NEET Biology Molecular Basis of Inheritance MCQs Set 19

Biology Objective Questions and Answers: Molecular Basis of Inheritance

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Multiple Choice Questions

Question 1: The sequence of amino acids in protein synthesis is decided by the sequence of
(a) tRNA
(b) mRNA
(c) cDNA
(d) rRNA
Show Answer & Explanation

Answer: (b) mRNA

Explanation:
1. The codons in mRNA specify the order of amino acids.
2. So the correct choice is option (b).

Teacher's Note:
1. mRNA carries the code.
2. tRNA reads it.

Question 2: The one gene-one enzyme hypothesis was postulated by
(a) R. Franklin
(b) Hershey and Chase
(c) A. Garrod
(d) Beadle and Tatum
Show Answer & Explanation

Answer: (d) Beadle and Tatum

Explanation:
1. Beadle and Tatum worked on Neurospora mutants and proposed that each gene controls one enzyme.
2. So the correct choice is option (d).

Teacher's Note:
1. Garrod: inborn errors of metabolism.
2. Neurospora experiments.

Question 3: One turn of the helix in B-form DNA is approximately
(a) 34 nm
(b) 0.34 nm
(c) 3.4 nm
(d) 2 nm
Show Answer & Explanation

Answer: (c) 3.4 nm

Explanation:
1. A turn contains 10 base pairs at 0.34 nm each.
2. So the correct choice is option (c).

Teacher's Note:
1. 10 x 0.34 nm.
2. 2 nm is the diameter.

Question 4: Triticale, the first man-made cereal crop, was obtained by crossing wheat with
(a) rye
(b) pearl millet
(c) sugarcane
(d) barley
Show Answer & Explanation

Answer: (a) rye

Explanation:
1. Triticale is an amphidiploid of wheat (Triticum) and rye (Secale).
2. So the correct choice is option (a).

Teacher's Note:
1. Triticum + Secale.
2. Combines wheat yield with rye hardiness.

Question 5: During protein synthesis the process halts at one point. Which group of codons can stop it?
(a) UUU, UCC, UAU
(b) UUC, UUA, UAC
(c) UAG, UGA, UAA
(d) UUG, UCA, UCG
Show Answer & Explanation

Answer: (c) UAG, UGA, UAA

Explanation:
1. UAA, UAG and UGA are stop (nonsense) codons.
2. So the correct choice is option (c).

Teacher's Note:
1. They code for no amino acid.
2. Release factors bind.

Question 6: Thymine is
(a) 5-methyl uracil
(b) 4-methyl uracil
(c) 3-methyl uracil
(d) 1-methyl uracil
Show Answer & Explanation

Answer: (a) 5-methyl uracil

Explanation:
1. Thymine is uracil with a methyl group on carbon 5.
2. So the correct choice is option (a).

Teacher's Note:
1. DNA uses T for stability.
2. RNA uses U.

Question 7: Differentiation of organs and tissues in a developing organism is associated with
(a) developmental mutations
(b) differential expression of genes
(c) lethal mutations
(d) deletion of genes
Show Answer & Explanation

Answer: (b) differential expression of genes

Explanation:
1. All cells have the same genes but different sets are switched on in different tissues.
2. So the correct choice is option (b).

Teacher's Note:
1. Gene regulation.
2. Cells do not lose genes.

Question 8: The molecular basis of organ differentiation depends on modulation of transcription by
(a) RNA polymerase
(b) ribosome
(c) transcription factors
(d) anticodon
Show Answer & Explanation

Answer: (c) transcription factors

Explanation:
1. Transcription factors control whether RNA polymerase transcribes a gene.
2. So the correct choice is option (c).

Teacher's Note:
1. Regulation at transcription.
2. Not by ribosomes.

Question 9: The two polynucleotide chains in DNA are
(a) parallel
(b) discontinuous
(c) antiparallel
(d) semiconservative
Show Answer & Explanation

Answer: (c) antiparallel

Explanation:
1. One chain runs 5' to 3' and the other 3' to 5'.
2. So the correct choice is option (c).

