Multiple Choice Questions (MCQs) for JEE Physics: Magnetism and Matter
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Multiple Choice Questions
Assertion (A): Electromagnets are made of soft iron.
Reason (R): The coercivity of soft iron is small.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (a) Both A and R are true, and R is the correct explanation of A.
Explanation:
1. An electromagnet must be easy to magnetise and demagnetise.
2. Small coercivity of soft iron makes this possible.
Teacher's Note:
1. Low coercivity.
(a) 2
(b) 1
(c) 0.5
(d) 0.25
Show Answer & Explanation
Answer: (a) 2
Explanation:
1. W = MB(1 - cos θ).
2. W(90°) = MB and W(60°) = MB/2, so n = 2.
Teacher's Note:
1. W = MB(1 - cos θ).
(a) \( B=\mu_0(H+I) \)
(b) \( B=H+4\pi I \)
(c) \( H=\mu_0(B+I) \)
(d) none of these
Show Answer & Explanation
Answer: (a) \( B=\mu_0(H+I) \)
Explanation:
1. B = μ₀(H + I), where I is the magnetisation.
Teacher's Note:
1. Know the basic fact.
(a) a ferromagnetic material becomes paramagnetic
(b) a paramagnetic material becomes diamagnetic
(c) a ferromagnetic material becomes diamagnetic
(d) a paramagnetic material becomes ferromagnetic
Show Answer & Explanation
Answer: (a) a ferromagnetic material becomes paramagnetic
Explanation:
1. Above the Curie point the domain order is destroyed by thermal agitation and the ferromagnet behaves as a paramagnet.
Teacher's Note:
1. Know the basic fact.
(a) 6
(b) \( 3\sqrt3 \)
(c) \( 3(2-\sqrt3) \)
(d) 3
Show Answer & Explanation
Answer: (c) \( 3(2-\sqrt3) \)
Explanation:
1. W = MB(1 - cos 30°) = 20 × 0.3 × (1 - √3/2) = 3(2 - √3).
Teacher's Note:
1. W = MB(1 - cos θ).
(a) \( M \)
(b) \( M/\sqrt2 \)
(c) \( M/2 \)
(d) \( 2M \)
Show Answer & Explanation
Answer: (b) \( M/\sqrt2 \)
Explanation:
1. M = m l.
2. After bending, the poles are separated by the diagonal √((l/2)² + (l/2)²) = l/√2.
3. The new moment is m l/√2 = M/√2.
Teacher's Note:
1. Moment = pole strength × pole separation.
(a) \( 5\times10^{-6}\ \text{N m} \)
(b) data is insufficient
(c) \( \tfrac13\times10^{-5}\ \text{N m} \)
(d) \( 5\sqrt3\times10^{-6}\ \text{N m} \)
Show Answer & Explanation
Answer: (a) \( 5\times10^{-6}\ \text{N m} \)
Explanation:
1. τ = MH sin θ.
2. τ(30°)/τ(90°) = sin 30° = 1/2, so τ = 5 × 10⁻⁶ N m.
Teacher's Note:
1. τ is proportional to sin θ.
(a) 6 : 4
(b) 30 : 16
(c) 2.6 : 1
(d) 1.5 : 1
Show Answer & Explanation
Answer: (c) 2.6 : 1
Explanation:
1. T is proportional to 1/√M.
2. M1 + M2 is proportional to 1/16 and M1 - M2 to 1/36.
3. M1 : M2 = (1/16 + 1/36) : (1/16 - 1/36) = 52 : 20 = 2.6 : 1.
Teacher's Note:
1. Square the periods.
(a) diamagnetic materials
(b) paramagnetic materials
(c) ferromagnetic materials
(d) all of the above
Show Answer & Explanation
Answer: (a) diamagnetic materials
Explanation:
1. Only diamagnetic materials have χ less than zero.
Teacher's Note:
1. Know the basic fact.
(a) stay in the north-south direction only
(b) stay in the east-west direction only
(c) become rigid showing no movement
(d) stay in any position
Show Answer & Explanation
Answer: (d) stay in any position
Explanation:
1. The field is vertical, so the horizontal component is zero and no torque acts on the needle in the horizontal plane.
Teacher's Note:
1. Know the basic fact.
(a) 4 : 5
(b) 16 : 25
(c) 64 : 125
(d) \( 2:\sqrt5 \)
Show Answer & Explanation
Answer: (c) 64 : 125
Explanation:
1. The needle lies on the axial line of each magnet, and the two axial fields are opposite.
2. M1/40³ = M2/50³, so M1 : M2 = 64000 : 125000 = 64 : 125.
Teacher's Note:
1. Axial field is proportional to M/d³.
(a) R = 0
(b) V = 0
(c) H = 0
(d) θ = 0°
Show Answer & Explanation
Answer: (c) H = 0
Explanation:
1. The compass needle responds to the horizontal component H, which is zero at the poles.
Teacher's Note:
1. Know the basic fact.
(a) permeability
(b) magnetic intensity
(c) magnetic induction
(d) magnetic susceptibility
Show Answer & Explanation
Answer: (d) magnetic susceptibility
Explanation:
1. χ = I/H.
