Chemistry Objective Questions and Answers: General Principles and Processes Of Isolation Of Elements
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Multiple Choice Questions
(a) copper(I) sulphide (Cu2S)
(b) sulphur dioxide
(c) iron(II) sulphide
(d) carbon monoxide
Show Answer & Explanation
Answer: (a) copper(I) sulphide (Cu2S)
Explanation:
1. In the Bessemer converter, 2Cu2O + Cu2S → 6Cu + SO2.
2. This is self-reduction, so Cu2S is the reductant.
Teacher's Note:
1. The product is blister copper (about 98% Cu).
(a) Cu + SO2
(b) Cu + SO3
(c) CuO + CuS
(d) Cu2O + S
Show Answer & Explanation
Answer: (a) Cu + SO2
Explanation:
1. 2Cu2O + Cu2S → 6Cu + SO2.
2. Sulphide ion is oxidised to SO2 while Cu+ is reduced to Cu.
Teacher's Note:
1. Self-reduction needs no external reductant.
(a) CaSiO3
(b) FeSiO3
(c) CuSiO3
(d) SiO2
Show Answer & Explanation
Answer: (b) FeSiO3
Explanation:
1. Iron is oxidised to FeO in roasting and combines with the added silica: FeO + SiO2 → FeSiO3.
Teacher's Note:
1. Silica is an acidic flux for the basic FeO.
(a) Cu2O + FeS
(b) Cu2O + Cu2S
(c) FeS + SiO2
(d) Cu2S + FeS
Show Answer & Explanation
Answer: (d) Cu2S + FeS
Explanation:
1. Matte, the product of smelting the roasted ore with silica, is a molten mixture of Cu2S and FeS.
Teacher's Note:
1. Matte is then treated in the Bessemer converter.
(a) 60% Cu
(b) 90% Cu
(c) 98% Cu
(d) 100% Cu
Show Answer & Explanation
Answer: (c) 98% Cu
Explanation:
1. It is called blister copper because SO2 escapes during solidification, making a blistered surface; purity about 98%.
Teacher's Note:
1. It is refined by electrolysis or poling.
(a) FeS + Cu2O → Cu2S + FeO
(b) 2Cu2S + 3O2 → 2Cu2O + 2SO2
(c) 2CuFeS2 + O2 → Cu2S + 2FeS + SO2
(d) FeO + SiO2 → FeSiO3
Show Answer & Explanation
Answer: (c) 2CuFeS2 + O2 → Cu2S + 2FeS + SO2
Explanation:
1. Partial roasting of the concentrated ore (c) is done in a reverberatory furnace before the converter stage.
2. The other three occur in the converter.
Teacher's Note:
1. The converter handles matte, not raw ore.
(a) cuprous sulphide
(b) ferrous oxide
(c) cupric oxide
(d) cuprous oxide
Show Answer & Explanation
Answer: (b) ferrous oxide
Explanation:
1. FeO + SiO2 → FeSiO3 (slag).
Teacher's Note:
1. Limestone, not silica, is used as a flux in iron extraction.
(a) CaSiO3
(b) FeSiO3
(c) SiO2
(d) Coke
Show Answer & Explanation
Answer: (c) SiO2
Explanation:
1. Copper extraction adds SiO2 to slag away FeO.
2. Iron extraction already contains silica as gangue and needs CaO to remove it.
Teacher's Note:
1. Flux is chosen to match the impurity: acidic impurities need basic flux and basic ones need acidic flux.
(a) Cu
(b) Pb
(c) Hg
(d) Zn
Show Answer & Explanation
Answer: (c) Hg
Explanation:
1. HgS + O2 → Hg + SO2: HgO formed is unstable and decomposes at roasting temperature.
Teacher's Note:
1. Hg is the only common metal that comes from roasting alone.
(a) carbon
(b) electrolysis
(c) self-reduction
(d) cyanide process
Show Answer & Explanation
Answer: (c) self-reduction
Explanation:
1. 2PbS + 3O2 → 2PbO + 2SO2 and then PbS + 2PbO → 3Pb + SO2.
Teacher's Note:
1. Lead is also obtained by carbon reduction of PbO.
(a) Ag2S
(b) PbS
(c) CuFeS2
(d) HgS
Show Answer & Explanation
Answer: (a) Ag2S
Explanation:
1. Pb, Cu and Hg are obtained by self-reduction.
2. Ag2S is leached with NaCN and displaced by zinc.
Teacher's Note:
1. Silver is a noble metal that is extracted by cyanide leaching.
(a) carbon reduction and self-reduction respectively
(b) self-reduction and carbon reduction respectively
(c) electrolysis and self-reduction
(d) self-reduction and electrolysis
Show Answer & Explanation
Answer: (b) self-reduction and carbon reduction respectively
Explanation:
1. Lead from galena: partial roasting then self-reduction.
2. Tin from cassiterite SnO2: reduced with carbon.
Teacher's Note:
1. Remember Pb = self, Sn = carbon.
(a) Al
(b) Cr
(c) Cu
(d) Na
Show Answer & Explanation
Answer: (b) Cr
Explanation:
1. Cr2O3 + 2Al → Al2O3 + 2Cr.
2. Aluminium acts as the reducing agent for oxides that cannot be reduced by carbon.
Teacher's Note:
1. Cr and Mn are extracted this way.
(a) an oxidising agent
(b) a flux
(c) a reducing agent
(d) an ignition agent
Show Answer & Explanation
Answer: (c) a reducing agent
Explanation:
1. Al is oxidised to Al2O3 and reduces the metal oxide.
Teacher's Note:
1. The strongly exothermic reaction is ignited with magnesium ribbon.
(a) heating cryolite in a limited supply of air
(b) reducing aluminium oxide with coke
(c) reducing aluminium oxide with sodium
(d) electrolysing aluminium oxide dissolved in fused cryolite
Show Answer & Explanation
Answer: (d) electrolysing aluminium oxide dissolved in fused cryolite
Explanation:
1. Al2O3 is electrolysed in molten Na3AlF6 with CaF2 (Hall-Heroult process).
Teacher's Note:
1. Carbon reduction of Al2O3 is not feasible below very high temperature.
(a) Al(OH)3 in NaOH solution
(b) molten mica and CaF2
(c) a molten mixture of Al2O3, Na3AlF6 and CaF2
(d) molten potash alum
Show Answer & Explanation
Answer: (c) a molten mixture of Al2O3, Na3AlF6 and CaF2
Explanation:
1. Alumina is dissolved in cryolite with fluorspar, lowering the melting point to about 1230 K and improving conductivity.
Teacher's Note:
1. Pure alumina melts at about 2323 K.
(a) they form Al4C3
(b) they melt and mix with the electrolyte
(c) oxygen liberated at the anode reacts with the carbon to form CO and CO2
(d) carbon anodes reduce Al2O3
Show Answer & Explanation
Answer: (c) oxygen liberated at the anode reacts with the carbon to form CO and CO2
Explanation:
1. O2− is discharged at the anode as oxygen, which burns the graphite away as CO and CO2.
Teacher's Note:
1. Cathode: Al3+ + 3e− → Al.
(a) Cryolite lowers the working temperature
(b) Al is obtained at the cathode
(c) Anode rods are consumed by oxidation
(d) Pure aluminium floats above the molten electrolyte
Show Answer & Explanation
Answer: (d) Pure aluminium floats above the molten electrolyte
Explanation:
1. Molten aluminium is denser than the electrolyte, so it collects at the bottom of the cell and is tapped from there.
Teacher's Note:
1. The cell lining acts as the cathode.
(a) N2 and coke
(b) NaCN
(c) NaOH
(d) Na2CO3
Show Answer & Explanation
Answer: (c) NaOH
Explanation:
1. Al2O3·2H2O + 2NaOH → 2NaAlO2 + 3H2O at 500 K and 35 bar.
Teacher's Note:
1. Fe2O3 and TiO2 do not dissolve.
(a) NaAlO2 only
(b) Na2Ti(OH)6 only
(c) both NaAlO2 and Na2SiO3
(d) Na2SiO3 only
Show Answer & Explanation
Answer: (c) both NaAlO2 and Na2SiO3
Explanation:
1. Amphoteric Al2O3 and acidic SiO2 dissolve in NaOH.
2. Fe2O3 and TiO2 remain as residue.
Teacher's Note:
1. Aluminate is later precipitated as Al(OH)3 by CO2.
(a) self-reduction
(b) Dow's sea water process
(c) thermite reduction
(d) leaching followed by metal displacement
Show Answer & Explanation
Answer: (b) Dow's sea water process
Explanation:
1. In Dow's process Mg(OH)2 precipitated from sea water with lime is converted into MgCl2 and electrolysed in the fused state.
Teacher's Note:
1. Carnallite can also be electrolysed.
(a) Ca and Cl2
(b) Na and CO2
(c) Al and Cl2
(d) Mg and Cl2
Show Answer & Explanation
Answer: (d) Mg and Cl2
Explanation:
1. Carnallite KCl·MgCl2 contains Mg2+, which is reduced at the cathode more readily than K+; Cl2 is evolved at the anode.
Teacher's Note:
1. NaCl and CaCl2 are added to lower the melting point.
(a) the melting point of the electrolyte decreases and its conductivity increases
(b) the melting point increases and conductivity decreases
(c) both melting point and conductivity decrease
(d) both melting point and conductivity increase
Show Answer & Explanation
Answer: (a) the melting point of the electrolyte decreases and its conductivity increases
Explanation:
1. The mixture is a eutectic-type melt with a lower melting point and more mobile ions.
Teacher's Note:
1. Fused MgCl2 alone is a poor conductor.
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Multiple Choice Questions (MCQs) for JEE Chemistry General Principles and Processes Of Isolation Of Elements
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