Download CTET MCQs for CTET : Science
Access targeted multiple-choice questions for Science designed to align with the latest CTET academic syllabus for CTET . These objective practice sets help students evaluate their conceptual understanding and improve exam readiness.
Chapter-wise Objective Questions: Science
Access the complete set of multiple-choice questions for Science below. This focused format allows students to isolate specific topics for thorough review and uninterrupted practice alongside official CTET textbooks.
These 30 CTET Science Paper 2 multiple choice questions cover science content and pedagogy of science. Each question has the correct answer with a step-by-step explanation and a short teacher's note, so you can practise for the Central Teacher Eligibility Test and check your understanding.
Multiple Choice Questions
(a) Conversion of nitrogen compounds into gaseous nitrogen
(b) Conversion of ammonia into nitrates by the bacteria present in soil
(c) Release of nitrogen present in dead organic matter back into soil
(d) Conversion of atmospheric nitrogen to a more usable form for living organisms
Show Answer & Explanation
Answer: (d) Conversion of atmospheric nitrogen to a more usable form for living organisms
Explanation:
1. Nitrogen fixation converts inert atmospheric nitrogen (N₂) into compounds such as ammonia or nitrates.
2. Rhizobium, Azotobacter and lightning do this, so plants can absorb the nitrogen.
Teacher's Note:
1. Option (a) describes denitrification and option (b) describes nitrification.
2. Remember: fixation means taking N₂ from the air into a usable form.
(a) The spring is neither compressed nor pulled out and is lying on the ground.
(b) The spring is compressed to the minimum and is lying on the ground.
(c) The spring is compressed to the minimum and is placed at a height.
(d) The spring is pulled out to the maximum and is placed at a height.
Show Answer & Explanation
Answer: (a) The spring is neither compressed nor pulled out and is lying on the ground.
Explanation:
1. Elastic potential energy is zero when the spring is in its natural length, neither compressed nor stretched.
2. On the ground there is no gravitational potential energy either, so the total is least in option (a).
Teacher's Note:
1. Both compression and stretching store elastic energy.
2. Height adds gravitational potential energy, so check both kinds.
(a) kg m/s², Nm
(b) kg m²/s², Ws
(c) kg m/s², Ws
(d) kg m²/s², J/s
Show Answer & Explanation
Answer: (b) kg m²/s², Ws
Explanation:
1. 1 J = 1 N m = 1 kg m²/s², and 1 Ws = 1 W × 1 s = 1 J.
2. So kg m²/s² and Ws are both units of energy (work).
3. kg m/s² is the newton (force) and J/s is the watt (power), so the other pairs differ.
Teacher's Note:
1. Reduce each unit to base units before comparing.
2. Watt-second and kilowatt-hour are units of energy, not power.
W, X, Y, Z respectively are :
(a) zygote, foetus, uterus, embryo
(b) zygote, embryo, uterus, foetus
(c) embryo, zygote, fallopian tube, foetus
(d) Zygote, foetus, fallopian tube, embryo
Show Answer & Explanation
Answer: (b) zygote, embryo, uterus, foetus
Explanation:
1. The fused sperm and egg form a zygote (W), which divides to form the developing embryo (X).
2. The embryo implants in the wall of the uterus (Y).
3. When all body parts can be identified, the stage is called the foetus (Z).
Teacher's Note:
1. The order of stages is zygote, embryo, foetus.
2. Fertilisation occurs in the fallopian tube but implantation occurs in the uterus.
(a) PbSO₄ + Fe
(b) Al + CuSO₄
(c) Zn + CaSO₄
(d) Mg + ZnSO₄
Show Answer & Explanation
Answer: (c) Zn + CaSO₄
Explanation:
1. A metal displaces another from its salt only if it is more reactive than that metal.
2. Fe > Pb, Al > Cu and Mg > Zn, so (a), (b) and (d) occur.
3. Zn is less reactive than Ca, so Zn cannot displace Ca from CaSO₄.
Teacher's Note:
1. Use the reactivity series: K, Na, Ca, Mg, Al, Zn, Fe, Pb, H, Cu, Ag, Au.
2. The metal must be above the one it is replacing.
A. Distance - time graph of a body at rest
B. Velocity - time graph of a body moving with uniform acceleration
C. Distance - time graph of a body moving with uniform acceleration
D. Velocity - time graph of a body at rest
Choose the correct option:
(a) A, B and D
(b) A, B and C
(c) C and D
(d) A and B
Show Answer & Explanation
Answer: (a) A, B and D
Explanation:
1. At rest, distance is constant (horizontal line) and velocity is zero (line along the time axis), so A and D are straight.