Teacher's Note:
1. Opposite polarity.
2. Semiconservative is about replication.

Question 10: In hexaploid wheat, the haploid (n) and basic (x) chromosome numbers are
(a) n = 7 and x = 21
(b) n = 21 and x = 21
(c) n = 21 and x = 14
(d) n = 21 and x = 7
Show Answer & Explanation

Answer: (d) n = 21 and x = 7

Explanation:
1. Hexaploid wheat is 2n = 42. Basic number x = 7 and gametes carry three sets, so n = 21.
2. So the correct choice is option (d).

Teacher's Note:
1. 6 sets of x = 7.
2. n is the gamete number.

Question 11: Which nitrogen base is not found in DNA?
(a) thymine
(b) cytosine
(c) guanine
(d) uracil
Show Answer & Explanation

Answer: (d) uracil

Explanation:
1. Uracil occurs in RNA, not in DNA.
2. So the correct choice is option (d).

Teacher's Note:
1. DNA: A, T, G, C.
2. RNA: A, U, G, C.

Question 12: A polysome is formed by
(a) a ribosome with several subunits
(b) ribosomes attached to each other in a line
(c) several ribosomes attached to a single mRNA
(d) many ribosomes attached to the ER
Show Answer & Explanation

Answer: (c) several ribosomes attached to a single mRNA

Explanation:
1. Many ribosomes translate one mRNA at the same time, forming a polysome.
2. So the correct choice is option (c).

Teacher's Note:
1. Increases protein output.
2. Seen as beads on a string.

Question 13: Which pair of nitrogenous bases is wrongly matched with its category?
(a) guanine, adenine - purines
(b) adenine, thymine - purines
(c) thymine, uracil - pyrimidines
(d) uracil, cytosine - pyrimidines
Show Answer & Explanation

Answer: (b) adenine, thymine - purines

Explanation:
1. Adenine is a purine but thymine is a pyrimidine.
2. So the correct choice is option (b).

Teacher's Note:
1. Pu: A, G.
2. Py: C, T, U.

Question 14: Haploids are more suitable for mutation studies than diploids because
(a) haploids are more abundant
(b) all mutations, dominant or recessive, are expressed in haploids
(c) haploids are reproductively more stable
(d) mutagens penetrate haploids better
Show Answer & Explanation

Answer: (b) all mutations, dominant or recessive, are expressed in haploids

Explanation:
1. With a single allele of each gene there is no second allele to mask a recessive mutation.
2. So the correct choice is option (b).

Teacher's Note:
1. No masking by a dominant allele.
2. Used in microbial genetics.

Question 15: Removal of introns and joining of exons in a defined order in a transcription unit is called
(a) capping
(b) splicing
(c) tailing
(d) transformation
Show Answer & Explanation

Answer: (b) splicing

Explanation:
1. Splicing joins exons after removing introns from hnRNA.
2. So the correct choice is option (b).

Teacher's Note:
1. Capping adds 5' methyl guanosine.
2. Tailing adds poly A.

Question 16: Semiconservative replication of DNA was first demonstrated in
(a) Salmonella typhimurium
(b) Drosophila melanogaster
(c) Escherichia coli
(d) Streptococcus pneumoniae
Show Answer & Explanation

Answer: (c) Escherichia coli

Explanation:
1. Meselson and Stahl used E. coli grown in 15N medium and density gradient centrifugation.
2. So the correct choice is option (c).

Teacher's Note:
1. Heavy nitrogen 15N.
2. CsCl gradient.

Question 17: A point mutation involves
(a) deletion of a segment
(b) insertion of a segment
(c) a change in a single base pair
(d) duplication of a segment
Show Answer & Explanation

Answer: (c) a change in a single base pair

Explanation:
1. A point mutation alters one base pair of DNA, as in sickle cell anaemia.
2. So the correct choice is option (c).

Teacher's Note:
1. Single base change.
2. Deletion or insertion can cause frameshift.

