GSEB Class 6 Maths Solutions Chapter 8 Decimals Exercise 8.5

Gujarat Board Textbook Solutions Class 6 Maths Chapter 8 Decimals Ex 8.5

 

Question 1. Find the sum in each of the following:
(a) 0.007 + 8.5 + 30.08
(b) 15 + 0.632 + 13.8
(c) 27.076 + 0.55 + 0.004
(d) 25.65 + 9.005 + 3.7
(e) 0.75 + 10.425 + 2
(f) 280.69 + 25.2 + 38
Answer:
(a) 0.007 + 8.5 + 30.08

So, the total of 0.007, 8.5, and 30.08 comes to 38.587.
(b) 15 + 0.632 + 13.8
Therefore, adding 15, 0.632, and 13.8 results in 29.432.
(c) 27.076 + 0.55 + 0.004
So, the sum of 27.076, 0.55, and 0.004 is 27.63.
(d) 25.65 + 9.005 + 3.7
Hence, combining 25.65, 9.005, and 3.7 gives 38.355.
(e) 0.75 + 10.425 + 2
Therefore, the sum of 0.75, 10.425, and 2 comes to 13.175.
(f) 280.69 + 25.2 + 38
So, adding 280.69, 25.2, and 38 results in 343.89.
In simple words: To find the sum of these decimal numbers, you should line up the decimal points and then add the numbers column by column, starting from the rightmost digit.

Exam Tip: Always align the decimal points vertically when adding or subtracting decimals to ensure correct place value addition.

 

Question 2. Rashid spent Rs 35.75 for Maths book and Rs 32.60 for Science book. Find the total amount spent by Rashid.
Answer:
The money Rashid spent on his Maths book was Rs 35.75.
He also spent Rs 32.60 on his Science book.
His total spending came to Rs \( (35.75 + 32.60) = \text{Rs } 68.35 \).
In simple words: Add the cost of the Maths book and the Science book together to get the full amount Rashid spent.

Exam Tip: When dealing with money, always remember to add the rupee values directly to find the total sum.

 

Question 3. Radhika's mother gave her Rs 10.50 and her father gave her Rs 15.80, find the total amount given to Radhika by the parents.
Answer:
Radhika's mother gave her Rs 10.50.
Her father gave her Rs 15.80.
So, the total money she received was Rs 26.30.
In simple words: To find out how much money Radhika got in total, add the amount her mother gave her to the amount her father gave her.

Exam Tip: Make sure to correctly add the decimal amounts, aligning the decimal points, to get an accurate total.

 

Question 4. Nasreen bought 3 m 20 cm cloth for her shirt and 2 m 5 cm cloth for her trouser. Find the total length of cloth bought by her.
Answer:
For her shirt, Nasreen purchased 3 meters and 20 centimeters of cloth.
For her trousers, she bought 2 meters and 5 centimeters of fabric.
The overall length of cloth she obtained was \( (3 \text{ m } 20 \text{ cm}) + (2 \text{ m } 5 \text{ cm}) \).
We know that \( \therefore 1 \text{ cm} = \frac{1}{100} \text{ m} \).
So, \( \left( 3\text{ m} + \frac{20}{100}\text{ m} \right) + \left( 2\text{ m} + \frac{5}{100}\text{ m} \right) \).
Converting the measurements to meters, we get: \( (3 + 0.20) \text{ m} + (2 + 0.05) \text{ m} = 3.20 \text{ m} + 2.05 \text{ m} = 5.25 \text{ m} \).
Therefore, the total length of cloth Nasreen bought is 5.25 m.
In simple words: First, change all the centimeters to meters. Then, add the lengths of cloth for the shirt and the trouser to get the total amount of cloth she purchased.

Exam Tip: Always convert all units to a common measurement (like meters in this case) before performing addition or subtraction to prevent errors.

