Official Class 6 Mathematics Worksheets: Chapter 04 Data Handling and Presentation
Explore structured practice materials through the CBSE Class 6 Mathematics Data Handling and Presentation Practice Paper Worksheet Set 02 with Answers. Tailored for Class 6 learners, utilizing these Mathematics worksheets ensures thorough preparation and strengthens problem-solving accuracy before final school evaluations.
Solved Practice Worksheets for Mathematics
Navigate directly to the solved Mathematics worksheets using the digital viewer below. Each practice set includes detailed step-by-step solutions, allowing students to instantly cross-check their work and identify areas requiring further revision.
This is Class 6 Maths Ganita Prakash Chapter 4 Data Handling and Presentation Practice Paper 10, a 40-mark test of 20 questions arranged in Sections A to E, with a step-by-step answer under every question. It checks how well you read scales on bar graphs and keys in pictographs (buses, cars, apples and birds), make frequency tables with tally marks, arrange raw data in order, and choose a sensible scale for a bar graph of meals sold in a school cafeteria.
Section A: Multiple Choice Questions (1 Mark Each)
(a) 5
(b) 7
(c) 8
(d) 10
Show Answer & Explanation
Answer: (b) 7
Explanation:
1. Students who like Cricket, Football or Badminton = 10 + 15 + 8 = 33.
2. All the other students like Hockey: 40 − 33 = 7.
3. So the frequency of Hockey is 7.
Teacher's Note:
1. Frequency means how many times a choice occurs.
2. When the total is given, subtract the known frequencies to get the missing one.
(a) 5 kg
(b) 20 kg
(c) 75 kg
(d) 15 kg
Show Answer & Explanation
Answer: (c) 75 kg
Explanation:
1. Each unit of the bar stands for 15 kg.
2. 5 units stand for 5 × 15 = 75 kg.
3. So the student weighs 75 kg.
Teacher's Note:
1. Value = number of units × scale.
2. Do not add 5 and 15; multiply them.
(a)
(b)
(c)
(d)
Show Answer & Explanation
Answer: (b)
Explanation:
1. 4 symbols stand for 4 × 25 = 100 buses, so 112 − 100 = 12 buses are still left.
2. Half a symbol stands for 25 ÷ 2 = 12.5 buses, which is the closest picture of 12 buses.
3. So 112 buses are best shown by 4 symbols and a half symbol (5 symbols would mean 125 buses).
Teacher's Note:
1. When the number is not an exact multiple of the key, draw the nearest part of a symbol.
2. Always check the remaining amount after the full symbols.
(a) 6 trees
(b) 60 trees
(c) 16 trees
(d) 600 trees
Show Answer & Explanation
Answer: (b) 60 trees
Explanation:
1. 1 unit length stands for 10 trees.
2. 6 units stand for 6 × 10 = 60 trees.
3. So 60 trees were planted on Monday.
Teacher's Note:
1. Read the height, then multiply by the scale.
2. 16 comes from adding, which is wrong.
(a) 45
(b) 9
(c) 5
(d) 10
Show Answer & Explanation
Answer: (b) 9
Explanation:
1. Each symbol stands for 5 cars.
2. Number of symbols = 45 ÷ 5 = 9.
3. So 9 symbols are needed.
Teacher's Note:
1. Symbols needed = total ÷ value of one symbol.
2. Check: 9 × 5 = 45.
(a) 1
(b) 2
(c) 3
(d) 4
Show Answer & Explanation
Answer: (b) 2
Explanation:
1. “At least 150 cm” means 150 cm or more.
2. Only the two heights of 150 cm qualify; 145, 148 and 147 are less.
3. So 2 students.
Teacher's Note:
1. “At least” includes the number itself.
2. Go through the list one value at a time.
(a) 15,000
(b) 7500
(c) 75,000
(d) 1500
Show Answer & Explanation
Answer: (c) 75,000
Explanation:
1. Each unit stands for 5000 people.
2. 15 units stand for 15 × 5000 = 75,000 people.
3. So the population is 75,000.
Teacher's Note:
1. Large numbers need a large scale.
2. Count the zeros carefully: 15 × 5 = 75, then add three zeros.
(a) 2 complete symbols and a partial symbol
(b) 2 complete symbols and a half symbol
(c) 1 complete symbol and a partial symbol
(d) 2 complete symbols
Show Answer & Explanation
Answer: (a) 2 complete symbols and a partial symbol
Explanation:
1. 2 complete symbols show 2 × 5 = 10 footballs; 12 − 10 = 2 footballs are left.
