Read and download the Chapter 25 Symmetry PDF from the official ICSE Book for Class 7 Mathematics. Updated for the 2026-27 academic session, you can access the complete Mathematics textbook in PDF format for free.
ICSE Class 7 Mathematics Chapter 25 Symmetry Digital Edition
For Class 7 Mathematics, this chapter in ICSE Class 7 Maths Chapter 25 Symmetry provides a detailed overview of important concepts. We highly recommend using this text alongside the ICSE Solutions for Class 7 Mathematics to learn the exercise questions provided at the end of the chapter.
Chapter 25 Symmetry ICSE Book Class Class 7 PDF (2026-27)
Chapter 25
Symmetry
Including Reflection and Rotation
25.1 Review
Concept of symmetry is already done in Class VI.
Revision: A geometrical figure is said to be symmetric about a line in it, if on folding the figure about this line, the two parts of the figure exactly coincide.
The adjoining figure shows a quadrilateral ABCD and a line PQ in it. If the figure is folded about the line PQ and the two parts of the figure coincide, i.e., A and D coincide, B and C coincide, AB and DC coincide and so on, then the whole figure is said to be symmetric about the line PQ.
If the figure is symmetric about a line in it, the line is said to be a line of symmetry or an axis of symmetry. Thus, in the figure ABCD, discussed above, line PQ is the line of symmetry of ABCD.
25.2 Lines of Symmetry of Given Geometrical Figures
It is not necessary that every figure under consideration will definitely have a line of symmetry. If we consider different types of triangle, we find:
1. A scalene triangle has no line of symmetry:
We can not have a line in a scalene triangle about which if the figure (triangle) is folded, the two parts of the figure will coincide.
2. An isosceles triangle has only one line of symmetry.
The bisector of angle of vertex which is also the perpendicular bisector of its base.
3. An equilateral triangle has three lines of symmetry.
The bisectors of the angle of vertices which are also the perpendicular bisectors of its sides.
4. Line(s) of symmetry of different types of quadrilaterals are shown below by dotted lines:
(i) [No line of symmetry]
(ii) Parallelogram [No line of symmetry]
(iii) Rectangle [Two lines of symmetry]
(iv) Rhombus [Two lines of symmetry]
(v) Square [Four lines of symmetry]
(vi) Kite-shaped figure [One line of symmetry]
(vii) Trapezium [No line of symmetry]
(viii) Isosceles trapezium [One line of symmetry]
5. In each of the following, the dotted line/lines are the line(s) of symmetry of the given figure:
(i) [A semi-circle with a vertical dotted line through its diameter]
(ii) [A rectangle with horizontal and vertical dotted lines through its center]
(iii) [A curved hourglass shape with a vertical dotted line]
(iv) [A bowtie shape with horizontal and vertical dotted lines]
(v) [A triangle with a vertical dotted line through its apex]
(vi) [A triangle with a vertical dotted line through its apex]
(vii) [Three vertical parallel dotted lines]
(viii) [A triangle with dotted lines showing reflection]
6. As shown below,
(i) a circle has infinite lines of symmetry; every line through its centre.
(ii) a semi-circle has one line of symmetry.
(iii) a quadrant (one-fourth) of a circle has one line of symmetry and so on.
(i) [A circle with multiple dotted lines through its center]
(ii) [A semi-circle with a vertical dotted line]
(iii) [A quadrant with a diagonal dotted line] [A quadrant]
Exercise 25 (A)
1. For each figure, given below, draw the line(s) of symmetry, if possible:
(i) [A rectangle with a curved indentation on one side]
(ii) [A right-angled triangle]
(iii) [A right-angled triangle]
(iv) [A T-shaped figure]
(v) [An arrow pointing right]
(vi) [A circle with a triangle on the right]
(vii) [An isosceles triangle]
(viii) [An arrow pointing right]
2. Write capital letters A to Z of English alphabet and in each case, if possible, draw the largest number of lines of symmetry.
3. By drawing a free hand sketch of each of the following, draw in each case, the line(s) of symmetry, if any:
(i) a scalene triangle
(ii) an isosceles right angled triangle
(iii) a rhombus
(iv) a kite shaped figure
(v) a rectangle
(vi) a square
(vii) an isosceles triangle.
