ICSE Class 8 Maths Chapter 13 Exponents PDF Download

Download ICSE Class 8 Mathematics Textbooks

Explore the complete ICSE textbook for Class 8 Mathematics. Tailored for the 2026-27 curriculum, this resource breaks down complex topics to help students prepare effectively for school examinations.

Access Chapter 13 Exponents for Class 8 Mathematics

Access the complete PDF for Chapter 13 Exponents below. This focused excerpt allows students to isolate specific topics for thorough review. Cross-reference your textbook exercises with our detailed ICSE Solutions for Class 8 Mathematics.

Chapter 13: Exponents

13.1 Review

Exponent

If x is a real number and n is a natural number, we know:

x × x × x × x ....... n times = xn

where xn is called an exponential expression with base x and exponent (or index, or power) n.

xn is read as 'x raised to the power n' or simply 'x to the power n'.

Laws of Exponents

1. Product Law: am × an = am + n

e.g. 37 × 34 = 37 + 4 = 311, x8 × x5 = x8 + 5 = x13 and so on.

2. Quotient Law: \[\frac{a^m}{a^n} = a^{m-n} \text{ if } m > n\]

\[= \frac{1}{a^{n-m}} \text{ if } n > m\]

e.g. \[\frac{3^7}{3^4} = 3^{7-4} = 3^3, \frac{x^5}{x^8} = \frac{1}{x^{8-5}} = \frac{1}{x^3}\] and so on.

3. Power law: (am)n = amn

e.g. (37)4 = 37 × 4 = 328, (x8)5 = x40 and so on.

Test Yourself

1. 2 × 2 × 2 × 2 .............. 15 times = .............. and is read as: ............................................

2. -5 × -5 × -5 × .............. 12 times = .............. and is read as: ......................................

3. a5 × a7 = ............., a5 × a-7 = ............., a-5 × a7 = ............ and a-5 × a-7 = ............

4. \[\frac{a^8}{a^2} = ............., \frac{a^5}{a^8} = ............., \frac{a^5}{a^{-8}} = ............. \text{ and } \frac{a^8}{a^{-5}} = .............\]

5. (a5)8 = ............., (a8)5 = ............., (a-8)5 = .............. and (a-8)-5 = ............

6. 315 × 36 × 3-10 = ............., 54 × 5-7 × 56 = ............ and 72 × 78 × 7-6 = ............

7. \[\frac{2^5 \times 2^4}{2^9} = ............., \frac{4^6 \times 4^{-3}}{4^2} = ............ \text{ and } \frac{8^5 \times 8^4}{8^{-3}} = ............\]

Teacher's Note

Understanding exponents helps us express very large numbers like the distance to stars or very small numbers like the size of atoms in a simple, compact form.

13.2 More About Exponents

1. (a × b)n = an × bn

e.g. (a5 × b-3)4 = (a5)4 × (b-3)4 = a20 × b-12 and (34 × 5-3)-2 = 3-8 × 56

2. \[\left(\frac{a}{b}\right)^n = \frac{a^n}{b^n}\]

e.g. \[\left(\frac{a^{-3}}{b^4}\right)^6 = \frac{(a^{-3})^6}{(b^4)^6} = \frac{a^{-18}}{b^{24}} \text{ and } \left(\frac{5^7}{3^{-4}}\right)^{-3} = \frac{5^{-21}}{3^{12}}\]

3. a0 = 1; if a ≠ 0

i.e. any non-zero number raised to the power zero is always equal to one (1).

e.g. 50 = 1, 70 = 1, (-8)0 = 1, (2-5)0 = 1 and so on.

4. a-m = \[\frac{1}{a^m}\] and \[\frac{1}{a^{-m}}\] = am; if a ≠ 0

e.g. 2-3 = \[\frac{1}{2^3}\], 5-7 = \[\frac{1}{5^7}\], \[\frac{1}{2^{-3}}\] = 23, \[\frac{3^5}{2^3}\] and so on.

5. \[\sqrt[n]{a} = a^{\frac{1}{n}}\] and \[\sqrt[n]{a^m} = a^{\frac{m}{n}}\]

e.g. \[\sqrt{5} = 5^{\frac{1}{2}}\], \[\sqrt[6]{5^7} = 5^{\frac{7}{6}}\], \[\sqrt[3]{a^2 \times b^4} = a^{\frac{2}{3}} \times b^{\frac{4}{3}}\], etc.

Also remember that:

(i) (-a)m = am; if m is even

e.g. (-5)4 = -5 × -5 × -5 × -5 = 54

(ii) (-a)m = -am; if m is odd.

e.g. (-5)3 = -5 × -5 × -5 = -53

Test Yourself

8. (a2b-3)4 = ..............................

9. (b-4x2)-2 = ......................................

10. (3x2y)2 = ................................

11. \[\left(\frac{5m^2}{2n^3}\right)^3 = ......................................\]

12. \[\left(\frac{2a}{b^2}\right)^5 = ...............................\]

13. \[\left(x^{\frac{2}{3}} \cdot y^{\frac{-3}{2}}\right)^6 = ................................\]

14. (a2b)-2.(ab)-3 = .................................... = ..................

15. (1253)0 = .............

16. (-2)5 × (-2)3 = ................... = ..................

Teacher's Note

Exponent rules simplify calculations in physics and chemistry, such as measuring pH levels or calculating half-lives of radioactive materials.

