Download Class 6 Mathematics Worksheets for All Chapters
Access printable practice worksheets for All Chapters designed to align with the 2026-27 academic syllabus for Class 6 Mathematics. These structured exercises help students evaluate their conceptual understanding and improve exam readiness.
Access All Chapters Questions and Exercises
View or download the dedicated All Chapters practice resource below. Engaging with these objective and subjective questions daily ensures continuous academic progress and mastery of the 2026-27 curriculum.
Questions
Q1. The whole number p such that p + 2 = 8 is [1 mark]
(a) 10
(b) 4
(c) 6
(d) 12
View Answer & Explanation
Answer: (c) 6. p = 8 − 2 = 6.
Teacher's Note:
1. Subtract 2 from both sides.
2. Check by adding back.
Q2. What is the HCF of two consecutive numbers? [1 mark]
(a) 1
(b) 0
(c) 2
(d) 3
View Answer & Explanation
Answer: (a) 1. Consecutive numbers share no common factor other than 1.
Teacher's Note:
1. Take an example such as 8 and 9.
2. Their only common factor is 1.
Q3. What is the LCM of 7 and 9? [1 mark]
(a) 3
(b) 9
(c) 63
(d) 16
View Answer & Explanation
Answer: (c) 63. They are co-prime, so the LCM is 7 × 9 = 63.
Teacher's Note:
1. For co-prime numbers the LCM is their product.
2. Check that 7 and 9 have no common factor.
Q4. List all prime numbers less than 100 that end with 3. [1 mark]
View Answer & Explanation
Answer: 3, 13, 23, 43, 53, 73 and 83.
Teacher's Note:
1. Test each number ending in 3 for divisibility by 2, 3, 5 and 7.
2. Numbers like 33, 63 and 93 are multiples of 3.
Q5. Where will the hour hand of a clock stop if it starts from 7 and turns through 2 right angles? [1 mark]
View Answer & Explanation
Answer: Two right angles = 180°, which is 6 hours. Starting at 7 and moving clockwise 6 hours, it stops at 1.
Teacher's Note:
1. Each hour mark is 30° apart.
2. Divide 180° by 30° to get the number of hours.
Q6. Find the product of the largest 3-digit number and the smallest 4-digit number. [1 mark]
View Answer & Explanation
Answer: 999 × 1000 = 9,99,000.
Teacher's Note:
1. Identify the two numbers first.
2. Multiplying by 1000 adds three zeros.
Q7. Simplify by suitable rearrangement: 2962 + 567 + 1538 + 633 [1 mark]
View Answer & Explanation
Answer: (2962 + 1538) + (567 + 633) = 4500 + 1200 = 5700.
Teacher's Note:
1. Pair numbers that make round totals.
2. Add the pairs.
Q8. Simplify by suitable rearrangement: 128 × 40 × 8 × 25 [1 mark]
View Answer & Explanation
Answer: (40 × 25) × (128 × 8) = 1000 × 1024 = 1,024,000.
Teacher's Note:
1. Pair factors whose product is a power of 10.
2. Then multiply the rest.
Q9. Simplify by suitable rearrangement: 8 × 25 × 125 × 40 [1 mark]
View Answer & Explanation
Answer: (8 × 125) × (25 × 40) = 1000 × 1000 = 10,00,000.
Teacher's Note:
1. Look for pairs that give 1000.
2. Multiply the two results.
Q10. Write the smallest 4-digit number and give its prime factorisation. [1 mark]
View Answer & Explanation
Answer: The smallest 4-digit number is 1000 = 2³ × 5³.
Teacher's Note:
1. Divide by 2 until it is no longer divisible, then by 5.
2. Write repeated factors as powers.
Q11. Express as the sum of three odd primes: (a) 15 (b) 35 (c) 61 [1 mark]
View Answer & Explanation
Answer: (a) 15 = 3 + 5 + 7
(b) 35 = 5 + 7 + 23
(c) 61 = 7 + 13 + 41
Teacher's Note:
1. Try small odd primes first.
2. More than one answer may be correct.
Q12. Make a factor tree for 80, 72 and 108 and write their prime factorisations. [1 mark]
View Answer & Explanation
Answer: 80 = 2⁴ × 5; 72 = 2³ × 3²; 108 = 2² × 3³.
