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ICSE Class 8 Mathematics Geometry Chapter 31 Symmetry Reflection and Rotation Digital Edition
For Class 8 Mathematics, this chapter in ICSE Class 8 Maths Geometry Chapter 31 Symmetry Reflection and Rotation provides a detailed overview of important concepts. We highly recommend using this text alongside the ICSE Solutions for Class 8 Mathematics to learn the exercise questions provided at the end of the chapter.
Geometry Chapter 31 Symmetry Reflection and Rotation ICSE Book Class Class 8 PDF (2026-27)
Symmetry, Reflection, and Rotation
Symmetry
Symmetry refers to the exact match in size and shape between two halves, parts of sides of an object or a figure.
An axis of symmetry divides a plane figure into two congruent halves. A rhombus is symmetrical about its diagonals. A rectangle is symmetrical about the two axes joining the mid-points of opposite sides. A kite is symmetrical about its vertical diagonal. A square is symmetrical about its two diagonals and about the two axes joining the mid-points of opposite sides.
An angle is symmetrical about its bisector. In Figure 31.2, all points on arm OA are symmetrical about angle bisector OC, with their respective images. Point X is symmetrical to its image, point X1, as both X and X1 are equidistant from any point on ray OC.
A line segment is symmetrical about its perpendicular bisector. In Figure 31.1, all points on line segment PQ are symmetrical about perpendicular bisector XY, with their respective images. Point A is symmetrical to its image, point A1, as both A and A1 are equidistant from any point on XY.
A plane figure through which no axis of symmetry can be drawn is said to be asymmetric. However an asymmetric figure may have point symmetry. If a parallelogram is rotated about the point O where its diagonals intersect, after half-a-turn or a rotation of 180°, it will look exactly the same in size, shape, and orientation.
Rotational Order of Regular Polygons
The number of times a figure looks the same in a complete rotation of 360° is known as the rotational order of the figure.
| Triangle | \[\frac{360°}{120°} = 3\] |
| Quadrilateral | \[\frac{360°}{90°} = 4\] |
| Pentagon | \[\frac{360°}{72°} = 5\] |
| Hexagon | \[\frac{360°}{60°} = 6\] |
| Octagon | \[\frac{360°}{45°} = 8\] |
| Nonagon | \[\frac{360°}{40°} = 9\] |
| Decagon | \[\frac{360°}{36°} = 10\] |
Reflection
Reflection is a transformation such that any two corresponding points in the object and image are both at the same distance from a fixed straight line.
On reflection of a point P(x, y) (Figure 31.3) about the X axis, the abscissa of its image P1 remains the same, but the sign of its ordinate changes.
On reflection of a point Q(a, b) about the Y axis, the ordinate of its image Q1 remains the same, but the sign of its abscissa changes.
Example 1
Reflection of line segment P(3, 7) Q(7, 3) in Figure 31.4 about the X and Y axes to form images P1Q1 and P2Q2 respectively.
Example 2
Reflection of triangle A(0, 7) B(7, 7) C(7, 0) in Figure 31.5 about the X and Y axes to form images triangle A1B1C1 and triangle A2B2C2 respectively.
Thus, on reflection:
1. the shape and size of a geometrical figure does not change.
2. the orientation of the figure is reversed with respect to the axis of reflection.
3. the position of a point on the axis of reflection does not change.
4. the image of a line perpendicular to the axis of reflection will also be perpendicular to the axis of reflection.
5. the image of a line parallel to the axis of reflection will also be parallel to the axis of reflection.
Try this! Plot a point (4, 8) and find its image when it is reflected about the X axis.
Rotation
Rotation is a transformation about a fixed point such that every point in the object turns through the same angle relative to the fixed point.
1. The turning of a point P(x, y) in a clockwise direction about the origin by 90°, forms an image P1 whose abscissa is the same as the ordinate of the original point and whose ordinate is the opposite sign of the abscissa of the original point. Or P(x, y) rotated clockwise about origin by 90° = P1(y, -x)
2. The turning of a point X(a, b) in an anti-clockwise direction about the origin by 90°, forms an image X1 whose abscissa is the opposite sign of the ordinate of the original point and whose ordinate the same as the abscissa of the original point. Or X(a, b) rotated anti-clockwise about origin by 90° = X1(-b, a)
3. The turning of a point A(p, q) about the origin by 180°, forms an image A1 whose abscissa and ordinate have the opposite signs as the abscissa and ordinate of the original points respectively. Or A(p, q) rotated about origin by 180° = A1(-p, -q)
Example 3
Rotation of line segment P(2, 9) Q(8, 3) about the origin by:
(i) 90° clockwise, to form image P1Q1
(ii) 90° anti-clockwise, to form image P2Q2
(iii) 180° to form image P3Q3
See Figure 31.6.
Example 4
Rotation of triangle A(2, 2) B(5, 8) C(10, 3) about the origin by:
(i) 90° clockwise, to form image A1 B1 C1
(ii) 90° anti-clockwise, to form image A2 B2 C2
(iii) 180° to form image A3 B3 C3
See Figure 31.7.
Try this! Plot a point (4, 8) and find its image when it is rotated about the origin through 180°.
Proof of Pythagoras' Theorem by Rotation
Given triangle ABC where A(2, 5), B(2, 2), and C(6, 2), show that AB2 + BC2 = AC2.
