Download JEE MCQs for JEE Chemistry: Polymers
Access targeted multiple-choice questions for Polymers designed to align with the latest JEE academic syllabus for JEE Chemistry. These objective practice sets help students evaluate their conceptual understanding and improve exam readiness.
Chapter-wise Objective Questions: Polymers
View or download the dedicated Polymers MCQ resource below. Practicing these 50 objective questions regularly builds familiarity with standard exam patterns and helps secure higher marks in final Chemistry evaluations.
Multiple Choice Questions
(a) Orlon : acrylonitrile
(b) Nylon-6,6 : hexamethylenediamine and adipic acid
(c) Dacron : ethylene glycol and terephthalic acid
(d) Caprolactam : nylon-6,10
Show Answer & Explanation
Answer: (d) Caprolactam : nylon-6,10
Explanation:
1. Caprolactam is the monomer of nylon-6, not nylon-6,10.
2. Nylon-6,10 is made from hexamethylenediamine and sebacic acid.
3. Answer: (d)
Teacher's Note:
1. Link each biomolecule with its structure and characteristic reaction; most questions here are direct recall of these links.
(a) Butadiene only
(b) Buta-1,3-diene and styrene
(c) Styrene only
(d) Butadiene and acrylonitrile
Show Answer & Explanation
Answer: (b) Buta-1,3-diene and styrene
Explanation:
1. Buna-S is a copolymer: Bu (butadiene), na (sodium catalyst), S (styrene).
2. Butadiene with acrylonitrile gives Buna-N.
3. Answer: (b)
Teacher's Note:
1. Link each biomolecule with its structure and characteristic reaction; most questions here are direct recall of these links.
(a) a and b
(b) c and d
(c) a and c
(d) a, b and d
Show Answer & Explanation
Answer: (b) c and d
Explanation:
1. Nylon-6,6 and nylon-6,10 contain amide linkages, so they are polyamides.
2. Glyptal and Dacron are polyesters.
3. Answer: (b)
Teacher's Note:
1. Link each biomolecule with its structure and characteristic reaction; most questions here are direct recall of these links.
(a) –[CH(C6H5)–CH2]n–
(b) –[CH2–C(Cl)=CH–CH2]n–
(c) –[CH2–CH(CN)]n–
(d) –[CH2–C(CH3)=CH–CH2]n–
Show Answer & Explanation
Answer: (b) –[CH2–C(Cl)=CH–CH2]n–
Explanation:
1. Neoprene is the polymer of chloroprene, 2-chlorobuta-1,3-diene.
2. Its repeating unit is therefore CH2–C(Cl)=CH–CH2.
3. The first is polystyrene, the third polyacrylonitrile and the fourth natural rubber.
4. Answer: (b)
Teacher's Note:
1. Link each biomolecule with its structure and characteristic reaction; most questions here are direct recall of these links.
(a) Isoprene : natural rubber
(b) Nylon : polyamide
(c) Nylon-6 : adipic acid
(d) Ziegler-Natta catalyst : TiCl4 + (C2H5)3Al
Show Answer & Explanation
Answer: (c) Nylon-6 : adipic acid
Explanation:
1. Nylon-6 is made from caprolactam.
2. Adipic acid is used, with hexamethylenediamine, for nylon-6,6.
3. Answer: (c)
Teacher's Note:
1. Link each biomolecule with its structure and characteristic reaction; most questions here are direct recall of these links.
(a) Nylon-6 : caprolactam
(b) Buna-N : elastomer
(c) Alitame : artificial sweetener
(d) Tranquilliser : ranitidine
Show Answer & Explanation
Answer: (d) Tranquilliser : ranitidine
Explanation:
1. Ranitidine is an antacid (an H2-receptor antagonist), not a tranquilliser.
2. The other three matches are correct.
3. Answer: (d)
Teacher's Note:
1. Link each biomolecule with its structure and characteristic reaction; most questions here are direct recall of these links.
(a) Nylon-6 : polyamide
(b) Buna-S : copolymer
(c) Bakelite : thermoplastic
(d) Polythene : addition polymer
Show Answer & Explanation
Answer: (c) Bakelite : thermoplastic
Explanation:
1. Bakelite is a cross-linked thermosetting polymer, because once moulded it cannot be softened again.
2. Answer: (c)
Teacher's Note:
1. Link each biomolecule with its structure and characteristic reaction; most questions here are direct recall of these links.
