutes 15 km
and 15 minutes \( \frac{15}{2} = \frac{15 \times 5}{2 \times 5} = \frac{75}{10} \) = 7.5 km
∴ In 45 minutes 15 km + 7.5 km = 22.5 km
Answer: The rickshaw will travel 22.5 km in three quarters of an hour.
In simple words: In one hour (60 minutes), the rickshaw travels 30 km. Three quarters of an hour is 45 minutes. Calculate distance for 30 minutes (half of 30 km) and 15 minutes (quarter of 30 km), then add them.

🎯 Exam Tip: To find distance for a fraction of an hour, first determine the distance per hour, then multiply by the fractional part of the hour (e.g., 3/4). Show the breakdown of minutes and corresponding distances.

Question 8.During Cleanliness Week, children cleaned the public park in their town. They collected three quarter kilograms of plastic bags and five and a half kilograms of other garbage. How much garbage did they collect in all? Solution: 1 kg = 1000 gm
So, \( \frac{1}{4} \) kg = \( \frac{1000}{4} \) = 250 gm
Three quarters = \( \frac{1}{4} + \frac{1}{4} + \frac{1}{4} \) = 250 + 250 + 250 = 750 gm

kg	gm
	750	Plastic
+ 5	500	Garbage
5	1250
5+1	250
6 kg 250 gm

∴ 6 kg 250 gm
Answer: They collected 6 kg 250 gm of garbage in all.
In simple words: Convert fractions of kilograms to grams (three-quarters is 750g, half is 500g). Then add the weights of plastic bags and other garbage, carrying over grams to kilograms if the sum exceeds 1000g.

🎯 Exam Tip: Always convert fractional measurements to a common unit (e.g., grams) before adding. Remember that 1 kg = 1000 gm. Clearly show your conversion and addition steps.

Question 9.If one shirt needs 2 m 50cm of cloth, how much cloth do we need for 5 shirts? Solution:

m	cm
2	50
x	5
10	250
10 + 2	50
12	50

250 cm = 200 cm + 50 cm
= 2 m + 50 cm
∴ 12 m 50 cm cloth needs
Answer: We need 12 m 50 cm of cloth for 5 shirts.
In simple words: Multiply the cloth needed for one shirt (2 m 50 cm) by 5. Convert any excess centimeters (over 100 cm) into meters and add to the meter total.

🎯 Exam Tip: When multiplying measurements with mixed units, multiply each unit separately. Then, convert the smaller unit (cm) if it exceeds its base (100 cm) and carry over to the larger unit (m). This ensures accurate final measurement.

Question 10.If a car travels 60 km in an hour, how far will it travel in
(1) 2 hours?
(2) 15 minutes?
(3) half an hour?
(4) three and a half hours? Solution: 60 kmph
In 60 minutes 60 km
Hence, 1 minute 1 km
(1) 2 hours = 2 x 60 = 120 km
(2) In 15 minutes = 15 km
(3) In half an hour 60 \( \div \) 2 = 30 km
(4) In three and half hours
= 3 x 60 + 30
= 180 + 30
= 210 km
∴
(1) 120 km
(2) 15 km
(3) 30 km
(4) 210 km
Answer:
(1) In 2 hours, the car will travel 120 km.
(2) In 15 minutes, the car will travel 15 km.
(3) In half an hour, the car will travel 30 km.
(4) In three and a half hours, the car will travel 210 km.
In simple words: Since the car travels 60 km in an hour, multiply 60 by the number of hours or fraction of an hour to find the total distance. For minutes, remember 1 minute = 1 km.

🎯 Exam Tip: For speed, distance, and time problems, establish the rate per unit (e.g., km per hour or km per minute). Then, apply this rate consistently to solve for different time intervals, converting units as needed for precision.

Question 11.If one gold bangle is made from 12 grams 250 milligrams of gold, how much gold will be needed to make 8 such bangles? (1000mg = 1 g) Solution:

gram	milligram
12	250
x	8
96	2000
96 + 2	000
98	000

∴ 98 grams gold needed
Answer: 98 grams of gold will be needed to make 8 such bangles.
In simple words: Multiply the amount of gold for one bangle (12g 250mg) by 8. Convert the total milligrams to grams (1000 mg = 1 g) and add to the total grams.

