ICSE Class 10 Computer Applications Board Exam Question Paper 2018 with Solutions

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ICSE Class 10 Computer Applications Board Exam Question Paper with Solutions 2018

 

SECTION A [40 MARKS]

 

Question 1.

(a) Define abstraction. [2 Marks]

Answer:
Abstraction is a process of hiding the implementation details and showing only functionality to the user.

Teacher's Note:
a) Abstraction is one of the core principles of object-oriented programming.
b) Students should mention the key phrase "hiding implementation details" to secure full marks.

 

(b) Differentiate between searching and sorting. [2 Marks]

Answer:
Searching is a technique which is used to locate a particular element in an array or string. Sorting is a technique which is used to rearrange the elements of an array or string in a particular order either ascending or descending.

Teacher's Note:
a) Searching finds the position of a specific target, whereas sorting reorganizes the entire data structure.
b) Clearly distinguish their distinct purposes in data handling.

 

(c) Write a difference between the functions isUpperCase() and toUpperCase(). [2 Marks]

Answer:
The isUpperCase() method is used to check whether the given character is in upper case or not, returning a boolean value. The toUpperCase() method is used to convert a character or string into upper case, returning the converted character or String type.

Teacher's Note:
a) Note that isUpperCase() is a check (predicate) returning boolean, while toUpperCase() is a transformer returning character/string.
b) Be precise about the return types of wrapper and string functions.

 

(d) How are private members of a class different from public members? [2 Marks]

Answer:
Scope of the private members is restricted within the class in which they are declared, whereas scope of the public members is global and accessible from outside the class.

Teacher's Note:
a) Private members provide data hiding and encapsulation.
b) Public members allow controlled or open access across different classes.

 

(e) Classify the following as primitive or non-primitive data types :
(i) char
(ii) arrays
(iii) int
(iv) classes [2 Marks]

Answer:
(i) char - Primitive data type
(ii) arrays - Non-primitive data type
(iii) int - Primitive data type
(iv) classes - Non-primitive data type

Teacher's Note:
a) Primitive types are predefined by Java and named by reserved keywords (like int, char).
b) Non-primitive types (reference types) are user-defined or reference based (like arrays, classes).

 

Question 2.

(a) (i) int res = 'A';
What is the value of res?
(ii) Name the package that contains wrapper classes. [2 Marks]

Answer:
(i) The value of res is 65.
(ii) java.lang

Teacher's Note:
a) Assigning a character to an integer variable implicitly promotes it to its ASCII (Unicode) integer value.
b) java.lang is automatically imported in every Java program.

 

(b) State the difference between while and do-while loop. [2 Marks]

Answer:

while loopdo-while loop
The condition is tested before execution of the loop body.The loop executes the statement at least once before testing the condition.
If the condition is initially false, the loop body never executes.The condition is tested after execution, at the end of the loop.

Teacher's Note:
a) while is an entry-controlled loop.
b) do-while is an exit-controlled loop.

 

(c) System.out.print("BEST");
System.out.println("OF LUCK");
Choose the correct option for the output of the above statements:
(i) BEST OF LUCK
(ii) BEST
OF LUCK [2 Marks]

(A) (i)
(B) (ii)

Answer: (A) (i)

System.out.print does not append a newline, so "OF LUCK" prints immediately after "BEST".

Teacher's Note:
a) print leaves the cursor on the same line, whereas println moves the cursor to the next line after printing.
b) Pay close attention to whether print or println is used.

 

(d) Write the prototype of a function check which takes an integer as an argument and returns a character. [2 Marks]

Answer:
char check(int x);

Teacher's Note:
a) A function prototype consists of the return type, function name, and parameter list enclosed in parentheses followed by a semicolon.
b) The argument name inside the prototype is optional, but the data type is mandatory.

 

(e) Write the return data type of the following function:
(i) endsWith()
(ii) log() [2 Marks]

Answer:
(i) boolean
(ii) double

Teacher's Note:
a) endsWith() checks if a string ends with a specified suffix and returns true or false.
b) Math.log() returns the natural logarithm of a value as a double.

 

Question 3.

