JEE Chemistry Amines MCQs Set 16

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Chapter-wise Objective Questions: Amines

View or download the dedicated Amines MCQ resource below. Practicing these 50 objective questions regularly builds familiarity with standard exam patterns and helps secure higher marks in final Chemistry evaluations.

Multiple Choice Questions

Question 1: A mixture of benzene and aniline can be separated by
(a) hot water
(b) dil. HCl
(c) dil. NaOH
(d) alcohol
Show Answer & Explanation

Answer: (b) dil. HCl

Explanation:
1. Aniline forms water-soluble anilinium chloride, whereas benzene stays in the organic layer.

Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.

Question 2: The compound A with the following sequence of reactions gave benzoic acid: A → (NaNO2/HCl) B → (KCN) C → (H3O+) benzoic acid. The compound A is
(a) nitrobenzene
(b) aniline
(c) benzaldehyde
(d) amides
Show Answer & Explanation

Answer: (b) aniline

Explanation:
1. Aniline is diazotised (B), the Sandmeyer cyanation gives benzonitrile (C), and hydrolysis gives benzoic acid.

Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.

Question 3: Which of the chemicals are used to manufacture methyl isocyanate that caused the Bhopal tragedy? (i) methylamine (ii) phosgene (iii) phosphine (iv) dimethylamine
(a) (i) and (iii)
(b) (iii) and (iv)
(c) (i) and (ii)
(d) (ii) and (iv)
Show Answer & Explanation

Answer: (c) (i) and (ii)

Explanation:
1. CH3NH2 + COCl2 → CH3NCO + 2HCl.

Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.

Question 4: An isocyanide on hydrolysis gives
(a) an amide
(b) a carboxylic acid and ammonia
(c) an N-substituted amide
(d) a primary amine and formic acid
Show Answer & Explanation

Answer: (d) a primary amine and formic acid

Explanation:
1. RNC + 2H2O → RNH2 + HCOOH.

Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.

Question 5: Methyl isocyanide on hydrolysis gives
(a) CH3NH2
(b) HCOOH
(c) CH3COOH
(d) both CH3NH2 and HCOOH
Show Answer & Explanation

Answer: (d) both CH3NH2 and HCOOH

Explanation:
1. CH3NC + 2H2O → CH3NH2 + HCOOH.

Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.

Question 6: Pure aniline is a
(a) colourless solid
(b) brown-coloured solid
(c) colourless liquid
(d) brown-coloured liquid
Show Answer & Explanation

Answer: (c) colourless liquid

Explanation:
1. Freshly purified aniline is a colourless oily liquid that darkens on air oxidation.

Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.

Question 7: Reduction of methyl isocyanide gives
(a) ethylamine
(b) methylamine
(c) dimethylamine
(d) trimethylamine
Show Answer & Explanation

Answer: (c) dimethylamine

Explanation:
1. CH3-N≡C + 4[H] → CH3-NH-CH3.

Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.

Question 8: The reaction of aniline with benzaldehyde is
(a) polymerisation
(b) condensation
(c) addition
(d) substitution
Show Answer & Explanation

Answer: (b) condensation

Explanation:
1. Water is eliminated as a Schiff base forms, which is a condensation.

Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.

Question 9: In the reaction C6H5CHO + H2NC6H5 → C6H5N=HCC6H5 + H2O, the compound C6H5N=CHC6H5 is known as
(a) aldol
(b) Schiff's base
(c) condensation product of an ester
(d) Benedict's reagent
Show Answer & Explanation

Answer: (b) Schiff's base

Explanation:
1. An imine formed from an aldehyde or ketone and a primary amine is a Schiff base.

Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.

Question 10: The unshared pair of electrons on a cyanide ion can act as a
(a) isocyanide centre
(b) amido centre
(c) cationic centre
(d) nucleophilic centre
Show Answer & Explanation

Answer: (d) nucleophilic centre

Explanation:
1. The lone pair on carbon is donated to electrophiles, so the ion acts as a nucleophile.

Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.

