JEE Chemistry Polymers MCQs Set 12

Download JEE MCQs for JEE Chemistry: Polymers

Access targeted multiple-choice questions for Polymers designed to align with the latest JEE academic syllabus for JEE Chemistry. These objective practice sets help students evaluate their conceptual understanding and improve exam readiness.

Chapter-wise Objective Questions: Polymers

Navigate directly to the 50 objective questions for Polymers using the digital viewer below. Each practice set includes verified answer keys, allowing students to instantly cross-check their work and identify areas requiring further revision.

Multiple Choice Questions

Question 1: Starch is a polymer of
(a) beta-D-glucose
(b) both alpha-D-glucose and beta-D-glucose
(c) alpha-D-glucose
(d) D-fructose
Show Answer & Explanation

Answer: (c) alpha-D-glucose

Explanation:
1. Starch consists of amylose (unbranched, alpha-1,4 links) and amylopectin (branched, alpha-1,4 and alpha-1,6 links).
2. Both are built entirely from alpha-D-glucose units.

Teacher's Note:
1. Cellulose is the beta-D-glucose polymer.
2. Starch is the storage polysaccharide of plants.

Question 2: Which of the following polymers has an amide linkage?
(a) Nylon-6,6
(b) Terylene
(c) Teflon
(d) Bakelite
Show Answer & Explanation

Answer: (a) Nylon-6,6

Explanation:
1. Nylon-6,6 is formed from hexamethylenediamine and adipic acid and has repeating -CO-NH- amide links.
2. Terylene has ester links, Teflon is a fluorocarbon chain and Bakelite is a phenol-formaldehyde network.

Teacher's Note:
1. Polyamides contain the -CONH- group, like proteins.
2. Polyesters contain the -COO- group.

Question 3: Nylon-6,6 is made by using hexamethylenediamine and
(a) phenol
(b) benzaldehyde
(c) succinic acid
(d) adipic acid
Show Answer & Explanation

Answer: (d) adipic acid

Explanation:
1. Nylon-6,6 is the condensation polymer of hexane-1,6-diamine and hexanedioic acid (adipic acid), both with six carbon atoms.
2. Water is eliminated at each amide link formed.

Teacher's Note:
1. The two 6s in the name are the carbon counts of the diamine and the diacid.
2. Nylon-6,10 uses sebacic acid with a 10-carbon chain.

Question 4: Which of the following is a nitrogen containing polymer?
(a) Polyvinyl chloride
(b) Nylon
(c) Bakelite
(d) Terylene
Show Answer & Explanation

Answer: (b) Nylon

Explanation:
1. Nylon contains amide (-CONH-) links, so it has nitrogen.
2. PVC contains chlorine, and Bakelite and Terylene contain only C, H and O.

Teacher's Note:
1. Polyamides, polyacrylonitrile and Buna-N contain nitrogen.
2. Check the monomer formulae.

Question 5: Buna-S is a copolymer of
(a) 1,3-butadiene only
(b) 1,3-butadiene and styrene
(c) 1,3-butadiene and acrylonitrile
(d) styrene only
Show Answer & Explanation

Answer: (b) 1,3-butadiene and styrene

Explanation:
1. Buna-S is formed by addition copolymerisation of 1,3-butadiene (Bu) with styrene, using sodium (Na) as catalyst (S).
2. Buna-N uses acrylonitrile in place of styrene.

Teacher's Note:
1. Bu = butadiene, na = sodium, S = styrene.
2. Buna-N has N for nitrile.

Question 6: The polymer obtained from caprolactam is
(a) nylon-6,6
(b) nylon-6,10
(c) nylon-60
(d) nylon-6
Show Answer & Explanation

Answer: (d) nylon-6

Explanation:
1. Caprolactam is a six-carbon cyclic amide.
2. On heating at 530 K with a trace of water it undergoes ring opening and polymerisation to nylon-6, whose repeating unit is -NH-(CH2)5-CO-.

Teacher's Note:
1. Nylon-6 is made from a single monomer.
2. Nylon-6,6 needs two monomers.

