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Chapter 13: Exponents
13.1 Review
Exponent
If x is a real number and n is a natural number, we know:
x × x × x × x ....... n times = xn
where xn is called an exponential expression with base x and exponent (or index, or power) n.
xn is read as 'x raised to the power n' or simply 'x to the power n'.
Laws of Exponents
1. Product Law: am × an = am + n
e.g. 37 × 34 = 37 + 4 = 311, x8 × x5 = x8 + 5 = x13 and so on.
2. Quotient Law: \[\frac{a^m}{a^n} = a^{m-n} \text{ if } m > n\]
\[= \frac{1}{a^{n-m}} \text{ if } n > m\]
e.g. \[\frac{3^7}{3^4} = 3^{7-4} = 3^3, \frac{x^5}{x^8} = \frac{1}{x^{8-5}} = \frac{1}{x^3}\] and so on.
3. Power law: (am)n = amn
e.g. (37)4 = 37 × 4 = 328, (x8)5 = x40 and so on.
Test Yourself
1. 2 × 2 × 2 × 2 .............. 15 times = .............. and is read as: ............................................
2. -5 × -5 × -5 × .............. 12 times = .............. and is read as: ......................................
3. a5 × a7 = ............., a5 × a-7 = ............., a-5 × a7 = ............ and a-5 × a-7 = ............
4. \[\frac{a^8}{a^2} = ............., \frac{a^5}{a^8} = ............., \frac{a^5}{a^{-8}} = ............. \text{ and } \frac{a^8}{a^{-5}} = .............\]
5. (a5)8 = ............., (a8)5 = ............., (a-8)5 = .............. and (a-8)-5 = ............
6. 315 × 36 × 3-10 = ............., 54 × 5-7 × 56 = ............ and 72 × 78 × 7-6 = ............
7. \[\frac{2^5 \times 2^4}{2^9} = ............., \frac{4^6 \times 4^{-3}}{4^2} = ............ \text{ and } \frac{8^5 \times 8^4}{8^{-3}} = ............\]
Teacher's Note
Understanding exponents helps us express very large numbers like the distance to stars or very small numbers like the size of atoms in a simple, compact form.
13.2 More About Exponents
1. (a × b)n = an × bn
e.g. (a5 × b-3)4 = (a5)4 × (b-3)4 = a20 × b-12 and (34 × 5-3)-2 = 3-8 × 56
2. \[\left(\frac{a}{b}\right)^n = \frac{a^n}{b^n}\]
e.g. \[\left(\frac{a^{-3}}{b^4}\right)^6 = \frac{(a^{-3})^6}{(b^4)^6} = \frac{a^{-18}}{b^{24}} \text{ and } \left(\frac{5^7}{3^{-4}}\right)^{-3} = \frac{5^{-21}}{3^{12}}\]
3. a0 = 1; if a ≠ 0
i.e. any non-zero number raised to the power zero is always equal to one (1).
e.g. 50 = 1, 70 = 1, (-8)0 = 1, (2-5)0 = 1 and so on.
4. a-m = \[\frac{1}{a^m}\] and \[\frac{1}{a^{-m}}\] = am; if a ≠ 0
e.g. 2-3 = \[\frac{1}{2^3}\], 5-7 = \[\frac{1}{5^7}\], \[\frac{1}{2^{-3}}\] = 23, \[\frac{3^5}{2^3}\] and so on.
5. \[\sqrt[n]{a} = a^{\frac{1}{n}}\] and \[\sqrt[n]{a^m} = a^{\frac{m}{n}}\]
e.g. \[\sqrt{5} = 5^{\frac{1}{2}}\], \[\sqrt[6]{5^7} = 5^{\frac{7}{6}}\], \[\sqrt[3]{a^2 \times b^4} = a^{\frac{2}{3}} \times b^{\frac{4}{3}}\], etc.
Also remember that:
(i) (-a)m = am; if m is even
e.g. (-5)4 = -5 × -5 × -5 × -5 = 54
(ii) (-a)m = -am; if m is odd.
e.g. (-5)3 = -5 × -5 × -5 = -53
Test Yourself
8. (a2b-3)4 = ..............................
9. (b-4x2)-2 = ......................................
10. (3x2y)2 = ................................