Question 11: Electrophilic substitution of aniline with bromine gives
(a) 1,4,6-tribromoaniline
(b) 2,4,6-tribromoaniline
(c) 4-bromoaniline
(d) 3-bromoaniline
Show Answer & Explanation

Answer: (b) 2,4,6-tribromoaniline

Explanation:
1. Both ortho positions and the para position are activated.

Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.

Question 12: Mustard gas is obtained by
(a) the action of dilute acids on mustard seeds
(b) treating ethylene with mustard oil
(c) treating sulphur chloride with ethylene
(d) none of these
Show Answer & Explanation

Answer: (c) treating sulphur chloride with ethylene

Explanation:
1. Ethylene reacts with sulphur monochloride to give (ClCH2CH2)2S.

Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.

Question 13: Which of the following is capable of forming a zwitter ion?
(a) C6H5OH
(b) C6H4(NH2)2
(c) CH2(OH)CH(OH)CH2OH
(d) H2N-CH2-COOH
Show Answer & Explanation

Answer: (d) H2N-CH2-COOH

Explanation:
1. A molecule with both an acidic COOH and a basic NH2 group transfers a proton internally: H3N+CH2COO-.

Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.

Question 14: Which reducing agent is likely to be most effective in bringing about RCONH2 → RCH2NH2?
(a) H2-Ni
(b) NaBH4
(c) LiAlH4
(d) Na-alcohol
Show Answer & Explanation

Answer: (c) LiAlH4

Explanation:
1. Amides are not reduced by NaBH4 and need a strong hydride donor like LiAlH4.

Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.

Question 15: Hydrolysis of acetonitrile in acidic medium produces
(a) CH3CH2OH
(b) CH3COOH
(c) CH3NC
(d) CH3COOCH3
Show Answer & Explanation

Answer: (b) CH3COOH

Explanation:
1. CH3CN + 2H2O → CH3COOH + NH3.

Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.

Question 16: The refluxing of (CH3)2NCOCH3 with acid gives
(a) (CH3)2NH + CH3COOH
(b) (CH3)2NCOOH + CH4
(c) 2CH3OH + CH3CONH2
(d) 2CH3NH2 + CH3COOH
Show Answer & Explanation

Answer: (a) (CH3)2NH + CH3COOH

Explanation:
1. Hydrolysis of the amide bond gives the acid and the amine (as its salt).

Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.

Question 17: p-Chloroaniline and anilinium hydrochloride can be distinguished by
(a) Sandmeyer reaction
(b) carbylamine reaction
(c) Hinsberg's reagent
(d) AgNO3
Show Answer & Explanation

Answer: (d) AgNO3

Explanation:
1. Anilinium chloride ionises and gives a white precipitate of AgCl immediately.
2. p-Chloroaniline has covalent chlorine and does not.

Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.

Question 18: Product obtained by electrolytic reduction of nitrobenzene in the presence of H2SO4 is
(a) o-aminophenol
(b) m-aminophenol
(c) p-aminophenol
(d) none of these
Show Answer & Explanation

Answer: (c) p-aminophenol

Explanation:
1. Phenylhydroxylamine formed in strongly acidic medium rearranges (Bamberger) to p-aminophenol.

Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.

Question 19: Cyclohexanone + NH2OH gives A, which with PPA (H3O+) gives B. The product B is
(a) cyclohexanone
(b) 2-hydroxycyclohexanone
(c) caprolactam
(d) epsilon-caprolactone
Show Answer & Explanation

Answer: (c) caprolactam

Explanation:
1. A is the oxime.
2. Beckmann rearrangement in polyphosphoric acid gives the seven-membered lactam, caprolactam.

Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.

Question 20: In the sequence C6H5NH2 → ((CH3CO)2O) X → (Br2/CCl4) Y → (H2O) Z, the final product Z is
(a) p-bromoaniline
(b) p-bromoacetophenone
(c) o-bromoacetophenone
(d) o-bromoacetanilide
Show Answer & Explanation

Answer: (a) p-bromoaniline

Explanation:
1. X = acetanilide.
2. The NHCOCH3 group directs bromination to the para position, and hydrolysis of the amide gives p-bromoaniline.

Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.