Question 7: Ziegler-Natta catalyst is
(a) \( \ce{(C2H5)3Al} \) with \( \ce{TiCl4} \)
(b) \( \ce{K[PtCl3(C2H4)]} \) (Zeise's salt)
(c) \( \ce{(Ph3P)3RhCl} \) (Wilkinson's catalyst)
(d) \( \ce{Fe(C5H5)2} \) (ferrocene)
Show Answer & Explanation

Answer: (a) \( \ce{(C2H5)3Al} \) with \( \ce{TiCl4} \)

Explanation:
1. The Ziegler-Natta catalyst is a combination of triethylaluminium and titanium tetrachloride.
2. It gives stereoregular, high density polyethylene and isotactic polypropylene.
3. The other three are Zeise's salt, Wilkinson's catalyst and ferrocene.

Teacher's Note:
1. Wilkinson's catalyst is used for hydrogenation.
2. Ziegler-Natta catalysts give stereoregular polymers.

Question 8: Match the polymer with its monomer(s): (A) Bakelite, (B) Polypropylene, (C) Glyptal, (D) Nylon-6 with (p) caprolactam, (q) ethylene glycol and phthalic anhydride, (r) propene, (s) phenol and formaldehyde.
(a) A-r, B-s, C-p, D-q
(b) A-s, B-q, C-r, D-p
(c) A-s, B-r, C-q, D-p
(d) A-p, B-r, C-q, D-s
Show Answer & Explanation

Answer: (c) A-s, B-r, C-q, D-p

Explanation:
1. Bakelite is the condensation polymer of phenol and formaldehyde.
2. Polypropylene is the addition polymer of propene.
3. Glyptal is the polyester of ethylene glycol and phthalic anhydride.
4. Nylon-6 is obtained from caprolactam.

Teacher's Note:
1. Learn each polymer with its monomers.
2. Glyptal is used in paints and lacquers.

Question 9: Which of the following contains the isoprene unit?
(a) Polyethylene
(b) Nylon-6,6
(c) Dacron
(d) Natural rubber
Show Answer & Explanation

Answer: (d) Natural rubber

Explanation:
1. Natural rubber is cis-1,4-polyisoprene, built from 2-methylbuta-1,3-diene (isoprene).
2. The others contain no isoprene unit.

Teacher's Note:
1. Isoprene is 2-methyl-1,3-butadiene.
2. Neoprene is the chlorine analogue (chloroprene).

Question 10: Which of the following is a condensation polymer?
(a) Polystyrene
(b) Polyester
(c) PVC
(d) Teflon
Show Answer & Explanation

Answer: (b) Polyester

Explanation:
1. Polyesters form from a diol and a diacid with loss of water at each link.
2. Polystyrene, PVC and Teflon are addition polymers of vinyl-type monomers.

Teacher's Note:
1. Condensation polymers lose a small molecule at each step.
2. Addition polymers lose nothing.

Question 11: Which of the following monomers polymerises most easily?
(a) \( \ce{CH2=CH-CH=CH2} \)
(b) \( \ce{CH3CH2C#CH} \)
(c) \( \ce{CH3CH2CH=CH2} \)
(d) \( \ce{HC#C-C#CH} \)
Show Answer & Explanation

Answer: (a) \( \ce{CH2=CH-CH=CH2} \)

Explanation:
1. Radical addition polymerisation is easiest when the growing radical is stabilised.
2. 1,3-Butadiene gives a delocalised (allylic) radical on addition, so it polymerises most readily.
3. But-1-ene gives only a secondary alkyl radical, and the alkynes are less reactive.

Teacher's Note:
1. Conjugated dienes polymerise easily.
2. The more stable the intermediate radical, the faster the chain growth.

Question 12: Acetylene is dimerised with \( \ce{CuCl / NH4Cl} \) to vinylacetylene, which reacts with HCl to give chloroprene. Polymerisation of this chloroprene produces
(a) polyvinyl chloride
(b) Buna-S
(c) neoprene
(d) polystyrene
Show Answer & Explanation

Answer: (c) neoprene

Explanation:
1. Vinylacetylene adds HCl across the triple bond to form 2-chlorobuta-1,3-diene (chloroprene).
2. Addition polymerisation of chloroprene gives polychloroprene, called neoprene, a synthetic rubber.