🎯 Exam Tip: When multiplying mixed units, multiply the smaller unit first. Convert any excess (e.g., mg over 1000) to the larger unit (g) and carry it over before summing the larger unit column. This ensures proper unit conversion and total weight.

Question 12.How many pouches of 20g cloves each can be made from 1 kg 240g of cloves? Solution: 1 kg 240 gm
= 1000 gm + 240 gm
= 1240 gm

\( 20 \overline{) 1240} \)
    62
   -120
     40
    -40
     00
∴ 62 pouches can be made
Answer: 62 pouches of 20g cloves each can be made.
In simple words: First convert the total weight of cloves (1 kg 240g) into grams. Then divide the total grams by the weight of cloves per pouch (20g) to find the number of pouches.

🎯 Exam Tip: Always convert all measurements to the smallest common unit (e.g., kilograms to grams) before performing division to avoid errors. Clearly show your conversion and division steps.

Question 13.Seema's mother bought 2m 70cm of cloth for a kurta and 2 m 40cm for a shirt. How much cloth did she buy in all? Solution: 70 cm + 40 cm
= 110 cm
= 1 m 10 cm

m	cm
2	70
+ 2	40
5	10

cloth for Kurta
cloth for Shirt
∴ 5 m 10 cm cloth in all
Answer: Seema's mother bought 5 m 10 cm of cloth in all.
In simple words: Add the meters and centimeters separately. If the centimeters exceed 100, convert 100 cm to 1 meter and add it to the meter total.

🎯 Exam Tip: For addition of mixed units, add the smaller unit (centimeters) first. If the sum is 100 or more, convert it to the larger unit (meters) and carry it over to the meter column. This ensures correct total measurement.

Question 14.A water tank holds 125 l of water. If 97 l 500 ml of the water is used, how much water remains in the tank? Solution: 1 litre = 1000 ml

l	ml
124	1000
125	000	water tank holds
- 97	500	water used
27	500	water remain

∴ 27 l 500 ml water remain in tank
Answer: 27 l 500 ml of water remains in the tank.
In simple words: Subtract the used water (97 l 500 ml) from the total water (125 l). Borrow 1 liter (1000 ml) from the liters column if you can't subtract the milliliters directly.

🎯 Exam Tip: For subtraction with mixed units, if the smaller unit (ml) in the subtrahend is larger than in the minuend, borrow 1 from the larger unit (l) and convert it to the smaller unit (1 l = 1000 ml) before subtracting. Clearly show the borrowing and conversion steps.

Question 15.Harminder bought 57 kg 500g of wheat from one shop and 36 kg 800 g of wheat from another shop. How much wheat did he buy altogether? Solution:

kg	gm
57	500	bought from 1 shop
+ 36	800	bought from another shop
93	1300
1
94	300

500 + 800 = 1300 gm
= 1000 + 300
= 1 kg 300 gm
∴ 94 kg 300 gm bought altogether
Answer: Harminder bought 94 kg 300 gm of wheat altogether.
In simple words: Add the kilograms and grams of wheat bought from both shops separately. Convert excess grams (over 1000g) into kilograms and add to the total kilograms.

🎯 Exam Tip: When adding weights, sum the gram amounts first. If the total grams exceed 1000, remember that 1000 grams equal 1 kilogram, and carry over the kilograms to the kg column. This is a common point for errors.

Question 16.Renu took part in a 100m race. She tripped and fell after running 80 m 50 cm. How much distance did she have left to run? Solution:

m	cm
99	100
100	00
- 80	50
19	50

Borrow 1 m = 100 cm
So, 100 m = 99 m + 100 cm
Total distance to run
Distance covered
Distance left to run
∴ 19 m 50 cm distance left to run
Answer: Renu had 19 m 50 cm distance left to run.
In simple words: Subtract the distance Renu ran (80 m 50 cm) from the total race distance (100 m). You'll need to borrow 1 meter (100 cm) to subtract the centimeters.

