GSEB Class 8 Maths Solutions Chapter 1 સંમેય સંખ્યાઓ Exercise 1.2

Get the most accurate GSEB Solutions for Class 8 Mathematics Chapter 01 સંમેય સંખ્યાઓ here. Updated for the 2026-27 academic session, these solutions are based on the latest GSEB textbooks for Class 8 Mathematics. Our expert-created answers for Class 8 Mathematics are available for free download in PDF format.

Detailed Chapter 01 સંમેય સંખ્યાઓ GSEB Solutions for Class 8 Mathematics

For Class 8 students, solving GSEB textbook questions is the most effective way to build a strong conceptual foundation. Our Class 8 Mathematics solutions follow a detailed, step-by-step approach to ensure you understand the logic behind every answer. Practicing these Chapter 01 સંમેય સંખ્યાઓ solutions will improve your exam performance.

Class 8 Mathematics Chapter 01 સંમેય સંખ્યાઓ GSEB Solutions PDF

Exercise 1.2

 

Question 1. Represent these numbers on the number line.
1. \( \frac { 7 }{ 4 } \)
2. \( \frac { -5 }{ 6 } \)
Answer:
(i) To represent \( \frac { 7 }{ 4 } \), we make 7 markings each at a distance equal to \( \frac { 1 }{ 4 } \) on the right of 0. The 7th point represents the rational number \( \frac { 7 }{ 4 } \).
(ii) To represent \( \frac { -5 }{ 6 } \) on the number line, we make 5 markings each at a distance equal to \( \frac { 1 }{ 6 } \) on the left of 0. We consider the 5th point.
In simple words: To show a fraction on a number line, divide the space between whole numbers into equal parts based on the denominator, then count the steps from zero.

Exam Tip: Always ensure your markings are equally spaced to maintain accuracy on the number line.

 

Question 2. Represent \( \frac { -2 }{ 11 } \), \( \frac { -5 }{ 11 } \), \( \frac { -9 }{ 11 } \) on the number line.
Answer: To represent \( \frac { -2 }{ 11 } \), \( \frac { -5 }{ 11 } \), and \( \frac { -9 }{ 11 } \) on a number line, we make 11 markings each being equal to a distance of \( \frac { 1 }{ 11 } \) on the left of 0. The points are marked accordingly on the left side of zero.
In simple words: Since these are negative fractions, count the required number of steps to the left of zero on a line divided into 11 parts.

Exam Tip: Label the points clearly as A, B, and C to correspond with the given fractions for better presentation.

 

Question 3. Write five rational numbers which are smaller than 2.
Answer: There can be unlimited rational numbers smaller than 2. Five of them are: 0, -1, \( \frac { 1 }{ 2 } \), \( \frac { 1 }{ 4 } \), 1.
In simple words: Any number to the left of 2 on the number line is smaller than 2.

Exam Tip: You can choose any simple integers or fractions as long as they are less than 2.

 

Question 4. Find ten rational numbers between \( \frac { -2 }{ 5 } \) and \( \frac { 1 }{ 2 } \).
Answer: To convert \( \frac { -2 }{ 5 } \) and \( \frac { 1 }{ 2 } \) to have the same denominators:
We have \( \frac { -2 }{ 5 } = \frac{-2 \times 4}{5 \times 4} = \frac { -8 }{ 20 } \) and \( \frac { 1 }{ 2 } = \frac{1 \times 10}{2 \times 10} = \frac { 10 }{ 20 } \).
The rational numbers between \( \frac { -8 }{ 20 } \) and \( \frac { 10 }{ 20 } \) are \( \frac { 9 }{ 20 } \), \( \frac { 8 }{ 20 } \), \( \frac { 7 }{ 20 } \), \( \frac { 6 }{ 20 } \), \( \frac { 5 }{ 20 } \), \( \frac { 4 }{ 20 } \), \( \frac { 3 }{ 20 } \), \( \frac { 2 }{ 20 } \), \( \frac { 1 }{ 20 } \), 0.
In simple words: Make the denominators the same first, then pick any ten numbers that fall between the two new numerators.

Exam Tip: Converting to a common denominator is the most reliable method to find multiple rational numbers between two fractions.