Teacher's Note:
1. Neoprene is polychloroprene.
2. It resists oil and heat better than natural rubber.

Question 13: Among nylon-6, Buna-N, Buna-S, nylon-6,6, nylon-6,10, PVC, polystyrene and Teflon, the number of condensation polymers is
(a) 2
(b) 4
(c) 3
(d) 5
Show Answer & Explanation

Answer: (c) 3

Explanation:
1. Nylon-6, nylon-6,6 and nylon-6,10 are polyamides formed by condensation (or ring opening and condensation) polymerisation.
2. Buna-N, Buna-S, PVC, polystyrene and Teflon are addition polymers.
3. So there are 3.

Teacher's Note:
1. Count only polyamides here.
2. Nylon-6 is regarded as a condensation polymer.

Question 14: Among PVC, Terylene, Teflon, neoprene, Buna-S, nylon-6,6 and Bakelite, the number of addition polymers is
(a) 4
(b) 3
(c) 5
(d) 2
Show Answer & Explanation

Answer: (a) 4

Explanation:
1. PVC, Teflon, neoprene and Buna-S are made by addition polymerisation.
2. Terylene, nylon-6,6 and Bakelite are condensation polymers.
3. So there are 4.

Teacher's Note:
1. Addition polymers come from unsaturated monomers.
2. Condensation polymers come from bi- or poly-functional monomers.

Question 15: Which of the following are polyamides: protein, nylon-6,6, nylon-6 and polystyrene?
(a) Nylon-6,6 and nylon-6 only
(b) Protein and nylon-6,6 only
(c) All four
(d) Protein, nylon-6,6 and nylon-6 only
Show Answer & Explanation

Answer: (d) Protein, nylon-6,6 and nylon-6 only

Explanation:
1. Proteins are natural polyamides with peptide links (-CONH-).
2. Nylon-6,6 and nylon-6 are synthetic polyamides.
3. Polystyrene has a hydrocarbon backbone with no amide group.

Teacher's Note:
1. A peptide bond is an amide bond.
2. Polystyrene is an addition polymer.

Question 16: Preparation of nylon-6,6 from hexamethylenediamine and adipic acid is an example of
(a) addition polymerisation and homopolymerisation
(b) condensation polymerisation and copolymerisation
(c) addition polymerisation and copolymerisation
(d) condensation polymerisation and homopolymerisation
Show Answer & Explanation

Answer: (b) condensation polymerisation and copolymerisation

Explanation:
1. Water is lost in forming each amide link, so it is condensation polymerisation.
2. Two different monomers are used, so the product is a copolymer.

Teacher's Note:
1. Two different monomers mean copolymer.
2. Elimination of small molecules means condensation.

Question 17: Which of the following are condensation polymers: Terylene, Bakelite, polyvinyl chloride, nylon-6,6?
(a) Terylene and PVC only
(b) Terylene, Bakelite and nylon-6,6
(c) Bakelite and PVC only
(d) Terylene, Bakelite, PVC and nylon-6,6
Show Answer & Explanation

Answer: (b) Terylene, Bakelite and nylon-6,6

Explanation:
1. Terylene (polyester), Bakelite (phenol-formaldehyde) and nylon-6,6 (polyamide) are formed with loss of small molecules.
2. PVC is an addition polymer of vinyl chloride.

Teacher's Note:
1. PVC is made from chloroethene by addition.
2. Check the monomers.

Question 18: The heterogeneous catalyst used in the polymerisation of ethylene to high density polyethylene is
(a) Wilkinson's catalyst
(b) benzoyl peroxide
(c) Lindlar's catalyst
(d) Ziegler-Natta catalyst, triethylaluminium with titanium tetrachloride
Show Answer & Explanation

Answer: (d) Ziegler-Natta catalyst, triethylaluminium with titanium tetrachloride

Explanation:
1. Ziegler-Natta catalyst is a solid TiCl4 surface activated by trialkylaluminium.
2. It polymerises ethylene at low pressure and temperature to linear high density polyethylene.
3. Peroxides are homogeneous radical initiators used in low density polyethylene.