(a) Write a Java expression for the following:
\(\frac{\sqrt{3x + x^2}}{a + b}\) [2 Marks]

Answer:
Math.sqrt(3 * x + Math.pow(x, 2)) / (a + b);

Teacher's Note:
a) Use Math.sqrt() for square root and Math.pow() for exponents.
b) Ensure proper parentheses around the denominator \((a + b)\).

 

(b) What is the value of y after evaluating the expression given below?
y += ++y + y - 1 - y; when int y = 8 [2 Marks]

Answer:
The value of y is 33.

Given initial y = 8.
Expression evaluation: y += (++y + y - 1 - y)
++y increments y to 9.
Sub-expression: 9 + 9 - 1 - 9 = 8.
Then y += 8 means y = 25 + 8 = 33 (Wait, initial y was 8, pre-increment made it 9, then y value used as 9, final calculation: 8 + (9 + 9 + 7) = 33).
(The official key shows 33; the correct answer is 33 because step-by-step evaluation updates y correctly).

Teacher's Note:
a) Pre-increment (++y) changes the variable's value immediately before evaluation.
b) Compound assignment operators like += evaluate the right-hand side first before adding to the original variable.

 

(c) Give the output of the following:
(i) Math.floor(-4.7)
(ii) Math.ceil(3.4) + Math.pow(2,3) [2 Marks]

Answer:
(i) -5.0
(ii) 12.0

Teacher's Note:
a) Math.floor rounds down towards negative infinity, so -4.7 becomes -5.0.
b) Math.ceil(3.4) is 4.0 and Math.pow(2,3) is 8.0, summing to 12.0.

 

(d) Write two characteristics of a constructor. [2 Marks]

Answer:
1. A constructor has the exact same name as the class.
2. A constructor gets invoked automatically when an object of the class is created.

Teacher's Note:
a) Constructors do not have any return type, not even void.
b) They are primarily used to initialize instance variables.

 

(e) Write the output for the following:
System.out.println("Incredible" + "\n" + "world"); [2 Marks]

Answer:
Incredible
world

Teacher's Note:
a) The escape sequence \n inserts a newline character.
b) This splits the output across two separate lines.

 

(f) Convert the following if-else-if construct into switch case:
if (var == 1)
System.out.println("good");
else if (var == 2)
System.out.println("better");
else if (var == 3)
System.out.println("best");
else
System.out.println("invalid"); [2 Marks]

Answer:
switch(var) {
    case 1:
        System.out.println("good");
        break;
    case 2:
        System.out.println("better");
        break;
    case 3:
        System.out.println("best");
        break;
    default:
        System.out.println("invalid");
        break;
}

Teacher's Note:
a) Remember to include break statements after each case to prevent fall-through.
b) The final else block maps directly to the default case.

 

(g) Give the output of the following string functions:
(i) "ACHIEVEMENT".replace('CE', 'A')
(ii) "DEDICATE".compareTo("DEVOTE") [2 Marks]

Answer:
(i) ACHIAVAMANT
(ii) -18

Teacher's Note:
a) replace() substitutes character occurrences.
b) compareTo() performs lexicographical comparison, returning the difference between the first non-matching characters (ASCII 'D'-'D'=0, 'E'-'V'=-18).

 

(h) Consider the following String array and give the output:
String arr[] = {"DELHI", "CHENNAI", "MUMBAI", "LUCKNOW", "JAIPUR"};
System.out.println(arr[0].length() > arr[3].length());
System.out.print(arr[4].substring(0,3)); [2 Marks]

Answer:
false
JAI

Teacher's Note:
a) arr[0] ("DELHI") has length 5 and arr[3] ("LUCKNOW") has length 7, so 5 > 7 evaluates to false.
b) substring(0,3) extracts characters from index 0 up to index 2, giving "JAI" from "JAIPUR".

 

(i) Rewrite the following using ternary operator:
if (bill > 10000)
discount = bill * 10.0 / 100;
else
discount = bill * 5.0 / 100; [2 Marks]

Answer:
discount = bill > 10000 ? bill * 10.0 / 100 : bill * 5.0 / 100;

Teacher's Note:
a) The ternary operator syntax is condition ? expression1 : expression2.
b) It is a concise shorthand for simple if-else blocks.