Plotting the points on a graph paper we have triangle ABC (Figure 31.8 (i)), where angle ABC = 90°. Now if point A is rotated clockwise about point C (Figure 31.8(ii)), point A will travel along an arc of a circle with C as centre and radius equal to the length of line segment AC. Rotate point A about C till the ordinate of its image A1 is 2. What is the abscissa of point A1?
AB is a vertical line segment whose length measures ordinate - ordinate = 5 - 2 = 3 units. Therefore, Area of square ABED = AB2 = 3 × 3 = 9 unit2.
BC is a horizontal line segment whose length measures abscissa - abscissa = 6 - 2 = 4 units. Therefore, Area of square BCGF = BC2 = 4 × 4 = 16 unit2.
CA1 is a horizontal line segment whose length measures abscissa - abscissa = 11 - 6 = 5 units. Therefore, Area of square CA1IH = CA12 = 5 × 5 = 25 unit2.
But 9 unit2 + 16 unit2 = 25 unit2. Therefore, AB2 + BC2 = CA12.
But CA1 = CA (as a point and its image on rotation are equidistant from their point of symmetry). Therefore, AB2 + BC2 = CA2. Q.E.D
Exercise 31.1
1. How many axes of symmetry can be drawn through:
(i) an oval
(ii) the English letter C
(iii) an isosceles trapezium
(iv) a regular pentagon
2. Identify any three letters of the English alphabet through which no line of symmetry can be drawn.
3. What is the order of rotational symmetry of:
(i) an oval
(ii) an isosceles triangle
(iii) the English letter J
(iv) a circle
4. Plot a point P(-3, 8) and find its image:
(i) P1 when reflected about the X axis.
(ii) P2 when reflected about the Y axis.
(iii) P3 when rotated clockwise by 90° about the origin.
(iv) P4 when rotated anti-clockwise by 90° about the origin.
(v) P5 when rotated by 180° about the origin.
5. Plot line segment A(1, 9) B(12, 2) and find its image:
(i) A1 B1 when reflected about the X axis.
(ii) A2 B2 when reflected about the Y axis.
(iii) A3 B3 when rotated clockwise by 90° about the origin.
(iv) A4 B4 when rotated anti-clockwise by 90° about the origin.
(v) A5 B5 when rotated by 180° about the origin.
6. Plot line segment A(-6, 9) B(6, 9) and find its image:
(i) A1 B1 when reflected about the X axis.
(ii) A2 B2 when reflected about the Y axis.
(iii) A3 B3 when rotated clockwise by 90° about the origin.
(iv) A4 B4 when rotated anti-clockwise by 90° about the origin.
(v) A5 B5 when rotated by 180° about the origin.
7. Plot triangle P(3, 1) Q(7, 9) R(11, 2) and find its image:
(i) P1 Q1 R1 when reflected about the X axis.
(ii) P2 Q2 R2 when reflected about the Y axis.
(iii) P3 Q3 R3 when rotated clockwise by 90° about the origin.
(iv) P4 Q4 R4 when rotated anti-clockwise by 90° about the origin.
(v) P5 Q5 R5 when rotated by 180° about the origin.
8. Plot quadrilateral A(1, 9) B(3, 1) C(9, 1) D(14, 12) and find its image:
(i) A1 B1 C1 D1 when reflected about the X axis.
(ii) A2 B2 C2 D2 when reflected about the Y axis.
(iii) A3 B3 C3 D3 when rotated clockwise by 90° about the origin.
(iv) A4 B4 C4 D4 when rotated anti-clockwise by 90° about the origin.
(v) A5 B5 C5 D5 when rotated by 180° about the origin.
9. Plot pentagon P(0, 5) Q(3, 0) R(9, 0) S(12, 6) T(7, 10) and find its image:
(i) P1 Q1 R1 S1 T1 when reflected about the X axis.
(ii) P2 Q2 R2 S2 T2 when reflected about the Y axis.
(iii) P3 Q3 R3 S3 T3 when rotated clockwise by 90° about the origin.
(iv) P4 Q4 R4 S4 T4 when rotated anti-clockwise by 90° about the origin.
(v) P5 Q5 R5 S5 T5 when rotated by 180° about the origin.
10. If point P(5, 5) in the first quadrant of a graph is rotated about the origin by 180°, find the axis about which it is reflected.
11. Plot a line segment A(5, 2) B(5, 10) and rotate point A about point B by 90° in a clockwise direction to form its image B1. Write the coordinates of point B1.
12. Plot a triangle A(0, 5) B(0, 0) C(12, 0). Rotate point A about point C in a clockwise direction till it lies on the X-axis and find the position of its image A1.
Revision Exercise
1. How many axes of symmetry can be drawn through:
(i) an equilateral triangle
(ii) a regular octagon
(iii) the English letter H.
(iv) a square
2. What is the order of rotational symmetry of:
(i) a rectangle
(ii) an isosceles trapezium
(iii) the English Letter R.
(iv) a rhombus
3. Plot line segment A(-3, 7) B(3, 7) and find its image:
(i) A1 B1 when reflected about the X-axis.
(ii) A2 B2 C2 D2 when reflected about the Y axis.
(iii) A3 B3 C3 D3 when rotated clockwise by 90° about the origin.
(iv) A4 B4 when rotated anti-clockwise by 90° about the origin.
4. Plot a line segment P (6, 3) Q (6, 15) and rotate point Q about point P by 90° in a clockwise direction to form its image B1. Write the co-ordinates of point Q1.
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ICSE Book Class 8 Mathematics Geometry Chapter 31 Symmetry Reflection and Rotation
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