Chemistry Objective Questions and Answers: General Principles and Processes Of Isolation Of Elements
Access targeted multiple-choice questions for General Principles and Processes Of Isolation Of Elements designed to align with the latest JEE academic syllabus for JEE Chemistry. These objective practice sets help students evaluate their conceptual understanding and improve exam readiness.
Download General Principles and Processes Of Isolation Of Elements MCQs with Answers
Navigate directly to the 50 objective questions for General Principles and Processes Of Isolation Of Elements using the digital viewer below. Each practice set includes verified answer keys, allowing students to instantly cross-check their work and identify areas requiring further revision.
Multiple Choice Questions
(a) collector
(b) frother
(c) depressant
(d) activator
Show Answer & Explanation
Answer: (b) frother
Explanation:
1. Pine oil and eucalyptus oil produce a stable froth that carries the ore particles to the surface, so they are frothers.
2. Collectors are xanthates, depressants include NaCN and an activator is CuSO4.
3. Answer: (b)
Teacher's Note:
1. Frother: stable froth. Collector: makes ore water repellent.
2. Pine oil, cresols and eucalyptus oil are frothers.
(a) CuSO4
(b) NaCN
(c) pine oil
(d) sodium ethyl xanthate
Show Answer & Explanation
Answer: (b) NaCN
Explanation:
1. NaCN forms a soluble complex with ZnS surface and prevents it from floating, so PbS alone is carried in the froth.
2. CuSO4 is an activator and xanthate a collector.
3. Answer: (b)
Teacher's Note:
1. Depressant stops one sulphide from floating.
2. NaCN depresses ZnS.
(a) ZnO and CO2
(b) ZnO and CO
(c) Zn and CO2
(d) ZnS and CO2
Show Answer & Explanation
Answer: (a) ZnO and CO2
Explanation:
1. Calcination is heating in limited or no air; carbonates decompose to oxides.
2. ZnCO3 → ZnO + CO2.
3. Answer: (a)
Teacher's Note:
1. Calcination removes water or CO2.
2. No major oxidation occurs in calcination.
(a) Cu2O and FeO
(b) Cu2S and a little FeS
(c) Cu and FeSiO3
(d) CuO and SiO2
Show Answer & Explanation
Answer: (b) Cu2S and a little FeS
Explanation:
1. During smelting, FeO combines with silica to give FeSiO3 slag.
2. The molten mass left, called matte, consists mainly of Cu2S with a little FeS.
3. Answer: (b)
Teacher's Note:
1. Matte is the sulphide mixture.
2. Slag floats over matte.
(a) FeO + SiO2 → FeSiO3
(b) FeS + SiO2 → FeSiO3 + S
(c) Fe + SiO2 → FeSiO3
(d) Fe2O3 + SiO2 → FeSiO3
Show Answer & Explanation
Answer: (a) FeO + SiO2 → FeSiO3
Explanation:
1. Iron has more affinity for oxygen than copper, so it forms FeO.
2. Acidic flux SiO2 combines with basic FeO to give fusible FeSiO3 slag.
3. Answer: (a)
Teacher's Note:
1. Flux + gangue gives slag.
2. Silica is the flux in copper smelting.
(a) Cu2S + 2Cu2O → 6Cu + SO2
(b) Cu2O + C → 2Cu + CO
(c) CuO + CO → Cu + CO2
(d) CuSO4 + Zn → Cu + ZnSO4
Show Answer & Explanation
Answer: (a) Cu2S + 2Cu2O → 6Cu + SO2
Explanation:
1. Part of Cu2S is oxidised to Cu2O; this oxide then reacts with the remaining sulphide: 2Cu2O + Cu2S → 6Cu + SO2.
2. No external reducing agent is needed, so this is self reduction, and the product is blister copper.
3. Answer: (a)
Teacher's Note:
1. Self reduction: oxide reacts with sulphide of the same metal.
2. Used for Cu, Pb and Hg.
(a) magnetite
(b) haematite
(c) siderite
(d) iron pyrites
Show Answer & Explanation
Answer: (b) haematite
Explanation:
1. Haematite, Fe2O3, is the main ore of iron for the blast furnace; magnetite Fe3O4 is also used but less commonly, and siderite is FeCO3.
2. Answer: (b)
Teacher's Note:
1. Ores: haematite Fe2O3, magnetite Fe3O4, siderite FeCO3, pyrites FeS2.
2. Haematite is the chief ore.
(a) carbon
(b) carbon monoxide
(c) hydrogen
(d) silicon
Show Answer & Explanation
Answer: (b) carbon monoxide
Explanation:
1. Hot coke burns to CO2, which reacts with more carbon to give CO.
2. CO rising through the charge reduces iron oxides: Fe2O3 + 3CO → 2Fe + 3CO2.
3. Answer: (b)
Teacher's Note:
1. The reduction occurs in stages: Fe2O3, Fe3O4, FeO, Fe.
2. The zone temperature is about 675–975 K.
(a) 2.5–5%
(b) 0.12–0.25%
(c) 0.25–2%
(d) 4–6%
Show Answer & Explanation
Answer: (b) 0.12–0.25%
Explanation:
1. Wrought iron is the purest commercial form of iron and has only 0.12–0.25% carbon.
2. Steel has 0.25–2% and pig/cast iron 2.5–5%.
3. Answer: (b)
Teacher's Note:
1. Order of carbon content: cast iron > steel > wrought iron.
2. Order of melting point is the reverse.
(a) Cast iron
(b) Steel
(c) Wrought iron
(d) Pig iron
Show Answer & Explanation
Answer: (c) Wrought iron
Explanation:
1. Melting point rises as carbon content falls.
2. Wrought iron has the least carbon, so it has the highest melting point.
3. Answer: (c)
Teacher's Note:
1. Wrought iron > steel > cast iron.
2. Carbon lowers the melting point.
(a) nitriding
(b) case hardening
(c) annealing
(d) tempering
Show Answer & Explanation
Answer: (a) nitriding
Explanation:
1. Ammonia gives a hard iron nitride coating on the surface.
2. This surface treatment is called nitriding.
3. Answer: (a)
Teacher's Note:
1. Case hardening uses charcoal.
2. Nitriding uses NH3.
(a) scrap zinc
(b) sodium
(c) carbon
(d) hydrogen
Show Answer & Explanation
Answer: (a) scrap zinc
Explanation:
1. Silver ore is leached with NaCN to form Na[Ag(CN)2].
2. Zinc then displaces silver: 2Na[Ag(CN)2] + Zn → Na2[Zn(CN)4] + 2Ag.
3. Answer: (a)
Teacher's Note:
1. Zn is more electropositive than Ag.
2. Gold is extracted in the same way.
(a) oxidise Na2S formed and drive the reaction forward
(b) reduce Ag+
(c) remove CO2
(d) dissolve silver
Show Answer & Explanation
Answer: (a) oxidise Na2S formed and drive the reaction forward
Explanation:
1. Ag2S + 4NaCN ⇌ 2Na[Ag(CN)2] + Na2S is reversible.
2. Air oxidises Na2S to Na2S2O3 and Na2SO4, so the reaction goes to completion.
3. Answer: (a)
Teacher's Note:
1. Removal of a product shifts equilibrium forward.
2. Oxygen from air is the oxidant.
(a) Fe2O3
(b) SiO2
(c) TiO2
(d) CaO
Show Answer & Explanation
Answer: (b) SiO2
Explanation:
1. Serpeck's process is used for white bauxite containing silica: bauxite is heated with coke in nitrogen to give AlN, while silica is removed as volatile SiO.
2. AlN is hydrolysed to Al(OH)3 and NH3.
3. Answer: (b)
Teacher's Note:
1. Silica impurity: Serpeck's process.
2. Iron oxide impurity: Baeyer's or Hall's process.
(a) it dissolves in the electrolyte
(b) oxygen liberated at the anode burns it to CO and CO2
(c) it is reduced
(d) it forms Al4C3
Show Answer & Explanation
Answer: (b) oxygen liberated at the anode burns it to CO and CO2
Explanation:
1. Oxygen liberated at the anode reacts with hot graphite to form CO and CO2.
2. So the anode is consumed gradually and must be replaced.
3. Answer: (b)
Teacher's Note:
1. Cathode is the carbon-lined tank.
2. Aluminium collects at the bottom.
(a) aluminium
(b) copper
(c) zinc
(d) lead
Show Answer & Explanation
Answer: (a) aluminium
Explanation:
1. Hoop's process uses molten impure aluminium as the anode and molten pure aluminium as the cathode, with a molten cryolite-fluoride electrolyte in between.
2. Answer: (a)
Teacher's Note:
1. Three liquid layers of different densities.
2. Aluminium can be refined to 99.98%.
(a) MgCl2 with NaCl and NaF in an atmosphere of coal gas
(b) MgO in cryolite
(c) MgSO4 solution
(d) Mg(OH)2 in water
Show Answer & Explanation
Answer: (a) MgCl2 with NaCl and NaF in an atmosphere of coal gas
Explanation:
1. Fused MgCl2 (mixed with NaCl and NaF) is electrolysed at about 970 K in an iron pot, which acts as the cathode.
2. Coal gas prevents the attack of air on molten Mg.
3. Answer: (a)
Teacher's Note:
1. Aqueous electrolysis would not give Mg.
2. Chlorine is liberated at the graphite anode.
(a) liquation
(b) zone refining
(c) cupellation
(d) poling
Show Answer & Explanation
Answer: (b) zone refining
Explanation:
1. Zone refining depends on the impurities being more soluble in the molten metal than in the solid.
2. A moving heater carries impurities to one end of the rod.
3. Answer: (b)
Teacher's Note:
1. Semiconductor-grade silicon uses zone refining.
2. The impure end is cut off.
(a) Van Arkel method
(b) Mond process
(c) Parke's process
(d) electrolytic refining in aqueous solution
Show Answer & Explanation
Answer: (a) Van Arkel method
Explanation:
1. In the Van Arkel method the impure metal is heated with iodine at about 523 K to form volatile TiI4, which on a hot tungsten filament at about 1700 K decomposes to pure titanium.
