Maharashtra Board Class 12 Maths Part 1 Chapter 1 Mathematical Logic 1.10 Solutions

Get the most accurate MSBSHSE Solutions for Class 12 Maths Commerce Chapter 1 Mathematical Logic 1.10 here. Updated for the 2026-27 academic session, these solutions are based on the latest MSBSHSE textbooks for Class 12 Maths Commerce. Our expert-created answers for Class 12 Maths Commerce are available for free download in PDF format.

Detailed Chapter 1 Mathematical Logic 1.10 MSBSHSE Solutions for Class 12 Maths Commerce

For Class 12 students, solving MSBSHSE textbook questions is the most effective way to build a strong conceptual foundation. Our Class 12 Maths Commerce solutions follow a detailed, step-by-step approach to ensure you understand the logic behind every answer. Practicing these Chapter 1 Mathematical Logic 1.10 solutions will improve your exam performance.

Class 12 Maths Commerce Chapter 1 Mathematical Logic 1.10 MSBSHSE Solutions PDF

Question 1. Express the truth of each of the following statements by Venn diagrams:
(i) Some hardworking students are obedient.

Answer:
(i) Let U : set of all students
S : set of all hardworking students
O : set of all obedient students.
The shaded region represents the common elements between both sets. Then the Venn diagram representing the truth of the given statement is as below:
U S O
In simple words: The diagram shows two overlapping circles inside a box. The overlapping shaded part represents students who are both hardworking and obedient.

🎯 Exam Tip: Always define the universal set U and clearly label each circle with its corresponding set letter to secure full marks.

 

Question 1. Represent the following statements using Venn diagrams:
(ii) No circles are polygons.
(iii) All teachers are scholars and scholars are teachers.
(iv) If a quadrilateral is a rhombus, then it is a parallelogram.

Answer:
(ii) Let \( U \) : set of closed geometrical figures in the plane
\( P \) : set of all polygons
\( C \) : set of all circles.
Then the Venn diagram represents the truth of the given statement as follows: U P C
\( P \cap C = \emptyset \)

(iii) Let \( U \) : set of all human beings
\( T \) : set of all teachers
\( S \) : set of all scholars.
Then the Venn diagram represents the truth of the given statement as below: U T = S
\( T = S \)

(iv) Let \( U \) : set of all quadrilaterals
\( R \) : set of all rhombuses
\( P \) : set of all parallelograms.
Then the Venn diagram represents the truth of the given statement as below: U P R
\( R \subseteq P \)
Venn diagrams provide a clear visual representation of logical relationships between different sets.
In simple words: We use circles inside a rectangle to show how different groups of things relate to each other. Disjoint circles mean the groups have nothing in common, while one circle inside another means one group is completely part of the larger group.

🎯 Exam Tip: Always define the universal set \( U \) clearly at the beginning of your solution, and ensure the circles are properly labeled inside the rectangle to secure full marks.

 

Question 2. Draw the Venn diagrams for the truth of the following statements:
(i) Some share brokers are chartered accountants.
(ii) No wicket-keeper is a bowler in a cricket team.

Answer:
(i) Let \( U \) be the set of all human beings, \( S \) be the set of all share brokers, and \( C \) be the set of all chartered accountants. The statement "Some share brokers are chartered accountants" implies that there is at least one person who belongs to both categories. Therefore, the intersection of these two sets is non-empty, which is represented mathematically as \( S \cap C \neq \emptyset \). These diagrams visually simplify complex logical relationships between different groups of people. U S C
(ii) Let \( U \) be the set of all human beings, \( W \) be the set of all wicket keepers, and \( B \) be the set of all bowlers. The statement "No wicket-keeper is a bowler in a cricket team" implies that there is no individual who is both a wicket-keeper and a bowler. Therefore, the two sets have no elements in common, which is represented mathematically as \( W \cap B = \emptyset \). U W B
In simple words: To show "some" of two groups overlap, we draw two circles that cross each other and shade the middle part. To show "no" overlap between two groups, we draw two completely separate circles that do not touch.

🎯 Exam Tip: Always define the universal set \( U \) clearly before drawing Venn diagrams, and ensure you label each set with its corresponding capital letter to secure full marks.