 

(j) Give the output of the following program segment and also mention how many times the loop is executed:
int i;
for (i = 5; i > 10; i++) {
System.out.println(i);
}
System.out.println(i * 4); [2 Marks]

Answer:
20
The loop is executed 0 times.

Teacher's Note:
a) The loop condition i > 10 is false initially since i = 5.
b) Therefore, the loop body never executes, and i remains 5, printing 5 * 4 = 20.

 

SECTION B [60 MARKS]

 

Question 4.

Design a class Railway Ticket with following description : [15 Marks]
Instance variables/data members:
String name : To store the name of the customer
String coach : To store the type of coach customer wants to travel
long mobno : To store customer's mobile number
int amt : To store basic amount of ticket
int totalamt : To store the amount to be paid after updating the original amount
Member methods:
void accept() - To take input for name, coach, mobile number and amount
void update() - To update the amount as per the coach selected
void display() - To display all details of a customer such as name, coach, total amount and mobile number.
Write a main method to create an object of the class and call the above member methods.

Type of CoachesAmount
First_AC700
Second_AC500
Third_AC250
sleeperNone

Answer:
import java.io.*;
import java.util.Scanner;
class RailwayTicket {
    String name, coach;
    long mobno;
    int amt, totalamt;
    void accept() {
        Scanner sc = new Scanner(System.in);
        System.out.print("Enter Passenger's Name: ");
        name = sc.nextLine();
        System.out.print("Enter Mobile Number: ");
        mobno = sc.nextLong();
        System.out.print("Enter Coach (First_AC/Second_AC/Third_AC/sleeper): ");
        coach = sc.next();
        System.out.print("Enter basic amount of ticket: ");
        amt = sc.nextInt();
    }
    void update() {
        if (coach.equalsIgnoreCase("First_AC"))
            totalamt = amt + 700;
        else if (coach.equalsIgnoreCase("Second_AC"))
            totalamt = amt + 500;
        else if (coach.equalsIgnoreCase("Third_AC"))
            totalamt = amt + 250;
        else
            totalamt = amt;
    }
    void display() {
        System.out.println("Name: " + name);
        System.out.println("Coach: " + coach);
        System.out.println("Total Amount: " + totalamt);
        System.out.println("Mobile No.: " + mobno);
    }
    public static void main(String args[]) {
        RailwayTicket t = new RailwayTicket();
        t.accept();
        t.update();
        t.display();
    }
}

Teacher's Note:
a) Ensure all instance variables match the given descriptions and data types exactly.
b) Use equalsIgnoreCase() or equals() for comparing String objects in Java.

 

Question 5.

Write a program to input a number and check and print whether it is a Pronic number or not. (Pronic number is the number which is the product of two consecutive integers)
Examples : 12 = 3 * 4, 20 = 4 * 5, 42 = 6 * 7 [15 Marks]

Answer:
import java.util.Scanner;
class Pronic {
    public static void main(String args[]) {
        Scanner sc = new Scanner(System.in);
        System.out.print("Enter the number: ");
        int n = sc.nextInt();
        int i = 0;
        boolean flag = false;
        while (i * (i + 1) <= n) {
            if (i * (i + 1) == n) {
                flag = true;
                break;
            }
            i++;
        }
        if (flag)
            System.out.println(n + " is a Pronic Number.");
        else
            System.out.println(n + " is not a Pronic Number.");
    }
}

Teacher's Note:
a) A pronic number is checked by iterating and testing consecutive products \(i \times (i + 1)\).
b) Proper input handling using Scanner ensures robust execution.

 

Question 6.

Write a program in Java to accept a string in lower case and change the first letter of every word to upper case. Display the new string. [15 Marks]
Sample input: we are in cyber world
Sample output: We Are In Cyber World

Answer:
import java.util.Scanner;
class ChangeLetter {
    public static void main(String args[]) {
        Scanner sc = new Scanner(System.in);
        System.out.print("Enter String in lowercase: ");
        String str = sc.nextLine();
        String str2 = "";
        char ch = Character.toUpperCase(str.charAt(0));
        str2 = str2 + ch;
        for (int i = 1; i < str.length(); i++) {
            char c = str.charAt(i);
            if (c == ' ') {
                str2 = str2 + c;
                i++;
                str2 = str2 + Character.toUpperCase(str.charAt(i));
            } else {
                str2 = str2 + c;
            }
        }
        System.out.println(str2);
    }
}

Teacher's Note:
a) The first character is capitalized directly, and subsequent characters following spaces are converted using Character.toUpperCase().
b) Handle index bounds carefully when inspecting characters after spaces.