2. Answer: (a)
Teacher's Note:
1. Vapour-phase refining.
2. Used for small quantities of very pure metal.
(a) Ni(CO)4
(b) NiO
(c) NiS
(d) Ni(NH3)6Cl2
Show Answer & Explanation
Answer: (a) Ni(CO)4
Explanation:
1. Impure nickel is heated with CO at about 330–350 K to form volatile Ni(CO)4.
2. The carbonyl decomposes at about 450–470 K to give pure nickel and CO.
3. Answer: (a)
Teacher's Note:
1. Mond's process: vapour phase refining.
2. CO is recycled.
(a) Zn and Fe
(b) Ag, Au and Pt
(c) Cu only
(d) CuSO4
Show Answer & Explanation
Answer: (b) Ag, Au and Pt
Explanation:
1. Less electropositive impurities such as Ag, Au and Pt do not oxidise at the anode and fall as anode mud.
2. More electropositive impurities such as Zn and Fe go into solution.
3. Answer: (b)
Teacher's Note:
1. Anode: impure copper. Cathode: pure copper.
2. Electrolyte: acidified CuSO4.
(a) its line lies below the line of the other metal oxide
(b) its line lies above the line of the other metal oxide
(c) the two lines are parallel
(d) its oxide is more stable than CO2
Show Answer & Explanation
Answer: (a) its line lies below the line of the other metal oxide
Explanation:
1. The metal whose oxide has the more negative ΔG° of formation (line lower down) can reduce oxides lying above it.
2. The overall ΔG° of the redox reaction is then negative.
3. Answer: (a)
Teacher's Note:
1. Lower line means more stable oxide.
2. Aluminium reduces Cr2O3 by this rule.
(a) Malachite – CuCO3·Cu(OH)2
(b) Zinc blende – ZnCO3
(c) Magnetite – Fe2O3
(d) Cryolite – Na3AlF6·CaF2
Show Answer & Explanation
Answer: (a) Malachite – CuCO3·Cu(OH)2
Explanation:
1. Malachite is the basic copper carbonate CuCO3·Cu(OH)2.
2. Zinc blende is ZnS, magnetite is Fe3O4 and cryolite is Na3AlF6.
3. Answer: (a)
Teacher's Note:
1. Calamine is ZnCO3.
2. Haematite is Fe2O3.
(a) Al2O3·2H2O
(b) Na3AlF6
(c) Al2O3
(d) KAl(SO4)2·12H2O
Show Answer & Explanation
Answer: (a) Al2O3·2H2O
Explanation:
1. Bauxite is hydrated alumina, Al2O3·2H2O.
2. Cryolite is Na3AlF6 and corundum is anhydrous Al2O3.
3. Answer: (a)
Teacher's Note:
1. Bauxite is the main source of aluminium.
2. It is purified by Baeyer's or Hall's process.
(a) have low melting points and are associated with high melting impurities
(b) have high boiling points
(c) are volatile
(d) are present with oxidisable impurities
Show Answer & Explanation
Answer: (a) have low melting points and are associated with high melting impurities
Explanation:
1. The impure metal is heated on a sloping hearth; the low melting pure metal flows down, leaving the infusible impurities behind.
2. It is used for Sn, Pb, Bi and Sb.
3. Answer: (a)
Teacher's Note:
1. Different melting points allow separation.
2. Distillation is used for volatile metals like Zn and Hg.
Free study material for Chemistry
Download Chapter MCQs: JEE Chemistry General Principles and Processes Of Isolation Of Elements
About General Principles and Processes Of Isolation Of Elements MCQs for JEE Chemistry
Review structured objective questions for JEE Chemistry General Principles and Processes Of Isolation Of Elements. Built according to official JEE guidelines, these MCQ sets support daily revision and core concept reinforcement.
How to Verify Your MCQ Answers
Cross-reference your completed choices with comprehensive NCERT solutions for JEE Chemistry to ensure absolute clarity across all sub-topics in this chapter.
Enhance Speed with Online MCQ Tests
Wrap up your chapter revision by testing your knowledge against standard question formats. Everything on our platform is provided free of charge.
FAQs
You can get most exhaustive JEE Chemistry General Principles and Processes of Isolation of Elements MCQs Set 19 for free on StudiesToday.com. These MCQs for JEE Chemistry are updated for the 2026-27 academic session as per JEE examination standards.
Yes, our JEE Chemistry General Principles and Processes of Isolation of Elements MCQs Set 19 include the latest type of questions, such as Assertion-Reasoning and Case-based MCQs. 50% of the JEE paper is now competency-based.
By solving our JEE Chemistry General Principles and Processes of Isolation of Elements MCQs Set 19, JEE students can improve their accuracy and speed which is important as objective questions provide a chance to secure 100% marks in the Chemistry.
Yes, Chemistry MCQs for JEE have answer key and brief explanations to help students understand logic behind the correct option as its important for 2026 competency-focused JEE exams.
Yes, you can also access online interactive tests for JEE Chemistry General Principles and Processes of Isolation of Elements MCQs Set 19 on StudiesToday.com as they provide instant answers and score to help you track your progress in Chemistry.