Example 1:

Evaluate:

(i) \[4^{\frac{3}{2}} \times 125^{\frac{-2}{3}}\]

(ii) \[\left(\frac{8}{27}\right)^{\frac{2}{3}} + (32)^{\frac{-2}{5}}\]

(iii) -24 - \[(\sqrt{3})^0\] × (-2)6 ÷ 4

Solution:

(i) \[4^{\frac{3}{2}} \times 125^{\frac{-2}{3}} = (2^2)^{\frac{3}{2}} \times (5^3)^{\frac{-2}{3}}\]

[4 = 2 × 2 = 22, 125 = 5 × 5 × 5 = 53]

\[= 2^3 \times 5^{-2}\]

\[= \frac{8}{5^2}\]

\[= \frac{8}{25}\]

(Ans.)

\[2 \times \frac{3}{2} = 3 \text{ and } 3 \times \frac{-2}{3} = -2\]

\[2^3 = 2 \times 2 \times 2 = 8 \text{ and } 5^{-2} = \frac{1}{5^2}\]

(ii) \[\left(\frac{8}{27}\right)^{\frac{2}{3}} + (32)^{\frac{-2}{5}} = \left(\frac{2}{3}\right)^{3 \times \frac{2}{3}} + (2^5)^{\frac{-2}{5}}\]

\[\frac{8}{27} = \frac{2 \times 2 \times 2}{3 \times 3 \times 3} = \left(\frac{2}{3}\right)^3\]

and 32 = 2 × 2 × 2 × 2 × 2 = 25

\[= \left(\frac{2}{3}\right)^2 + 2^{-2}\]

\[3 \times \frac{2}{3} = 2 \text{ and } 5 \times \frac{-2}{5} = -2\]

\[= \frac{2^2}{3^2} \times \frac{1}{2^{-2}}\]

\[\frac{1}{2^{-2}} = 2^2\]

\[= \frac{4}{9} \times 2^2\]

\[= \frac{4 \times 4}{9} = \frac{16}{9} = 1\frac{7}{9}\]

(Ans.)

(iii) Given expression

= -24 - 1 × 26 ÷ 22

= -24 - 24

= -16 - 16 = -32

[(\(\sqrt{3}\))0 = 1; (-2)6 = 26 and 4 = 2 × 2 = 22]

[26 ÷ 22 = 26-2 = 24]

(Ans.)

Teacher's Note

Learning to evaluate complex exponential expressions builds problem-solving skills useful in fields like finance for calculating compound interest and in biology for modeling population growth.

Example 2:

Simplify: \[\frac{x^{m+n} \times x^{n+l} \times x^{l+m}}{(x^m \times x^n \times x^l)^2}\]

Solution:

Given expression = \[\frac{x^{m+n+n+l+l+m}}{x^{2m} \times x^{2n} \times x^{2l}}\]

= \[\frac{x^{2m+2n+2l}}{x^{2m+2n+2l}}\] = 1

(Ans.)

Example 3:

Simplify: \[\left(\frac{x^a}{x^b}\right)^{a+b} \times \left(\frac{x^b}{x^c}\right)^{b+c} \times \left(\frac{x^c}{x^a}\right)^{c+a}\]

Solution:

Given expression = (xa-b)a + b × (xb-c)b + c × (xc-a)c + a

= x(a-b)(a + b) × x(b-c)(b + c) × x(c-a)(c + a)

= xa2 - b2 × xb2 - c2 × xc2 - a2

= xa2 - b2 + b2 - c2 + c2 - a2

= x0 = 1

(Ans.)

Teacher's Note

Simplifying complex exponent expressions like these is essential in algebra and calculus, where such manipulations appear frequently in real-world applications from engineering to computer science.

This is a preview of the first 3 pages. To get the complete book, click below.

Chapter 13 Exponents Digital Textbook & Resources for Class 8 Mathematics

Download Textbook: Chapter 13 Exponents (Class 8 Mathematics)

Secure your copy of the ICSE Textbook for Class 8 Mathematics Chapter 13 Exponents. Widely adopted across educational institutions, final question papers map directly to the framework outlined in this chapter.

Complete Chapter E-Books for Class 8 Mathematics

Explore our exhaustive library of ICSE books in English Medium spanning all subjects in Class 8. Every chapter features comprehensive explanations followed by extensive end-of-chapter exercises.

Maximize Conceptual Clarity with ICSE E-Books

Elevate your study routine by reviewing our comprehensive NCERT Solutions and revision notes available on our platform free of charge.

FAQs

Where can I download the latest ICSE Class 8 Maths Chapter 13 Exponents PDF Download in PDF for 2026-27?

You can download the latest, teacher-verified PDF for ICSE Class 8 Maths Chapter 13 Exponents PDF Download for free on StudiesToday.com. These digital editions are updated as per 2026-27 session and are optimized for mobile reading.

Does this Mathematics book follow the latest ICSE rationalized syllabus?

Yes, our collection of Class 8 Mathematics ICSE books follow the 2026 rationalization guidelines. All deleted chapters have been removed and has latest content for you to study.

Why is it better to download ICSE Class 8 Maths Chapter 13 Exponents PDF Download chapter-wise?

Downloading chapter-wise PDFs for Class 8 Mathematics allows for faster access, saves storage space, and makes it easier to focus in 2026 on specific topics during revision.

Are these ICSE books for Class 8 Mathematics sufficient for scoring 100%?

ICSE books are the main source for ICSE exams. By reading ICSE Class 8 Maths Chapter 13 Exponents PDF Download line-by-line and practicing its questions, students build strong understanding to get full marks in Mathematics.