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ICSE Class 8 Mathematics Chapter 17 Formulae Digital Edition
For Class 8 Mathematics, this chapter in ICSE Class 8 Maths Chapter 17 Formulae provides a detailed overview of important concepts. We highly recommend using this text alongside the ICSE Solutions for Class 8 Mathematics to learn the exercise questions provided at the end of the chapter.
Chapter 17 Formulae ICSE Book Class Class 8 PDF (2026-27)
Chapter 17: Formulae
(Including change of subject and substitution)
17.1 Review
1. Formula
A formula is an equation, which shows the relationship between two or more quantities.
For example: Speed = Distance/Time shows the relationship between Speed, Distance and Time; so it is a formula.
[Formulae is plural of formula.]
2. Framing A Formula
To express a given statement in the form of an equation is called framing a formula.
| Statement | Corresponding Formula |
|---|---|
1. The sum of two numbers x and y is 40. | x + y = 40 |
2. A man has a total of ₹ M consisting of x coins of ₹ 2 each, y coins of one rupee each and z coins of 50 paise each. | M = ₹ \(2x + y + \frac{50z}{100}\) = ₹ \(2x + y + \frac{z}{2}\) |
3. The ages of two brothers are x years and (x + 5) years. After 10 years, the younger will be half of his brother's age. | x + 10 = \(\frac{1}{2}\) (x + 5 + 10) \(\Rightarrow\) x + 10 = \(\frac{1}{2}\) (x + 15) |
Teacher's Note
Formulas are used in everyday life, such as calculating distance traveled when you know speed and time, or finding the total cost of items when you know the unit price.
Test Yourself
1. If x kg of rice is bought at ₹ m per kg and whole of it is sold at ₹ n per kg, then total cost price of the rice = ₹............; total S.P. of the rice = ₹............; profit made ₹ .................. and profit % ..................................
2. The total value in ₹ P, of x coins of ₹ 5 each, y coins of ₹ 2 each, z coins of ₹ 1 each and r coins of 50 paise each is ₹ P = .............................
3. The force (F) applied on a body is equal to the product of its mass (m) and acceleration (a) produced in the body. \(\therefore\) F = ..........
4. A boy runs for m hours at x km/hr and for n hours at y km/h, distance run by him in m hours = .................... km, distance run by him in n hours = .................... km and total distance run in (m + n) hours = .................... km. \(\therefore\) Formula for his average speed = .................... km/hr.
Example 1
A labourer is engaged for 50 days on the condition that he receives ₹ 25 for each day he works and gives ₹ 10 for each day he is absent. If he works for x days, form a formula to find his total wages, ₹ W, for 50 days.
Solution
Given, the labourer works for x days, so he remains absent for (50 - x) days.
Since, for each day's work, he gets ₹ 25
\(\therefore\) For x days' work, he gets ₹ 25x
Since, for being absent for one day, he gives ₹ 10
\(\therefore\) For being absent (50 - x) days, he gives ₹ 10 (50 - x)
\(\therefore\) His total wages i.e. ₹ W = ₹ 25x - ₹ 10 (50 - x)
= ₹ (25x - 500 + 10x)
= ₹ (35x - 500)
Exercise 17 (A)
1. Make a formula for each of the following statements:
(i) "The reciprocal of the focal length f, is equal to the sum of the reciprocals of the object distance u and image distance v."
(ii) "The number of diagonals d, that can be drawn from one vertex of an n-sided polygon to all the other vertices is equal to the number of sides less 3."
(iii) "The distance s metres, which a falling body covers in time t seconds, is 4.8 times the square of the time t."
(iv) "The mean 'M' of the five quantities a, b, c, d and e is equal to their sum divided by the number of quantities."
2. A bus is carrying x children. If each of y children pays ₹ 2.50 and each of the remaining pays ₹ 5.25, find the total collection 'C' in rupees.
3. A worker is engaged for 100 days, on the condition that he will be paid ₹ x per day for each day he works and will be charged ₹ y per day for each day he is absent. Frame a formula to find his earning 'E' in rupees, if he works for 'd' days only.
4. A shopkeeper buys x kg sugar for ₹ y and sells it at ₹ z per kg. Find the expression for his (i) profit (ii) profit per cent.
5. A shopkeeper buys a kg of rice at ₹ x per kg and another b kg of rice at ₹ y per kg. If he sells the mixture at ₹ z per kg, find the expression for his (i) total profit (ii) profit per cent.
6. A man buys m articles at ₹ x each and another n articles for ₹ y. If he sells all the articles at ₹ z per article, frame an equation to find his profit.
7. During a certain month, a firm posted x letters with ₹ 5 stamps on each and another y letters with ₹ 3.50 stamps on each. Obtain an expression to find the total money, ₹ M, spent on postage.
8. Find the total money 'M' in rupees, in a purse, if the purse contains 2x notes of ₹ 5 each, 3y notes of ₹ 2 each, 6z coins of ₹ 1 each and 8r coins of 50 paise each.
9. A worker in a factory is paid ₹ x per hour for the normal work and double this rate for the overtime work. Find the total earning ₹ E in rupees of a worker who works for 20 hours out of which y hours is the overtime.
