Practice MCQs for JEE Chemistry Coordination Compounds
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Multiple Choice Questions
(a) tetrahedral
(b) pyramidal
(c) pentagonal
(d) square planar
Show Answer & Explanation
Answer: (d) square planar
Explanation:
1. Pt2+ is \( d8 \) and, being \( 5d \), forms dsp2 square planar complexes.
Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.
(a) +2
(b) +4
(c) +3
(d) +5
Show Answer & Explanation
Answer: (c) +3
Explanation:
1. Oxide is \( -2 (x4 = -8) \), while ethene and water are neutral. For two Mo: \( 2x - 8 = -2 \), so \( x = +3 \).
Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.
(a) \( \ce{[Fe(H2O)6]^{3+}} \)
(b) \( \ce{[FeCl6]^{3-}} \)
(c) \( \ce{[Fe(CN)6]^{3-}} \)
(d) \( \ce{[Fe(C2O4)3]^{3-}} \)
Show Answer & Explanation
Answer: (c) \( \ce{[Fe(CN)6]^{3-}} \)
Explanation:
1. Cyanide forms an extremely stable hexacyano complex with Fe3+ (overall \( \log \beta \) about 43), more than oxalate, water or chloride.
Teacher's Note:
1. Strong field ligands with high charge density form very stable complexes.
(a) 0.0
(b) 0.4
(c) -2
(d) +2
Show Answer & Explanation
Answer: (a) 0.0
Explanation:
1. \( e2 t2^3 \): \( 2(-0.6) + 3(+0.4) = 0 \).
Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.
(a) \( \ce{[Co(NH3)4Cl]Cl2.NH3} \)
(b) \( \ce{[Co(NH3)5Cl]Cl2} \)
(c) \( \ce{[Co(NH3)3Cl]Cl2.2NH3} \)
(d) \( \ce{[Co(NH3)4Cl2]Cl.NH3} \)
Show Answer & Explanation
Answer: (b) \( \ce{[Co(NH3)5Cl]Cl2} \)
Explanation:
1. Three ions with two precipitable Cl- indicates [Co(NH3)5Cl]2+ and 2 Cl-.
Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.
(a) (1) only
(b) (1) and (2) only
(c) (2) and (3) only
(d) All are correct
Show Answer & Explanation
Answer: (d) All are correct
Explanation:
1. All three statements are standard facts about these complexes (square planar dsp2 in (3)).
Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.
(a) Geometrical and optical
(b) Optical and ionisation
(c) Geometrical and ionisation
(d) Geometrical only
Show Answer & Explanation
Answer: (c) Geometrical and ionisation
Explanation:
1. cis and trans forms (geometrical) exist, and exchanging Cl- with Br- gives ionisation isomers. Neither isomer is chiral.
Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.
(a) 1.128 A
(b) 1.078 A
(c) 1.158 A
(d) 1.118 A
Show Answer & Explanation
Answer: (c) 1.158 A
Explanation:
1. Back donation from Fe \( d \) orbitals into the CO \( \pi\cdot \) orbital lowers the \( C-O \) bond order, so the bond lengthens beyond \( 1.128 A \).
Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.
(a) 1 mol
(b) 2 mol
(c) 3 mol
(d) no precipitate
Show Answer & Explanation
Answer: (b) 2 mol
Explanation:
1. The compound is [Co(NH3)5Cl]Cl2 (coordination number 6). Only the two ionisable chloride ions precipitate.
Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.
(a) It shows ionisation isomerism only
(b) All of these
(c) It is an inner orbital complex only
(d) It is diamagnetic only
Show Answer & Explanation
Answer: (b) All of these
Explanation:
1. The complex is [Co(NH3)5(NO2)]Cl2, which shows ionisation isomerism, uses d2sp3 (inner orbital) and has no unpaired electron \( (t2g6) \).
Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.
(a) The oxidation number of Pt is +4
(b) It is Zeise's salt
(c) It is a pi-bonded complex
(d) Four ligands surround the platinum atom
Show Answer & Explanation
Answer: (a) The oxidation number of Pt is +4
Explanation:
1. Charge: \( x + 0 - 3 = -1 \) gives \( x = +2 \).
Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.
(a) (ii) and (iv)
(b) (i) and (ii)
(c) (ii), (iii) and (iv)
(d) (i), (ii) and (iv)
Show Answer & Explanation
Answer: (a) (ii) and (iv)
Explanation:
1. Fe(CO)5 (dsp3) and Cr(CO)6 (d2sp3) use inner \( d \) orbitals and are diamagnetic. Ni(CO)4 is sp3 (outer), and V(CO)6 is paramagnetic.
Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.
(a) 3
(b) 2
(c) 0
(d) 5
Show Answer & Explanation
Answer: (a) 3
Explanation:
1. Square planar Mabcd has 3 geometrical isomers.
Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.
(a) \( \ce{[Co(NH3)3Cl3]} \)
(b) \( \ce{[Co(NH3)4Cl2]Cl} \)
(c) \( \ce{[Co(NH3)6]Cl3} \)
(d) \( \ce{[Co(NH3)5Cl]Cl2} \)
Show Answer & Explanation
Answer: (c) \( \ce{[Co(NH3)6]Cl3} \)
Explanation:
1. It gives four ions (1 cation \( + 3 \) Cl-), the most among the options.
Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.