 

Question 5. Naresh walked 2 km 35 m in the morning and 1 km 7 m in the evening. How much distance did he walk in all?
Answer:
Distance walked by Naresh:
In the morning, he walked 2 kilometers and 35 meters, and in the evening, he covered 1 kilometer and 7 meters.
The overall distance Naresh walked was \( (2 \text{ km } 35 \text{ m}) + (1 \text{ km } 7 \text{ m}) \).
We know that \( \therefore 1 \text{ m} = \frac{1}{1000} \text{ km} \).
We convert meters to kilometers: \( \left( 2 \text{ km} + \frac{35}{1000} \text{ km} \right) + \left( 1 \text{ km} + \frac{7}{1000} \text{ km} \right) \).
This results in \( (2 + 0.035) \text{ km} + (1 + 0.007) \text{ km} = 3.042 \text{ km} \).
Therefore, he walked a total of 3.042 km.
In simple words: To find the total distance, change the meters to kilometers. Then, add the distance he walked in the morning to the distance he walked in the evening.

Exam Tip: When combining distances with different units, convert all units to a single, consistent unit (like kilometers) before adding them together.

 

Question 6. Sunita traveled 15 km 268 m by bus, 7 km 7 m by car, and 500 m on foot in order to reach her school. How far is her school from her residence?
Answer:
Distance covered:
Sunita travelled 15 kilometers and 268 meters by bus.
She also went 7 kilometers and 7 meters by car.
And she walked 500 meters.
The overall distance she travelled was \( (15 \text{ km } 268 \text{ m}) + (7 \text{ km } 7 \text{ m}) + 500 \text{ m} \).
Converting all units to kilometers, we get: \( \left( 15\text{ km} + \frac{268}{1000}\text{ km} \right) + \left( 7\text{ km} + \frac{7}{1000}\text{ km} \right) + \left( 0\text{ km} + \frac{500}{1000}\text{ km} \right) \).
This calculation equals \( (15 + 0.268) \text{ km} + (7 + 0.007) \text{ km} + (0.500) \text{ km} = 15.268 \text{ km} + 7.007 \text{ km} + 0.500 \text{ km} = 22.775 \text{ km} \).
Therefore, the total distance from her home to school is 22.775 km.
In simple words: To find the total distance, convert all meters into kilometers first. Then, add up all the distances Sunita travelled by bus, car, and foot.

Exam Tip: Remember to express all lengths in the same unit (e.g., kilometers) before summing them up to avoid mistakes in your final calculation.

 

Question 7. Ravi purchased 5 kg 400 g rice, 2 kg 20 g sugar, and 10 kg 850 g flour. Find the total weight of his purchases.
Answer:
Weight of rice = 5 kg 400 g
Weight of sugar = 2 kg 20 g
Weight of flour = 10 kg 850 g
The overall weight of his purchased items was \( (5 \text{ kg } 400 \text{ g}) + (2 \text{ kg } 20 \text{ g}) + (10 \text{ kg } 850 \text{ g}) \).
We know that \( \therefore 1 \text{ g} = \frac{1}{1000} \text{ kg} \).
Converting grams to kilograms: \( \left( 5\text{ kg} + \frac{400}{1000}\text{ kg} \right) + \left( 2\text{ kg} + \frac{20}{1000}\text{ kg} \right) + \left( 10\text{ kg} + \frac{850}{1000}\text{ kg} \right) \).
This gives us \( (5 + 0.400) \text{ kg} + (2 + 0.020) \text{ kg} + (10 + 0.850) \text{ kg} \).
Adding these amounts: \( 5.400 \text{ kg} + 2.020 \text{ kg} + 10.850 \text{ kg} = 18.270 \text{ kg} \).
Consequently, the final total weight of everything Ravi bought amounted to 18.270 kg.
In simple words: Convert all the grams to kilograms. Then, add the weights of the rice, sugar, and flour to find the total weight of all the items Ravi purchased.

Exam Tip: Always make sure to convert all weight units to a single common unit (e.g., kilograms) before calculating the total weight to avoid errors.