Class 10 Chemistry Chapter 05 Mole Concept and Stoichiometry: ICSE Study Material
Review the ICSE Class 10 Chemistry Chapter 05 Mole Concept and Stoichiometry designed for Class 10 Chemistry students. Published under the latest ICSE guidelines for 2026-27, this chapter-wise resource supports daily study and targeted revision.
Read and Download Chapter 05 Mole Concept and Stoichiometry
View or download the dedicated Chapter 05 Mole Concept and Stoichiometry resource below. This chapter-by-chapter structuring ensures easy navigation for daily study routines. For comprehensive exam preparation, pair this reading with our verified ICSE Solutions.
Chapter 5: Mole Concept and Stoichiometry
Important Points to Remember
1. Gay Lussac's law - whenever the gases combine chemically, they do so in volumes which bear a simple ratio to each other as well as to the product if gaseous, under the same conditions of temperature and pressure.
2. Gay Lussac published the result of his experiment on different gases under the name: "The Law of Combining Volumes of Gases".
3. Gay Lussac's law is applicable only to gases and not to solids and liquids.
4. Atomic weight is the number which represents how many times one atom of a substance is heavier than 1/12th the mass of an atom of Carbon -12.
5. Molecular weight is the number which represents how many times one molecule of a substance is heavier than 1/12th the mass of an atom of Carbon -12.
6. Molecular weight expressed in grams is called gram molecular weight.
7. Avogadro's Law - According to Avogadro, under the similar conditions of temperature and pressure, equal volumes of all gases contain equal number of molecules.
8. The volume occupied by one mole of a gas at S.T.P. (Standard Temperature and Pressure) is called molar volume. It is equal to 22.4 dm³ or 22.4 litres.
9. The gram molecular weight of all gases at S.T.P. contains molecules equal to Avogadro's number which is 6.023 × 10²³ and it occupies a volume equal to molar volume which is 22.4 dm³ or 22.4 litres.
10. Number of moles = \[\frac{\text{Weight in grams of the substance}(W)}{\text{Molecular weight of the substance}(M)}\]
Or \[n = \frac{W}{M}\]
11. Number of molecules = No. of moles × Avogadro's number
12. The relationship between mole, gram molecular weight, molar volume, and number of molecules can be summarized as follows:
| S. No. | Name of the Gas | Mole | Gram Molecular Weight | Number of Molecules | Molar Volume |
|---|---|---|---|---|---|
| (1) | O₂ | 1 mole | 32 g | 6.023×10²³ | 22.4 litres |
| (2) | N₂ | 1 mole | 28 g | 6.023×10²³ | 22.4 litres |
| (3) | H₂ | 1 mole | 2 g | 6.023×10²³ | 22.4 litres |
| (4) | CO₂ | 1 mole | 44 g | 6.023×10²³ | 22.4 litres |
13. Atomicity is the number of atoms present in one molecule of an element.
14. Metals are monoatomic, i.e., containing one atom in its molecule.
Teacher's Note
When you bake a cake, the leavening agent (baking soda) reacts in precise proportions - just like how gases combine in simple volume ratios according to Gay-Lussac's law, showing how chemistry's laws help recipes work perfectly every time.
Continuation of Important Points
15. Inert gases are monoatomic.
16. Gases like Hydrogen (H₂), Oxygen (O₂), Nitrogen (N₂) are diatomic, i.e., containing two atoms in its molecule.
17. The elements containing more than two atoms in its molecule are called as polyatomic. Example - Ozone: O₃, Phosphorus: P₄, Sulphur: S₈
18. Vapour density is the ratio between the mass of certain volume of gas or vapour to the mass of same volume of hydrogen under the similar conditions of temperature and pressure.
\[\text{Vapour density} = \frac{\text{Mass of certain volume of gas or vapour}}{\text{Mass of same volume of Hydrogen}}\]
19. Vapour density is a ratio, so it has no units.
20. \[\text{Molecular weight} = 2 \times \text{Vapour density}\]
21. The percentage composition of a compound is defined as the percentage by weight of each element present in the molecule of a compound.
\[\text{Percentage composition of a compound} = \frac{\text{Weight of an element in a molecule of a compound}}{\text{Gram molecular weight of compound}} \times 100\]
22. Empirical formula is the formula of a chemical substance which tells the simplest whole number ratio of the atoms of different elements present in its one molecule.
23. Molecular formula is the formula of a chemical substance which represents the actual number of atoms of each element present in its single molecule.
24. In a chemical equation, reactants are written on the left side of the arrow and products are written on the right side of the arrow.
Reactants - Products
25. For the calculation of the numericals based on equation, the equation must be completely balanced.
26. The molecular weights of the products and reactants must be calculated which are required for solving the numerical.
27. Unitary Method is used to find the weight of product or reactant as per the requirement of the problem.
28. In case of gases, the volume required is 22.4 dm³ for every mole of a gas.
\[\text{Relative Atomic Mass} = \frac{\text{Mass of one atom of an element}}{\text{1/12th of mass of an atom of carbon-12}}\]
29. Relative atomic mass can also be defined with respect to hydrogen. It is the number that represents, how many times one atom of an element is heavier than one atom of hydrogen, whose weight has been taken as unity.
\[\text{Relative Atomic Mass} = \frac{\text{Mass of one atom of an element}}{\text{Mass of one atom of hydrogen (weight taken as unity)}}\]
30. The relative atomic mass of an element expressed in grams is called gram atomic mass or gram atom.
31. \[\text{Relative Molecular Mass} = \frac{\text{Mass of one molecule of a substance}}{\text{Mass of 1/12 th of an atom of C-12}}\]
32. Relative molecular mass can also be defined with respect to hydrogen. It is the number that represents how many times one molecule of a substance is heavier than one atom of hydrogen whose weight is taken as unity.
Teacher's Note
Understanding molecular formulas helps us determine exactly how much medicine to prescribe - the ratio of atoms in a drug molecule determines its effectiveness and safety, showing how chemistry directly impacts healthcare decisions.
This is a preview of the first 3 pages. To get the complete book, click below.
Free study material for Chemistry
Chapter 05 Mole Concept and Stoichiometry Digital Textbook & Resources for Class 10 Chemistry
Download Textbook: Chapter 05 Mole Concept and Stoichiometry (Class 10 Chemistry)
Access the official ICSE Textbook for Class 10 Chemistry Chapter 05 Mole Concept and Stoichiometry, updated for the current academic session. Recognized as the core reading material across schools nationwide, board evaluations rely entirely on this syllabus.
Complete Chapter E-Books for Class 10 Chemistry
Browse our comprehensive suite of ICSE books in English Medium designed for Class 10 students, offering clear conceptual breakdowns and concluding practice problems.
Maximize Conceptual Clarity with ICSE E-Books
Elevate your study routine by reviewing our comprehensive NCERT Solutions and revision notes available on our platform free of charge.
FAQs
You can download the latest, teacher-verified PDF for ICSE Class 10 Chemistry Chapter 05 Mole Concept and Stoichiometry for free on StudiesToday.com. These digital editions are updated as per 2026-27 session and are optimized for mobile reading.
Yes, our collection of Class 10 Chemistry ICSE books follow the 2026 rationalization guidelines. All deleted chapters have been removed and has latest content for you to study.
Downloading chapter-wise PDFs for Class 10 Chemistry allows for faster access, saves storage space, and makes it easier to focus in 2026 on specific topics during revision.
ICSE books are the main source for ICSE exams. By reading ICSE Class 10 Chemistry Chapter 05 Mole Concept and Stoichiometry line-by-line and practicing its questions, students build strong understanding to get full marks in Chemistry.