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MSBSHSE Class 12 Maths Commerce Part I Chapter 8 Differential Equation and Applications Digital Edition
For Class 12 Maths Commerce, this chapter in Maharashtra Board Class 12 Maths Commerce Part I Chapter 8 Differential Equation and Applications PDF Download provides a detailed overview of important concepts. We highly recommend using this text alongside the MSBSHSE Solutions for Class 12 Maths Commerce to learn the exercise questions provided at the end of the chapter.
Part I Chapter 8 Differential Equation and Applications MSBSHSE Book Class 12 PDF (2026-27)
Differential Equations and Applications
Let's Study
Differential Equation
Ordinary differential equation
Order and degree of a differential equation
Solution of a differential equation
Formation of a differential equation
Applications of differential equations
Let's Recall
Independent variable
Dependent variable
Equation
Derivatives
Integration
Let's Learn
8.1 Differential Equations
Definition
An equation involving dependent variable(s), independent variable and derivative(s) of dependent variable(s) with respect to the independent variable is called a differential equation.
For example:
\(\frac{dy}{dx} + y = x\)
\(x^2 \frac{d^2y}{dx^2} + x \frac{dy}{dx} + y = 0\)
\(\frac{d^2y}{dt^2} = 2t\)
\(r \frac{dr}{d\theta} + e^\theta = 8\)
\(\sqrt{1 + \frac{dy}{dx}} = \frac{d^2y}{dx^2}\)
\(x \, dx + y \, dy = 0\)
8.1.1 Ordinary Differential Equation
A differential equation in which the dependent variable, say y, depends only on one independent variable, say x, is called an ordinary differential equation.
8.1.2 Order Of A Differential Equation
It is the order of the highest order derivative occurring in the differential equation.
\(\frac{dy}{dx} + y = x\) is of order 1
\(x^2 \frac{d^2y}{dx^2} + x \frac{dy}{dx} + y = 0\) is of order 2
\(\left(\frac{d^2y}{dx^2}\right)^2 + x \frac{dy}{dx} = 2y\) is of order 2
\(\frac{2dy}{dx} = e^x\) is of order 1
8.1.3 Degree Of A Differential Equation
It is the power of the highest order derivative when all the derivatives are made free from fractional indices and negative sign, if any.
For example:
\(x^2 \left(\frac{d^2y}{dx^2}\right) + x \frac{dy}{dx} + y = 0\)
In this equation, the highest order derivative is \(\frac{d^2y}{dx^2}\) and its power is one. Therefore this equation has degree one.
Teacher's Note
Order tells us which derivative is highest. Degree tells us the power of that highest derivative. Like in a school, order is the class number and degree is how many times the student appears.
Exam Trick
Remember: First remove all roots and negative signs. Then find the power of the highest derivative. That power is the degree. Order is always just the number of the derivative.
Points to Remember
Order is the highest derivative in the equation.
Degree is the power of that highest derivative.
Always remove roots and negative signs before finding degree.
Order and degree are always positive whole numbers.
Order is never the same as degree if there is a root.
Solution Of A Differential Equation
A function of the form \(y = f(x) + c\) which satisfies the given differential equation is called the solution of the differential equation.
Every differential equation has two types of solutions: 1) General and 2) Particular
1) General Solution
A solution of the differential equation in which the number of arbitrary constants is equal to order of differential equation is called a general solution.
2) Particular Solution
A solution of the differential equation which can be obtained from the general solution by giving particular values to the arbitrary constants is called a particular solution.
Solved Examples
1) Verify that the function \(y = ae^x + be^{2x}\), where \(a, b \in \mathbb{R}\) is a solution of the differential equation \(\frac{d^2y}{dx^2} - \frac{dy}{dx} - 2y = 0\).
Solution: Consider the function
\(y = ae^x + be^{2x}\) .......... (I)
Differentiating both sides of equation I with respect to x, we get
\(\frac{dy}{dx} = ae^x + 2be^{2x}\) .......... II and
Differentiating both sides of equation II with respect to x, we get
\(\frac{d^2y}{dx^2} = ae^x + 4be^{2x}\) .......... III
Now, L.H.S = \(\frac{d^2y}{dx^2} - \frac{dy}{dx} - 2y\)
= \(ae^x + 4be^{2x} - (ae^x + 2be^{2x}) - 2(ae^x + be^{2x})\) from II and III
= \(2ae^x + 2be^{2x}\)
= \(2(ae^x + be^{2x}) - 2y\) from I
= R.H.S
Therefore, the given function is a general solution of the given differential equation.
Teacher's Note
To verify a solution, differentiate it as many times as needed, then put all values in the equation. If both sides match, it is correct. Like checking if a student's homework answer is right.
Exam Trick
Count the arbitrary constants in the solution. If there are n constants and the equation is order n, then it is a general solution. If constants have values, it is a particular solution.
Points to Remember
General solution has arbitrary constants.
Particular solution has no arbitrary constants.
Number of constants equals the order of the equation for general solution.
To verify, differentiate and substitute back in the equation.
Both sides of equation must be equal after verification.
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MSBSHSE Book Class 12 Maths Commerce Part I Chapter 8 Differential Equation and Applications
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