🎯 Exam Tip: In subtraction problems involving mixed units, if the smaller unit (cm) in the minuend is less than the subtrahend, borrow from the larger unit (m), converting 1 m to 100 cm. Clearly show this borrowing and conversion.

Question 17.A sack had 40kg 300 grams of vegetables. There were 17kg 700 g potatoes, 13 kg 400g cabbage and the rest were onions. What was the weight of the onions? Solution:

kg	gm
17	700	potatoes
+ 13	400	cabbage
30	1100
1
31	100

kg	gm
40	300	Total weight
- 31	100	weight of potato and cabage
9	200

∴ Weight of onions is 9 kg 200 gm
Answer: The weight of the onions is 9 kg 200 gm.
In simple words: First, add the weight of potatoes and cabbage. Then, subtract this combined weight from the total weight of vegetables in the sack to find the weight of the onions. Remember to convert grams to kilograms when adding/subtracting.

🎯 Exam Tip: This is a two-step problem: first add known weights, then subtract from the total. Be careful with carrying over when adding grams (1000g = 1kg) and borrowing when subtracting (1kg = 1000g).

Question 18.One day, Gurminder Singh walked 3 km 750m and Parminder Singh walked 2km 825m. Who walked farther and by how much? Solution:

km	m
2	1750	1 km = 1000 m borrowed
3	750	Gurminder walked
- 2	825	Parminder walked
0	925

∴ Gurminder walked more by 925 metres
Answer: Gurminder Singh walked farther than Parminder Singh by 925 meters.
In simple words: To find who walked farther and by how much, subtract the shorter distance from the longer distance. Remember to borrow 1 km (1000m) if the meters cannot be subtracted directly.

🎯 Exam Tip: When comparing and finding differences in mixed units, convert to common units or apply borrowing carefully. Always subtract the smaller quantity from the larger quantity to find the difference. State clearly who walked farther.

Question 19.Suresh bought 3kg 250g of tomatoes, 2 kg 500g of peas and 1kg 750g of cauliflower. How much was the total weight of the vegetables he bought? Solution:

kg	gm
	1500 gm = 1 kg 500 gm
3	250	tomatoes
+ 2	500	peas
+ 1	750	cauliflower
6	1500
6+1	500
7	500

∴ Total weight 7 kg 500 gm
Answer: The total weight of vegetables Suresh bought was 7 kg 500 gm.
In simple words: Add the weights of tomatoes, peas, and cauliflower. Sum the grams and kilograms separately. Convert excess grams (over 1000g) into kilograms and add to the total kilograms.

🎯 Exam Tip: When adding multiple mixed measurements, perform addition in columns (grams and kilograms). Always handle the smaller unit (grams) first, converting any sum greater than 1000g to kilograms and carrying it over to the kilograms column.

Question 20.Jalgaon, Bhusawal, Akola, Amravati and Nagpur lie serially on a certain route. The distances between Akola and these other places are given below.
Use them to make word problems and solve the problems.
Amravati - 95 km, Bhusawal - 154 km,
Nagpur - 249 km, Jalgaon - 181 km Solution:
(1) What is the distance between Bhusaval and Nagpur?
249 km - 154 km = 95 km
∴ The distance between Bhusaval and Nagpur is 95 km
(2) What is the distance between Amravati and Jalgaon?
181 km - 95 km = 86 km
∴ The distance between Amravati and Jalgaon is 86 km.
Answer:
(1) The distance between Bhusaval and Nagpur is 95 km.
(2) The distance between Amravati and Jalgaon is 86 km.
In simple words: To find the distance between two intermediate points on a serial route, subtract the distance of the closer point from Akola from the distance of the farther point from Akola.

🎯 Exam Tip: When dealing with serial distances from a common reference point (like Akola here), treat the distances as values on a number line. Subtracting the smaller distance from the larger distance gives the segment length between those two points.

Question 21.Complete the following table and prepare the total bill.

