Chemistry Objective Questions and Answers: Polymers
Review structured MCQ sets for JEE Chemistry Polymers. Built according to official JEE guidelines, these downloadable questions support daily revision and core concept reinforcement.
Download Polymers MCQs with Answers
Access the complete set of multiple-choice questions for Polymers below. This focused format allows students to isolate specific topics for thorough review and uninterrupted practice alongside official JEE textbooks.
Multiple Choice Questions
(a) polystyrene
(b) nylon
(c) PVC
(d) polypropylene
Show Answer & Explanation
Answer: (b) nylon
Explanation:
1. Polystyrene, PVC and polypropylene are formed by chain addition of vinyl monomers.
2. Nylon is a polyamide formed by condensation of a diamine with a diacid (or from caprolactam), so it is not an addition polymer.
Teacher's Note:
1. Addition polymers come from unsaturated monomers.
2. Nylon forms with loss of water.
(a) free radical polymerisation
(b) cationic polymerisation
(c) anionic polymerisation
(d) Ziegler-Natta polymerisation
Show Answer & Explanation
Answer: (a) free radical polymerisation
Explanation:
1. LDPE is made by heating ethene at high pressure (1000-2000 atm) and about 350-570 K with a peroxide initiator, a free radical process.
2. HDPE is made with a Ziegler-Natta catalyst.
Teacher's Note:
1. LDPE: free radical, branched.
2. HDPE: Ziegler-Natta, linear.
(a) toy making
(b) surface coating
(c) photofilm making
(d) electrical insulators
Show Answer & Explanation
Answer: (b) surface coating
Explanation:
1. Glyptal is a thermosetting polyester of phthalic acid and glycerol, and it is used in paints and lacquers as a surface coating.
Teacher's Note:
1. Glyptal gives paints and lacquers.
2. It is a cross-linked polyester.
(a) terylene
(b) polyethylene
(c) polypropylene
(d) nylon-6
Show Answer & Explanation
Answer: (d) nylon-6
Explanation:
1. Nylon-6 fibres have high tensile strength and are used for tyre cords.
2. Polyethylene and polypropylene are not used as cord fibres.
Teacher's Note:
1. Strong fibres reinforce tyres.
2. Nylon is a polyamide fibre.
(a) melamine and tetrafluoroethane
(b) malonic acid and hexamethylenetetramine
(c) melamine and vinyl acetate
(d) melamine and formaldehyde
Show Answer & Explanation
Answer: (d) melamine and formaldehyde
Explanation:
1. Melamine and formaldehyde undergo condensation polymerisation to give melamine-formaldehyde resin, a hard thermosetting plastic used for unbreakable crockery.
Teacher's Note:
1. Melamine polymer = melamine plus HCHO.
2. It is a cross-linked polymer.
(a) less than 1
(b) greater than 1
(c) 1
(d) 0
Show Answer & Explanation
Answer: (b) greater than 1
Explanation:
1. Polydispersity index = Mw / Mn = 40000 / 30000 = 1.33.
2. It is greater than 1 for any polymer with chains of different lengths.
Teacher's Note:
1. PDI of 1 means all chains are the same length.
2. Real polymers always have PDI above 1.
(a) (i) > (ii) > (iii)
(b) (ii) > (iii) > (i)
(c) (ii) < (iii) < (i)
(d) (iii) < (i) < (ii)
Show Answer & Explanation
Answer: (c) (ii) < (iii) < (i)
Explanation:
1. Buna-S is an elastomer with weak van der Waals forces.
2. Polythene is a thermoplastic with intermediate forces.
3. Nylon-6,6 is a fibre with strong hydrogen bonding between chains, so it has the strongest forces.
Teacher's Note:
1. Elastomer < thermoplastic < fibre.
2. Hydrogen bonding gives the highest forces.
(a) \( \ce{S8} \)
(b) \( \ce{CF4} \)
(c) \( \ce{Cl2F2} \)
(d) \( \ce{C2F2} \)
Show Answer & Explanation
Answer: (a) \( \ce{S8} \)
Explanation:
1. Vulcanisation heats natural rubber with sulphur (\( \ce{S8} \)) so that sulphur forms cross-links between the polymer chains.