2. For uniform acceleration v = u + at, a straight line, so B is straight.
3. Distance s = ut + ½at² is a parabola, so C is curved.
Teacher's Note:
1. Uniform acceleration gives a straight v-t graph but a curved s-t graph.
2. A line along the time axis still counts as a straight line.
Assertion (A) : Electric current is a vector quantity.
Reason (R) : Electric current is a quantity having magnitude as well as direction.
(a) (A) is true, but (R) is false.
(b) Both (A) and (R) are true, but (R) is not the correct explanation of (A).
(c) (A) is false, but (R) is true.
(d) Both (A) and (R) are true and (R) is the correct explanation of (A).
Show Answer & Explanation
Answer: (c) (A) is false, but (R) is true.
Explanation:
1. Current has magnitude and a direction of flow, so R is true as a statement.
2. But it does not obey the vector addition law (triangle law), so it is a scalar and A is false.
Teacher's Note:
1. Having direction is not enough to make a quantity a vector; it must add by the vector rules.
2. Current, pressure and surface-tension are other direction-like scalars.
A. Plastids
B. Mitochondria
C. Nucleus
D. Vacuole
Choose the correct option:
(a) C and D
(b) B and C
(c) A, B and C
(d) A, B and D
Show Answer & Explanation
Answer: (c) A, B and C
Explanation:
1. The nucleus holds the main DNA of the cell.
2. Mitochondria and plastids have their own circular DNA and ribosomes.
3. Vacuoles contain no DNA.
Teacher's Note:
1. Mitochondria and plastids are semi-autonomous organelles.
2. This supports the endosymbiotic origin of these organelles.
Column A: a. Plastic bottle, b. Silk scarf, c. Cotton shirt, d. Banana peel, e. Paper
Column B: i. 2 - 5 months, ii. 1 - 2 weeks, iii. 10 - 30 days, iv. 4 years, v. Several years
Choose the correct option:
(a) a-iv, b-v, c-iii, d-i, e-ii
(b) a-v, b-iv, c-i, d-ii, e-iii
(c) a-iv, b-v, c-ii, d-i, e-iii
(d) a-v, b-i, c-ii, d-iii, e-iv
Show Answer & Explanation
Answer: (b) a-v, b-iv, c-i, d-ii, e-iii
Explanation:
1. Plastic takes several years (v); silk takes about 4 years (iv); cotton takes 2-5 months (i).
2. Banana peel takes 1-2 weeks (ii) and paper takes 10-30 days (iii).
3. This matches a-v, b-iv, c-i, d-ii, e-iii.
Teacher's Note:
1. Plastic is non-biodegradable and lasts the longest.
2. Natural fibres and food waste decompose faster.
(a) Zero
(b) 1.47 N
(c) 14.7 N
(d) 147 N
Show Answer & Explanation
Answer: (a) Zero
Explanation:
1. Constant velocity means zero acceleration.
2. By Newton's second law, net force = mass × acceleration = 0.
3. Air resistance exactly balances the weight.
Teacher's Note:
1. Do not multiply mass by g here; weight is not the net force once drag balances it.
2. Falling at constant (terminal) velocity means balanced forces.
(a) 14, 13 and 10
(b) 10, 13 and 14
(c) 13, 13 and 10
(d) 13, 10 and 14
Show Answer & Explanation
Answer: (d) 13, 10 and 14
Explanation:
1. Protons = atomic number = 13.
2. The 3+ ion has lost 3 electrons, so electrons = 13 − 3 = 10.
3. Neutrons = 27 − 13 = 14.
Teacher's Note:
1. Ionisation changes electrons only, never protons or neutrons.
2. Neutrons = mass number − atomic number.
- She puts two teaspoonfuls of distilled water and few drops of hydrochloric acid in A.