Foodstuff	Weight (kg)	Rate (per kg)	Cost
Sugar	2.5	32
Rice	4.0	35
Chana Dal	1.5	60
Toor Dal	3.0	70
Wheat	7.0	21
Oil	1.5	110
		Total

Solution:

Food Stuff	Weight (kg)	Rate (per kg)	Cost
Sugar	2.5	32	2.5 x 32 = 80.00
Rice	4.0	35	35 x 4 = 140.00
Chana dal	1.5	60	1.5 x 60 = 90.00
Toor dal	3.0	70	70 x 3 = 210.00
Wheat	7.0	21	21 x 7 = 147.00
Oil	1.5	110	110 x 1.5 = 165.00
		Total	832.00

Answer: The completed table shows the individual costs and a total bill of Rs. 832.00.
In simple words: To complete the bill, multiply the weight of each foodstuff by its rate per kg to find its cost. Then, add all the individual costs to get the total bill.

🎯 Exam Tip: For bill preparation, calculate the cost for each item by multiplying quantity (weight) by its unit price (rate per kg). Ensure accuracy in decimal multiplication, then sum all individual costs to get the grand total. Careful calculation prevents common errors.

Problems On Measurement Problem Set 47 Additional Important Questions And Answers

Question 1.One can contains 30 l 560 ml of milk, while second contains 25 l 890 ml of milk and third one contains 20 l 760 ml of milk. How much milk is there in the three cans together? Solution:

l	ml
2	2
30	560	milk in one can
+25	890	milk in second can
+20	760	milk in third can
77	210	milk in three cans

∴ 77 l 210 ml total milk
Answer: There is 77 l 210 ml of milk in the three cans together.
In simple words: Add the milk quantities from all three cans. Sum the milliliters and liters separately, converting excess milliliters (over 1000 ml) to liters and carrying them over.

🎯 Exam Tip: When adding multiple quantities with mixed units, always add the smaller units (ml) first. Convert any sum exceeding the base (1000 ml) into the larger unit (l) and carry it over to ensure accurate total measurement.

Question 2.Add the following:
(1) Rs. 13, 85 paise + Rs. 16, 40 paise
(2) 15 kg 280 gm + 18 kg 920 gm
(3) 24 l 690 ml + 25 l 780 ml
(4) 22 km 750 m + 27 km 500 m
(5) 17 m 40 cm + 19 m 85 cm
(6) 38 cm 8 mm + 17 cm 2 mm
(7) 10 km 950 m + 15 km 125 m
(8) 83 kg 468 gm + 109 kg 532 gm Answer:
(1) Rs. 30, 25 paise
(2) 34 kg 200 gm
(3) 50 l 470 ml
(4) 50 km 250 m
(5) 37 m 25 cm
(6) 56 cm
(7) 26 km 75 m
(8) 193 kg
Answer:
(1) Rs. 30 and 25 paise
(2) 34 kg 200 gm
(3) 50 l 470 ml
(4) 50 km 250 m
(5) 37 m 25 cm
(6) 56 cm
(7) 26 km 75 m
(8) 193 kg
In simple words: For each part, add the respective units separately. For money, 100 paise = 1 Rupee. For mass, 1000 gm = 1 kg. For volume, 1000 ml = 1 l. For length, 1000 m = 1 km, 100 cm = 1 m, 10 mm = 1 cm. Convert and carry over as needed.

🎯 Exam Tip: When adding mixed units, always convert and carry over from the smaller unit to the larger unit based on their respective conversion factors (e.g., 100 paise = Rs. 1, 1000g = 1kg). Display your answer with proper units.

Question 3.Subtract the following:
(1) Rs. 21, 30 paise - Rs. 13, 80 paise
(2) 16 kg 130 gm - 9 kg 250 gm
(3) 9 l 350 ml - 5 l 470 ml
(4) 41 m 10 cm - 14 m 40 cm
(5) 38 km 175 m - 20 km 365 m
(6) 27 cm 5 mm - 11 cm 8 mm
(7) 28 km 725 m - 13 km 590 m
(8) 380 kg - 232 kg 730 gm Answer:
(1) Rs. 7, 50 paise
(2) 6 kg 880 gm
(3) 3 l 880 ml
(4) 26 m 30 cm
(5) 17 km 810 m
(6) 15 cm 7 mm
(7) 15 km 135 m
(8) 147 kg 270 gm
Answer:
(1) Rs. 7 and 50 paise
(2) 6 kg 880 gm
(3) 3 l 880 ml
(4) 26 m 30 cm
(5) 17 km 810 m
(6) 15 cm 7 mm
(7) 15 km 135 m
(8) 147 kg 270 gm
In simple words: For each part, subtract the smaller units first. If the smaller unit in the top number is less than in the bottom, borrow from the larger unit, converting it according to the standard unit conversion (e.g., 1 Rupee = 100 paise, 1 kg = 1000 gm, etc.).