(a) cis-1,4-polyisoprene
(b) trans-1,4-polyisoprene
(c) cis-1,4-neoprene
(d) trans-1,4-neoprene
Show Answer & Explanation
Answer: (a) cis-1,4-polyisoprene
Explanation:
1. Natural rubber is a polymer of isoprene (2-methylbuta-1,3-diene) with all double bonds in cis configuration.
2. The trans form is gutta-percha.
3. Answer: (a)
Teacher's Note:
1. Link each biomolecule with its structure and characteristic reaction; most questions here are direct recall of these links.
(a) 1,3-Butadiene and vinyl chloride
(b) 1,3-Butadiene and acrylonitrile
(c) Chloroprene and vinyl chloride
(d) Chloroprene and acrylonitrile
Show Answer & Explanation
Answer: (b) 1,3-Butadiene and acrylonitrile
Explanation:
1. Buna-N (nitrile rubber) is formed from buta-1,3-diene and acrylonitrile (CH2=CH–CN).
2. Answer: (b)
Teacher's Note:
1. Link each biomolecule with its structure and characteristic reaction; most questions here are direct recall of these links.
(a) 3-Hydroxybutanoic acid and 3-hydroxypentanoic acid
(b) 2-Hydroxybutanoic acid and 2-hydroxypentanoic acid
(c) 4-Hydroxybutanoic acid and 4-hydroxypentanoic acid
(d) 3-Hydroxybutanoic acid and 2-hydroxypentanoic acid
Show Answer & Explanation
Answer: (a) 3-Hydroxybutanoic acid and 3-hydroxypentanoic acid
Explanation:
1. Poly-β-hydroxybutyrate-co-β-hydroxyvalerate is a biodegradable polyester.
2. The β position is carbon 3, so the monomers are 3-hydroxybutanoic and 3-hydroxypentanoic acids.
3. Answer: (a)
Teacher's Note:
1. Link each biomolecule with its structure and characteristic reaction; most questions here are direct recall of these links.
(a) Styrene
(b) Nylon-6,6
(c) Teflon
(d) Natural rubber
Show Answer & Explanation
Answer: (b) Nylon-6,6
Explanation:
1. Nylon-6,6 forms from hexamethylenediamine and adipic acid with loss of water.
2. Teflon (polytetrafluoroethylene) is an addition polymer, and polystyrene is too.
3. Answer: (b)
Teacher's Note:
1. Link each biomolecule with its structure and characteristic reaction; most questions here are direct recall of these links.
(a) A linear condensation product of phenol and formaldehyde
(b) A cross-linked condensation product of urea and formaldehyde
(c) A cross-linked condensation product of phenol and formaldehyde
(d) A linear condensation product of urea and formaldehyde
Show Answer & Explanation
Answer: (a) A linear condensation product of phenol and formaldehyde
Explanation:
1. Phenol with less than one equivalent of HCHO under acidic conditions gives the linear polymer novolac.
2. Heating it with more HCHO cross-links it into Bakelite.
3. Answer: (a)
Teacher's Note:
1. Link each biomolecule with its structure and characteristic reaction; most questions here are direct recall of these links.
Free study material for Chemistry
Download Chapter MCQs: JEE Chemistry Polymers
Download Multiple Choice Questions: Polymers (JEE Chemistry)
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FAQs
You can get most exhaustive JEE Chemistry Polymers MCQs Set 14 for free on StudiesToday.com. These MCQs for JEE Chemistry are updated for the 2026-27 academic session as per JEE examination standards.
Yes, our JEE Chemistry Polymers MCQs Set 14 include the latest type of questions, such as Assertion-Reasoning and Case-based MCQs. 50% of the JEE paper is now competency-based.
By solving our JEE Chemistry Polymers MCQs Set 14, JEE students can improve their accuracy and speed which is important as objective questions provide a chance to secure 100% marks in the Chemistry.
Yes, Chemistry MCQs for JEE have answer key and brief explanations to help students understand logic behind the correct option as its important for 2026 competency-focused JEE exams.
Yes, you can also access online interactive tests for JEE Chemistry Polymers MCQs Set 14 on StudiesToday.com as they provide instant answers and score to help you track your progress in Chemistry.