JEE Chemistry Amines MCQs Set 15

Chemistry Objective Questions and Answers: Amines

Access targeted multiple-choice questions for Amines designed to align with the latest JEE academic syllabus for JEE Chemistry. These objective practice sets help students evaluate their conceptual understanding and improve exam readiness.

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Access the complete set of multiple-choice questions for Amines below. This focused format allows students to isolate specific topics for thorough review and uninterrupted practice alongside official JEE textbooks.

Multiple Choice Questions

Question 1: When an organic compound was treated with a mixture of sodium nitrite and hydrochloric acid in the ice-cold state, nitrogen gas was evolved copiously. The compound is
(a) a nitro compound
(b) a primary amine
(c) an aliphatic primary amine
(d) an aromatic primary amine
Show Answer & Explanation

Answer: (c) an aliphatic primary amine

Explanation:
1. Aliphatic primary amines give unstable diazonium ions that lose N2 immediately.
2. Aromatic ones give stable diazonium salts at 0-5°C.

Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.

Question 2: Which statement is not correct?
(a) Amines form hydrogen bonds
(b) Ethylamine has a higher boiling point than propane
(c) Methylamine is more basic than ammonia
(d) Dimethylamine is less basic than methylamine
Show Answer & Explanation

Answer: (d) Dimethylamine is less basic than methylamine

Explanation:
1. In water, dimethylamine (pKb 3.27) is slightly more basic than methylamine (3.38).
2. The other statements are correct.

Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.

Question 3: Which of the following is not used as an explosive?
(a) trinitrotoluene
(b) trinitrobenzene
(c) picric acid
(d) nitrobenzene
Show Answer & Explanation

Answer: (d) nitrobenzene

Explanation:
1. Nitrobenzene is a solvent and a raw material for aniline, not an explosive.

Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.

Question 4: Primary amines react with nitrous acid to yield
(a) insoluble nitrite salts
(b) a yellow oily layer
(c) nitrogen gas
(d) an azo dye
Show Answer & Explanation

Answer: (c) nitrogen gas

Explanation:
1. RNH2 + HNO2 → ROH + N2 + H2O.

Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.

Question 5: Which of the following has the smell of bitter almonds?
(a) nitromethane
(b) nitroethane
(c) nitrobenzene
(d) aniline
Show Answer & Explanation

Answer: (c) nitrobenzene

Explanation:
1. Nitrobenzene smells of bitter almonds.

Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.

Question 6: Reaction of nitrous acid with an aliphatic primary amine in the cold gives
(a) an alcohol
(b) a diazonium salt
(c) a nitrite
(d) a dye
Show Answer & Explanation

Answer: (a) an alcohol

Explanation:
1. The unstable diazonium ion reacts with water to give an alcohol and nitrogen.

Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.

Question 7: In the presence of acid, hydrolysis of methyl cyanide gives
(a) acetic acid
(b) methylamine
(c) methyl alcohol
(d) formic acid
Show Answer & Explanation

Answer: (a) acetic acid

Explanation:
1. CH3CN + 2H2O + H+ → CH3COOH + NH4+.

Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.

Question 8: The amine which does not react with acetyl chloride, or which cannot be acetylated, is
(a) CH3NH2
(b) (CH3)2NH
(c) (CH3)3N
(d) none of these
Show Answer & Explanation

Answer: (c) (CH3)3N

Explanation:
1. Acylation needs an N-H bond.
2. A tertiary amine has none.

Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.

Question 9: Fusion of sodium with an amine gives mainly
(a) NaCN
(b) NaN3
(c) NaSCN
(d) NaNO2
Show Answer & Explanation

Answer: (a) NaCN

Explanation:
1. In the Lassaigne test, N from the organic compound with carbon and sodium forms sodium cyanide.

Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.

Question 10: Which of the following is most basic?
(a) C6H5NH2
(b) (CH3)2NH
(c) (CH3)3N
(d) NH3
Show Answer & Explanation

Answer: (b) (CH3)2NH

Explanation:
1. In water, secondary methylamine has the best balance of the +I effect and solvation of the ammonium ion.

Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.

