JEE Chemistry Amines MCQs Set 14

Practice MCQs for JEE Chemistry Amines

Access targeted multiple-choice questions for Amines designed to align with the latest JEE academic syllabus for JEE Chemistry. These objective practice sets help students evaluate their conceptual understanding and improve exam readiness.

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Multiple Choice Questions

Question 1: A solution of methylamine
(a) turns blue litmus red
(b) turns red litmus blue
(c) does not affect red or blue litmus
(d) bleaches litmus
Show Answer & Explanation

Answer: (b) turns red litmus blue

Explanation:
1. Methylamine is basic and ionises in water to give OH-.

Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.

Question 2: Mark the correct statement.
(a) Methylamine is slightly acidic
(b) Methylamine is less basic than NH3
(c) Methylamine is a stronger base than NH3
(d) Methylamine forms salts with alkalis
Show Answer & Explanation

Answer: (c) Methylamine is a stronger base than NH3

Explanation:
1. The +I effect of methyl makes the nitrogen lone pair more available.

Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.

Question 3: The product of the mustard oil reaction is
(a) alkyl isothiocyanate
(b) dithiocarbonate
(c) dithioethylacetate
(d) thioether
Show Answer & Explanation

Answer: (a) alkyl isothiocyanate

Explanation:
1. Primary amine, CS2 and HgCl2 give RNCS.

Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.

Question 4: Which of the following is the azo group?
(a) -N=
(b) -N=N-
(c) -CO-NH-
(d) -NH-
Show Answer & Explanation

Answer: (b) -N=N-

Explanation:
1. An azo compound contains two nitrogens joined by a double bond, between two carbon groups.

Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.

Question 5: Oil of mirbane is
(a) aniline
(b) nitrobenzene
(c) p-nitroaniline
(d) p-aminoazobenzene
Show Answer & Explanation

Answer: (b) nitrobenzene

Explanation:
1. Nitrobenzene is called oil of mirbane (it smells like bitter almonds).

Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.

Question 6: The maximum number of -NO2 groups that can be introduced in benzene by nitration is usually
(a) 4
(b) 2
(c) 3
(d) 6
Show Answer & Explanation

Answer: (c) 3

Explanation:
1. Strongly deactivated rings accept at most three nitro groups under vigorous conditions (1,3,5-trinitrobenzene).

Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.

Question 7: Nitrobenzene at room temperature is
(a) a gas
(b) a liquid
(c) a solid
(d) a solution
Show Answer & Explanation

Answer: (b) a liquid

Explanation:
1. It is a pale yellow oily liquid (boiling point about 484 K).

Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.

Question 8: In the explosive amatol, TNT is mixed with
(a) ammonium citrate
(b) ammonium nitrate
(c) ammonium oxalate
(d) ammonium sulphate
Show Answer & Explanation

Answer: (b) ammonium nitrate

Explanation:
1. Amatol is TNT with ammonium nitrate.

Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.

Question 9: By reduction of nitrosobenzene, which of the following is not obtained?
(a) aniline
(b) azobenzene
(c) phenylhydroxylamine
(d) nitrobenzene
Show Answer & Explanation

Answer: (d) nitrobenzene

Explanation:
1. Reduction removes oxygen or adds hydrogen.
2. Nitrobenzene has more oxygen than nitrosobenzene and would be formed by oxidation.

Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.

Question 10: By the presence of a halogen atom in the ring, the basic properties of aniline are
(a) increased
(b) decreased
(c) unchanged
(d) doubled
Show Answer & Explanation

Answer: (b) decreased

Explanation:
1. The electron-withdrawing halogen lowers the electron density on nitrogen.

Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.

Question 11: In the mustard oil reaction, an amine is treated with
(a) Na/C2H5OH
(b) Sn/HCl
(c) CS2
(d) K2Cr2O7/H2SO4
Show Answer & Explanation

Answer: (c) CS2

Explanation:
1. Primary amine + CS2 + HgCl2 gives alkyl isothiocyanate (mustard oil).

Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.

Question 12: Primary nitro compounds, when reacted with HNO2, form crystalline solids (nitrolic acids) which on treatment with NaOH give
(a) a red solution
(b) a blue solution
(c) a white precipitate
(d) yellow colouration
Show Answer & Explanation

Answer: (a) a red solution

Explanation:
1. Primary nitro compounds give a red nitrolic acid salt; secondary give blue pseudonitroles; tertiary give no reaction.

Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.

Question 13: Secondary nitro compounds, when reacted with HNO2, form crystalline solids which on treatment with NaOH give
(a) a red solution
(b) a blue solution
(c) a white precipitate
(d) yellow colouration
Show Answer & Explanation

Answer: (b) a blue solution

Explanation:
1. Secondary nitroalkanes give pseudonitroles, which dissolve in alkali to give a blue colour.

Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.

Question 14: Which possess a powerful mustard smell (and are called mustard oils)?
(a) alkyl isocyanides
(b) alkyl cyanates
(c) alkyl isothiocyanates
(d) alkyl thiocyanates
Show Answer & Explanation

Answer: (c) alkyl isothiocyanates

Explanation:
1. R-N=C=S compounds have the pungent mustard smell.

Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.

Question 15: On heating acetamide in the presence of P2O5, which of the following is formed?
(a) ammonium acetate
(b) acetonitrile
(c) NH3
(d) methylamines
Show Answer & Explanation

Answer: (b) acetonitrile

Explanation:
1. Dehydration of the primary amide gives the nitrile.

Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.

Question 16: When chloroform reacts with ethylamine in the presence of alcoholic KOH, the compound formed is
(a) ethyl cyanide
(b) ethyl isocyanide
(c) formic acid
(d) an amide
Show Answer & Explanation

Answer: (b) ethyl isocyanide

Explanation:
1. Carbylamine reaction: C2H5NH2 + CHCl3 + 3KOH → C2H5NC + 3KCl + 3H2O.

Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.

Question 17: Hofmann's hypobromite reaction affords a method of
(a) preparing a tertiary amine
(b) preparing a mixture of amines
(c) stepping down a series
(d) stepping up a series
Show Answer & Explanation

Answer: (c) stepping down a series

Explanation:
1. The amine has one carbon less than the amide.

Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.

Question 18: The compound which, on reaction with aqueous nitrous acid at low temperature, produces an oily nitrosoamine is
(a) diethylamine
(b) ethylamine
(c) aniline
(d) methylamine
Show Answer & Explanation

Answer: (a) diethylamine

Explanation:
1. A secondary amine forms an N-nitroso compound, an oily yellow liquid.

Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.

Question 19: Identify the product Z in the series CH3CN → (Na + C2H5OH) X → (HNO2) Y → (K2Cr2O7/H2SO4) Z.
(a) CH3CHO
(b) CH3CONH2
(c) CH3COOH
(d) CH3CH2NHCH3
Show Answer & Explanation

Answer: (c) CH3COOH

Explanation:
1. X = ethylamine; Y = ethanol (nitrous acid replaces NH2 by OH).
2. Oxidation with dichromate gives acetic acid.

Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.

Question 20: The end product of the reactions C2H5NH2 → (HNO2) A → (PCl5) B → (NH3) C is
(a) ethyl cyanide
(b) ethylamine
(c) methylamine
(d) acetamide
Show Answer & Explanation

Answer: (b) ethylamine

Explanation:
1. A = ethanol; B = ethyl chloride.
2. Ammonolysis returns C2H5NH2.

Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.

Question 21: Primary and secondary amines are distinguished by
(a) Br2/KOH
(b) HClO4
(c) HNO2
(d) NH3
Show Answer & Explanation

Answer: (c) HNO2

Explanation:
1. Primary amines evolve N2 with nitrous acid, secondary amines give oily nitrosoamines.

Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.

Question 22: Which one of the following will give a primary amine on hydrolysis?
(a) nitroparaffin
(b) alkyl cyanide
(c) oxime
(d) alkyl isocyanide
Show Answer & Explanation

Answer: (d) alkyl isocyanide

Explanation:
1. RNC + 2H2O → RNH2 + HCOOH.
2. Nitriles give acids, oximes give carbonyl compounds and nitroparaffins give acids (via hydroxylamine).

Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.

Question 23: Methylamine reacts with HNO2 giving
(a) CH3O-N=O
(b) CH3-O-CH3
(c) CH3OH
(d) both (a) and (b)
Show Answer & Explanation

Answer: (c) CH3OH

Explanation:
1. CH3NH2 + HNO2 → CH3OH + N2 + H2O.

Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.

Question 24: Nitrobenzene on reduction by zinc and NH4Cl gives
(a) aniline
(b) nitrosobenzene
(c) hydrazobenzene
(d) phenylhydroxylamine
Show Answer & Explanation

Answer: (d) phenylhydroxylamine

Explanation:
1. Neutral medium stops reduction at C6H5NHOH.

Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.

Question 25: The decreasing order of the basic character of the three amines and ammonia is
(a) NH3 > CH3NH2 > C2H5NH2 > C6H5NH2
(b) C2H5NH2 > CH3NH2 > NH3 > C6H5NH2
(c) C6H5NH2 > C2H5NH2 > CH3NH2 > NH3
(d) CH3NH2 > C2H5NH2 > C6H5NH2 > NH3
Show Answer & Explanation

Answer: (b) C2H5NH2 > CH3NH2 > NH3 > C6H5NH2

Explanation:
1. Alkyl groups increase electron density on N, so alkylamines are stronger than ammonia.
2. Aniline is weaker because of lone-pair delocalisation, and ethyl donates slightly more than methyl.

Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.

Question 26: The correct order of increasing basicity (in water) is
(a) NH3 < C6H5NH2 < (C2H5)2NH < C2H5NH2 < (C2H5)3N
(b) C6H5NH2 < NH3 < (C2H5)3N < (C2H5)2NH < C2H5NH2
(c) C6H5NH2 < NH3 < C2H5NH2 < (C2H5)3N < (C2H5)2NH
(d) C6H5NH2 < (C2H5)3N < NH3 < C2H5NH2 < (C2H5)2NH
Show Answer & Explanation

Answer: (c) C6H5NH2 < NH3 < C2H5NH2 < (C2H5)3N < (C2H5)2NH

Explanation:
1. pKb values: aniline 9.4, ammonia 4.75, ethylamine 3.29, triethylamine 3.25, diethylamine 3.0.
2. So the increasing basicity order is aniline, ammonia, ethylamine, triethylamine, diethylamine.

Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.

Question 27: Among nitrobenzene, benzene, aniline and phenol, the strongest basic behaviour in acid medium is shown by
(a) phenol
(b) aniline
(c) nitrobenzene
(d) benzene
Show Answer & Explanation

Answer: (b) aniline

Explanation:
1. Aniline accepts a proton on N to form anilinium ion.
2. The others have no basic site.

Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.

Question 28: Aniline, on treatment with excess of bromine water, gives
(a) aniline bromide
(b) o-bromoaniline
(c) p-bromoaniline
(d) 2,4,6-tribromoaniline
Show Answer & Explanation

Answer: (d) 2,4,6-tribromoaniline

Explanation:
1. The strongly activating NH2 group makes all ortho and para positions react without a catalyst, giving a white precipitate.

Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.

Question 29: Unpleasant-smelling carbylamines are formed by heating alkali and chloroform with
(a) any amine
(b) any aliphatic amine
(c) any aromatic amine
(d) any primary amine
Show Answer & Explanation

Answer: (d) any primary amine

Explanation:
1. Primary aliphatic or aromatic amines both give isocyanides.

Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.

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