4. Draw a triangle with:
(i) no line of symmetry,
(ii) only one line of symmetry,
(iii) exactly two lines of symmetry,
(iv) exactly three lines of symmetry,
(v) more than three lines of symmetry.
In each case, if possible, represent the line(s) of symmetry by dotted lines. Also, write the special name of the triangle drawn.
5. Draw a quadrilateral with:
(i) no line of symmetry.
(ii) only one line of symmetry.
(iii) exactly two lines of symmetry.
(iv) exactly three lines of symmetry.
(v) exactly four lines of symmetry.
(vi) more than four lines of symmetry.
In each case, if possible, represent the line(s) of symmetry by dotted lines. Also, write the special name of the quadrilateral drawn
It is clear from the question numbers 4 and 5, given above, that:
1. The largest number of lines of symmetry of a triangle is three (3).
2. The largest number of lines of symmetry of a quadrilateral is four (4).
As the number of sides in a triangle is 3, the largest number of lines of symmetry in it is 3 and as the number of sides in a quadrilateral is 4, the largest number of lines of symmetry in it is 4.
In the same way:
1. The largest number of lines of symmetry of a pentagon is 5, as a pentagon has 5 sides.
2. The hexagon has 6 sides and so the largest number of lines of symmetry of a hexagon is 6.
In general, we can say, that if a polygon has n sides, the largest number of lines of symmetry, it can have is n.
6. Construct an equilateral triangle with each side 6 cm. In the triangle drawn, draw all possible lines of symmetry.
7. Construct a triangle ABC in which AB = AC = 5 cm and BC = 5.6 cm. If possible, draw its lines of symmetry.
8. Construct a triangle PQR such that PQ = QR = 5.5 cm and angle PQR = 90°. If possible, draw its lines of symmetry.
9. If possible, draw a rough sketch of a quadrilateral which has exactly two lines of symmetry.
10. A quadrilateral ABCD is symmetric about its diagonal AC. Name the sides of this quadrilateral which are equal.
Teacher's Note
Symmetry is visible in nature - from butterfly wings to snowflakes to human faces. Understanding symmetry helps us appreciate the balance and harmony in the world around us and is fundamental to design, art, and architecture.
25.3 Reflection
In physics, we have studied that if any object is placed at a certain distance before a plane mirror, its image is formed at the same distance behind the mirror.
The given figure shows a candle placed at a distance 'd' before a plane mirror MM'. The image of the candle is obtained in the mirror at the same distance 'd' behind the mirror.
If we see, geometrically, the line joining the candle (C) and its image (C') is perpendicularly bisected by the mirror line MM'.
Now if we want to find the image of a point P in line AB, we consider the point P as an object, the line AB as plane mirror and we find point P' on the other side of AB so that PP' is perpendicularly bisected by AB.
For this, from the given point P, draw perpendicular to AB which meets AB at point O. From PO produced, cut OP' = OP.
P' is the reflection (image) of the given point P in the line AB.
Example 1:
The given figure shows a line segment AB and a line l.
1. Find, geometrically, the reflection of AB in the line l.
Solution:
From the point A, draw AO perpendicular to the line l and from AO produced cut OA' such that OA' = OA.
In the same way, from the point B, draw BP perpendicular to the line l and from BP produced cut PB' such that BP = PB.
Join A' and B'.
A' B' is the required reflection of AB in line the l.
Teacher's Note
When you look in a mirror, you see your reflection - a flipped version of yourself. Understanding geometric reflection helps explain why mirrors reverse left and right, and is used in designing optics, telescopes, and even in understanding how light behaves.
25.4 Reflection In X-Axis
Reflection in x-axis means the x-axis is considered as the plane mirror, the given point as the object and then we find (calculate) its image.
Let P (x, y) be a point as shown in the figure. When it is reflected in x-axis to point P', the co-ordinates of image point P' are (x, -y).
Thus, reflection of P (x, y) in x-axis = P' (x, -y)
In other words:
Image of P (x, y) in x-axis = P' (x, -y)
We can say, when a point (x, y) is reflected in x-axis, the sign of its second component (ordinate) changes, i.e., the sign of y changes and so the image of (x, y) in x-axis is (x, -y).
