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Multiple Choice Questions
(a) an iron container as cathode and a graphite rod as anode
(b) a nickel cathode and a graphite anode
(c) an iron container as anode and a nickel cathode
(d) a nickel container as cathode and an iron anode
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Answer: (a) an iron container as cathode and a graphite rod as anode
Explanation:
1. Mg is liberated at the iron cathode (the cell wall), chlorine at the graphite anode.
Teacher's Note:
1. The graphite anode resists chlorine.
(a) liquation
(b) leaching
(c) cupellation
(d) levigation
Show Answer & Explanation
Answer: (d) levigation
Explanation:
1. Levigation (gravity separation) washes away the lighter earthy matter and leaves the denser ore.
Teacher's Note:
1. It is used for oxide ores such as haematite and cassiterite.
(a) Cerussite
(b) Salt cake
(c) Calamine
(d) Malachite
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Answer: (b) Salt cake
Explanation:
1. Salt cake is sodium sulphate, which is not used for extracting a metal economically.
Teacher's Note:
1. Malachite is a copper ore, calamine a zinc ore and cerussite a lead ore.
(a) \( \ce{Cu2SO3} \)
(b) \( \ce{Cu + SO2} \)
(c) \( \ce{CuO + CuS} \)
(d) \( \ce{Cu + SO3} \)
Show Answer & Explanation
Answer: (b) \( \ce{Cu + SO2} \)
Explanation:
1. Self-reduction: \( \ce{2Cu2O + Cu2S -> 6Cu + SO2} \).
Teacher's Note:
1. The oxide acts as oxidant and the sulphide as reductant.
(a) uses green poles of wood
(b) reduces SnO2 to Sn
(c) oxidises iron impurities and removes them as scum
(d) all of the above
Show Answer & Explanation
Answer: (a) uses green poles of wood
Explanation:
1. Molten impure copper containing cuprous oxide is stirred with green wood poles; the hydrocarbon gases formed reduce the oxide to copper.
Teacher's Note:
1. Poling is used for metals such as Cu and Sn that contain their own oxide as impurity.
(a) Al
(b) Mg
(c) Zn
(d) Cu
Show Answer & Explanation
Answer: (a) Al
Explanation:
1. Sapphire and ruby are corundum, \( \ce{Al2O3} \), coloured by trace impurities.
Teacher's Note:
1. Corundum is a gem form of alumina.
(a) Zn, Cu, Pb
(b) Fe, Al, Ti
(c) Zn, Cu, Mg
(d) Cu, Ag, Au
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Answer: (a) Zn, Cu, Pb
Explanation:
1. Zinc blende, copper pyrites and galena are sulphides. Mg occurs as chloride or carbonate, Al and Ti as oxides, and Ag and Au are partly native.
Teacher's Note:
1. Sulphide ores are concentrated by froth flotation.
(a) Calamine
(b) Haematite
(c) Bauxite
(d) Chalcopyrite
Show Answer & Explanation
Answer: (b) Haematite
Explanation:
1. Magnetic separation uses the magnetic nature of the ore or its gangue. Iron oxides such as haematite and chromite respond to a magnet.
Teacher's Note:
1. It is also used for tin stone containing magnetic wolframite as impurity.
(a) Feldspar : \( \ce{Be3Al2Si6O18} \)
(b) Corundum : \( \ce{Al2O3} \)
(c) Bauxite : \( \ce{Al2O3.2H2O} \)
(d) Cryolite : \( \ce{3NaF.AlF3} \)
Show Answer & Explanation
Answer: (a) Feldspar : \( \ce{Be3Al2Si6O18} \)
Explanation:
1. The formula \( \ce{Be3Al2Si6O18} \) is that of beryl. Feldspar is \( \ce{KAlSi3O8} \).
Teacher's Note:
1. Beryl is the ore of beryllium.
(a) iodide of the metal
(b) pure metal
(c) impurities react with iodine
(d) none of these
Show Answer & Explanation
Answer: (b) pure metal
Explanation:
1. At 1800 K the iodide is unstable on the hot filament and decomposes to pure zirconium; the iodide forms at a lower temperature.
Teacher's Note:
1. The temperature decides whether the iodide forms (low) or decomposes (high).
(a) Argentite and cuprite are oxides
(b) Malachite and azurite are ores of copper
(c) Calamine and siderite are carbonates
(d) Zinc blende and iron pyrites are sulphides
Show Answer & Explanation
Answer: (a) Argentite and cuprite are oxides
Explanation:
1. Argentite is silver sulphide, \( \ce{Ag2S} \); only cuprite is an oxide.
Teacher's Note:
1. Remember argentite as 'silver glance'.
(a) Zn
(b) Ca
(c) Pb
(d) Mg
Show Answer & Explanation
Answer: (a) Zn
Explanation:
1. Calamine is zinc carbonate, \( \ce{ZnCO3} \).
Teacher's Note:
1. Zinc ores to remember: zinc blende (ZnS), calamine (ZnCO3) and zincite (ZnO).
(a) 78
(b) 19.5
(c) 39
(d) 3.9
Show Answer & Explanation
Answer: (c) 39
Explanation:
1. n = 2: \( \Delta G=nFE=2\times96500\times2.02=389.9 \) kJ per mole.