Question 11: In the reaction CH3CN + 2H → (HCl/ether) X → (boiling H2O) Y, the term Y is
(a) acetone
(b) ethylamine
(c) acetaldehyde
(d) dimethylamine
Show Answer & Explanation

Answer: (c) acetaldehyde

Explanation:
1. Stephen reduction gives the imine hydrochloride X.
2. Hydrolysis of X gives acetaldehyde.

Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.

Question 12: Which of the following compounds does not react with NaNO2 and HCl?
(a) C6H5OH
(b) C6H5NH2
(c) (CH3)3CNO2
(d) (CH3)2CHNO2
Show Answer & Explanation

Answer: (c) (CH3)3CNO2

Explanation:
1. A tertiary nitroalkane has no alpha hydrogen.
2. Phenol is nitrosated, aniline is diazotised and a secondary nitroalkane gives a pseudonitrole.

Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.

Question 13: In the reduction of nitrobenzene, which of the following is an intermediate?
(a) C6H5N=O
(b) C6H5NH-NHC6H5
(c) C6H5-N=N-C6H5
(d) C6H5N(→O)=N-C6H5
Show Answer & Explanation

Answer: (a) C6H5N=O

Explanation:
1. Stepwise reduction is ArNO2 → ArNO → ArNHOH → ArNH2.
2. The other compounds form only by bimolecular condensation in alkaline medium.

Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.

Question 14: Aniline, when treated with conc. HNO3, gives mainly
(a) 4-nitroaniline
(b) 2-nitroaniline
(c) p-benzoquinone
(d) nitrobenzene
Show Answer & Explanation

Answer: (c) p-benzoquinone

Explanation:
1. Concentrated nitric acid oxidises aniline, giving a black tar and p-benzoquinone, rather than direct nitration.

Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.

Question 15: Which one of the following is not a base?
(a) N2H4
(b) NH2OH
(c) (CH3)3N
(d) HN3
Show Answer & Explanation

Answer: (d) HN3

Explanation:
1. Hydrazoic acid is a weak acid.
2. Hydrazine, hydroxylamine and trimethylamine have lone pairs on N and are bases.

Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.

Question 16: If methyl is the alkyl group, then the order of basicity (in water) is correct as
(a) R2NH > RNH2 > R3N > NH3
(b) R2NH > R3N > RNH2 > NH3
(c) RNH2 > NH3 > R2NH > R3N
(d) NH3 > RNH2 > R2NH > R3N
Show Answer & Explanation

Answer: (a) R2NH > RNH2 > R3N > NH3

Explanation:
1. pKb: dimethylamine 3.27, methylamine 3.38, trimethylamine 4.22, ammonia 4.75.

Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.

Question 17: Which of the following has the minimum heat of dissociation?
(a) (CH3)3N → BF3
(b) (CH3)3N → B(CH3)F2
(c) (CH3)3N → B(CH3)2F
(d) (CH3)3N → B(CH3)3
Show Answer & Explanation

Answer: (d) (CH3)3N → B(CH3)3

Explanation:
1. The adduct with trimethylborane has the greatest steric strain (front-strain) between methyl groups on N and B.
2. So it is least stable and has the lowest heat of dissociation.

Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.

Question 18: The major product (70 to 80 per cent) of the reaction between m-dinitrobenzene and NH4HS is
(a) 1,3-dinitrobenzene (unchanged)
(b) 3-nitroaniline
(c) 1,3-diaminobenzene
(d) 3-aminobenzenethiol
Show Answer & Explanation

Answer: (b) 3-nitroaniline

Explanation:
1. Ammonium hydrosulphide (the Zinin reduction) reduces one nitro group selectively, giving m-nitroaniline.

Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.

Question 19: In the diazotisation of aniline with sodium nitrite and hydrochloric acid, an excess of hydrochloric acid is used primarily to
(a) suppress the concentration of free aniline available for coupling
(b) suppress hydrolysis of phenol
(c) insure a stoichiometric amount of nitrous acid
(d) neutralise the base liberated
Show Answer & Explanation

Answer: (a) suppress the concentration of free aniline available for coupling

Explanation:
1. Free aniline would couple with the diazonium ion to give diazoamino compounds, which the excess acid prevents.

Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.

Question 20: A primary amine can be converted to an alcohol by the action of
(a) alkali
(b) nitrous acid
(c) a reducing agent
(d) an oxidising agent
Show Answer & Explanation

Answer: (b) nitrous acid

Explanation:
1. RNH2 + HNO2 → ROH + N2 + H2O.

Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.

Question 21: Arrange in increasing order of basicity (in water): CH3NH2, (CH3)2NH, C6H5NH2, (CH3)3N.
(a) (CH3)3N < (CH3)2NH < CH3NH2 < C6H5NH2
(b) (CH3)3N > (CH3)2NH > CH3NH2 > C6H5NH2
(c) C6H5NH2 < (CH3)3N < CH3NH2 < (CH3)2NH
(d) C6H5NH2 > (CH3)3N > CH3NH2 > (CH3)2NH
Show Answer & Explanation

Answer: (c) C6H5NH2 < (CH3)3N < CH3NH2 < (CH3)2NH

Explanation:
1. Aniline (pKb 9.4) is far weaker than the alkylamines.
2. For methyl groups in water the order is (CH3)2NH (3.27) > CH3NH2 (3.38) > (CH3)3N (4.22).

Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.

Question 22: CH3CN + CH3MgI → A → (H2O/H+) B. The compound B is
(a) acetic acid
(b) acetone
(c) acetaldehyde
(d) ethyl alcohol
Show Answer & Explanation

Answer: (b) acetone

Explanation:
1. The Grignard reagent adds to the C≡N group, and hydrolysis of the imine gives the ketone CH3COCH3.

Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.

Question 23: CH3CN is known as acetonitrile because
(a) it contains an aceto group
(b) on hydrolysis it gives acetic acid
(c) both (a) and (b)
(d) none of these
Show Answer & Explanation

Answer: (b) on hydrolysis it gives acetic acid

Explanation:
1. Nitriles are named after the acid they give on hydrolysis, here acetic acid.

Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.

Question 24: What is formed when nitrobenzene is reduced using zinc and alkali?
(a) phenol
(b) aniline
(c) nitrosobenzene
(d) hydrazobenzene
Show Answer & Explanation

Answer: (d) hydrazobenzene

Explanation:
1. Zinc and alkali (basic medium) reduce nitrobenzene to hydrazobenzene through azoxy and azo compounds.

Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.

Question 25: RCOCl + 2Me2NH → A + Me2NH2+Cl-. Here A is
(a) RCON(Me)2
(b) RCONH2
(c) RCONHMe
(d) (RCO)2NH
Show Answer & Explanation

Answer: (a) RCON(Me)2

Explanation:
1. Dimethylamine is acylated at N, giving the N,N-dimethylamide, and the second mole of amine takes up the HCl.

Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.

Question 26: Decreasing order of basicity of (1) CH3CONH2, (2) CH3CH2NH2, (3) PhCH2CONH2 is
(a) 1 > 2 > 3
(b) 2 > 1 > 3
(c) 3 > 2 > 1
(d) none of these
Show Answer & Explanation

Answer: (b) 2 > 1 > 3

Explanation:
1. The amine is by far the most basic.
2. Amides are very weak bases, and the phenyl group (-I effect) makes phenylacetamide weaker than acetamide.

Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.

Question 27: Among the following, the strongest base is
(a) C6H5NH2
(b) p-NO2-C6H4NH2
(c) m-NO2-C6H4NH2
(d) C6H5CH2NH2
Show Answer & Explanation

Answer: (d) C6H5CH2NH2

Explanation:
1. In benzylamine the lone pair is not delocalised in the ring.
2. The aniline types are weakened by the aryl group, and nitro groups reduce basicity further.

Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.

Question 28: Aniline and methylamine can be differentiated by
(a) reaction with chloroform and aqueous KOH
(b) diazotisation followed by coupling with phenol
(c) reaction with acetic anhydride
(d) none of these
Show Answer & Explanation

Answer: (b) diazotisation followed by coupling with phenol

Explanation:
1. Only aniline gives a stable diazonium salt that couples with phenol to give a coloured azo dye.
2. Methylamine loses N2 on diazotisation.

Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.

Question 29: The amine which can react with C6H5-SO2-Cl to form a product insoluble in alkali is
(a) a primary amine
(b) a secondary amine
(c) a tertiary amine
(d) both primary and secondary amines
Show Answer & Explanation

Answer: (b) a secondary amine

Explanation:
1. The sulphonamide of a secondary amine has no N-H, so it is not acidic and does not dissolve in alkali.

Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.

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