Teacher's Note:
1. Split each number into any two factors and keep splitting until only primes remain.
2. Every tree gives the same prime factors.
Q13. Is it possible to draw these triangles? Give reasons: (a) a triangle with two obtuse angles (b) an equilateral triangle with each angle 70° (c) a triangle with each angle less than 60°. [1 mark]
View Answer & Explanation
Answer: (a) No; two obtuse angles total more than 180°. (b) No; 3 × 70° = 210°, not 180°. (c) No; three angles each below 60° total less than 180°.
Teacher's Note:
1. The angles of a triangle always add up to 180°.
2. Check each case against this.
Q14. A merchant had ₹9,07,640. He ordered 48 refrigerators at ₹16,000 each. How much money remains? [1 mark]
View Answer & Explanation
Answer: Cost = 48 × 16,000 = ₹7,68,000. Remaining = 9,07,640 − 7,68,000 = ₹1,39,640.
Teacher's Note:
1. First find the total cost.
2. Then subtract it from the money he had.
Q15. (a) Find the angle between the hands of a clock at 5 o'clock. (b) What fraction of a revolution do you turn if you face west and turn clockwise to face south? [1 mark]
View Answer & Explanation
Answer: (a) 5 × 30° = 150°. (b) West → north → east → south is 270°, i.e. \( \dfrac{3}{4} \) of a revolution.
Teacher's Note:
1. One hour on the clock is 30°.
2. Clockwise from west you pass north and east before south.
Q16. Using the distributive property find (a) 894 × 38 + 894 × 62 (b) 2398 × 144 − 2398 × 44 (c) 350 × 998 (d) 3847 × 1007 [1 mark]
View Answer & Explanation
Answer: (a) 894 × 100 = 89,400
(b) 2398 × 100 = 2,39,800
(c) 350 × (1000 − 2) = 3,49,300
(d) 3847 × (1000 + 7) = 38,73,929
Teacher's Note:
1. Take out the common factor, or split the number into a round number plus or minus a small one.
2. Work out each part.
Q17. Divide 64296 by 521 and check the result using the division algorithm. [1 mark]
View Answer & Explanation
Answer: Quotient 123 and remainder 213. Check: 521 × 123 + 213 = 64,083 + 213 = 64,296.
Teacher's Note:
1. Divisor × quotient + remainder must equal the dividend.
2. Make sure the remainder is smaller than the divisor.
Q18. On dividing 36410 by 145 the remainder is 15. Find the quotient. [1 mark]
View Answer & Explanation
Answer: 36410 = 145 × q + 15, so 145q = 36395 and q = 251.
Teacher's Note:
1. Subtract the remainder from the dividend first.
2. Then divide by the divisor.
Q19. Find the HCF of 180 and 192 by prime factorisation. [1 mark]
View Answer & Explanation
Answer: 180 = 2² × 3² × 5 and 192 = 2⁶ × 3. Common part = 2² × 3 = 12.
Teacher's Note:
1. Take only the common primes with their lowest powers.
2. Multiply them.
Q20. Find the LCM of 28 and 44 by prime factorisation. [1 mark]
View Answer & Explanation
Answer: 28 = 2² × 7 and 44 = 2² × 11. LCM = 2² × 7 × 11 = 308.
Teacher's Note:
1. Take every prime with its highest power.
2. Multiply them.
Q21. Find the smallest 5-digit number exactly divisible by 15, 20 and 25. [1 mark]
View Answer & Explanation
Answer: LCM of 15, 20, 25 = 300. 10000 ÷ 300 leaves remainder 100, so the number is 10000 + (300 − 100) = 10,200.
Teacher's Note:
1. Find the LCM first.
2. Then move up from 10000 to the next multiple.
Q22. Find the greatest number that divides 245 and 1029 leaving remainder 5 in each case. [1 mark]
View Answer & Explanation
Answer: Subtract the remainder: 240 and 1024. HCF(240, 1024) = 16.
Teacher's Note:
1. Remove the remainder from each number.
2. The answer is their HCF.
Q23. Find the longest tape that can measure exactly 658 cm, 940 cm and 1128 cm. [1 mark]
View Answer & Explanation
Answer: HCF of 658, 940 and 1128 = 94 cm (658 = 94 × 7, 940 = 94 × 10, 1128 = 94 × 12).