Teacher's Note:
1. Goodyear's process.
2. Sulphur bridges make rubber harder and less sticky.
(a) propylene and p-HO-C6H4-OH
(b) benzoic acid and ethanol
(c) terephthalic acid and ethylene glycol
(d) benzoic acid and p-HO-C6H4-OH
Show Answer & Explanation
Answer: (c) terephthalic acid and ethylene glycol
Explanation:
1. Dacron (terylene) is formed by condensation of ethylene glycol with terephthalic acid at 420-460 K with a catalyst.
2. The link formed is an ester group, so Dacron is a polyester.
Teacher's Note:
1. Polyester needs a diol and a diacid.
2. PET is the polymer.
(a) nylon-6
(b) teflon
(c) terylene
(d) nylon-6,6
Show Answer & Explanation
Answer: (a) nylon-6
Explanation:
1. Caprolactam is heated with a trace of water at 533-543 K to give nylon-6 by ring-opening polymerisation.
Teacher's Note:
1. Nylon-6 comes from one monomer.
2. Nylon-6,6 needs two.
(a) neoprene
(b) Buna-N
(c) nylon-6,6
(d) bakelite
Show Answer & Explanation
Answer: (d) bakelite
Explanation:
1. Bakelite is a highly cross-linked polymer that sets permanently on heating and cannot be remoulded.
2. Neoprene and Buna-N are elastomers and nylon-6,6 is a fibre.
Teacher's Note:
1. Thermosetting = three-dimensional cross-linked network.
2. Examples: bakelite, melamine resin.
(a) terylene
(b) nylon
(c) rubber
(d) vulcanised rubber
Show Answer & Explanation
Answer: (b) nylon
Explanation:
1. A polyamide contains repeating amide (-CONH-) links.
2. Nylon is a polyamide, whereas terylene is a polyester and the rubbers are hydrocarbons.
Teacher's Note:
1. Amide link = CONH.
2. Proteins are natural polyamides.
(a) natural rubber
(b) synthetic rubber
(c) highly vulcanised rubber
(d) polypropene
Show Answer & Explanation
Answer: (c) highly vulcanised rubber
Explanation:
1. Ebonite is obtained by vulcanising natural rubber with 30-50 percent sulphur, which gives a hard, rigid material.
Teacher's Note:
1. Normal vulcanised rubber contains 3-5 percent sulphur.
2. Ebonite has far more.
(a) HCHO and melamine
(b) HCHO and ethylene
(c) melamine and ethylene
(d) none of these
Show Answer & Explanation
Answer: (a) HCHO and melamine
Explanation:
1. Melamine and formaldehyde condense with loss of water to form melamine-formaldehyde resin.
Teacher's Note:
1. Condensation of two bifunctional monomers.
(a) \( \ce{COOH(CH2)4COOH} \) and p-\( \ce{NH2C6H4NH2} \)
(b) \( \ce{COOH(CH2)4COOH} \) and \( \ce{NH2(CH2)6NH2} \)
(c) \( \ce{COOH(CH2)6COOH} \) and \( \ce{NH2(CH2)4NH2} \)
(d) p-\( \ce{COOHC6H4COOH} \) and \( \ce{NH2(CH2)6NH2} \)
Show Answer & Explanation
Answer: (b) \( \ce{COOH(CH2)4COOH} \) and \( \ce{NH2(CH2)6NH2} \)
Explanation:
1. Nylon-6,6 is formed from hexane-1,6-diamine (six carbons) and hexanedioic (adipic) acid (six carbons).
2. The condensation loses water and forms amide links.
Teacher's Note:
1. Both monomers contain six carbons.
2. Option a would give an aramid-type polymer.
(a) \( \ce{CH2=C(CH3)2} \)
(b) \( \ce{CH3CH=CHCH3} \)
(c) \( \ce{CH3CH=CH2} \)
(d) \( \ce{(CH3)2C=C(CH3)2} \)
Show Answer & Explanation
Answer: (a) \( \ce{CH2=C(CH3)2} \)
Explanation:
1. The repeat unit \( \ce{-CH2-C(CH3)2-} \) comes from isobutylene (2-methylpropene).
2. Each monomer adds to the carbocation end to give the next tertiary carbocation.
Teacher's Note:
1. Repeat unit shows the monomer after opening the double bond.
2. A tertiary carbocation is stabilised by two methyl groups.
(a) melmac
(b) bakelite
(c) polythene
(d) vulcanised rubber
Show Answer & Explanation
Answer: (c) polythene
Explanation:
1. Polythene is a linear or branched thermoplastic with no cross-links.
2. Melmac (melamine resin), bakelite and vulcanised rubber contain cross-links.
Teacher's Note:
1. Thermoplastics are not cross-linked.
2. Thermosets are.
(a) Mn = (Mw) to the power 1/2
(b) Mn = Mw
(c) Mw > Mn
(d) Mw < Mn
Show Answer & Explanation
Answer: (c) Mw > Mn
Explanation:
1. Heavier chains contribute more to the weight average than to the number average.
2. So Mw is greater than Mn for a polydisperse polymer, and they are equal only for a monodisperse sample.
Teacher's Note:
1. Mw / Mn is at least 1.
2. Equality means uniform chain length.
(a) polytetrafluoroethylene (Teflon)
(b) PVC
(c) PAN
(d) PMMA
Show Answer & Explanation
Answer: (a) polytetrafluoroethylene (Teflon)
Explanation:
1. Free radical polymerisation of tetrafluoroethene under pressure gives polytetrafluoroethylene, known as Teflon.
Teacher's Note:
1. Initiators like peroxides start radical addition.
2. Teflon is chemically very inert.
(a) nylon, PVC
(b) PAN, PTFE
(c) PCTFE, PTFE
(d) bakelite, alkyl resin
Show Answer & Explanation
Answer: (c) PCTFE, PTFE
Explanation:
1. PCTFE (polychlorotrifluoroethylene) and PTFE are both fluorinated polymers that are chemically inert, heat-resistant and non-stick.
2. The other pairs differ in type of polymer and use.
Teacher's Note:
1. Fluoropolymers behave alike.
2. Compare structure to compare properties.
(a) PMMA is plexiglass
(b) SBR is natural rubber
(c) PTFE is Teflon
(d) LDPE is low density polythene
Show Answer & Explanation
Answer: (b) SBR is natural rubber
Explanation:
1. SBR (styrene-butadiene rubber) is a synthetic rubber, the same as Buna-S.
2. The other three statements are correct.
Teacher's Note:
1. SBR = Buna-S.
2. Natural rubber is polyisoprene.
(a) bakelite
(b) teflon
(c) nylon-6,6
(d) dacron
Show Answer & Explanation
Answer: (b) teflon
Explanation:
1. In an addition homopolymer the repeat unit has the same formula as the monomer.
2. Teflon is \( \ce{(CF2-CF2)n} \) from \( \ce{CF2=CF2} \).
3. The condensation polymers lose small molecules, so their repeat units differ from the monomers.
Teacher's Note:
1. Addition polymers keep the monomer formula.
2. Condensation polymers do not.
(a) ABS
(b) SBR
(c) NBR
(d) nylon-2,6
Show Answer & Explanation
Answer: (a) ABS
Explanation:
1. ABS is made from acrylonitrile, butadiene and styrene.
2. SBR and NBR are copolymers of two monomers each.
Teacher's Note:
1. A = acrylonitrile, B = butadiene, S = styrene.
2. Count the monomers in each.
(a) polyethylene
(b) polybutadiene
(c) polystyrene
(d) polyacetylene
Show Answer & Explanation
Answer: (d) polyacetylene
Explanation:
1. Polyacetylene has an extended system of conjugated double bonds.
2. When doped with iodine or similar agents it becomes electrically conducting.
Teacher's Note:
1. Conjugation allows electron movement.
2. Ordinary saturated polymers are insulators.
(a) aniline
(b) 4,5,6-triamino-1,2,3-triazine
(c) 2,4,6-triamino-1,3,5-triazine
(d) 2,5-diaminopyridine
Show Answer & Explanation
Answer: (c) 2,4,6-triamino-1,3,5-triazine
Explanation:
1. Melamine is 2,4,6-triamino-1,3,5-triazine, a ring with three nitrogens and three NH2 groups.
2. Its NH2 groups condense with formaldehyde to form a cross-linked resin.
Teacher's Note:
1. Melamine = triaminotriazine.
2. Three NH2 groups give cross-linking.
(a) (A)-(ii), (B)-(i), (C)-(iii), (D)-(iv)
(b) (A)-(ii), (B)-(iv), (C)-(iii), (D)-(i)
(c) (A)-(iii), (B)-(iv), (C)-(ii), (D)-(i)
(d) (A)-(iii), (B)-(i), (C)-(ii), (D)-(iv)
Show Answer & Explanation
Answer: (d) (A)-(iii), (B)-(i), (C)-(ii), (D)-(iv)
Explanation:
1. Polystyrene is moulded into toys, and glyptal is used for paints and lacquers.
2. PVC is used for rain coats and bakelite is used for gramophone records and computer discs.
Teacher's Note:
1. Match each polymer with its main product.
2. PVC films are waterproof.
(a) artificial silk is derived from cellulose
(b) nylon-6,6 is an example of an elastomer
(c) the repeat unit in natural rubber is isoprene
(d) both starch and cellulose are polymers of glucose
Show Answer & Explanation
Answer: (b) nylon-6,6 is an example of an elastomer
Explanation:
1. Nylon-6,6 is a fibre, with strong hydrogen bonding between chains, and not an elastomer.
2. The other statements are true.
Teacher's Note:
1. Elastomers are weakly bonded and stretch.
2. Nylon forms strong fibres.
(a) \( \ce{CH2=CH-CN} \) and \( \ce{CH2=CH-CH=CH2} \)
(b) \( \ce{H2N-CH2-COOH} \) and \( \ce{H2N-(CH2)5-COOH} \)
(c) ethylene glycol and terephthalic acid
(d) styrene and butadiene
Show Answer & Explanation
Answer: (b) \( \ce{H2N-CH2-COOH} \) and \( \ce{H2N-(CH2)5-COOH} \)
Explanation:
1. Glycine and 6-aminohexanoic acid give nylon-2-nylon-6, a biodegradable polyamide.
2. The other sets give NBR, polyester PET and SBR, which are not readily biodegradable.
Teacher's Note:
1. Polymers with peptide-like links can be broken by enzymes.
2. Look for amino acid monomers.
(a) \( \ce{-(CH2-C(Cl)=CH-CH2)n-} \) (neoprene)
(b) \( \ce{-(CH2-CHCl)n-} \) (PVC)
(c) \( \ce{-(NH-(CH2)6-NH-CO-(CH2)4-CO)n-} \) (nylon-6,6)
(d) a phenol-formaldehyde polymer with ortho-hydroxybenzyl units joined by CH2 groups (bakelite)
Show Answer & Explanation
Answer: (d) a phenol-formaldehyde polymer with ortho-hydroxybenzyl units joined by CH2 groups (bakelite)
Explanation:
1. The phenol-formaldehyde polymer is a cross-linked three-dimensional network, so it is thermosetting.
2. Neoprene is an elastomer, PVC is a thermoplastic and nylon-6,6 is a fibre.
Teacher's Note:
1. Cross-links make a thermoset.
2. Bakelite is the classic example.
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Polymers Objective Questions & Solutions for JEE Chemistry
Download Multiple Choice Questions: Polymers (JEE Chemistry)
Review structured objective questions for JEE Chemistry Polymers. Built according to official JEE guidelines, these MCQ sets support daily revision and core concept reinforcement.
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