 

Question 3. Represent the following statements by Venn diagrams:
(i) Some non-resident Indians are not rich.
(ii) No circle is a rectangle.
(iii) If n is a prime number and n ≠ 2, then it is odd.
Answer:
(i) Let U : set of all human beings
N : set of all non-resident Indians
R : set of all rich people.
Then the Venn diagram represents the truth of the given statement is as below: U N R \( N - R \neq \phi \)

(ii) Let U : set of all geometrical figures
C : set of all circles
R : set of all rectangles
Then the Venn diagram represents the truth of the given statement is as below: U C R \( C \cap R = \phi \)

(iii) Let U : set of all real numbers
P : set of all prime numbers n, where \( n \neq 2 \)
O : set of all odd numbers.
Then the Venn diagram represents the truth of the given statement is as below: U O P \( P \subseteq O \)
In simple words: Venn diagrams help us see how different groups relate to each other. We can show if groups overlap slightly, are completely separate, or if one group fits entirely inside another.

🎯 Exam Tip: Clearly define the universal set \( U \) and all other sets before drawing. Label every set and the universal set \( U \) in your diagram to secure full marks.

Venn Diagram: \( P \subset O \)

The relation \( P \subset O \) indicates that set P is a proper subset of set O. In a Venn diagram, this is represented by drawing the circle for set P completely inside the circle for set O, within the universal set U.

U O P

 

🎯 Exam Tip: When representing the subset relation \( A \subset B \), always ensure the circle representing the subset (A) is drawn entirely inside the boundary of the parent set (B) to secure full marks.

MSBSHSE Solutions Class 12 Maths Commerce Chapter 1 Mathematical Logic 1.10

Students can now access the MSBSHSE Solutions for Chapter 1 Mathematical Logic 1.10 prepared by teachers on our website. These solutions cover all questions in exercise in your Class 12 Maths Commerce textbook. Each answer is updated based on the current academic session as per the latest MSBSHSE syllabus.

Detailed Explanations for Chapter 1 Mathematical Logic 1.10

Our expert teachers have provided step-by-step explanations for all the difficult questions in the Class 12 Maths Commerce chapter. Along with the final answers, we have also explained the concept behind it to help you build stronger understanding of each topic. This will be really helpful for Class 12 students who want to understand both theoretical and practical questions. By studying these MSBSHSE Questions and Answers your basic concepts will improve a lot.

Benefits of using Maths Commerce Class 12 Solved Papers

Using our Maths Commerce solutions regularly students will be able to improve their logical thinking and problem-solving speed. These Class 12 solutions are a guide for self-study and homework assistance. Along with the chapter-wise solutions, you should also refer to our Revision Notes and Sample Papers for Chapter 1 Mathematical Logic 1.10 to get a complete preparation experience.

FAQs

Where can I find the latest Maharashtra Board Class 12 Maths Part 1 Chapter 1 Mathematical Logic 1.10 Solutions for the 2026-27 session?

The complete and updated Maharashtra Board Class 12 Maths Part 1 Chapter 1 Mathematical Logic 1.10 Solutions is available for free on StudiesToday.com. These solutions for Class 12 Maths Commerce are as per latest MSBSHSE curriculum.

Are the Maths Commerce MSBSHSE solutions for Class 12 updated for the new 50% competency-based exam pattern?

Yes, our experts have revised the Maharashtra Board Class 12 Maths Part 1 Chapter 1 Mathematical Logic 1.10 Solutions as per 2026 exam pattern. All textbook exercises have been solved and have added explanation about how the Maths Commerce concepts are applied in case-study and assertion-reasoning questions.

How do these Class 12 MSBSHSE solutions help in scoring 90% plus marks?

Toppers recommend using MSBSHSE language because MSBSHSE marking schemes are strictly based on textbook definitions. Our Maharashtra Board Class 12 Maths Part 1 Chapter 1 Mathematical Logic 1.10 Solutions will help students to get full marks in the theory paper.

Do you offer Maharashtra Board Class 12 Maths Part 1 Chapter 1 Mathematical Logic 1.10 Solutions in multiple languages like Hindi and English?

Yes, we provide bilingual support for Class 12 Maths Commerce. You can access Maharashtra Board Class 12 Maths Part 1 Chapter 1 Mathematical Logic 1.10 Solutions in both English and Hindi medium.

Is it possible to download the Maths Commerce MSBSHSE solutions for Class 12 as a PDF?

Yes, you can download the entire Maharashtra Board Class 12 Maths Part 1 Chapter 1 Mathematical Logic 1.10 Solutions in printable PDF format for offline study on any device.