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For Class 9 Mathematics, this chapter in ICSE Class 9 Maths Chapter 02 Profit Loss and Discount provides a detailed overview of important concepts. We highly recommend using this text alongside the ICSE Solutions for Class 9 Mathematics to learn the exercise questions provided at the end of the chapter.
Chapter 2 Profit Loss and Discount ICSE Book Class Class 9 PDF (2026-27)
Profit, Loss And Discount
Exercise 2 (A)
Question 1
Find the profit or loss percent, when:
(i) C.P. = Rs. 55 and S.P. = Rs. 72.60
(ii) C.P. = Rs. 490 and S.P. = Rs. 416.50
(iii) C.P. = Rs. 112, overheads = Rs. 14 and S.P. = Rs. 94.50.
Solution (i)
C.P. = Rs. 55
S.P. = Rs. 72.60
Gain = S.P. - C.P. = Rs. 72.60 - Rs. 55.00 = Rs. 17.60
Gain percent = \(\frac{\text{Gain} \times 100}{\text{C.P.}}\)
= \(\frac{17.60 \times 100}{55}\) %
= \(\frac{1760 \times 100}{100 \times 55}\) % = 32 %
Solution (ii)
C.P. = Rs. 490
S.P. = Rs. 416.50
Loss = C.P. - S.P. = Rs. 490.00 - 416.50 = Rs. 73.50
Loss % = \(\frac{\text{Loss} \times 100}{\text{C.P.}}\) = \(\frac{73.50 \times 100}{490}\) %
= \(\frac{7350 \times 100}{100 \times 490}\) % = 15%
Solution (iii)
C.P. = Rs. 112
Overheads = Rs. 14
Total C.P. = Rs. 112 + Rs. 14 = Rs. 126
S.P. = Rs. 94.50
Loss = C.P. - S.P. = Rs. 126 - Rs. 94.50 = Rs. 31.50
Loss % = \(\frac{\text{Loss} \times 100}{\text{C.P.}}\) = \(\frac{31.50 \times 100}{126}\) %
= \(\frac{3150 \times 100}{100 \times 126}\) % = 25% Ans.
Teacher's Note
Understanding profit and loss helps in everyday shopping and business transactions, allowing us to make informed decisions about purchases and pricing.
Question 2
Find S.P. when:
(i) C.P. = Rs. 435 and loss = 16%
(ii) C.P. = Rs. 172, overheads = Rs. 61 and gain = 12%.
Solution (i)
C.P. = Rs. 435, Loss = 16%
S.P. = \(\frac{\text{C.P.} \times (100 - \text{Loss} \%)}{100}\)
= \(\frac{435 (100 - 16)}{100}\) = \(\frac{435 \times 84}{100}\)
= Rs. 365.40.
Solution (ii)
C.P. = Rs. 172
Overheads = Rs. 61
Total C.P. = Rs. 172 + Rs. 61 = Rs. 233
Gain = 12%
S.P. = \(\frac{\text{C.P.}(100 + \text{gain} \%)}{100}\)
= \(\frac{233(100 + 12)}{100}\) = \(\frac{233 \times 112}{100}\)
= Rs. 260.96 Ans.
Question 3
Find C.P. when:
(i) a cycle is sold for Rs. 1485 at a profit of 8%.
(ii) a fan is sold for Rs. 657.60 at a loss of 4%.
Solution (i)
S.P. of cycle = Rs. 1485
Profit = 8%
C.P. = \(\frac{\text{S.P.} \times 100}{100 + \text{gain} \%}\) = \(\frac{1485 \times 100}{100 + 8}\)
= Rs. \(\frac{1485 \times 100}{108}\) = Rs. 1375.
Gain = S.P. - C.P. = Rs. 188.60 - Rs. 164 = Rs. 24.60
Gain % = \(\frac{\text{Gain} \times 100}{\text{C.P}}\) = \(\frac{24.60 \times 100}{164}\) = \(\frac{2460 \times 100}{100 \times 164}\) % = 15%. Ans.
Question 4
If oranges are bought at 11 for Rs. 30 and sold at 10 for Rs. 31, find loss or gain percent.
Solution
L.C.M. of 11 and 10 = 110
C.P. of 110 oranges = \(\frac{110 \times 30}{11}\) = Rs. 300
S.P. of 110 oranges = \(\frac{110 \times 31}{10}\) = Rs. 341
Gain = S.P. - C.P. = Rs. 341 - Rs. 300 = Rs. 41 Ans.
Gain % = \(\frac{\text{Gain} \times 100}{\text{C.P.}}\) = \(\frac{41 \times 100}{300}\) % = \(\frac{41}{3}\) % = 13\(\frac{2}{3}\) % Ans.
Question 5
By selling an article for Rs. 123, the shopkeeper loses 25%. Find the gain or loss percent, if the article be sold for Rs. 188.60.
Solution
In first case, S.P. = Rs. 123
Loss = 25%
C.P. = \(\frac{\text{S.P.} \times 100}{100 - \text{Loss} \%}\) = \(\frac{123 \times 100}{100 - 25}\)
= \(\frac{123 \times 100}{75}\) = Rs. 164
In second case,
S.P. = Rs. 188.60
C.P. = Rs. 164
Teacher's Note
When shopping during sales, calculating the actual profit or loss helps us understand whether we are getting a genuine discount or being misled by artificially inflated original prices.