2. 2 footballs are less than half a symbol (half = 2.5), so a small part of a symbol is needed.
3. So we need 2 complete symbols and a partial symbol.
Teacher's Note:
1. A half symbol would mean 2.5 footballs, not 2.
2. A partial symbol is any piece smaller than a full one.
Assertion (A): In a bar graph with a scale of 1 unit length = 100 people, a bar of height 8 units and a bar of height 12 units represent a total of 2000 people.
Reason (R): The total number of people is calculated by adding the unit lengths of the bars and multiplying by the scale.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (a) Both A and R are true, and R is the correct explanation of A.
Explanation:
1. Total units = 8 + 12 = 20; 20 × 100 = 2000 people. So A is true.
2. R describes exactly this method (add the units, then multiply by the scale), so R is true.
3. R explains how the total in A is found, so the answer is (a).
Teacher's Note:
1. 8 × 100 + 12 × 100 gives the same 2000.
2. Check whether R is the working behind A.
Assertion (A): In a pictograph, a single symbol can be used to represent a large number of items.
Reason (R): This is necessary when the data values are very large, as it prevents the pictograph from becoming cluttered and difficult to read.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (a) Both A and R are true, and R is the correct explanation of A.
Explanation:
1. A key like “one symbol = 100 people” is common, so A is true.
2. With large numbers, one symbol per item would need hundreds of pictures, so R is true.
3. R gives the reason for A, so the answer is (a).
Teacher's Note:
1. The key keeps a pictograph short and readable.
2. Choose a key that divides the data neatly.
Section B: Short Answer Questions (2 Marks Each)
Question 11. The following data shows the number of absent students in a class over a week:
Monday: 4, Tuesday: 2, Wednesday: 5, Thursday: 1, Friday: 3.
If a teacher wants to represent this data using a pictograph with the symbol = 1 student, how would she show the data for Wednesday and Friday?
Answer:
One symbol stands for 1 student, so the number of symbols equals the number of absent students.
Wednesday: 5 students absent, so 5 symbols.
Friday: 3 students absent, so 3 symbols.
In simple words: Draw one face for each absent student: 5 faces for Wednesday and 3 for Friday.
Teacher's Note:
1. Every symbol in a pictograph must be the same size.
2. Always write the key next to the pictograph.
Question 12. A bar graph shows the number of students in each class. The bar for Class 6 is 12 units high, and the bar for Class 7 is 15 units high. If the scale is 1 unit length = 5 students, what is the total number of students in both classes?
Answer:
Class 6: 12 × 5 = 60 students.
Class 7: 15 × 5 = 75 students.
Total = 60 + 75 = 135 students.
Quick check: (12 + 15) × 5 = 27 × 5 = 135.
In simple words: Change each bar height into students and add: 60 + 75 = 135.
Teacher's Note:
1. Multiply each height by the scale before adding.
2. Adding the units first and then multiplying gives the same answer.
Question 13. Arrange the following raw data set in ascending order and find the smallest and largest values:
15, 22, 10, 18, 25, 15, 22, 10, 20.
How many times does the value 15 appear in this dataset?
Answer:
Ascending order (smallest to largest): 10, 10, 15, 15, 18, 20, 22, 22, 25.
Smallest value = 10; largest value = 25.
The value 15 appears 2 times.
In simple words: Put the numbers in order from small to big; 10 is the smallest, 25 the largest and 15 occurs twice.
Teacher's Note:
1. Count the values before and after sorting; both should be 9.
2. Ascending means increasing order.
Answer:
Draw tally marks in groups of five (the fifth mark crosses the first four):
| Colour | Tally Marks | Frequency |
|---|---|---|
| Blue | 8 | |
| Red | 12 | |
| Green | 6 | |
| Yellow | 4 | |
| Pink | 10 | |
| Total | 40 |
Total students surveyed = 8 + 12 + 6 + 4 + 10 = 40.
In simple words: Make a table with one row for each colour, tally marks in fives, and the number in the last column.