Teacher's Note:
1. Divided by 10 = 39.
(a) tin-p, zinc-q, iron-r, lead-s
(b) tin-q, zinc-p, iron-s, lead-r
(c) tin-s, zinc-r, iron-q, lead-p
(d) tin-q, zinc-p, iron-r, lead-s
Show Answer & Explanation
Answer: (b) tin-q, zinc-p, iron-s, lead-r
Explanation:
1. Tin: cassiterite; zinc: calamine; iron: siderite (\( \ce{FeCO3} \)); lead: cerussite (\( \ce{PbCO3} \)).
Teacher's Note:
1. Learn ores in groups: carbonates (calamine, siderite, cerussite, malachite), oxides (haematite, cassiterite, bauxite) and sulphides (galena, blende, pyrites).
(a) Sn and Ag
(b) Fe and Ni
(c) Ag and Au
(d) Pb and Zn
Show Answer & Explanation
Answer: (c) Ag and Au
Explanation:
1. Ag, Au and Pt are less electropositive than copper and are not oxidised at the anode.
Teacher's Note:
1. Active metals like Zn and Fe go into solution.
(a) preferential washing of ores and gangue
(b) difference in densities of ore particles and impurities
(c) difference in chemical properties
(d) none of these
Show Answer & Explanation
Answer: (b) difference in densities of ore particles and impurities
Explanation:
1. Heavier ore particles settle first and the lighter gangue is washed away.
Teacher's Note:
1. Gravity separation is a physical method.
(a) PbS forms a soluble complex while ZnS forms froth
(b) NaCN is never added in froth flotation
(c) Pb(CN)2 is precipitated and ZnS is unaffected
(d) ZnS forms the soluble complex \( \ce{Na2[Zn(CN)4]} \) while PbS forms froth
Show Answer & Explanation
Answer: (d) ZnS forms the soluble complex \( \ce{Na2[Zn(CN)4]} \) while PbS forms froth
Explanation:
1. Cyanide forms a soluble tetracyanozincate with ZnS, which prevents it from floating. PbS does not react and floats in the froth.
Teacher's Note:
1. A depressant selectively stops one sulphide from entering the froth, which allows separation of two sulphide ores.
(a) \( \ce{HgS + O2 -> HgO + SO2; HgO + HgS -> Hg + SO2} \)
(b) All of these
(c) \( \ce{PbS + O2 -> PbO + SO2; PbO + PbS -> Pb + SO2} \)
(d) \( \ce{Cu2S + O2 -> Cu2O + SO2; Cu2S + Cu2O -> Cu + SO2} \)
Show Answer & Explanation
Answer: (b) All of these
Explanation:
1. In each, the partly oxidised ore reacts with the unreacted sulphide to give the metal, with no external reducing agent.
Teacher's Note:
1. Cu, Pb and Hg are the metals commonly obtained by self-reduction.
(a) Parke's process (addition of zinc)
(b) cupellation
(c) fractional crystallisation
(d) liquation
Show Answer & Explanation
Answer: (a) Parke's process (addition of zinc)
Explanation:
1. Molten zinc dissolves silver (and not lead); the zinc-silver alloy is then distilled to leave silver.
Teacher's Note:
1. Cupellation is used afterwards to remove the last traces of lead from silver.
(a) 8
(b) 16
(c) 32
(d) 24
Show Answer & Explanation
Answer: (b) 16
Explanation:
1. Net \( \Delta G=3(-394)-2(-1520)=+1858 \) kJ.
Teacher's Note:
1. Electrons transferred: 12. \( E=1858000/(12\times96500)=1.60 \) V, and 1.60 x 10 = 16.
(a) Al
(b) Hg
(c) Ag
(d) Cu
Show Answer & Explanation
Answer: (a) Al
Explanation:
1. Aluminium lies above zinc in the electrochemical series, so zinc cannot reduce its ions.
Teacher's Note:
1. Zn displaces metals lower in the series.
(a) cyanide leaching followed by reduction
(b) electrolytic reduction
(c) carbon reduction
(d) self-reduction
Show Answer & Explanation
Answer: (b) electrolytic reduction
Explanation:
1. Magnesium is very electropositive and its oxide is stable, so electrolysis of the fused chloride is used.
Teacher's Note:
1. In the Dow process the electrolyte is molten \( \ce{MgCl2} \) with NaCl and \( \ce{CaCl2} \).
(a) borax makes gold softer
(b) gold oxide is reduced by borax
(c) heat and air oxidise the impurities, and the oxides combine with molten borax to form a slag
(d) air increases the temperature at which gold dissolves in borax
Show Answer & Explanation
Answer: (c) heat and air oxidise the impurities, and the oxides combine with molten borax to form a slag
Explanation:
1. Impurities (base metals) are oxidised and fluxed away by borax as metal borate slag, leaving gold.
Teacher's Note:
1. Borax is a flux for basic oxides.
(a) it is a non-metal
(b) the heat of formation of \( \ce{CO2} \) is more than that of \( \ce{Al2O3} \)
(c) pure carbon is not available
(d) the heat of formation of \( \ce{Al2O3} \) is too high
Show Answer & Explanation
Answer: (d) the heat of formation of \( \ce{Al2O3} \) is too high
Explanation:
1. Alumina is so stable that its free energy of formation is more negative than that of CO or \( \ce{CO2} \) at normal furnace temperatures.
Teacher's Note:
1. Hence electrolysis is needed.
(a) fractional distillation
(b) recrystallisation
(c) diffusion
(d) fractional crystallisation (zone refining)
Show Answer & Explanation
Answer: (d) fractional crystallisation (zone refining)
Explanation:
1. Zone refining relies on different solubility of impurities in the molten and solid phases, which is fractional crystallisation.
Teacher's Note:
1. It is used for semiconductors.
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