Teacher's Note:
1. The longest tape is the HCF of the three lengths.
2. Check by dividing each length.
Q24. Four bells ring every 4, 7, 12 and 14 seconds. If they start together at 12 o'clock, when will they next ring together? [1 mark]
View Answer & Explanation
Answer: LCM of 4, 7, 12, 14 = 84 seconds. They next ring together after 1 minute 24 seconds, at 12:01:24.
Teacher's Note:
1. The common ringing time is the LCM.
2. Convert seconds to minutes at the end.
Q25. Test whether (a) 828184 is divisible by 4 and 8 (b) 735108 is divisible by 6. [1 mark]
View Answer & Explanation
Answer: (a) Last two digits 84 ÷ 4 = 21, so divisible by 4; last three digits 184 ÷ 8 = 23, so divisible by 8. (b) It is even and its digit sum 24 is divisible by 3, so it is divisible by 6.
Teacher's Note:
1. Use the last-digit tests for 4 and 8.
2. A number divisible by both 2 and 3 is divisible by 6.
Q26. The population of a town is 80,000. There are 42,457 men and 23,296 women. Find the number of children. [1 mark]
View Answer & Explanation
Answer: Adults = 42,457 + 23,296 = 65,753. Children = 80,000 − 65,753 = 14,247.
Teacher's Note:
1. Add men and women first.
2. Subtract the total from the population.
Q27. A student multiplied 7635 by 56 instead of 65. By how much was the answer different from the correct one? [1 mark]
View Answer & Explanation
Answer: The difference is 7635 × (65 − 56) = 7635 × 9 = 68,715. His answer was smaller by this amount.
Teacher's Note:
1. Use the distributive idea to avoid multiplying twice.
2. Note which product is larger.
Q28. There are 136 apples, 170 mangoes and 255 oranges, arranged in heaps with the same number of fruits and no mixing. Find the greatest possible number of fruits in each heap and the number of heaps. [1 mark]
View Answer & Explanation
Answer: HCF(136, 170, 255) = 17 fruits per heap. Heaps = 8 + 10 + 15 = 33.
Teacher's Note:
1. The heap size is the HCF.
2. Divide each count by it and add.
Q29. Name the type of each triangle: (a) ∆DEF with DE = EF = FD = 6 cm (b) ∆PQR with ∠Q = 90° and PQ = QR (c) ∆ABC with ∠A = 110°, ∠B = 30°, ∠C = 40°. [1 mark]
View Answer & Explanation
Answer: (a) Equilateral triangle. (b) Right-angled isosceles triangle. (c) Obtuse-angled triangle.
Teacher's Note:
1. Classify by sides and by angles.
2. An obtuse triangle has one angle larger than 90°.
Free study material for Mathematics
Practice Worksheet and Study Resources for Class 6 Mathematics All Chapters
Download Practice Sheet: All Chapters (Class 6 Mathematics)
Explore reliable practice questions for All Chapters tailored for Class 6 Mathematics learners. Use these structured worksheets to evaluate preparedness and strengthen problem-solving skills.
Concept Clarification for All Chapters
Each worksheet is structured around standard CBSE textbooks, allowing students to check their working steps and correct mistakes early in their revision.
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FAQs
You can download the teacher-verified PDF for CBSE Class 6 Mathematics Prime Time and Whole-Number Operations Worksheet Set 27 from StudiesToday.com. These practice sheets for Class 6 Mathematics are designed as per the latest CBSE academic session.
Yes, our CBSE Class 6 Mathematics Prime Time and Whole-Number Operations Worksheet Set 27 includes a variety of questions like Case-based studies, Assertion-Reasoning, and MCQs as per the 50% competency-based weightage in the latest curriculum for Class 6.
Yes, we have provided detailed solutions for CBSE Class 6 Mathematics Prime Time and Whole-Number Operations Worksheet Set 27 to help Class 6 and follow the official CBSE marking scheme.
Daily practice with these Mathematics worksheets helps in identifying understanding gaps. It also improves question solving speed and ensures that Class 6 students get more marks in CBSE exams.
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