Teacher's Note:
1. Know the basic fact.
(a) I only
(b) II only
(c) I, II and III
(d) II and IV
Show Answer & Explanation
Answer: (b) II only
Explanation:
1. Only II is incorrect: domain theory explains ferromagnetism, not paramagnetism.
Teacher's Note:
1. Domains belong to ferromagnetism.
(a) convective currents in the earth's core
(b) diversive current in the earth's core
(c) rotational motion of the earth
(d) translational motion of the earth
Show Answer & Explanation
Answer: (a) convective currents in the earth's core
Explanation:
1. Convective motion of molten conducting material in the outer core is the accepted source of the earth's field.
Teacher's Note:
1. Know the basic fact.
(a) diamagnetic
(b) paramagnetic
(c) ferromagnetic
(d) non-magnetic
Show Answer & Explanation
Answer: (c) ferromagnetic
Explanation:
1. Ferromagnetic domains stay aligned, giving retentivity.
Teacher's Note:
1. Know the basic fact.
(a) \( 10^{2} \)
(b) 1
(c) \( 10^{4} \)
(d) \( 10^{3} \)
Show Answer & Explanation
Answer: (c) \( 10^{4} \)
Explanation:
1. μr = B/(μ₀ H) = 8π/(4π × 10⁻⁷ × 2 × 10³) = 10⁴.
Teacher's Note:
1. μr = B/(μ₀H).
(a) neither a force nor a torque
(b) a torque but not a force
(c) a force but not a torque
(d) a force and a torque
Show Answer & Explanation
Answer: (d) a force and a torque
Explanation:
1. The poles feel unequal forces in a non-uniform field, so there is a net force as well as a torque.
Teacher's Note:
1. Know the basic fact.
(a) zero, maximum
(b) maximum, minimum
(c) maximum, maximum
(d) minimum, minimum
Show Answer & Explanation
Answer: (a) zero, maximum
Explanation:
1. At the pole the field is vertical, so B_H = 0 and the dip is 90° (maximum).
Teacher's Note:
1. Know the basic fact.
(a) I and II
(b) I, II and III
(c) II and III
(d) I and III only
Show Answer & Explanation
Answer: (b) I, II and III
Explanation:
1. Above the Curie temperature the domains are destroyed and the material becomes paramagnetic.
2. So I, II and III are all incorrect.
Teacher's Note:
1. It becomes paramagnetic.
(a) \( \sqrt3\ \text{s} \)
(b) \( 3\sqrt3\ \text{s} \)
(c) \( 3\ \text{s} \)
(d) \( 6\ \text{s} \)
Show Answer & Explanation
Answer: (b) \( 3\sqrt3\ \text{s} \)
Explanation:
1. Initially the net moment is 3M and later 2M - M = M.
2. T is proportional to 1/√M, so T' = 3 × √(3M/M) = 3√3 s.
Teacher's Note:
1. T = 2π√(I/MB).
(a) I only
(b) II only
(c) I and II
(d) I, II and III
Show Answer & Explanation
Answer: (c) I and II
Explanation:
1. A paramagnet moves from weak to strong field, so I is false.
2. A ferromagnet is paramagnetic above its Curie temperature, so II is false.
3. III is true.
Teacher's Note:
1. Check the direction of motion.
(a) south pole to north pole
(b) north pole to south pole
(c) east to west
(d) west to east
Show Answer & Explanation
Answer: (a) south pole to north pole
Explanation:
1. By convention the moment points from the south pole to the north pole inside the magnet.
Teacher's Note:
1. Know the basic fact.
(a) NIA
(b) NI/A
(c) \( NI/\sqrt A \)
(d) \( N^2AI \)
Show Answer & Explanation
Answer: (a) NIA
Explanation:
1. M = N I A.
Teacher's Note:
1. Know the basic fact.
Assertion (A): The earth's magnetic field is due to the iron present in its core.
Reason (R): At a high temperature a magnet loses its magnetism.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (d) A is false, but R is true.
Explanation:
1. The core is too hot for iron to be ferromagnetic, so the assertion is false.
2. The reason is true: above the Curie point magnetism is lost.
Teacher's Note:
1. Core is above the Curie temperature.
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