Teacher's Note:
1. Tally marks for 12 are two crossed fives and two more strokes.
2. Add the frequencies to check the total.
Section C: Short Answer Questions (3 Marks Each)
7, 8, 5, 9, 7, 6, 8, 7, 5, 9, 8, 6, 7, 10, 8, 9, 7, 6, 8, 5
Prepare a frequency distribution table using tally marks. What is the most frequently occurring mark?
Answer:
Go through the marks one by one and put a tally mark against each:
| Marks | Tally Marks | Frequency |
|---|---|---|
| 5 | 3 | |
| 6 | 3 | |
| 7 | 5 | |
| 8 | 5 | |
| 9 | 3 | |
| 10 | 1 | |
| Total | 20 |
Check: 3 + 3 + 5 + 5 + 3 + 1 = 20 students.
Marks 7 and 8 each occur 5 times, more than any other mark. So the most frequently occurring marks are 7 and 8 (5 students each).
In simple words: 7 and 8 both appear 5 times, so they are the most common marks.
Teacher's Note:
1. Data can have two values that are equally most common.
2. Always check that the frequencies add up to the number of students.
Question 16. A pictograph shows the number of apples sold by a vendor over four days. The key is = 10 apples.
(a) How many more apples were sold on Thursday than on Wednesday?
(b) What was the total number of apples sold during the four days?
Answer:
Each stands for 10 apples.
(a) Thursday: 6 × 10 = 60 apples; Wednesday: 3 × 10 = 30 apples.
Difference = 60 − 30 = 30 apples more on Thursday.
(b) Total symbols = 4 + 5 + 3 + 6 = 18.
Total apples = 18 × 10 = 180 apples.
In simple words: Count the apples in each row and multiply by 10: 60 − 30 = 30 more, and 18 × 10 = 180 in all.
Teacher's Note:
1. The difference can also be found as (6 − 3) × 10.
2. Count the symbols carefully, row by row.
Question 17. A family's monthly budget is ₹15,000. They spend ₹5,000 on food, ₹3,000 on education, and ₹2,500 on transport. They want to create a bar graph to represent this. Using a scale of 1 unit length = ₹500, calculate the height of the bars for food, education, and transport.
Answer:
Height of a bar = amount ÷ 500.
Food: 5000 ÷ 500 = 10 units.
Education: 3000 ÷ 500 = 6 units.
Transport: 2500 ÷ 500 = 5 units.
In simple words: Divide each amount by ₹500 to get the bar heights 10, 6 and 5 units.
Teacher's Note:
1. The total budget of ₹15,000 is extra information not needed here.
2. Check: 10 × 500 = 5000.
Section D: Long Answer Question (5 Marks)
Monday: 300, Tuesday: 450, Wednesday: 250, Thursday: 500, Friday: 400.
(a) Prepare a frequency distribution table for this data.
(b) Draw a bar graph to represent the data, choosing an appropriate scale.
(c) On which day was the most number of meals sold, and how many more meals were sold on that day compared to the day with the least number of sales?
Answer:
(a)
| Day | Number of meals sold |
|---|---|
| Monday | 300 |
| Tuesday | 450 |
| Wednesday | 250 |
| Thursday | 500 |
| Friday | 400 |
| Total | 1900 |
(b) All the numbers are multiples of 50, so take the scale 1 unit length = 50 meals.
Bar heights: Monday 300 ÷ 50 = 6 units, Tuesday 450 ÷ 50 = 9 units, Wednesday 250 ÷ 50 = 5 units, Thursday 500 ÷ 50 = 10 units, Friday 400 ÷ 50 = 8 units.
(c) The most meals were sold on Thursday (500) and the least on Wednesday (250).
Difference = 500 − 250 = 250 meals.
In simple words: Make a table, draw bars with 1 unit = 50 meals, and Thursday beats Wednesday by 250 meals.
Teacher's Note:
1. Choose a scale that divides every value exactly, so all bars end on a grid line.
2. Bars must have equal width and equal gaps.
3. Label both axes and write the scale.
Section E: Case Study Based Questions (4 Marks Each)
Question 19. Case Study 1: The Bird Watchers' Club
A group of friends started a bird-watching club in their village. They decided to count the number of different types of birds they saw in the village park over a week. The following data was collected:
Sparrows: 25
Pigeons: 40
Crows: 35
Parrots: 15
They decided to make a pictograph to present their findings to other villagers. They chose a symbol to represent 5 birds.