(i) Reflection of (5, 4) in x-axis = (5, -4)
(ii) Image of (-5, 4) in x-axis = (-5, -4)
(iii) Image of (-5, -4) in x-axis = (-5, 4)
(iv) Image of (-8, 5) in x-axis = (-8, -5)
(v) Reflection of (3, 0) in x-axis = (3, 0)
(vi) Reflection of (0, -6) in x-axis = (0, 6)
(vii) Reflection of (0, 0) in x-axis = (0, 0) and so on.
25.5 Reflection In Y-Axis
As it is clear from the figure, given alongside, the reflection P (x, y) in y-axis is point P' (-x, y).
We can say, when a point (x, y) is reflected in y-axis, the sign of its first component (abscissa) changes, i.e., x changes and so the image of (x, y) in y-axis is (-x, y).
(i) Image of (5, 4) in y-axis = (-5, 4)
(ii) Reflection of (5, -4) in y-axis = (-5, -4)
(iii) Reflection of (-5, -4) in y-axis = (5, -4)
(iv) Image of (-8, 5) in y-axis = (8, 5)
(v) Image of (3, 0) in y-axis = (-3, 0)
(vi) Reflection of (0, -6) in y-axis = (0, -6)
(vii) Reflection of (0, 0) in y-axis = (0, 0) and so on.
25.6 Reflection In Origin
When point P (x, y) is reflected in origin, the signs of both of its components change, i.e., the image of P (x, y) is P' (-x, -y) as shown alongside.
(i) Image of (5, 4) in origin = (-5, -4)
(ii) Reflection of (5, -4) in origin = (-5, 4)
(iii) Image of (-5, -4) in origin = (5, 4)
(iv) Reflection of (-8, 5) in origin = (8, -5)
(v) Image of (3, 0) in origin = (-3, 0)
(vi) Reflection of (0, -6) in origin = (0, 6)
(vii) Reflection of (0, 0) in origin = (0, 0) and so on.
Exercise 25 (B)
1. In each figure, given below, find the image of the point P in the line AB:
(i) [A diagram showing point P and line AB]
(ii) [A diagram showing point P and line AB]
2. In each figure, given below, find the image of the line segment AB in the line PQ:
(i) [A diagram showing line segment AB and line PQ]
(ii) [A diagram showing line segment AB and line PQ]
3. Complete the following table:
| Point | Reflection in | ||
|---|---|---|---|
| x-axis | y-axis | origin | |
| (i) (8, 2) | ............................. | ............................. | ............................. |
| (ii) (5, 6) | ............................. | ............................. | ............................. |
| (iii) (4, -5) | ............................. | ............................. | ............................. |
| (iv) (6, -2) | ............................. | ............................. | ............................. |
| (v) (-3, 7) | ............................. | ............................. | ............................. |
| (vi) (-4, 5) | ............................. | ............................. | ............................. |
| (vii) (-2, -7) | ............................. | ............................. | ............................. |
| (viii) (-6, -3) | ............................. | ............................. | ............................. |
| (ix) (4, 0) | ............................. | ............................. | ............................. |
| (x) (-7, 0) | ............................. | ............................. | ............................. |
| (xi) (0, -6) | ............................. | ............................. | ............................. |
| (xii) (0, 8) | ............................. | ............................. | ............................. |
| (xiii) (0, 0) | ............................. | ............................. | ............................. |
4. A point P (7, 3) is reflected in x-axis to point P'. The point P' is further reflected in y-axis to point P''. Find:
(i) the co-ordinates of P'
(ii) the co-ordinates of P''
(iii) the image of P (7, 3) in origin.
5. A point A (-5, 4) is reflected in y-axis to point B. The point B is further reflected in origin to point C. Find:
(i) the co-ordinates of B
(ii) the co-ordinates of C
(iii) the image of A (-5, 4) in x-axis.
6. The point P (3, -8) is reflected in origin to point Q. The point Q is further reflected in x-axis to point R. Find:
(i) the co-ordinates of Q
(ii) the co-ordinates of R
(iii) the image of P (3, -8) in y-axis.
7. Each of the points A (3, 0), B (7, 0), C (-8, 0), D (-7, 0) and E (0, 0) is reflected in x-axis to points A', B', C', D' and E' respectively. Write the co-ordinates of each of the image points A', B', C', D' and E'.