10. (i) Find the number of hours 'h' in x days and y hours.
(ii) Frame a formula for finding the number of students 'n' that may be seated in a class room in which there are S single seats and D double seats.
Teacher's Note
Creating formulas helps us solve real-world problems systematically, like calculating earnings based on hours worked or finding costs based on quantities purchased.
17.2 Change Of The Subject Of A Formula
The subject of a formula is the variable which is expressed in terms of other variables.
For example: in formula A = \(\frac{1}{2}\) bh; A is expressed in terms of variables b and h; hence A is the subject of formula.
The same formula can be re-written as:
(i) b = \(\frac{2A}{h}\), b is the subject of formula.
(ii) h = \(\frac{2A}{b}\), h is the subject of formula.
Test Yourself
5. A = \(\frac{50}{x}\) \(\Rightarrow\) Ax = ........... and x = ............; here x is the subject of formula.
6. F = \(\frac{mv^2}{gr}\) \(\Rightarrow\) Fgr = ........... and g = ............; here g is the subject of formula.
7. I = \(\frac{E}{R + r}\) \(\Rightarrow\) IR + ........... = E \(\Rightarrow\) Ir = E.................... and r = ..........
8. a = \(\sqrt{\frac{b}{c}}\) \(\Rightarrow\) a^2 = ............, \(\Rightarrow\) a^2c = ........... and c = ..........
9. l = a + (n - 1)d \(\Rightarrow\) l = a + nd - d \(\Rightarrow\) l - a + d = ........... and n = ..........
10. \(\frac{1}{c}\) = \(\frac{ab}{a + b}\) \(\Rightarrow\) cab = ........... \(\Rightarrow\) cab - b = ..........., \(\Rightarrow\) b(.................) = ........... and b = ..........
Example 2
Given S = \(\frac{n}{2}\) (a + l); make l, the subject of formula.
Solution
S = \(\frac{n}{2}\) (a + l) \(\Rightarrow\) 2S = na + nl
\(\Rightarrow\) 2S - na = nl \(\Rightarrow\) l = \(\frac{2s - na}{n}\)
Example 3
Given T = 2\(\pi\) \(\sqrt{\frac{l}{g}}\); make g, the subject of formula.
Solution
Squaring both the sides of the given formula,
we get, T^2 = 4\(\pi\)^2 . \(\frac{l}{g}\)
\(\Rightarrow\) T^2g = 4\(\pi\)^2l \(\Rightarrow\) g = \(\frac{4\pi^2 l}{T^2}\)
Exercise 17 (B)
Change the subject of formulae for the indicated letter:
1. F = \(\frac{9}{5}\) C + 32; for C
2. A = P(1 + rt); for t
3. I = \(\frac{nE}{R + nr}\); for n
4. I = \(\frac{nE}{nR + r}\); for r
5. \(\frac{1}{f}\) = \(\frac{1}{v}\) + \(\frac{1}{u}\); for u
6. A = 2\(\pi\)r(r + h); for h
7. m = 4\(\sqrt{\frac{a}{b + c}}\); for b
8. z = \(\frac{a - b}{4b}\); for b
9. S = \(\frac{n}{2}\) [2a + (n - 1)d]; for d
10. T = \(\frac{1}{r}\) \(\sqrt{\frac{l}{\pi d}}\); for d
11. \(\frac{a + 1}{b}\) + 2 = \(\frac{3a}{b}\); for a
12. m = \(\frac{xy - z}{x - 1}\); for x
13. \(\frac{x - y}{x + y}\) = z; for y
14. \(\frac{P - 2l}{2}\) = b; for l
15. a = \(\sqrt{\frac{x + b}{x - b}}\); for x
16. F = \(\frac{mv - mu}{t}\); for u.
17. V = \(\pi\)(R^2 - r^2)h; for r.
18. s = u + \(\frac{1}{2}\) a(2t - 1); for a
19. s = u + \(\frac{1}{2}\) a(2t - 1); for t
20. a = \(\sqrt{\frac{15x + 16y}{x + y}}\); for y
Teacher's Note
Changing the subject of formulas is like solving for different variables in real situations - for example, if you know distance and time, you might rearrange to find speed instead.
17.3 Substitution
We know that area (A) of a rectangle is equal to the product of its length (l) and breadth (b) i.e. A = l × b.
Using this formula, the area of any rectangle can be obtained if its length and breadth are known. Also, the length can be found if its area and breadth are known, and the breadth, if its area and length are known.
The process of finding an unknown quantity of a formula, when each of the other quantities are known, is called substitution.
Test Yourself
11. In A = l × b;
(i) If l = 30 cm, and b = 25 cm; A = .................. cm^2 = .................. cm^2
(ii) If A = 132m^2 and l = 12 m; b = .................. m = .................. m
(iii) If A = 360 cm^2 and b = 40 cm; l = .................. cm = .................. cm
12. In A = \(\frac{22}{7}\) r^2
(i) If r = 14 cm, A = .................. cm^2 = ........... cm^2
(ii) If A = 154 m^2, r^2 = .................. = .........and r = .........m
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ICSE Book Class 8 Mathematics Chapter 17 Formulae
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