GSEB Class 7 Maths Solutions Chapter 2 Fractions and Decimals Exercise 2.4

Get the most accurate GSEB Solutions for Class 7 Mathematics Chapter 02 Fractions and Decimals here. Updated for the 2026-27 academic session, these solutions are based on the latest GSEB textbooks for Class 7 Mathematics. Our expert-created answers for Class 7 Mathematics are available for free download in PDF format.

Detailed Chapter 02 Fractions and Decimals GSEB Solutions for Class 7 Mathematics

For Class 7 students, solving GSEB textbook questions is the most effective way to build a strong conceptual foundation. Our Class 7 Mathematics solutions follow a detailed, step-by-step approach to ensure you understand the logic behind every answer. Practicing these Chapter 02 Fractions and Decimals solutions will improve your exam performance.

Class 7 Mathematics Chapter 02 Fractions and Decimals GSEB Solutions PDF

 

Question 1. Find:
(i) \( 12 \div \frac { 3 }{ 4 } \)
(ii) \( 14 \div \frac { 5 }{ 6 } \)
(iii) \( 8 \div \frac { 7 }{ 3 } \)
(iv) \( 4 \div \frac { 8 }{ 3 } \)
(v) \( 3 \div 2\frac { 1 }{ 3 } \)
(vi) \( 5 \div 3\frac { 4 }{ 7 } \)
Answer:
(i) \( 12 \div \frac { 3 }{ 4 } = 12 \times \frac { 4 }{ 3 } = \frac { 4 \times 4 }{ 1 } = 16 \)
(ii) \( 14 \div \frac { 5 }{ 6 } = 14 \times \frac { 6 }{ 5 } = \frac { 14 \times 6 }{ 5 } = \frac { 84 }{ 5 } = 16\frac { 4 }{ 5 } \)
(iii) \( 8 \div \frac { 7 }{ 3 } = 8 \times \frac { 3 }{ 7 } = \frac { 8 \times 3 }{ 7 } = \frac { 24 }{ 7 } = 3\frac { 3 }{ 7 } \)
(iv) \( 4 \div \frac { 8 }{ 3 } = 4 \times \frac { 3 }{ 8 } = \frac { 1 \times 3 }{ 2 } = \frac { 3 }{ 2 } = 1\frac { 1 }{ 2 } \)
(v) \( 3 \div 2\frac { 1 }{ 3 } = 3 \div \frac { 7 }{ 3 } = 3 \times \frac { 3 }{ 7 } = \frac { 9 }{ 7 } = 1\frac { 2 }{ 7 } \)
(vi) \( 5 \div 3\frac { 4 }{ 7 } = 5 \div \frac { 25 }{ 7 } = 5 \times \frac { 7 }{ 25 } = \frac { 7 }{ 5 } = 1\frac { 2 }{ 5 } \)
In simple words: To divide by a fraction, you flip the second fraction upside down (find its reciprocal) and then multiply. If you have a mixed number, change it to an improper fraction first before flipping.

Exam Tip: Remember to convert any mixed numbers into improper fractions before finding the reciprocal or performing division. Simplification should always be the last step.

 

Question 2. Find the reciprocal of each of the following fractions. Classify the reciprocals as proper fractions, improper fractions and whole numbers.
(i) \( \frac { 3 }{ 7 } \)
(ii) \( \frac { 5 }{ 8 } \)
(iii) \( \frac { 9 }{ 7 } \)
(iv) \( \frac { 6 }{ 5 } \)
(v) \( \frac { 12 }{ 7 } \)
(vi) \( \frac { 1 }{ 8 } \)
(vii) \( \frac { 1 }{ 11 } \)
Answer:
(i) The reciprocal of \( \frac { 3 }{ 7 } \) is \( \frac { 7 }{ 3 } \); (improper fraction)
(ii) The reciprocal of \( \frac { 5 }{ 8 } \) is \( \frac { 8 }{ 5 } \); (improper fraction)
(iii) The reciprocal of \( \frac { 9 }{ 7 } \) is \( \frac { 7 }{ 9 } \); (proper fraction)
(iv) The reciprocal of \( \frac { 6 }{ 5 } \) is \( \frac { 5 }{ 6 } \); (proper fraction)
(v) The reciprocal of \( \frac { 12 }{ 7 } \) is \( \frac { 7 }{ 12 } \); (proper fraction)
(vi) The reciprocal of \( \frac { 1 }{ 8 } \) is 8; (whole number)
(vii) The reciprocal of \( \frac { 1 }{ 11 } \) is 11; (whole number)
In simple words: To find the reciprocal of a fraction, just flip the top and bottom numbers. Then, check if the new fraction has a bigger top number (improper), a smaller top number (proper), or is a whole number.