8. Each of the points A (0, 4), B (0, 10), C (0, -4), D (0, -6) and E (0, 0) is reflected in y-axis to points A', B', C', D' and E' respectively. Write the co-ordinates of each of the image points A', B', C', D' and E'.
9. Each of the points A (0, 7), B (8, 0), C (0, -5), D (-7, 0) and E (0, 0) is reflected in origin to points A', B', C', D' and E' respectively. Write the co-ordinates of each of the image points A', B', C', D' and E'.
10. Mark points A (4, 5) and B (-5, 4) on a graph paper. Find A', the image of A in x-axis and B', the image of B in x-axis. Mark A' and B' also on the same graph paper. Join AB and A' B'.
Is AB = A' B' ?
11. Mark points A (6, 4) and B (4, -6) on a graph paper. Find A', the image of A in y-axis and B', the image of B in y-axis. Mark A' and B' also on the same graph paper.
12. Mark points A (-6, 5) and B (-4, -6) on a graph paper. Find A', the image of A in origin and B', the image of B in origin. Mark A' and B' also on the same graph paper. Join AB and A' B'. Is AB = A' B' ?
Teacher's Note
Reflection is used daily in photography, video editing, and even in designing buildings with mirror facades. Understanding how points transform under reflection helps in computer graphics, creating symmetrical designs, and solving real-world problems in architecture and engineering.
25.6 Rotation
Consider a triangle ABC which is free to rotate about its vertex A.
1. Let a rotation of 60° be given to this triangle about vertex A. in the clockwise direction so that the new position of the triangle is triangle AB'C' as shown alongside:
Each and every part of the given triangle will get rotated through 60° in the clockwise direction in such a way that the shapes and sizes of both the triangles are the same.
i.e., angle B'A'C' = angle BAC, angle AB'C' = angle ABC and angle AC'B' = angle ACB
And, AB' = AB, B'C' = BC and AC' = AC.
2. Now, let the given triangle ABC be rotated about vertex A through an angle of 60° in the anticlockwise direction and the resulting position of it be triangle AB''C''.
Clearly, the shapes and size of the two triangles are the same and so:
angle B''AC'' = angle BAC; angle AB''C'' = angle ABC and angle AC''B'' = angle ACB
And, AB'' = AB, AC'' = AC and B''C'' = BC.
1. Whatever be the angle of rotation of the figure, the resulting figure and the given figure are always same in shape and size.
2. The point, about which the figure is rotated, is called the centre of rotation.
This is a preview of the first 3 pages. To get the complete book, click below.
Free study material for Mathematics
ICSE Book Class 7 Mathematics Chapter 25 Symmetry
Download the official ICSE Textbook for Class 7 Mathematics Chapter 25 Symmetry, updated for the latest academic session. These e-books are the main textbook used by major education boards across India. All teachers and subject experts recommend the Chapter 25 Symmetry NCERT e-textbook because exam papers for Class 7 are strictly based on the syllabus specified in these books. You can download the complete chapter in PDF format from here.
Download Mathematics Class 7 NCERT eBooks in English
We have provided the complete collection of ICSE books in English Medium for all subjects in Class 7. These digital textbooks are very important for students who have English as their medium of studying. Each chapter, including Chapter 25 Symmetry, contains detailed explanations and a detailed list of questions at the end of the chapter. Simply click the links above to get your free Mathematics textbook PDF and start studying today.
Benefits of using ICSE Class 7 Textbooks
The Class 7 Mathematics Chapter 25 Symmetry book is designed to provide a strong conceptual understanding. Students should also access NCERT Solutions and revision notes on studiestoday.com to enhance their learning experience.
FAQs
You can download the latest, teacher-verified PDF for ICSE Class 7 Maths Chapter 25 Symmetry for free on StudiesToday.com. These digital editions are updated as per 2026-27 session and are optimized for mobile reading.
Yes, our collection of Class 7 Mathematics NCERT books follow the 2026 rationalization guidelines. All deleted chapters have been removed and has latest content for you to study.
Downloading chapter-wise PDFs for Class 7 Mathematics allows for faster access, saves storage space, and makes it easier to focus in 2026 on specific topics during revision.
NCERT books are the main source for ICSE exams. By reading ICSE Class 7 Maths Chapter 25 Symmetry line-by-line and practicing its questions, students build strong understanding to get full marks in Mathematics.