Question 6
A dealer sold two almirahs for Rs. 6090 each gaining 16% on one and losing 16% on the other. Find his net gain or loss percent in the whole transaction.
Solution
S.P. of first almirah = Rs. 6090
Gain % = 16%
C.P. = \(\frac{\text{S.P.} \times 100}{100 + \text{Gain} \%}\) = \(\frac{6090 \times 100}{100 + 16}\)
= Rs. \(\frac{6090 \times 100}{116}\) = Rs. 5250
S.P. of the second almirah = Rs. 6090
Loss = 16%
C.P. = \(\frac{\text{S.P.} \times 100}{100 - \text{Loss} \%}\) = \(\frac{6090 \times 100}{100 - 16}\)
= Rs. \(\frac{6090 \times 100}{84}\) = Rs. 7250
Total C.P. of both almirahs = Rs. 5250 + 7250 = Rs. 12500
and total S.P. = Rs. 6090 + Rs. 6090 = Rs. 12180
Loss = C.P. - S.P. = Rs. 12500 - 12180 = Rs. 320
Loss % = \(\frac{\text{Loss} \times 100}{\text{C.P.}}\) = \(\frac{320 \times 100}{12500}\) % = 2.56% Ans.
Question 7
By selling a book for Rs. 115.20, a man loses 10%. At what price should he sell it to gain 5%?
Solution
S.P. of book = Rs. 115.20
Loss = 10%
C.P. = \(\frac{\text{S.P.} \times 100}{100 - \text{Loss} \%}\) = \(\frac{115.20 \times 100}{100 - 10}\)
= \(\frac{11520 \times 100}{100 \times 90}\) = Rs. 128
If gain = 5%
then S.P. = \(\frac{\text{C.P.}(100 + \text{gain} \%)}{100}\)
= \(\frac{128 (100 + 5)}{100}\) = Rs. \(\frac{128 \times 105}{100}\)
= Rs. 134.40 Ans.
Question 8
A man sells an article at a profit of 25%. If he had bought it at 20% less and sold it for Rs. 10.50 less, he would have gained 30%. Find the cost price of the article.
Solution
Let C.P. of an article = Rs. 100
Gain = 25%
S.P. = Rs. 100 + 25 = Rs. 125
In second case C.P. = Rs. 100 - 20 = Rs. 80
Gain = 30%
S.P. = \(\frac{\text{C.P.}(100 + \text{Gain} \%)}{100}\)
= Rs. \(\frac{80 \times (100 + 30)}{100}\) = Rs. \(\frac{80 \times 130}{100}\)
= Rs. 104
Difference between two S.P.'s = Rs. 125 - 104 = Rs. 21
If difference is Rs. 21, then C.P. = Rs. 100 and if difference is Rs. 10.50, then
C.P. = Rs. \(\frac{100 \times 10.50}{21}\)
= Rs. \(\frac{100 \times 1050}{100 \times 21}\) = Rs. 50 Ans.
Question 9
20% more can be gained if a piece of cloth is sold for Rs. 83 instead of Rs. 78. Find the cost price of the piece of cloth.
Solution
Difference in both S.P.'s = Rs. 83 - Rs. 78 = Rs. 5
But difference in gain = 20%
If Rs. 20 is more then C.P. = Rs. 100 and if Rs. 5 is more, then C.P. = Rs. \(\frac{100 \times 5}{20}\) = Rs. 25 Ans.
Question 10
The difference between selling an article at 7% profit and at 16% profit is Rs. 63. Find the cost price of the article and also the two selling prices.
Solution
Difference in percent profit = 16% - 7% = 9%
9% of C.P. = Rs. 63
C.P. = \(\frac{63 \times 100}{9}\) = Rs. 700
Now first S.P. when gain is 7%
= \(\frac{\text{C.P.}(100 + \text{Gain} \%)}{100}\)
= \(\frac{700 (100 + 7)}{100}\)
= Rs. \(\frac{700 \times 107}{100}\) = Rs. 749
Similarly second S.P. when gain is 16%
= \(\frac{700 (100 + 16)}{100}\) = \(\frac{700 \times 116}{100}\)
= Rs. 812 Ans.
Question 11
A man sells an article at 5% above its cost price. If he had bought it at 5% less than what he paid for it and sold it Rs. 2 less, he would have gained 10%. Find the cost price of the article.
Solution
Let C.P. of the article = Rs. 100
First S.P. = Rs. 100 + 5 = Rs. 105
Second time C.P. = 100 - 5 = Rs. 95
Gain = 10%
S.P. = \(\frac{95 \times (100 + 10)}{100}\) = \(\frac{95 \times 110}{100}\)
= Rs. \(\frac{209}{2}\)
Teacher's Note
Profit and loss calculations are fundamental in small business operations, helping shopkeepers determine fair pricing and manage their inventory effectively.
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ICSE Book Class 9 Mathematics Chapter 2 Profit Loss and Discount
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