(a) 0
(b) 2
(c) 3
(d) 4
Show Answer & Explanation
Answer: (b) 2
Explanation:
1. Ma3b3: facial and meridional isomers.
Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.
(a) 2
(b) 3
(c) 4
(d) 5
Show Answer & Explanation
Answer: (b) 3
Explanation:
1. trans (1, achiral) plus cis (\( a \) pair of enantiomers) = 3.
Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.
(a) 100
(b) 25
(c) 75
(d) 50
Show Answer & Explanation
Answer: (b) 25
Explanation:
1. Four chlorides in total, of which only the one outside the sphere precipitates: 1/4 = 25%.
Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.
(a) -1
(b) +3
(c) +1
(d) +2
Show Answer & Explanation
Answer: (a) -1
Explanation:
1. Charge = \( +3 + 2(-2) + 0 = -1 \).
Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.
(a) Spin-only magnetic moment: \( \ce{[Cr(NH3)6]^{3+}} \) > \( \ce{[Mn(CN)6]^{3-}} \) > \( \ce{V(CO)6} \)
(b) Delta0: \( \ce{[Co(CN)6]^{3-}} \) > \( \ce{[Co(NH3)6]^{3+}} \) > \( \ce{[Co(H2O)6]^{3+}} \)
(c) Stability: \( \ce{[Ni(NH3)6]^{2+}} \) < \( \ce{[Ni(en)(NH3)4]^{2+}} \) < \( \ce{[Ni(en)3]^{2+}} \)
(d) M-C pi bond strength: \( \ce{Ni(CO)4} \) > \( \ce{[Co(CO)4]-} \) > \( \ce{[Fe(CO)4]^{2-}} \)
Show Answer & Explanation
Answer: (d) M-C pi bond strength: \( \ce{Ni(CO)4} \) > \( \ce{[Co(CO)4]-} \) > \( \ce{[Fe(CO)4]^{2-}} \)
Explanation:
1. Back bonding grows with negative charge on the metal, so the \( M-C \pi \) bond strength order is Fe(CO)4 2- > Co(CO)4- > Ni(CO)4, the reverse of the order given.
Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.
(a) Barium tetrafluoridochromate(II)
(b) Dichloridobis(urea)copper(II)
(c) All are possible
(d) Potassium tetrafluoridooxidochromate(VI)
Show Answer & Explanation
Answer: (d) Potassium tetrafluoridooxidochromate(VI)
Explanation:
1. Cr(VI) with \( O2- \) and four \( F- \) gives zero charge, so a potassium salt is not possible; the name suits a neutral CrOF4 only.
Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.
(a) coloured and paramagnetic
(b) colourless and paramagnetic
(c) coloured and octahedral
(d) colourless and diamagnetic
Show Answer & Explanation
Answer: (d) colourless and diamagnetic
Explanation:
1. Sc3+ is \( d0 \): no \( d-d \) transitions and no unpaired electrons.
Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.
(a) (a) is used in the detection of S2-
(b) The complex part of each compound is octahedral
(c) The oxidation state of Fe in (a) and (b) is +1
(d) (c) is used in the detection of Fe3+
Show Answer & Explanation
Answer: (c) The oxidation state of Fe in (a) and (b) is +1
Explanation:
1. In \( (a) \) Fe is \( +2 \) (NO+). In \( (b) \) Fe is formally \( +1 \) (NO+ with charges balancing). So the statement is wrong for \( (a) \).
Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.
(a) +2.4 Delta0 + 3P
(b) -3.6 Delta0 + 3P
(c) -2.4 Delta0 + 2P
(d) -1.8 Delta0 + 3P
Show Answer & Explanation
Answer: (c) -2.4 Delta0 + 2P
Explanation:
1. Co3+ is \( d6 \) low spin: \( t2g6 \), so CFSE = \( 6(-0.4) Delta0 = -2.4 Delta0 \), and two extra pairing energies \( (2P) \) are needed.
Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.
(a) estimating the concentration of iron
(b) measuring the solid state magnetic moment
(c) measuring the concentration of CN-
(d) thermally decomposing the compound
Show Answer & Explanation
Answer: (b) measuring the solid state magnetic moment
Explanation:
1. Fe(II) low spin \( d6 \) with NO+ is diamagnetic, whereas Fe(III) with NO would be paramagnetic.
Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.
(a) 3
(b) 4
(c) 2
(d) 5
Show Answer & Explanation
Answer: (c) 2
Explanation:
1. Ma3b3 octahedral: fac and mer.
Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.
(a) \( \ce{Na2[Fe(CN)5NO]} \)
(b) \( \ce{Na4[Fe(CN)5NO2]} \)
(c) \( \ce{NaFe[Fe(CN)6]} \)
(d) \( \ce{Na2[Fe(CN)6NO2]} \)
Show Answer & Explanation
Answer: (a) \( \ce{Na2[Fe(CN)5NO]} \)
Explanation:
1. Nitroprusside is pentacyanonitrosylferrate(II), Na2[Fe(CN)5NO].
Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.
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FAQs
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