JEE Chemistry States Of Matter MCQs Set 23

Multiple Choice Questions (MCQs) for JEE Chemistry: States Of Matter

Access targeted multiple-choice questions for States Of Matter designed to align with the latest JEE academic syllabus for JEE Chemistry. These objective practice sets help students evaluate their conceptual understanding and improve exam readiness.

Practice States Of Matter MCQs for JEE Chemistry

Access the complete set of multiple-choice questions for States Of Matter below. This focused format allows students to isolate specific topics for thorough review and uninterrupted practice alongside official JEE textbooks.

Multiple Choice Questions

Question 1: A ship sails in the Pacific Ocean where the temperature is 23.4°C. A balloon is filled with 2 L of air. What will be the volume of the balloon when the ship reaches the Indian Ocean, where the temperature is 26.1°C (pressure constant)?
(a) 12.01 L
(b) 6.01 L
(c) 2.01 L
(d) 1.02 L
Show Answer & Explanation

Answer: (c) 2.01 L

Explanation:
1. V2 = V1T2/T1 = 2 × 299.1/296.4.
2. = 2.018 L ≈ 2.01 L.
3. Answer: (c)

Teacher's Note:
1. Write the gas law or relation first and substitute carefully. Check units and that the result is physically reasonable.

Question 2: At 27°C and 500 mm Hg pressure a gas occupies 400 mL. What will be its pressure at a height where the temperature is 7°C and the volume is 550 mL?
(a) 340 mm
(b) 240 mm
(c) 440 mm
(d) 540 mm
Show Answer & Explanation

Answer: (a) 340 mm

Explanation:
1. P1V1/T1 = P2V2/T2.
2. P2 = 500 × 400 × 280/(300 × 550) = 339.4 ≈ 340 mm.
3. Answer: (a)

Teacher's Note:
1. Write the gas law or relation first and substitute carefully. Check units and that the result is physically reasonable.

Question 3: A methane and H2 mixture contains 10 g methane and 5 g hydrogen. If the total pressure of the mixture is 30 atm, what is the partial pressure of H2 in the mixture?
(a) 6 atm
(b) 129 atm
(c) 24 atm
(d) 189 atm
Show Answer & Explanation

Answer: (c) 24 atm

Explanation:
1. Moles: CH4 = 10/16 = 0.625; H2 = 5/2 = 2.5.
2. Mole fraction of H2 = 2.5/3.125 = 0.8, so p = 0.8 × 30 = 24 atm.
3. Answer: (c)

Teacher's Note:
1. Write the gas law or relation first and substitute carefully. Check units and that the result is physically reasonable.

Question 4: The temperature at which a real gas obeys the ideal gas law over an appreciable range of pressure is called:
(a) boiling temperature
(b) freezing temperature
(c) Boyle's temperature
(d) inversion temperature
Show Answer & Explanation

Answer: (c) Boyle's temperature

Explanation:
1. At the Boyle temperature the effects of attraction and molecular volume cancel.
2. The gas then follows Boyle's law over a wide pressure range.
3. Answer: (c)

Teacher's Note:
1. Write the gas law or relation first and substitute carefully. Check units and that the result is physically reasonable.

Question 5: At the critical temperature the value of the compressibility factor Zc is:
(a) 8/3
(b) 3/8
(c) 1/8
(d) 1/27
Show Answer & Explanation

Answer: (b) 3/8

Explanation:
1. For a van der Waals gas, Pc = a/27b2, Vc = 3b, Tc = 8a/27Rb.
2. Zc = PcVc/RTc = 3/8.
3. Answer: (b)

Teacher's Note:
1. Write the gas law or relation first and substitute carefully. Check units and that the result is physically reasonable.

Question 6: Which of the following is/are true? (i) At the critical temperature the surface separating two phases disappears; (ii) below the critical temperature a gas is called a vapour; (iii) a gas cannot be liquefied below the critical temperature; (iv) a gas with a higher critical temperature is more difficult to liquefy.
(a) (i), (iii), (iv)
(b) (i), (ii), (iv)
(c) (iii), (iv)
(d) (i), (ii)
Show Answer & Explanation

Answer: (d) (i), (ii)

Explanation:
1. (i) and (ii) are correct statements.
2. A gas can be liquefied only below Tc, so (iii) is false; a higher Tc makes liquefaction easier, so (iv) is false.
3. Answer: (d)

Teacher's Note:
1. Write the gas law or relation first and substitute carefully. Check units and that the result is physically reasonable.

Question 7: Which one of the following is correctly matched? (i) Z = 1, (ii) Z < 1, (iii) Z > 1, (iv) Zc = 3/8, with (A) negative deviation, (B) positive deviation, (C) ideal behaviour, (D) at critical conditions.
(a) (i)–A, (ii)–B, (iii)–C, (iv)–D
(b) (i)–B, (ii)–A, (iii)–D, (iv)–C
(c) (i)–C, (ii)–A, (iii)–B, (iv)–D
(d) (i)–D, (ii)–B, (iii)–A, (iv)–C
Show Answer & Explanation

Answer: (c) (i)–C, (ii)–A, (iii)–B, (iv)–D

Explanation:
1. Z = 1 is ideal behaviour; Z < 1 is negative deviation; Z > 1 is positive deviation.
2. Zc = 3/8 holds at the critical point.
3. Answer: (c)

Teacher's Note:
1. Write the gas law or relation first and substitute carefully. Check units and that the result is physically reasonable.

Question 8: A real gas shows ideal behaviour at:
(a) high pressure, high temperature
(b) high pressure, low temperature
(c) low pressure, low temperature
(d) low pressure, high temperature
Show Answer & Explanation

Answer: (d) low pressure, high temperature

Explanation:
1. Low pressure makes molecular volume negligible compared with the container.
2. High temperature makes kinetic energy overcome intermolecular attraction.
3. Answer: (d)

Teacher's Note:
1. Write the gas law or relation first and substitute carefully. Check units and that the result is physically reasonable.