🎯 Exam Tip: In subtraction problems, borrowing is key. When the smaller unit in the minuend is insufficient, borrow 1 from the larger unit and convert it (e.g., 1 m = 100 cm, 1 km = 1000 m). Show the borrowing process clearly for each step.

Question 4.Fill in the blanks:
(1) 1250 m = ............ km ............ m
(2) 2.5 m = ............ m ............ cm
(3) 3 l 50 ml = ............ ml
(4) Rs. 2.5 = ............ paise Answer:
(1) 1 km 250 m
(2) 2 m 50 cm
(3) 3050 ml
(4) 250 paise
Answer:
(1) 1 km 250 m
(2) 2 m 50 cm
(3) 3050 ml
(4) 250 paise
In simple words: Use standard unit conversions: 1 km = 1000 m, 1 m = 100 cm, 1 l = 1000 ml, and Rs. 1 = 100 paise to fill in the blanks.

🎯 Exam Tip: Memorize and correctly apply common conversion factors (e.g., 1000m = 1km, 100cm = 1m, 1000ml = 1l, Rs. 1 = 100 paise). This foundational knowledge is essential for quickly and accurately converting between units.

Question 5.(A) Match the following:

'A'	'B'
(1) Potato 3.5 kg, rate per kg 12	(a) Rs. 40
(2) Onion 2 kg, rate per kg 20.50	(b) Rs. 42
(3) Vegetables 2.5 kg, rate per kg 16	(c) Rs. 39
(4) Others 6.5 kg, rate per kg 6	(d) Rs. 41

Answer:
(1 - b),
(2 - d),
(3 - a),
(4 - c)
Answer:
(1) Potato 3.5 kg, rate per kg 12 = (b) Rs. 42 (3.5 * 12 = 42)
(2) Onion 2 kg, rate per kg 20.50 = (d) Rs. 41 (2 * 20.50 = 41)
(3) Vegetables 2.5 kg, rate per kg 16 = (a) Rs. 40 (2.5 * 16 = 40)
(4) Others 6.5 kg, rate per kg 6 = (c) Rs. 39 (6.5 * 6 = 39)
In simple words: Multiply the weight by the rate per kg for each item in column 'A' to find its total cost, then match it to the correct cost in column 'B'.

🎯 Exam Tip: For matching questions, calculate the value for each item on one side first. Then, systematically match these calculated values to the options provided on the other side. Double-check all multiplications.

Question 5.(B) Match the following:

'A'	'B'
(1) Half metre	(a) 5 cm
(2) Half kilometre	(b) 50 cm
(3) 50 millimetre	(c) 500 cm
(4) 5 kilometre	(d) 500 m
(5) 5 metre	(e) 5000 m

Answer:
(1 - b),
(2 - d),
(3 - a),
(4 - e),
(5 - c)
Answer:
(1) Half metre = (b) 50 cm
(2) Half kilometre = (d) 500 m
(3) 50 millimetre = (a) 5 cm
(4) 5 kilometre = (e) 5000 m
(5) 5 metre = (c) 500 cm
In simple words: Match the measurements in column 'A' to their equivalent values in column 'B' using standard unit conversions: 1 m = 100 cm, 1 km = 1000 m, 1 cm = 10 mm.

🎯 Exam Tip: Proficiency in unit conversions is critical. Review basic length conversions (m, cm, mm, km) thoroughly. For matching tasks, carefully convert each item to a common unit or its equivalent to ensure accurate pairings.

The provided page range (pages 15-16) does not contain any questions or answers that fit the specified content processing rules (e.g., "Question N.", Solution, "In simple words", "Exam Tip"). These pages primarily consist of navigational links, section headings, and copyright information. Therefore, there is no convertible content within this range.