 

Question 5. Find five rational numbers between:
1. \( \frac { 2 }{ 3 } \) and \( \frac { 4 }{ 5 } \)
2. \( \frac { -3 }{ 2 } \) and \( \frac { 5 }{ 3 } \)
3. \( \frac { 1 }{ 4 } \) and \( \frac { 1 }{ 2 } \)
Answer:
(i) Converting \( \frac { 2 }{ 3 } \) and \( \frac { 4 }{ 5 } \) to have the same denominator: \( \frac { 2 }{ 3 } = \frac { 40 }{ 60 } \) and \( \frac { 4 }{ 5 } = \frac { 48 }{ 60 } \). Five rational numbers are \( \frac { 41 }{ 60 } \), \( \frac { 42 }{ 60 } \), \( \frac { 43 }{ 60 } \), \( \frac { 44 }{ 60 } \), \( \frac { 45 }{ 60 } \).
(ii) Converting \( \frac { -3 }{ 2 } \) and \( \frac { 5 }{ 3 } \) to have the same denominator: \( \frac { -3 }{ 2 } = \frac { -9 }{ 6 } \) and \( \frac { 5 }{ 3 } = \frac { 10 }{ 6 } \). Five rational numbers are \( \frac { -8 }{ 6 } \), \( \frac { -7 }{ 6 } \), \( \frac { -6 }{ 6 } \), \( \frac { -5 }{ 6 } \), \( \frac { -4 }{ 6 } \).
(iii) Converting \( \frac { 1 }{ 4 } \) and \( \frac { 1 }{ 2 } \) to have the same denominator: \( \frac { 1 }{ 4 } = \frac { 8 }{ 32 } \) and \( \frac { 1 }{ 2 } = \frac { 16 }{ 32 } \). Five rational numbers are \( \frac { 9 }{ 32 } \), \( \frac { 10 }{ 32 } \), \( \frac { 11 }{ 32 } \), \( \frac { 12 }{ 32 } \), \( \frac { 13 }{ 32 } \).
In simple words: Find a common denominator for both fractions, then list the numbers that appear between the two resulting fractions.

Exam Tip: If you cannot find enough numbers, multiply the numerator and denominator by a larger factor to increase the gap.

 

Question 6. Write five rational numbers greater than – 2.
Answer: Five rational numbers greater than – 2 are: \( \frac { -3 }{ 2 } \), -1, \( \frac { -1 }{ 2 } \), 0, \( \frac { 1 }{ 2 } \).
In simple words: Any number to the right of -2 on the number line is greater than -2.

Exam Tip: Remember that for negative numbers, a smaller absolute value means the number is actually larger.

 

Question 7. Find the rational numbers between \( \frac { 3 }{ 5 } \) and \( \frac { 3 }{ 4 } \).
Answer: Converting \( \frac { 3 }{ 5 } \) and \( \frac { 3 }{ 4 } \) to have common denominators: \( \frac { 3 }{ 5 } = \frac { 3 \times 20 }{ 5 \times 20 } = \frac { 60 }{ 100 } \) and \( \frac { 3 }{ 4 } = \frac { 3 \times 25 }{ 4 \times 25 } = \frac { 75 }{ 100 } \). The rational numbers between them are \( \frac { 61 }{ 100 } \), \( \frac { 62 }{ 100 } \), \( \frac { 63 }{ 100 } \), \( \frac { 64 }{ 100 } \), \( \frac { 65 }{ 100 } \).
In simple words: By making the denominators 100, we can easily see the numbers that lie between 60/100 and 75/100.

Exam Tip: Always show the conversion steps clearly to demonstrate how you arrived at the common denominator.

Free study material for Mathematics

GSEB Solutions Class 8 Mathematics Chapter 01 સંમેય સંખ્યાઓ

Students can now access the GSEB Solutions for Chapter 01 સંમેય સંખ્યાઓ prepared by teachers on our website. These solutions cover all questions in exercise in your Class 8 Mathematics textbook. Each answer is updated based on the current academic session as per the latest GSEB syllabus.

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FAQs

Where can I find the latest GSEB Class 8 Maths Solutions Chapter 1 સંમેય સંખ્યાઓ Exercise 1.2 for the 2026-27 session?

The complete and updated GSEB Class 8 Maths Solutions Chapter 1 સંમેય સંખ્યાઓ Exercise 1.2 is available for free on StudiesToday.com. These solutions for Class 8 Mathematics are as per latest GSEB curriculum.

Are the Mathematics GSEB solutions for Class 8 updated for the new 50% competency-based exam pattern?

Yes, our experts have revised the GSEB Class 8 Maths Solutions Chapter 1 સંમેય સંખ્યાઓ Exercise 1.2 as per 2026 exam pattern. All textbook exercises have been solved and have added explanation about how the Mathematics concepts are applied in case-study and assertion-reasoning questions.

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Is it possible to download the Mathematics GSEB solutions for Class 8 as a PDF?

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