Question 9: 1 mol of a gas occupies 2.4 L at 27°C and 10 atm pressure. It shows:
(a) positive deviation
(b) negative deviation
(c) ideal behaviour
(d) none of these
Show Answer & Explanation

Answer: (b) negative deviation

Explanation:
1. Z = PV/nRT = 10 × 2.4/(0.0821 × 300) = 0.974.
2. Z < 1 means negative deviation (attractions dominate).
3. Answer: (b)

Teacher's Note:
1. Write the gas law or relation first and substitute carefully. Check units and that the result is physically reasonable.

Question 10: The van der Waals constants a and b for two gases are 4.6 and 0.04 for X, and 5.1 and 0.06 for Y. Which can be liquefied more easily by application of pressure?
(a) X
(b) Y
(c) both equally
(d) none of these
Show Answer & Explanation

Answer: (b) Y

Explanation:
1. A larger constant a means stronger intermolecular attraction.
2. Y has the larger a, so it is liquefied more easily.
3. Answer: (b)

Teacher's Note:
1. Write the gas law or relation first and substitute carefully. Check units and that the result is physically reasonable.

Question 11: Which of the following gases always shows positive deviation from ideal gas behaviour with increase in pressure?
(a) NH3
(b) CO2
(c) H2
(d) CO
Show Answer & Explanation

Answer: (c) H2

Explanation:
1. H2 has a very small attraction constant a, so Z > 1 at all pressures at ordinary temperature.
2. The others first show Z < 1.
3. Answer: (c)

Teacher's Note:
1. Write the gas law or relation first and substitute carefully. Check units and that the result is physically reasonable.

Question 12: If the ratio of the rates of diffusion of two gases A and B is 4 : 1, the ratio of their densities is:
(a) 1 : 16
(b) 1 : 4
(c) 1 : 2
(d) 1 : 8
Show Answer & Explanation

Answer: (a) 1 : 16

Explanation:
1. Rate is inversely proportional to √density.
2. dA/dB = (rB/rA)2 = (1/4)2 = 1 : 16.
3. Answer: (a)

Teacher's Note:
1. Write the gas law or relation first and substitute carefully. Check units and that the result is physically reasonable.

Question 13: Which of the following gases will have the highest value of van der Waals constant 'a'?
(a) H2
(b) He
(c) CO2
(d) NH3
Show Answer & Explanation

Answer: (d) NH3

Explanation:
1. Constant a measures intermolecular attraction.
2. NH3 forms hydrogen bonds, so it has the largest a.
3. Answer: (d)

Teacher's Note:
1. Write the gas law or relation first and substitute carefully. Check units and that the result is physically reasonable.

Question 14: At high temperature and low pressure, van der Waals equation becomes:
(a) (P + a/V2) = RT
(b) PV = RT
(c) P(V − b) = RT
(d) (P + a/V2)(V − b) = RT
Show Answer & Explanation

Answer: (b) PV = RT

Explanation:
1. At low pressure V is large, so a/V2 and b are negligible.
2. At high T the attraction is also unimportant, giving PV = RT.
3. Answer: (b)

Teacher's Note:
1. Write the gas law or relation first and substitute carefully. Check units and that the result is physically reasonable.

Question 15: In the van der Waals equation, the term a/V2 is introduced to correct for:
(a) the volume occupied by the molecules themselves
(b) the effect of kinetic energies of molecules
(c) the momentum changes when molecules collide
(d) the effect of forces of attraction between molecules
Show Answer & Explanation

Answer: (d) the effect of forces of attraction between molecules

Explanation:
1. Attractions reduce the pressure exerted on the walls.
2. The a/V2 term adds this lost pressure back.
3. Answer: (d)

Teacher's Note:
1. Write the gas law or relation first and substitute carefully. Check units and that the result is physically reasonable.

Question 16: At relatively high pressure, van der Waals equation reduces to:
(a) PV = RT
(b) PV = RT + a/V
(c) PV = RT + Pb
(d) PV = RT − a/V2
Show Answer & Explanation

Answer: (c) PV = RT + Pb

Explanation:
1. At high pressure V is small, so b matters but a/V2 is small next to P.
2. P(V − b) = RT gives PV = RT + Pb.
3. Answer: (c)

Teacher's Note:
1. Write the gas law or relation first and substitute carefully. Check units and that the result is physically reasonable.

Question 17: Which gas can be most readily liquefied?
(a) NH3
(b) Cl2
(c) SO2
(d) CO2
Show Answer & Explanation

Answer: (c) SO2

Explanation:
1. Liquefaction is easiest for the gas with the highest critical temperature.
2. Among these, Tc of SO2 (431 K) is the highest (NH3 405 K, Cl2 417 K, CO2 304 K).
3. Answer: (c)

Teacher's Note:
1. Write the gas law or relation first and substitute carefully. Check units and that the result is physically reasonable.

Question 18: The density of a gas is found to be 5.46 g/L at 27°C and 2 atm pressure. What will be its density at STP?
(a) 3 g/L
(b) 2 g/L
(c) 1.5 g/L
(d) 1 g/L
Show Answer & Explanation

Answer: (a) 3 g/L

Explanation:
1. M = dRT/P = 5.46 × 0.0821 × 300/2 = 67.2 g/mol.
2. d(STP) = M/22.4 = 3.0 g/L.
3. Answer: (a)

Teacher's Note:
1. Write the gas law or relation first and substitute carefully. Check units and that the result is physically reasonable.

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Multiple Choice Questions (MCQs) for JEE Chemistry States Of Matter

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FAQs

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