Question 18: Satellite DNA is useful as a tool in
(a) forensic science
(b) genetic engineering
(c) organ transplantation
(d) sex determination
Show Answer & Explanation

Answer: (a) forensic science

Explanation:
1. Satellite DNA is highly repetitive and varies between people, so it is the basis of DNA fingerprinting.
2. So the correct choice is option (a).

Teacher's Note:
1. VNTR polymorphism.
2. Does not code for protein.

Question 19: Which one does not follow the central dogma of molecular biology?
(a) Chlamydomonas
(b) HIV
(c) pea
(d) Mucor
Show Answer & Explanation

Answer: (b) HIV

Explanation:
1. HIV is a retrovirus that copies RNA into DNA (reverse transcription), reversing the usual flow.
2. So the correct choice is option (b).

Teacher's Note:
1. Reverse transcription: RNA to DNA.
2. DNA to RNA to protein is the standard flow.

Question 20: PCR and restriction fragment length polymorphism (RFLP) are methods for
(a) DNA sequencing
(b) genetic fingerprinting
(c) study of enzymes
(d) genetic transformation
Show Answer & Explanation

Answer: (b) genetic fingerprinting

Explanation:
1. Both reveal DNA variations used for genetic fingerprinting.
2. So the correct choice is option (b).

Teacher's Note:
1. DNA profiling.
2. VNTR analysis.

Question 21: What forms the basis of DNA fingerprinting?
(a) relative amount of DNA in ridges of fingertips
(b) satellite DNA occurring as highly repeated short segments
(c) relative proportion of purines and pyrimidines
(d) difference in DNA content of blood and skin
Show Answer & Explanation

Answer: (b) satellite DNA occurring as highly repeated short segments

Explanation:
1. Repeated sequences (VNTRs) differ in number between individuals, producing unique band patterns.
2. So the correct choice is option (b).

Teacher's Note:
1. Not fingertips.
2. Inherited bands.

Question 22: DNA fragments generated by restriction endonucleases can be separated by
(a) restriction mapping
(b) centrifugation
(c) PCR
(d) electrophoresis
Show Answer & Explanation

Answer: (d) electrophoresis

Explanation:
1. Gel electrophoresis separates the negatively charged DNA fragments by size.
2. So the correct choice is option (d).

Teacher's Note:
1. Smaller fragments move farther.
2. Agarose gel.

Question 23: Commonly used vectors for human genome sequencing are
(a) T-DNA
(b) BAC and YAC
(c) expression vectors
(d) T/A cloning vectors
Show Answer & Explanation

Answer: (b) BAC and YAC

Explanation:
1. Bacterial and yeast artificial chromosomes carry large inserts.
2. So the correct choice is option (b).

Teacher's Note:
1. Used in the Human Genome Project.
2. Large DNA inserts.

Question 24: What is the correct sequence of the steps of DNA fingerprinting? (a) separation by gel electrophoresis (b) digestion by restriction endonuclease (c) isolation of DNA (d) hybridisation with labelled VNTR probe (e) Southern blotting
(a) a, b, c, d, e
(b) b, d, e, a, c
(c) c, b, a, d, e
(d) c, b, a, e, d
Show Answer & Explanation

Answer: (d) c, b, a, e, d

Explanation:
1. DNA is isolated, cut, separated by electrophoresis, transferred to a membrane (Southern blot) and then hybridised with a labelled probe.
2. So the correct choice is option (d).

Teacher's Note:
1. Isolate, digest, run, blot, probe.
2. Probe goes last.

Question 25: In sea urchin DNA, 17% of bases are cytosine. The expected percentages of the other three bases are
(a) G 17%, A 16.5%, T 32.5%
(b) G 17%, A 33%, T 33%
(c) G 8.5%, A 50%, T 24.5%
(d) G 34%, A 24.5%, T 24.5%
Show Answer & Explanation

Answer: (b) G 17%, A 33%, T 33%

Explanation:
1. G = C = 17%, so A + T = 66%, and A = T = 33%.
2. So the correct choice is option (b).

Teacher's Note:
1. G = C, A = T.
2. Sum to 100.

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