Teacher's Note:
1. High density polyethylene needs Ziegler-Natta catalyst.
2. Low density polyethylene needs peroxide initiator at high pressure.

Question 19: Among cellulose, polyvinyl chloride, nylon and natural rubber, the polymer with the weakest intermolecular forces of attraction is
(a) natural rubber
(b) nylon
(c) polyvinyl chloride
(d) cellulose
Show Answer & Explanation

Answer: (a) natural rubber

Explanation:
1. Nylon and cellulose have hydrogen bonding, and PVC has dipole-dipole forces.
2. Natural rubber is a non-polar hydrocarbon polymer held only by weak van der Waals forces, hence it is an elastomer.

Teacher's Note:
1. Elastomers have the weakest forces; fibres the strongest.
2. Order: elastomer < thermoplastic < fibre.

Question 20: The total number of lone pairs of electrons in melamine is
(a) 3
(b) 9
(c) 6
(d) 12
Show Answer & Explanation

Answer: (c) 6

Explanation:
1. Melamine is 1,3,5-triazine-2,4,6-triamine, with 3 ring nitrogen atoms and 3 amino nitrogen atoms.
2. Each nitrogen carries one lone pair, so 6 lone pairs in all (the amino lone pairs are delocalised but still counted).

Teacher's Note:
1. Count one lone pair on each nitrogen.
2. Melamine is used with formaldehyde for melamine plastics.

Question 21: On complete hydrogenation, natural rubber produces
(a) vulcanised rubber
(b) polypropylene
(c) polybutylene
(d) an ethylene-propylene copolymer
Show Answer & Explanation

Answer: (d) an ethylene-propylene copolymer

Explanation:
1. Natural rubber is polyisoprene, with repeating unit -CH2-C(CH3)=CH-CH2-.
2. Hydrogenation saturates the double bond to -CH2-CH(CH3)-CH2-CH2-, which is an alternating ethylene-propylene unit.

Teacher's Note:
1. Add H2 across each C=C.
2. The saturated repeat has one propylene and one ethylene portion.

Question 22: Complete hydrolysis of cellulose gives
(a) D-fructose
(b) D-glucose
(c) D-ribose
(d) L-glucose
Show Answer & Explanation

Answer: (b) D-glucose

Explanation:
1. Cellulose is a linear polymer of beta-D-glucose joined by beta-1,4 glycosidic links.
2. Acid hydrolysis breaks all links and gives only D-glucose.

Teacher's Note:
1. Starch and cellulose both give glucose on hydrolysis.
2. Sucrose gives glucose and fructose.

Question 23: Nylon threads are made up of
(a) polyamide polymer
(b) polyvinyl polymer
(c) polyester polymer
(d) polyethylene polymer
Show Answer & Explanation

Answer: (a) polyamide polymer

Explanation:
1. Nylon-6,6 and nylon-6 are polyamides whose chains are held by hydrogen bonds between the -CONH- groups.
2. This gives high tensile strength suitable for fibres.

Teacher's Note:
1. Polyester fibres: Terylene.
2. Polyamide fibres: nylon.

Question 24: Which of the following is a fully fluorinated polymer?
(a) PVC
(b) Thiokol
(c) Teflon
(d) Neoprene
Show Answer & Explanation

Answer: (c) Teflon

Explanation:
1. Teflon is polytetrafluoroethylene, (-CF2-CF2-)n, with every hydrogen replaced by fluorine.
2. PVC contains chlorine, neoprene has chlorine and Thiokol is a polysulphide.

Teacher's Note:
1. Teflon: non-stick, inert.
2. Monomer: tetrafluoroethene.

Question 25: Bakelite is obtained from phenol by reacting it with
(a) acetaldehyde (CH3CHO)
(b) acetone
(c) formaldehyde (HCHO)
(d) ethylene glycol
Show Answer & Explanation

Answer: (c) formaldehyde (HCHO)

Explanation:
1. Phenol and formaldehyde condense in the presence of an acid or a base catalyst to give novolac or resol, which cross-link on heating to Bakelite.

Teacher's Note:
1. Bakelite is a thermosetting polymer.
2. Used for electrical switches and handles.

Multiple Choice Questions (MCQs) for JEE Chemistry Polymers

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