Exam Tip: A proper fraction has a numerator smaller than its denominator. An improper fraction has a numerator larger than or equal to its denominator. If the denominator is 1, it's a whole number.

 

Question 3. Find:
(i) \( \frac { 7 }{ 3 } \div 2 \)
(ii) \( \frac { 4 }{ 9 } \div 5 \)
(iii) \( \frac { 6 }{ 13 } \div 7 \)
(iv) \( 4\frac { 1 }{ 3 } \div 3 \)
(v) \( 3\frac { 1 }{ 2 } \div 4 \)
(vi) \( 4\frac { 4 }{ 7 } \div 7 \)
Answer:
(i) \( \frac { 7 }{ 3 } \div 2 = \frac { 7 }{ 3 } \times \frac { 1 }{ 2 } = \frac { 7 }{ 6 } \)
(ii) \( \frac { 4 }{ 9 } \div 5 = \frac { 4 }{ 9 } \times \frac { 1 }{ 5 } = \frac { 4 }{ 45 } \)
(iii) \( \frac { 6 }{ 13 } \div 7 = \frac { 6 }{ 13 } \times \frac { 1 }{ 7 } = \frac { 6 }{ 91 } \)
(iv) \( 4\frac { 1 }{ 3 } \div 3 = \frac { 13 }{ 3 } \div 3 = \frac { 13 }{ 3 } \times \frac { 1 }{ 3 } = \frac { 13 }{ 9 } = 1\frac { 4 }{ 9 } \)
(v) \( 3\frac { 1 }{ 2 } \div 4 = \frac { 7 }{ 2 } \div 4 = \frac { 7 }{ 2 } \times \frac { 1 }{ 4 } = \frac { 7 }{ 8 } \)
(vi) \( 4\frac { 4 }{ 7 } \div 7 = \frac { 31 }{ 7 } \div 7 = \frac { 31 }{ 7 } \times \frac { 1 }{ 7 } = \frac { 31 }{ 49 } \)
In simple words: When you divide a fraction by a whole number, remember that the whole number can be written as a fraction with 1 under it. Then, flip that whole number fraction and multiply.

Exam Tip: Always remember that dividing by a number is the same as multiplying by its reciprocal. This is a fundamental concept in fraction arithmetic.

 

Question 4. Find:
(i) \( \frac { 2 }{ 5 } \div \frac { 1 }{ 2 } \)
(ii) \( \frac { 4 }{ 9 } \div \frac { 2 }{ 3 } \)
(iii) \( \frac { 3 }{ 7 } \div \frac { 8 }{ 7 } \)
(iv) \( 2\frac { 1 }{ 3 } \div \frac { 3 }{ 5 } \)
(v) \( 3\frac { 1 }{ 2 } \div \frac { 8 }{ 3 } \)
(vi) \( 2\frac { 2 }{ 5 } \div 1\frac { 1 }{ 2 } \)
(vii) \( 3\frac { 1 }{ 5 } \div 1\frac { 2 }{ 3 } \)
(viii) \( 2\frac { 1 }{ 5 } \div 1\frac { 1 }{ 5 } \)
Answer:
(i) \( \frac { 2 }{ 5 } \div \frac { 1 }{ 2 } = \frac { 2 }{ 5 } \times \frac { 2 }{ 1 } = \frac { 2 \times 2 }{ 5 \times 1 } = \frac { 4 }{ 5 } \)
(ii) \( \frac { 4 }{ 9 } \div \frac { 2 }{ 3 } = \frac { 4 }{ 9 } \times \frac { 3 }{ 2 } = \frac { 2 \times 1 }{ 3 \times 1 } = \frac { 2 }{ 3 } \)
(iii) \( \frac { 3 }{ 7 } \div \frac { 8 }{ 7 } = \frac { 3 }{ 7 } \times \frac { 7 }{ 8 } = \frac { 3 \times 1 }{ 1 \times 8 } = \frac { 3 }{ 8 } \)
(iv) \( 2\frac { 1 }{ 3 } \div \frac { 3 }{ 5 } = \frac { 7 }{ 3 } \div \frac { 3 }{ 5 } = \frac { 7 }{ 3 } \times \frac { 5 }{ 3 } = \frac { 35 }{ 9 } = 3\frac { 8 }{ 9 } \)
(v) \( 3\frac { 1 }{ 2 } \div \frac { 8 }{ 3 } = \frac { 7 }{ 2 } \div \frac { 8 }{ 3 } = \frac { 7 }{ 2 } \times \frac { 3 }{ 8 } = \frac { 21 }{ 16 } = 1\frac { 5 }{ 16 } \)
(vi) \( 2\frac { 2 }{ 5 } \div 1\frac { 1 }{ 2 } = \frac { 12 }{ 5 } \div \frac { 3 }{ 2 } = \frac { 12 }{ 5 } \times \frac { 2 }{ 3 } = \frac { 4 \times 2 }{ 5 \times 1 } = \frac { 8 }{ 5 } = 1\frac { 3 }{ 5 } \)
(vii) \( 3\frac { 1 }{ 5 } \div 1\frac { 2 }{ 3 } = \frac { 16 }{ 5 } \div \frac { 5 }{ 3 } = \frac { 16 }{ 5 } \times \frac { 3 }{ 5 } = \frac { 48 }{ 25 } = 1\frac { 23 }{ 25 } \)
(viii) \( 2\frac { 1 }{ 5 } \div 1\frac { 1 }{ 5 } = \frac { 11 }{ 5 } \div \frac { 6 }{ 5 } = \frac { 11 }{ 5 } \times \frac { 5 }{ 6 } = \frac { 11 }{ 6 } = 1\frac { 5 }{ 6 } \)
In simple words: When dividing two fractions, simply flip the second fraction (find its reciprocal) and then multiply them together. If you have mixed numbers, convert them into improper fractions first.