Question 21: Benzaldehyde condenses with N,N-dimethylaniline in the presence of anhydrous ZnCl2 to give
(a) Michler's ketone
(b) an azo dye
(c) malachite green
(d) buffer yellow
Show Answer & Explanation

Answer: (c) malachite green

Explanation:
1. The condensation gives leuco-malachite green, which is oxidised to the triphenylmethane dye malachite green.

Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.

Question 22: The correct order of reactivity towards electrophilic substitution of aniline (I), benzene (II) and nitrobenzene (III) is
(a) I > II > III
(b) III > II > I
(c) II > III > I
(d) I < II < III
Show Answer & Explanation

Answer: (a) I > II > III

Explanation:
1. NH2 activates the ring, and NO2 deactivates it strongly.

Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.

Question 23: p-Toluidine is acetylated with acetic anhydride (A), brominated with Br2 in acetic acid (B) and then hydrolysed with H2O/H+ (C). The final product C is
(a) N-(2-bromo-4-methylphenyl)acetamide
(b) 2-bromo-4-methylaniline
(c) 3-bromo-4-methylaniline
(d) 2-bromo-4-methylphenol
Show Answer & Explanation

Answer: (b) 2-bromo-4-methylaniline

Explanation:
1. The acetamido group directs bromine ortho (para is blocked by CH3).
2. Acid hydrolysis then removes the acetyl group and restores the amino group.

Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.

Question 24: The correct order of increasing basic nature for NH3, CH3NH2 and (CH3)2NH is
(a) CH3NH2 < NH3 < (CH3)2NH
(b) (CH3)2NH < NH3 < CH3NH2
(c) NH3 < CH3NH2 < (CH3)2NH
(d) CH3NH2 < (CH3)2NH < NH3
Show Answer & Explanation

Answer: (c) NH3 < CH3NH2 < (CH3)2NH

Explanation:
1. Each methyl group increases the electron density on N, so the order is NH3 < CH3NH2 < (CH3)2NH in water.

Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.

Question 25: Nitrobenzene gives N-phenylhydroxylamine by
(a) Sn/HCl
(b) H2/Pd-C
(c) Zn/NaOH
(d) Zn/NH4Cl
Show Answer & Explanation

Answer: (d) Zn/NH4Cl

Explanation:
1. Neutral reduction with Zn/NH4Cl stops at C6H5NHOH.
2. Strongly acidic reagents give aniline and Zn/NaOH gives hydrazobenzene.

Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.

Question 26: Among the following, the weakest base is
(a) C6H5CH2NH2
(b) C6H5CH2NHCH3
(c) O2NCH2NH2
(d) CH3NHCHO
Show Answer & Explanation

Answer: (d) CH3NHCHO

Explanation:
1. The nitrogen lone pair of the amide-type compound is delocalised onto the carbonyl oxygen.
2. The others are amines, although the nitro group in (c) also lowers basicity strongly.

Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.

Question 27: RNH2 reacts with H2SO4 to form
(a) [RNH3]+HSO4-
(b) [RNH3]2+SO42-
(c) RNH2.H2SO4 (molecular adduct)
(d) no reaction
Show Answer & Explanation

Answer: (a) [RNH3]+HSO4-

Explanation:
1. The amine is protonated to the alkylammonium hydrogensulphate (with excess amine, the sulphate).

Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.

Question 28: A nitrogen-containing organic compound gave an oily liquid on heating with bromine and KOH solution. On shaking the product with acetic anhydride, an antipyretic drug was obtained. The starting compound was
(a) aniline
(b) benzamide
(c) acetamide
(d) nitrobenzene
Show Answer & Explanation

Answer: (b) benzamide

Explanation:
1. Hofmann degradation of benzamide gives aniline (the oily liquid).
2. Acetylation of aniline gives acetanilide, an antipyretic.

Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.

Question 29: Benzamide on reaction with POCl3 gives
(a) aniline
(b) chlorobenzene
(c) benzylamine
(d) benzonitrile
Show Answer & Explanation

Answer: (d) benzonitrile

Explanation:
1. POCl3 dehydrates primary amides to nitriles.

Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.

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FAQs

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