- She puts two teaspoonfuls of distilled water and some caustic soda in B.
- She puts two teaspoonfuls of distilled water and some sugar in C.
Which of the above solutions will conduct electricity?
(a) Only C
(b) A & B
(c) Only A
(d) A and C
Show Answer & Explanation
Answer: (b) A & B
Explanation:
1. HCl in water gives H⁺ and Cl⁻ ions, and caustic soda (NaOH) gives Na⁺ and OH⁻ ions, so A and B conduct.
2. Sugar dissolves as molecules and gives no ions, so C does not conduct.
Teacher's Note:
1. Distilled water alone does not conduct.
2. Acids, bases and salts conduct in solution; sugar and alcohol do not.
S₁: We will not experience any gravitational force on the surface of moon.
S₂: There is no oxygen on the surface of moon.
(a) Both S₁ and S₂ are true and S₂ is the correct reason for S₁
(b) Both S₁ and S₂ are true but S₂ is not the correct reason for S₁
(c) S₁ is incorrect and S₂ is correct
(d) Both S₁ and S₂ are incorrect
Show Answer & Explanation
Answer: (c) S₁ is incorrect and S₂ is correct
Explanation:
1. The moon has gravity about one sixth of the earth's, so S₁ is incorrect.
2. The moon has no atmosphere and so no oxygen, so S₂ is correct.
Teacher's Note:
1. Weak gravity is not zero gravity.
2. The moon's low gravity is why it cannot hold an atmosphere.
(A) so that they can be pulled out easily.
(B) they do not need long roots to absorb water.
(C) they do not need to absorb minerals
(D) it keeps them afloat in water
(a) (A) & (B)
(b) Only (B)
(c) (B) & (D)
(d) Only (C)
Show Answer & Explanation
Answer: (b) Only (B)
Explanation:
1. Aquatic plants are surrounded by water, which they absorb over the whole body surface.
2. So they do not need long roots; they still absorb minerals, and roots do not decide floating.
Teacher's Note:
1. Roots in such plants mainly act as anchors or are reduced.
2. Avoid statements that suggest a plant is built for human convenience.
(a) A curved line with steadily increasing slope
(b) A straight line parallel to the time-axis
(c) A straight line at a constant finite slope with time-axis
(d) A straight line parallel to the velocity-axis
Show Answer & Explanation
Answer: (b) A straight line parallel to the time-axis
Explanation:
1. The slope of a velocity-time graph equals acceleration.
2. Zero acceleration means zero slope, a straight line parallel to the time axis.
Teacher's Note:
1. A line parallel to the velocity axis is not possible for a moving body.
2. A constant finite slope means uniform acceleration.
(a) Both Raman & Shiksha are at 6 m from the mirror
(b) Raman is at 10 m and Shiksha is at 6 m from the mirror
(c) Raman is at 5 m and Shiksha is at 6 m from the mirror
(d) Both Raman & Shiksha are 5 m from the mirror
Show Answer & Explanation
Answer: (d) Both Raman & Shiksha are 5 m from the mirror
Explanation:
1. In a plane mirror the image is as far behind as the object is in front, so Raman's distance = 10 ÷ 2 = 5 m.
2. Shiksha is now 11 − 6 = 5 m from the mirror.
Teacher's Note:
1. Object-to-image distance is twice the object distance.
2. A common mistake is to take 10 m as the distance from the mirror.
(a) Carbon dioxide
(b) Carbon monoxide
(c) Nitrogen oxide
(d) Sulphur dioxide
Show Answer & Explanation
Answer: (b) Carbon monoxide
Explanation:
1. Incomplete combustion with limited oxygen forms carbon monoxide (CO).
2. CO binds haemoglobin more strongly than oxygen, lowering oxygen transport.
Teacher's Note:
1. Complete combustion gives CO₂.
2. Never use a coal or charcoal heater in a closed room.
(a) Sliding friction > Rolling friction > Static friction
(b) Static friction > Sliding friction > Rolling friction
(c) Static friction > Sliding friction = Rolling friction
(d) Rolling friction > Sliding friction > Static friction
Show Answer & Explanation
Answer: (b) Static friction > Sliding friction > Rolling friction
Explanation:
1. Static friction (limiting) is greater than sliding (kinetic) friction.
2. Rolling friction is the smallest of the three.
Teacher's Note:
1. It takes more force to start an object moving than to keep it moving.
2. This is why wheels and ball bearings reduce friction.
(a) Manually uproot the weeds
(b) Manually remove he flowers and seeds
(c) Burn the stubble after harvesting the crop
(d) Spray weedicide
Show Answer & Explanation
Answer: (a) Manually uproot the weeds
Explanation:
1. Uprooting weeds by hand removes the whole plant without chemicals.
2. Weedicides can harm crops, soil and farmers, and burning stubble pollutes the air.
Teacher's Note:
1. Removing only flowers and seeds leaves the weed alive.
2. Weeding should be done before the weeds flower and set seed.
(a) The activity should provide fun and enjoyment to the students
(b) The activity should help students break away from learning from the textbook
(c) The activity should provide some opportunities for hands on experiences.
(d) The activity should lead to conceptual understanding
Show Answer & Explanation
Answer: (d) The activity should lead to conceptual understanding
Explanation:
1. The purpose of any science activity is to build understanding of concepts.
2. Fun, hands-on work and variety are useful, but only if they lead to conceptual understanding.
Teacher's Note:
1. An activity that is merely fun may not teach the concept.
2. Always ask what the learner will understand at the end.
(a) Frequency of vibration of roar of lion is higher as compared to birds' sound.
(b) Frequency of vibration of roar of lion and birds' sound is same.
(c) Amplitude of vibration of roar of lion is larger as compared to bird's sound.
(d) Amplitude of vibration of roar of lion is low as compared to sound of bird.
Show Answer & Explanation
Answer: (c) Amplitude of vibration of roar of lion is larger as compared to bird's sound.
Explanation:
1. Loudness depends on the amplitude of vibration.
2. A lion's roar has a larger amplitude, so it is louder.
Teacher's Note:
1. Pitch (shrillness) depends on frequency, not loudness.
2. A bird's sound has a higher frequency, but a smaller amplitude.
(a) Vitamin D
(b) Vitamin C
(c) Vitamin B
(d) Vitamin K
Show Answer & Explanation
Answer: (a) Vitamin D
Explanation:
1. Vitamin D helps the intestine absorb calcium.
2. Its deficiency causes poor calcium absorption, leading to rickets in children.
Teacher's Note:
1. Sunlight helps the skin make vitamin D.
2. Vitamin C deficiency gives scurvy and vitamin K deficiency affects blood clotting.
(a) Bringing the magnet close to a piece of iron.
(b) Dipping the magnet in a heap of iron filings.
(c) Bringing the magnet close to another magnet.
(d) Freely suspending the magnet from the middle.
Show Answer & Explanation
Answer: (d) Freely suspending the magnet from the middle.
Explanation:
1. A freely suspended magnet comes to rest along the north-south direction.
2. The end pointing north is the north pole.
Teacher's Note:
1. Iron is attracted by both poles, so it cannot tell them apart.
2. Bringing it near another magnet needs a magnet with known poles.
A. Identify a mammal from a picture of 4 animals.
B. Find out if ice cubes melt at the same rate in hot and cold water.
C. Enlist various units to measure temperature.
D. Explore factors which determine the floating or sinking of objects in liquids.
(a) C and D
(b) A and D
(c) Only D
(d) B and D
Show Answer & Explanation
Answer: (d) B and D
Explanation:
1. Inquiry involves investigating a question by testing, comparing or exploring.
2. B (comparing melting rates) and D (exploring factors for floating) are investigations.
3. A and C only need identification or recall.
Teacher's Note:
1. Look for tasks that need the learner to question, plan and test.
2. Listing and identifying tasks assess recall, not inquiry.
(a) communicating
(b) predicting
(c) interpreting
(d) hypothesizing
Show Answer & Explanation
Answer: (a) communicating
Explanation:
1. Representing data in a graph is a way of presenting information to others.
2. This is the process skill of communicating.
Teacher's Note:
1. Reading meaning from the graph afterwards would be interpreting.
2. Communicating includes tables, graphs, drawings and reports.
Plant - Venation - Root
(A) Hibiscus - Reticulate - Fibrous root
(B) Rose - Reticulate - Tap root
(C) Bamboo - Parallel - Fibrous root
(D) Paddy - Reticulate - Fibrous root
(a) (B) & (C)
(b) (A) & (C)
(c) (A) & (D)
(d) (B) & (D)
Show Answer & Explanation
Answer: (c) (A) & (D)
Explanation:
1. Hibiscus is a dicot with reticulate venation and a tap root, so (A) is incorrect.
2. Paddy is a monocot with parallel venation and a fibrous root, so (D) is incorrect.
3. (B) and (C) are correct.
Teacher's Note:
1. Dicots have reticulate venation and tap roots; monocots have parallel venation and fibrous roots.
2. Bamboo and paddy are grasses, hence monocots.
(a) They all lack back bone
(b) They have scales on their body
(c) They lay eggs to reproduce
(d) They live in water
Show Answer & Explanation
Answer: (a) They all lack back bone
Explanation:
1. Amoeba is a protozoan, starfish is an echinoderm, and ant and spider are arthropods.
2. None of them has a backbone, so all are invertebrates.
Teacher's Note:
1. Amoeba reproduces by binary fission, so 'lay eggs' fails.
2. Ant and spider live on land, so 'live in water' fails.
(a) Boil the leaf first in water and then in alcohol
(b) Wash the bleached leaf
(c) Heat the leaf on a flame
(d) Add a few drops of iodine solution to the bleached leaf
Show Answer & Explanation
Answer: (c) Heat the leaf on a flame
Explanation:
1. The leaf is boiled in water, then in alcohol to remove chlorophyll, washed, and tested with iodine.
2. Heating the leaf directly on a flame is not a step, and alcohol is never heated directly.
Teacher's Note:
1. Alcohol is flammable, so it is heated in a water bath.
2. A blue-black colour with iodine shows starch.
(a) By increasing the water table of the place
(b) By decreasing the water table of the place
(c) By flooding lands with saline water
(d) By dissolving away rocks
Show Answer & Explanation
Answer: (c) By flooding lands with saline water
Explanation:
1. Cyclones push sea water onto the coast and flood the land.
2. The salt left behind makes the soil saline and less fertile.
Teacher's Note:
1. Salinity harms plant roots by drawing water out of them.
2. Sea-water flooding is also called storm surge.
(A) Light in weight
(B) High calorific value
(C) Burns slowly in absence of air
(a) Only (B)
(b) Only (A)
(c) (A) and (B)
(d) (B) and (D)
Show Answer & Explanation
Answer: (c) (A) and (B)
Explanation:
1. A rocket fuel must be light and have a high calorific value to give large thrust.
2. It burns rapidly, not slowly, so (C) is incorrect.
Teacher's Note:
1. Rockets carry their own oxidiser, so they can burn in space.
2. Liquid hydrogen is a common rocket fuel.
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FAQs
You can get most exhaustive CTET Science Paper 2 MCQs with Answers Set 01 for free on StudiesToday.com. These MCQs for CTET are updated for the 2026-27 academic session as per CTET examination standards.
Yes, our CTET Science Paper 2 MCQs with Answers Set 01 include the latest type of questions, such as Assertion-Reasoning and Case-based MCQs. 50% of the CTET paper is now competency-based.
By solving our CTET Science Paper 2 MCQs with Answers Set 01, CTET students can improve their accuracy and speed which is important as objective questions provide a chance to secure 100% marks in the .
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