11. \[\left(\frac{5m^2}{2n^3}\right)^3 = ......................................\]
12. \[\left(\frac{2a}{b^2}\right)^5 = ...............................\]
13. \[\left(x^{\frac{2}{3}} \cdot y^{\frac{-3}{2}}\right)^6 = ................................\]
14. (a2b)-2.(ab)-3 = .................................... = ..................
15. (1253)0 = .............
16. (-2)5 × (-2)3 = ................... = ..................
Teacher's Note
Exponent rules simplify calculations in physics and chemistry, such as measuring pH levels or calculating half-lives of radioactive materials.
Example 1:
Evaluate:
(i) \[4^{\frac{3}{2}} \times 125^{\frac{-2}{3}}\]
(ii) \[\left(\frac{8}{27}\right)^{\frac{2}{3}} + (32)^{\frac{-2}{5}}\]
(iii) -24 - \[(\sqrt{3})^0\] × (-2)6 ÷ 4
Solution:
(i) \[4^{\frac{3}{2}} \times 125^{\frac{-2}{3}} = (2^2)^{\frac{3}{2}} \times (5^3)^{\frac{-2}{3}}\]
[4 = 2 × 2 = 22, 125 = 5 × 5 × 5 = 53]
\[= 2^3 \times 5^{-2}\]
\[= \frac{8}{5^2}\]
\[= \frac{8}{25}\]
(Ans.)
\[2 \times \frac{3}{2} = 3 \text{ and } 3 \times \frac{-2}{3} = -2\]
\[2^3 = 2 \times 2 \times 2 = 8 \text{ and } 5^{-2} = \frac{1}{5^2}\]
(ii) \[\left(\frac{8}{27}\right)^{\frac{2}{3}} + (32)^{\frac{-2}{5}} = \left(\frac{2}{3}\right)^{3 \times \frac{2}{3}} + (2^5)^{\frac{-2}{5}}\]
\[\frac{8}{27} = \frac{2 \times 2 \times 2}{3 \times 3 \times 3} = \left(\frac{2}{3}\right)^3\]
and 32 = 2 × 2 × 2 × 2 × 2 = 25
\[= \left(\frac{2}{3}\right)^2 + 2^{-2}\]
\[3 \times \frac{2}{3} = 2 \text{ and } 5 \times \frac{-2}{5} = -2\]
\[= \frac{2^2}{3^2} \times \frac{1}{2^{-2}}\]
\[\frac{1}{2^{-2}} = 2^2\]
\[= \frac{4}{9} \times 2^2\]
\[= \frac{4 \times 4}{9} = \frac{16}{9} = 1\frac{7}{9}\]
(Ans.)
(iii) Given expression
= -24 - 1 × 26 ÷ 22
= -24 - 24
= -16 - 16 = -32
[(\(\sqrt{3}\))0 = 1; (-2)6 = 26 and 4 = 2 × 2 = 22]
[26 ÷ 22 = 26-2 = 24]
(Ans.)
Teacher's Note
Learning to evaluate complex exponential expressions builds problem-solving skills useful in fields like finance for calculating compound interest and in biology for modeling population growth.
Example 2:
Simplify: \[\frac{x^{m+n} \times x^{n+l} \times x^{l+m}}{(x^m \times x^n \times x^l)^2}\]
Solution:
Given expression = \[\frac{x^{m+n+n+l+l+m}}{x^{2m} \times x^{2n} \times x^{2l}}\]
= \[\frac{x^{2m+2n+2l}}{x^{2m+2n+2l}}\] = 1
(Ans.)
Example 3:
Simplify: \[\left(\frac{x^a}{x^b}\right)^{a+b} \times \left(\frac{x^b}{x^c}\right)^{b+c} \times \left(\frac{x^c}{x^a}\right)^{c+a}\]
Solution:
Given expression = (xa-b)a + b × (xb-c)b + c × (xc-a)c + a
= x(a-b)(a + b) × x(b-c)(b + c) × x(c-a)(c + a)
= xa2 - b2 × xb2 - c2 × xc2 - a2
= xa2 - b2 + b2 - c2 + c2 - a2
= x0 = 1
(Ans.)
Teacher's Note
Simplifying complex exponent expressions like these is essential in algebra and calculus, where such manipulations appear frequently in real-world applications from engineering to computer science.
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