Based on the information above, answer the following questions:
(a) How many symbols will be needed to represent the number of crows?
(b) Which bird was seen the most, and how many symbols would it have?
(c) What is the total number of symbols needed to represent all the birds?
(d) One of the friends suggested a scale of = 1 bird. What is the number of symbols needed with this scale and why is it not a good choice?
Answer:
(a) Crows: 35 ÷ 5 = 7 symbols.
(b) Pigeons were seen the most (40), so they get 40 ÷ 5 = 8 symbols.
(c) Total birds = 25 + 40 + 35 + 15 = 115, so total symbols = 115 ÷ 5 = 23 symbols (5 + 8 + 7 + 3).
(d) With 1 symbol = 1 bird, 115 symbols are needed. Drawing so many pictures takes a long time and space, and the pictograph becomes crowded and hard to read.
The pictograph with the key of 5 birds looks like this:
In simple words: Divide each count by 5; one picture per bird would need 115 pictures, which is far too many.
Teacher's Note:
1. A good key keeps the number of symbols small.
2. Check (c) by adding the symbols of each row.
Question 20. Case Study 2: School Library Book Circulation
A librarian wanted to understand the reading habits of students in classes 1 to 5. She collected data on the number of books issued to students in each class during a specific month. The data is as follows:
Class 1: 30 books
Class 2: 45 books
Class 3: 50 books
Class 4: 25 books
Class 5: 30 books
She decided to present this data using a bar graph with a suitable scale to make it easy to understand for the school principal.
Based on the information above, answer the following questions:
(a) Using a scale of 1 unit length = 5 books, what would be the height of the bar for Class 2?
(b) What is the combined total of books issued to the three classes that borrowed the fewest books?
(c) Compare the number of books issued in Class 1 and Class 5. What does this tell you?
(d) How much taller is the bar for Class 3 compared to the bar for Class 4 if the scale is 1 unit length = 5 books?
Answer:
(a) Height for Class 2 = 45 ÷ 5 = 9 units.
(b) The three smallest numbers are Class 4 (25), Class 1 (30) and Class 5 (30). Total = 25 + 30 + 30 = 85 books.
(c) Class 1 and Class 5 were both issued 30 books, so their bars are equally tall. Both classes borrowed the same number of books that month.
(d) Class 3: 50 ÷ 5 = 10 units; Class 4: 25 ÷ 5 = 5 units. The Class 3 bar is 10 − 5 = 5 units taller.
In simple words: Divide by 5 to get bar heights; the three lowest classes together borrowed 85 books.
Teacher's Note:
1. Equal values give bars of equal height.
2. Find heights first, then subtract.
Free study material for Mathematics
Chapter 04 Data Handling and Presentation Printable Worksheets and Exercises for Class 6 Mathematics
Download Chapter Worksheets: Class 6 Mathematics
Access structured practice worksheets for Chapter 04 Data Handling and Presentation aligned with the 2026 CBSE curriculum. These downloadable exercises for Class 6 Mathematics help students build accuracy and reinforce core concepts for upcoming school tests.
Concept Clarification for Chapter 04 Data Handling and Presentation
Each worksheet draws directly from authorized standard textbooks to maintain academic accuracy. Evaluating your finished exercises against expert-verified solutions helps master the formal presentation standards expected in school evaluations.
Effective Revision Strategies for School Exams
Consistent engagement with these exercises builds familiarity with recurring exam themes. If specific areas within Chapter 04 Data Handling and Presentation cause trouble, utilize our dedicated NCERT solutions for Class 6 Mathematics to clear up doubts immediately.
FAQs
You can download the latest chapter-wise printable worksheets for Class 6 Mathematics Chapter 04 Data Handling and Presentation for free from StudiesToday.com. These have been made as per the latest CBSE curriculum for this academic year.
Yes, Class 6 Mathematics worksheets for Chapter 04 Data Handling and Presentation focus on activity-based learning and also competency-style questions. This helps students to apply theoretical knowledge to practical scenarios.
Yes, we have provided solved worksheets for Class 6 Mathematics Chapter 04 Data Handling and Presentation to help students verify their answers instantly.
Yes, our Class 6 Mathematics test sheets are mobile-friendly PDFs and can be printed by teachers for classroom.
For Chapter 04 Data Handling and Presentation, regular practice with our worksheets will improve question-handling speed and help students understand all technical terms and diagrams.