JEE Chemistry Coordination Compounds MCQs Set 30

Chemistry Objective Questions and Answers: Coordination Compounds

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Multiple Choice Questions

Question 1: Which of the following compounds show optical isomerism? (a) cis-[Co(NH3)4Cl2]+ (b) trans-[Co(en)2Cl2]+ (c) cis-[Co(en)2Cl2]+ (d) [Co(en)3]3+
(a) (a) and (b)
(b) (b) and (c)
(c) (a), (b) and (d)
(d) (c) and (d)
Show Answer & Explanation

Answer: (d) (c) and (d)

Explanation:
1. cis-[Co(en)2Cl2]+ and [Co(en)3]3+ lack mirror planes and are chiral. The ammine cis complex and the trans complex have mirror planes.

Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.

Question 2: Which kind of isomerism is shown by the complex \( \ce{[Co(NH3)5(ONO)]SO4} \)?
(a) geometrical and optical isomerism
(b) Ionisation and linkage isomerism
(c) ionisation, linkage, geometrical and optical
(d) linkage, geometrical and optical
Show Answer & Explanation

Answer: (b) Ionisation and linkage isomerism

Explanation:
1. Nitrito (ONO) can change to nitro (linkage), and SO4 2- can exchange with ONO-. There is no geometrical or optical isomerism.

Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.

Question 3: Which pair of complexes is planar?
(a) \( \ce{[Ni(CN)4]^{2-}} \) and \( \ce{[Rh(CO)2(PPh3)2]+} \)
(b) \( \ce{[Ni(CN)4]^{4-}} \) and \( \ce{[PtCl4]^{2-}} \)
(c) \( \ce{[NiCl4]^{2-}} \) and \( \ce{[Ni(CN)4]^{2-}} \)
(d) \( \ce{[PtCl4]^{2-}} \) and \( \ce{Ni(CO)4} \)
Show Answer & Explanation

Answer: (a) \( \ce{[Ni(CN)4]^{2-}} \) and \( \ce{[Rh(CO)2(PPh3)2]+} \)

Explanation:
1. Both are d8 square planar. [Ni(CN)4]4- is Ni(0), tetrahedral; [NiCl4]2- and Ni(CO)4 are tetrahedral.

Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.

Question 4: The complexes \( \ce{[Pt(NH3)4][PtCl6]} \) and \( \ce{[Pt(NH3)4Cl2][PtCl4]} \) are:
(a) coordination isomers
(b) linkage isomers
(c) optical isomers
(d) ionisation isomers
Show Answer & Explanation

Answer: (a) coordination isomers

Explanation:
1. The ligands are exchanged between the cationic and anionic complexes, with the metal oxidation states changing as well.

Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.

Question 5: In which of the following complexes is nickel in its highest oxidation state?
(a) \( \ce{Ni(CO)4} \)
(b) \( \ce{[Ni(NH3)6](BF4)2} \)
(c) \( \ce{K4[Ni(CN)6]} \)
(d) \( \ce{K2NiF6} \)
Show Answer & Explanation

Answer: (d) \( \ce{K2NiF6} \)

Explanation:
1. Oxidation states of Ni: Ni(CO)4 = 0, K2NiF6 = +4, [Ni(NH3)6](BF4)2 = +2, K4[Ni(CN)6] = +2.

Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.

Question 6: Which pair of name and formula is not correct?
(a) Tetraamminecopper(II) sulphate : \( \ce{[Cu(NH3)4]SO4} \)
(b) Diamminesilver(I) chloride : \( \ce{[Ag(NH3)2]Cl} \)
(c) Potassium hexacyanidoferrate(III) : \( \ce{K4[Fe(CN)6]} \)
(d) Potassium amminepentachloridoplatinate(IV) : \( \ce{K[PtCl5(NH3)]} \)
Show Answer & Explanation

Answer: (c) Potassium hexacyanidoferrate(III) : \( \ce{K4[Fe(CN)6]} \)

Explanation:
1. Fe(III) with six CN- gives [Fe(CN)6]3-, so the formula is K3[Fe(CN)6]. K4[Fe(CN)6] is the iron(II) salt.

Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.

Question 7: Among the following metal carbonyls, the C-O bond order is lowest in:
(a) \( \ce{[V(CO)6]-} \)
(b) \( \ce{[Mn(CO)6]+} \)
(c) \( \ce{Fe(CO)5} \)
(d) \( \ce{Cr(CO)6} \)
Show Answer & Explanation

Answer: (a) \( \ce{[V(CO)6]-} \)

Explanation:
1. The negative charge on V increases pi back bonding the most, so C-O has the lowest bond order.

Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.

Question 8: Which of the following are organometallic compounds? (i) Al2(CH3)6 (ii) K[PtCl3(C2H4)] (iii) N(CH3)3
(a) (i) only
(b) (i) and (ii) only
(c) (iii) only
(d) (i), (ii) and (iii)
Show Answer & Explanation

Answer: (b) (i) and (ii) only

Explanation:
1. Organometallic compounds have at least one metal-carbon bond. Trimethylamine has an N-C bond only.

Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.

Question 9: Concentrated H2SO4 will not dehydrate which of the following complexes?
(a) \( \ce{[Cr(H2O)5Cl]Cl2.H2O} \)
(b) \( \ce{[Cr(H2O)4Cl2]Cl.2H2O} \)
(c) all of these
(d) \( \ce{[Cr(H2O)6]Cl3} \)
Show Answer & Explanation

Answer: (d) \( \ce{[Cr(H2O)6]Cl3} \)

Explanation:
1. All six water molecules in [Cr(H2O)6]Cl3 are coordinated; concentrated H2SO4 removes only lattice water.

Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.

Question 10: Which has the maximum paramagnetic nature?
(a) \( \ce{[Mn(H2O)6]^{2+}} \)
(b) \( \ce{[Cu(H2O)4]^{2+}} \)
(c) \( \ce{[Cu(NH3)4]^{2+}} \)
(d) \( \ce{[Fe(CN)6]^{4-}} \)
Show Answer & Explanation

Answer: (a) \( \ce{[Mn(H2O)6]^{2+}} \)

Explanation:
1. Mn2+ (d5, high spin with water) has five unpaired electrons (5.92 BM).

Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.

Question 11: Which of the following is not a pi-bonded complex?
(a) Zeise's salt
(b) Ferrocene
(c) Tetraethyl lead
(d) Bis(benzene)chromium
Show Answer & Explanation

Answer: (c) Tetraethyl lead

Explanation:
1. Pb(C2H5)4 has sigma Pb-C bonds. The others have pi bonds between the metal and the alkene or arene ring.

Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.

Question 12: For sodium nitroprusside, the oxidation number, coordination number and effective atomic number of iron are respectively:
(a) +3, 6, 36
(b) +2, 6, 36
(c) +3, 3, 36
(d) 6, +3, 35
Show Answer & Explanation

Answer: (b) +2, 6, 36

Explanation:
1. Na2[Fe(CN)5NO] with NO+: x - 5 + 1 = -2 gives +2. Six ligands, EAN = 24 + 12 = 36.

Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.

Question 13: A coordination complex has the formula PtCl4.2KCl. Conductance measurements indicate three ions per formula unit, and AgNO3 gives no precipitate. The coordination number of Pt is:
(a) 5
(b) 4
(c) 6
(d) 3
Show Answer & Explanation

Answer: (c) 6

Explanation:
1. The complex is K2[PtCl6]: 2 K+ and one complex ion. All six Cl- are bonded to Pt.

Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.

Question 14: Which of the following complexes show both geometrical and optical isomerism? (i) [Cr(ox)3]3- (ii) [Rh(en)2Cl2]+ (iii) [Co(NH3)2Cl2(en)]+
(a) (i) only
(b) (ii) and (iii) only
(c) (i) and (ii) only
(d) (i), (ii) and (iii)
Show Answer & Explanation

Answer: (b) (ii) and (iii) only

Explanation:
1. [Cr(ox)3]3- is chiral only (no geometrical isomers). Both (ii) and (iii) have cis (chiral) and trans forms.

Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.

Question 15: Diethylenetriamine is:
(a) a chelating agent only
(b) a tridentate neutral molecule that is also a chelating agent
(c) a tridentate monoanion
(d) bidentate
Show Answer & Explanation

Answer: (b) a tridentate neutral molecule that is also a chelating agent

Explanation:
1. dien, NH2CH2CH2NHCH2CH2NH2, binds through three N atoms and is a neutral chelating ligand.

Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.

Question 16: The isomerism exhibited by \( \ce{[Cr(NH3)2(H2O)2Cl2]+} \) is:
(a) ionisation and optical
(b) hydrate and optical
(c) coordinate and geometrical
(d) geometrical and optical
Show Answer & Explanation

Answer: (d) geometrical and optical

Explanation:
1. Ma2b2c2 has 5 geometrical forms, one of which is chiral, so geometrical and optical isomerism exist.

Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.

Question 17: Which of the following has an optical isomer?
(a) \( \ce{[Co(en)(NH3)2]^{2+}} \)
(b) \( \ce{[Co(H2O)4(en)]^{3+}} \)
(c) \( \ce{[Co(en)2(NH3)2]^{3+}} \)
(d) \( \ce{[Co(NH3)3Cl]+} \)
Show Answer & Explanation

Answer: (c) \( \ce{[Co(en)2(NH3)2]^{3+}} \)

Explanation:
1. The cis form of [Co(en)2(NH3)2]3+ is chiral. The other options lack a pair of non-superimposable mirror images.

Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.

Question 18: \( \ce{[Co(NH3)5NO2]Cl2} \) and \( \ce{[Co(NH3)5ONO]Cl2} \) are related as:
(a) geometrical isomers
(b) coordination isomers
(c) ionisation isomers
(d) linkage isomers
Show Answer & Explanation

Answer: (d) linkage isomers

Explanation:
1. NO2- binds through N in one and through O in the other.

Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.

Question 19: Total number of isomers (geometrical plus linkage) possible for \( \ce{[Pt(NH3)2(CN)2]} \), treating cyanide as an ambidentate ligand, is:
(a) 2
(b) 6
(c) 4
(d) 8
Show Answer & Explanation

Answer: (b) 6

Explanation:
1. Square planar Ma2b2 gives cis and trans. Each can have CN/CN, CN/NC or NC/NC: 3 x 2 = 6.

Teacher's Note:
1. Ambidentate ligands add linkage isomers.

Question 20: The crystal field splitting for Cr3+ in an octahedral field with ligands I-, H2O, NH3 and CN- increases in the order:
(a) \( \ce{CN-} \) < \( \ce{I-} \) < \( \ce{H2O} \) < \( \ce{NH3} \)
(b) \( \ce{CN-} \) < \( \ce{NH3} \) < \( \ce{H2O} \) < \( \ce{I-} \)
(c) \( \ce{I-} \) < \( \ce{H2O} \) < \( \ce{NH3} \) < \( \ce{CN-} \)
(d) \( \ce{NH3} \) < \( \ce{H2O} \) < \( \ce{I-} \) < \( \ce{CN-} \)
Show Answer & Explanation

Answer: (c) \( \ce{I-} \) < \( \ce{H2O} \) < \( \ce{NH3} \) < \( \ce{CN-} \)

Explanation:
1. This follows the spectrochemical series: I- < Br- < Cl- < F- < OH- < H2O < NH3 < en < NO2- < CN- < CO.

Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.

Question 21: The effective atomic numbers (EAN) of the central metal atom in Cr(CO)6 and in ferrocene [Fe(eta5-C5H5)2] respectively are:
(a) 36 and 35
(b) 34 and 36
(c) 35 and 36
(d) 36 and 36
Show Answer & Explanation

Answer: (d) 36 and 36

Explanation:
1. Cr(CO)6: 24 + 6 x 2 = 36. Ferrocene: Fe2+ (24 electrons) + 2 Cp- x 6 electrons = 36.

Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.

Question 22: Which of the following are square planar complexes? (i) [AuCl4]- (ii) [PtCl4]2- (iii) [MnBr4]2- (iv) [Cu(NH3)4]2+
(a) (i), (ii) and (iv)
(b) (i) and (ii) only
(c) (ii) and (iii) only
(d) (ii) and (iv) only
Show Answer & Explanation

Answer: (a) (i), (ii) and (iv)

Explanation:
1. Au3+ and Pt2+ are d8 square planar and Cu2+ in the ammine is dsp2. [MnBr4]2- is tetrahedral.

Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.

Question 23: Which of the following ligands are bidentate monovalent anions? (a) acetylacetonato (b) oxalato (c) dimethylglyoximato
(a) (a) only
(b) (c) only
(c) (b) and (c)
(d) (a) and (c)
Show Answer & Explanation

Answer: (d) (a) and (c)

Explanation:
1. Acetylacetonate and dimethylglyoximate each carry -1 and bind through two atoms. Oxalate carries -2.

Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.

Question 24: In the reaction Na2S + Na2[Fe(CN)5NO] giving Na4[Fe(CN)5NOS], the oxidation numbers of Fe in the reactant and product complexes respectively are:
(a) +2, +1
(b) +2, +3
(c) +3, +3
(d) +2, +2
Show Answer & Explanation

Answer: (d) +2, +2

Explanation:
1. The reaction adds S2- to the NO+ ligand (forming NOS 3-), but the iron stays in the +2 state.

Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.

Question 25: Which of the following is a high spin complex?
(a) \( \ce{[Co(NH3)6]^{3+}} \)
(b) \( \ce{[Fe(CN)6]^{4-}} \)
(c) \( \ce{[FeF6]^{3-}} \)
(d) \( \ce{[Ni(CN)4]^{2-}} \)
Show Answer & Explanation

Answer: (c) \( \ce{[FeF6]^{3-}} \)

Explanation:
1. F- is a weak field ligand, so Fe3+ (d5) in [FeF6]3- keeps five unpaired electrons.

Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.

Question 26: Among the following complex ions, the one that probably has the largest overall formation constant is:
(a) \( \ce{[Co(NH3)6]^{3+}} \)
(b) \( \ce{[Co(H2O)6]^{3+}} \)
(c) \( \ce{[Co(en)3]^{3+}} \)
(d) \( \ce{[Co(NH3)2(H2O)4]^{3+}} \)
Show Answer & Explanation

Answer: (c) \( \ce{[Co(en)3]^{3+}} \)

Explanation:
1. Chelation by three en rings gives the greatest stability (chelate effect).

Teacher's Note:
1. Work out the oxidation state, coordination number and geometry step by step.

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