Exam Tip: After multiplying fractions, always look for opportunities to simplify the resulting fraction by canceling common factors in the numerator and denominator before converting to a mixed number if needed.

Free study material for Mathematics

GSEB Solutions Class 7 Mathematics Chapter 02 Fractions and Decimals

Students can now access the GSEB Solutions for Chapter 02 Fractions and Decimals prepared by teachers on our website. These solutions cover all questions in exercise in your Class 7 Mathematics textbook. Each answer is updated based on the current academic session as per the latest GSEB syllabus.

Detailed Explanations for Chapter 02 Fractions and Decimals

Our expert teachers have provided step-by-step explanations for all the difficult questions in the Class 7 Mathematics chapter. Along with the final answers, we have also explained the concept behind it to help you build stronger understanding of each topic. This will be really helpful for Class 7 students who want to understand both theoretical and practical questions. By studying these GSEB Questions and Answers your basic concepts will improve a lot.

Benefits of using Mathematics Class 7 Solved Papers

Using our Mathematics solutions regularly students will be able to improve their logical thinking and problem-solving speed. These Class 7 solutions are a guide for self-study and homework assistance. Along with the chapter-wise solutions, you should also refer to our Revision Notes and Sample Papers for Chapter 02 Fractions and Decimals to get a complete preparation experience.

FAQs

Where can I find the latest GSEB Class 7 Maths Solutions Chapter 2 Fractions and Decimals Exercise 2.4 for the 2026-27 session?

The complete and updated GSEB Class 7 Maths Solutions Chapter 2 Fractions and Decimals Exercise 2.4 is available for free on StudiesToday.com. These solutions for Class 7 Mathematics are as per latest GSEB curriculum.

Are the Mathematics GSEB solutions for Class 7 updated for the new 50% competency-based exam pattern?

Yes, our experts have revised the GSEB Class 7 Maths Solutions Chapter 2 Fractions and Decimals Exercise 2.4 as per 2026 exam pattern. All textbook exercises have been solved and have added explanation about how the Mathematics concepts are applied in case-study and assertion-reasoning questions.

How do these Class 7 GSEB solutions help in scoring 90% plus marks?

Toppers recommend using GSEB language because GSEB marking schemes are strictly based on textbook definitions. Our GSEB Class 7 Maths Solutions Chapter 2 Fractions and Decimals Exercise 2.4 will help students to get full marks in the theory paper.

Do you offer GSEB Class 7 Maths Solutions Chapter 2 Fractions and Decimals Exercise 2.4 in multiple languages like Hindi and English?

Yes, we provide bilingual support for Class 7 Mathematics. You can access GSEB Class 7 Maths Solutions Chapter 2 Fractions and Decimals Exercise 2.4 in both English and Hindi medium.

Is it possible to download the Mathematics GSEB solutions for Class 7 as a PDF?

Yes, you can download the entire GSEB Class 7 Maths Solutions Chapter 2 Fractions and Decimals Exercise 2.4 in printable PDF format for offline study on any device.