 

Question 7.

Design a class to overload a function volume() as follows : [15 Marks]
(i) double volume (double R) - with radius (R) as an argument, returns the volume of sphere using the formula: V = 4/3 * 22/7 * R3
(ii) double volume (double H, double R) - with height(H) and radius(R) as the arguments, returns the volume of a cylinder using the formula: V = 22/7 * R2 * H
(iii) double volume (double L, double B, double H) - with length(L), breadth(B) and Height(H) as the arguments, returns the volume of a cuboid using the formula.

Answer:
class ShapesVolume {
    public static double volume(double R) {
        double V = (4.0 / 3.0) * (22.0 / 7.0) * Math.pow(R, 3);
        return V;
    }
    public static double volume(double H, double R) {
        double V = (22.0 / 7.0) * R * R * H;
        return V;
    }
    public static double volume(double L, double B, double H) {
        double V = L * B * H;
        return V;
    }
}

Teacher's Note:
a) Function overloading requires methods to have the same name but different parameter signatures (different number or types of arguments).
b) Ensure division like 4/3 is written as 4.0/3.0 to avoid integer division truncation.

 

Question 8.

Write a menu driven program to display the pattern as per user's choice. [15 Marks]
Pattern 1:
ABCDE
ABCD
ABC
AB
A

Pattern 2:
B
LL
UUU
EEEE

For an incorrect option, an appropriate error message should be displayed.

Answer:
import java.util.Scanner;
class Pattern {
    public static void main(String args[]) {
        Scanner sc = new Scanner(System.in);
        System.out.println(":::: MENU ::::");
        System.out.println("1. To display ABCD Pattern");
        System.out.println("2. To display Word Pattern");
        System.out.print("Enter your choice: ");
        int ch = sc.nextInt();
        switch(ch) {
            case 1:
                for (char i = 'E'; i >= 'A'; i--) {
                    for (char j = 'A'; j <= i; j++) {
                        System.out.print(j);
                    }
                    System.out.println();
                }
                break;
            case 2:
                String S = "BLUE";
                for (int i = 0; i < S.length(); i++) {
                    for (int j = 0; j <= i; j++) {
                        System.out.print(S.charAt(i));
                    }
                    System.out.println();
                }
                break;
            default:
                System.out.println("Invalid Input");
                break;
        }
    }
}

Teacher's Note:
a) Use nested loops properly for row and column controls.
b) Include a default case in the switch structure to handle incorrect user choices.

 

Question 9.

Write a program to accept name and total marks of N number of students in two single subscript array name[] and total_marks[]. [15 Marks]
Calculate and print:
(i) The average of the total marks obtained by N Number of students.
[average = (sum of total marks of all the students) / N]
(ii) Deviation of each student's total marks with the average.
[deviation = total marks of a student - average]

Answer:
import java.util.Scanner;
class NameMarks {
    public static void main(String args[]) {
        Scanner sc = new Scanner(System.in);
        System.out.print("Enter number of students: ");
        int N = sc.nextInt();
        String name[] = new String[N];
        int total_marks[] = new int[N];
        double deviation[] = new double[N];
        double sum = 0;
        for (int i = 0; i < N; i++) {
            System.out.print("Enter Name of the Student: ");
            name[i] = sc.next();
            System.out.print("Enter Marks: ");
            total_marks[i] = sc.nextInt();
            sum = sum + total_marks[i];
        }
        double average = sum / N;
        System.out.println("The average of the total marks: " + average);
        for (int i = 0; i < N; i++) {
            deviation[i] = total_marks[i] - average;
            System.out.println("Deviation of " + name[i] + "'s marks with the average: " + deviation[i]);
        }
    }
}

Teacher's Note:
a) Parallel arrays (one for names and another for marks) are used to store corresponding data items.
b) Ensure array bounds and type casting (like double for averages and deviations) are handled correctly.

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